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The two blocks A and B having masses m = 5 kg and M = 25 kg as shown in the figure are free to move. The coefficient offriction between the blocks is us = 0.4, but the coefficient offriction between ground and M is zero. The minimumhorizontal force F required to hold m against M is 30 K.Newton, where K is equal to |
| Answer» 150 NExplanation:According to this question We have been given thatMass of blocks A and B is 5 KG and 25 kg and FRICTION between the blocks is = 0.4Here, the BLOCK with mass m not to slide down,μR = mg , Where R = minimum force of action ⇒ R = 125 NMinimum acceleration of the M blocka = = f (minimum) = (M + m)a = = 150 N | |