Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The prefix 'milli 'represents ________factor and explain plx​

Answer»

EXPLANATION:

Milli- ... Milli- (symbol m) is a UNIT PREFIX in the metric system denoting a factor of one thousandth (10−3). Proposed in 1793 and adopted in 1795, the prefix comes from the Latin mille, meaning "one thousand" (the Latin plural is milia).

2.

Page No.:In france during the old Regime the church toa extracted its sharetexes fromof​

Answer»

Peasants were obliged to RENDER services to the LORD – to work in his house and fields – to serve in the ARMY or to participate in building roads. The Church too extracted its SHARE of taxes called tithes from the peasants, and finally, all members of the THIRD estate had to pay taxes to the state.

3.

To slow down a Car, a braking force of 1200 N is applied for 10 s. How much force would beneeded to produce the same change in velocity in 6 s.​

Answer»

ANSWER:

2000 NEWTON

EXPLANATION:

this is the answer

4.

the plane of a circular coil is horizontal. It has 20 turns each of 8cm radius. A current of 1A flows through its which appears to be clockwise from a point vertically above it. Find the magnitude and direction of the magnetic field at the centre of the coil.​

Answer»

EXPLAINATION

..here is the answer

.formula at centre B=u°iN/2R

..u°=4 PIE ×10^-7.

i=1A

N=20

R=8×10^-2 metre

..

putting all VALUE...

B=5pie×10^-5..

.

.direction right HAND thumb rule..gives in -K^.

5.

What is meant by electric current ? Write its S.I. Units.​

Answer»

Answer:

An electric current is said to exist when there is a NET flow of electric CHARGE through a REGION. ... The SI unit of electric current is the ampere, which is the flow of electric charge across a surface at the rate of one COULOMB per SECOND.

6.

the external diameter d1 and internal diameter d2, of a metal tube are found to be (64 ± 2) mm and (47 ± 1) mm respectively. The percentage error in (d1-d2) expected from these readings is at most: A 0.3% B 1% C 5% D 6% E 18%​

Answer»

Answer:

3℅d56&$E*e~td 5€™={°dzFs€€¢

7.

The height of building is 13Meter express this in ft​

Answer»

Answer:

13 metres =

42 FEET 7.811 inches

Explanation:

1m=3feet3.37inches

hope it helps you

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8.

Which is best , a parallel connection or a series connection ?

Answer»

ᴀᴅᴠᴀɴᴛᴀɢᴇs ᴏғ ʜᴀᴠɪɴɢ ᴀᴘᴘʟɪᴀɴᴄᴇs ɪɴ ᴘᴀʀᴀʟʟᴇʟ ʀᴀᴛʜᴇʀ ᴛʜᴀɴ ɪɴ sᴇʀɪᴇs: ᴛʜᴇ ᴘ.ᴅ (ᴠᴏʟᴛᴀɢᴇ) ᴀᴄʀᴏss ᴇᴀᴄʜ ʟᴀᴍᴘ ɪs ғɪxᴇᴅ, sᴏ ᴛʜᴇ ʟᴀᴍᴘ sʜɪɴᴇs ᴡɪᴛʜ ᴛʜᴇ sᴀᴍᴇ ʙʀɪɢʜᴛɴᴇss, ɪʀʀᴇsᴘᴇᴄᴛɪᴠᴇ ᴏғ ʜᴏᴡ ᴍᴀɴʏ ᴏᴛʜᴇʀ ʟᴀᴍᴘs ᴀʀᴇ sᴡɪᴛᴄʜᴇᴅ ᴏɴ.

9.

Find the gravitational force acting between earth (Me = 6x 10^24 kg) and Moon(Mm =7-34x 10^22 kg) if distance between them is 384,400 Km.​

Answer»

ANSWER:

fG=Gm1m2/r^2

=6.67x10^-11x6x10^24x7.34x10^22/384400^2

SOLVE this EQAUTION

10.

The angle between the tangents drawn from the origin to the parabola y^2==4a(x-a) is

Answer»

Explanation:

LET the equation of the tangent y=mx (SINCE c=0)

Putting y=mx in the eqn of PARABOLA

m^2x^2=4a(x-a)

m^2x^2-4ax+4a^2=0

D=0 (since the tangent cuts the parabola at 1 pt...ROOTS are equal)

(4a)^2=4(4a^2)m^2

m=+1 or m=-1

we get the slopes of the 2 tangents as +1 and -1

Product of slopes =-1

Therefore angle between them is 90

11.

Dimension of Planck's constant is(B)ML2T-2ML27-1(D)MLT-2(C)MLT-1​

Answer»

ANSWER :

[ML^2T^{-1}]

Planck's constant is given by the formula

\tt Planck's\ constant = \dfrac{energy}{<klux>FREQUENCY</klux>}

\tt h =  \dfrac{e}{ \nu}

The dimensions of energy E is [ML^2T^{-2}] and DIMENSION of frequency is [T^{-1}] .

Using them in the above formula :

\tt h = \dfrac{[ML^2T^{-2}]}{[T^{-1}]}

\tt h = [ML^2T^{-1}]

_________________________

Planck's constant gives the energy radiated by one QUANTA of photon to the frequency of the radiation .

Its value of 6.62 × 10^{-34} Js.

Its SI unit is Joule second .

It was given by Planck hence named after him .

12.

Why do objects fall towards centre of gravity of earth only...???​

Answer»

It is also true that a free falling (no air resistance) OBJECT FALLS with an ACCELERATION of 9.8 m/s2—but it's still just the gravitational field. It doesn't MATTER what object you put near the surface of the Earth, the gravitational field due to the Earth is constant and POINTING towards the center of the Earth.

13.

Why prisms are used in the telescope​

Answer»

Answer:

A star DIAGONAL, erecting lens or diagonal mirror is an angled mirror or prism used in telescopes that allows viewing from a direction that is PERPENDICULAR to the usual eyepiece AXIS. It allows more convenient and comfortable viewing when the telescope is pointed at, or near the zenith (i.e. directly overhead).

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14.

Explain how defects in a mental block can be detected using ultrasound.

Answer»

Answer:

Defects in metal BLOCKS do not allow ULTRASOUND to pass through them and they are REFLECTED BACK. This fact is used to detect defects in metal blocks.

Explanation:

Defects in metal blocks do not allow ultrasound to pass through them and they are reflected back. This fact is used to detect defects in metal blocks. Ultrasound is passed through one end of a metal block and detectors are placed on the other end. The defective PART of the metal block does not allow ultrasound to pass through it. As a result, it will not be detected by the detector. Hence, defects in metal blocks can be detected using ultrasound.

15.

Derive an expression for the electric potential and field at a point any wheredue to electric dipole?​

Answer»

Derive an EXPRESSION for ELECTRIC potential at a POINT due to an electric dipole. ... Let an electric dipole CONSIST of two equal and opposite point charges –q at A and +q at B ,separated by a small distance AB =2A ,with centre at O.

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16.

A body is released from a height of 19.6 m. Find the velocity by which it strikes the groundand also find time taken to reach the ground.​

Answer»

GiVen

h=19.6m

u=0

g=9.8m/s²

To find

i.final VELOCITY(v)

ii.TIME

Solution--

i.v²-u²=2gh

v²-0=2×9.8×19.6

v²=384.16

v=19.6m/s

ii.v=u+gt

19.6=0+9.8t

19.6=9.8t

t=19.6/9.8

t=2s

Thus,velocity by which it srikes the ground is 19.6m/s and time taken is 2 seconds.

17.

Current through 10 ohm resistor shown in figure is​

Answer»

Answer:

CONSTANT

Explanation:

current passing through ohmic resistance will be constant it is VERIFIED by OHM's LAW

18.

A pipe of copper having an internal cavity weighs 264 in air and 221 gm in water, find the volume of the cavity (density of cavity is 8.8)

Answer»

ANSWER:

∴ Mass of water displaced by COPPER PIECE when COMPLETELY immersed in water is equal to 43 GM. Volume of cavity = 43.0 – 30.0 = 13.0 cc.

19.

Find electric field on the axis of electric dipole? or equater of dipole.​

Answer»

Answer:

Now, suppose that the point P is situated on the right-bisector of the dipole AB at a distance r metre from its mid-point 0 (Fig. (a)]

Again Let E

1

and E

2

be the magnitudes of the INTENSITIES of the electric field at P due to the CHARGES +q and −q of the dipole respectively. The distance of P from each charge is

r

2

+l

2

. Therefore,

and E

1

=

4πε

0

1

(r

2

+l

2

)

q

AWAY from +q

The magnitudes of E

1

and E

2

are equal (but directions are different). On resolving E

1

and E

2

into two components PARALLEL and perpendicular to AB, the components perpendicular to AB (E

1

sinθandE

2

sinθ) cancel each other (because they are equal and opposite), while the components parallel to AB (E

1

cosθandE

2

cosθ ), being in the same direction, add up [Fig. (b)]. Hence the resultant INTENSITY of electric field at the point P is

E=E

1

cosθ+E

2

cosθ

=

4πε

0

1

(r

2

+l

2

)

q

cosθ+

4πε

0

1

(r

2

+l

2

)

q

cosθ

=

4πε

0

1

(r

2

+l

2

)

q

2cosθ

But 2ql=p (moment of electric dipole)

∴ =

4πε

0

1

(r

2

+l

2

)

32

p

The direction of electric field E is 'antiparallel' to the dipole axis.

If r is very large compared to 2l (r>>2l), then l

2

may be neglected in comparison to r

2

.

E=

4πε

0

1

r

3

p

Newton/Coulomb

20.

Two charges + 2 micro coulomb and +8micro coulomb are separated by adistance 10cm apart in air where should a thirdcharge +5 micro coulomb be placed so that +5 micro coulomb charge is inequilibrium.Also and intensity of electric field at a point medwayb/w the charges.​

Answer»

EXPLANATION:

ANSWER and explanation given

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21.

Two charges + 2 micro coulomb and +8micro coulomb are separated by adistance 10cm apart in air where should a thirdcharge tshic be placed so that the charge is inequilibriumAlso and intensity of electric field at a point medwayb/w the charges.​

Answer»

Answer:

Given conditions ⇒

q₁ = 12 μC = 12 × 10⁻⁶ C.

q₂ = 8 μC = 8 × 10⁻⁶ C.

Distance between them(r₁) = 10 cm. = 0.1 m.

Final Distance between them(r₂) = 6 cm . = 0.06 m.

Work done in bringing the charges UPTO the distance of 6 cm is given by,

W = K q₁ q₂ (1/r₂ - 1/r₁) 

= 9 × 10⁹ × 12 × 10⁻⁶ × 8 × 10⁻⁶(1/0.06 - 1/0.1)

= 864 × 10⁻³ (16.67 - 10)

= 864 × 10⁻³(6.67)

= 5760 × 10⁻³

= 5.76 J.

22.

draw a circuit diagram to connect three 4 ohm resistors in parallel with a 12volt battery made up of 6 volts each cell.​

Answer»

ANSWER:

Here is your answer BUDDY

23.

A substance having a density of 0.3 g/cm will _________ in/on water​

Answer»

Answer:

YES it can FLOAT

Explanation:

SUBSTANCES of 0.2 to 0.3 or lower can float on WATER

24.

Is kirchoff voltage law is connected with IR drops??​

Answer»

Explanation:

His voltage LAW states that for a closed loop series path the algebraic sum of all the voltages around any closed loop in a circuit is equal to ZERO. ... HENCE any voltage drops around the loop must be equal to any voltage sources MET along the WAY.

25.

The external and internal diameters of a hollow cylinder are measured as (5.32±0.01) cm and (4.98±0.01) cm respectively. The thickness of the cylinder will be – (0.34 ± 0.01) cm (0.17 ± 0.00) cm (0.34 ± 0.02) cm (0.17 ± 0.02) cm

Answer»

it is not a MATTER to MAKE ROPE incrafter and MOBILE PHONE

26.

Instantaneous velocity is same as the average velocity atall instants for(1) Uniform motion(2) Non-uniform motion(3) Rectilinear motion(4) None of these​

Answer»

ANSWER:

hhhgfddssdddssssssssssssdddddddffffffggghhjjjjjjjjhhhhhhhhvvffffd

Explanation:

gujgfghkpkgrrcg

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27.

What is first law of motion​

Answer»

Explanation:

Newton's first law STATES that an object will remain at rest or in uniform MOTION in a straight line unless acted upon by an EXTERNAL force.

28.

Which of the cable will be thicker 5A or 10A give reason​

Answer»

Answer:

10A

Explanation:

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29.

a current of 1A is flowing in the sides of an equilateral triangle of side 2m. find the magnetic field at the centroid of the triangle​

Answer»

Answer:

PHYSICS

A current 1A is FLOWING in the sides of EQUILATERAL TRIANGLE of SIDE 4.5×!0

−2

m. The magnetic induction at centroid of the triangle is

question

December 26, 2019

avatar

Suseela Kankate

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ANSWER

Magnetic field at the centroid is given by,

B=3

4πa

μ

0

I

(sinθ

1

+sinθ

2

)

Here, θ

1

2

=60

Length =4.5×10

−2

m

a=

2

1

cot60

=

2

3

4.5×10

−2

Therefore,

B=

4.5×10

−2

3×10

−7

×1×2

3

2

2

3

=4×10

−5

T

B=4×10

−5

T

Explanation:

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30.

Two bodies of masses 10 kg and 20 kg are moving towards each other on the same straightline with velocities 2 m/s and 3 m/s respectively. They both collide and get stick with each other.Find the direction of motion and magnitude of velocity by which they both move together.​

Answer»

FOLLOW me DEAR for your FUTURE DOUBTS ❤️ ❤️❤️

31.

5) Two charges + 2 kee and the are separated by adistance 10cm apart in air where should a thirdcharge tshic be placed so that the charge is inequilibriumAlso and intensity of electric field at a point medwayb/w the charges.​

Answer»

Answer:

Given conditions ⇒

q₁ = 12 μC = 12 × 10⁻⁶ C.

q₂ = 8 μC = 8 × 10⁻⁶ C.

Distance between them(r₁) = 10 cm. = 0.1 m.

Final Distance between them(r₂) = 6 cm . = 0.06 m.

Work done in bringing the charges upto the distance of 6 cm is given by,

W = k q₁ q₂ (1/r₂ - 1/r₁) 

= 9 × 10⁹ × 12 × 10⁻⁶ × 8 × 10⁻⁶(1/0.06 - 1/0.1)

= 864 × 10⁻³ (16.67 - 10)

= 864 × 10⁻³(6.67)

= 5760 × 10⁻³

= 5.76 J.

32.

Help me in this physics of class 8 ....​

Answer»

Answer:

GOOD MORNING FRND, here is your answer

1-a

2-e

3-d

4-b

5-c

Hope it helped u plz FOLLOW me

33.

The equivalent capacitance capacitance from the network shown in the figure isthis question carries 100 points​

Answer»

EQUIVALENT of C2 c3 is 200

then parallel with C1 gives 300

300 SERIES with c4 gives 30000/400= 300/4

options are wrong I think.......

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34.

100 degree Fahrenheit = _______ degree Celsius​

Answer»

ANSWER:

38 ..............

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35.

If sin theta = 0.74 theta= ?​

Answer»

ANSWER:

Here's your answer-------------

36.

a capacitor is fully charged with voltage v and after removing battery one plate is given a charge Q now what is the voltage between two plates?​

Answer»

Answer:

The stored electric charge in a capacitor, Q (in coulombs, abbreviated C) is equal to the product of the capacitance C (in Farads, abbreviated F) of the capacitor, and the voltage V (in volts, abbreviated V) across its terminals. That is, Q = C٠V. For EXAMPLE, if C = 33uF and V = 20V, then Q = (33٠10^-6)٠(20) = 660uC.

Because the PLATES are separated by an INSULATING material, charge cannot cross the gap. An equal amount of charge is therefore repelled from the opposite plate, leaving it with a charge that is equal and opposite to the charge on the first plate. The two CONDUCTORS of.

37.

women and beautiful are electric potential intensity inside a liquid at temperature T1 and t2 to T1 is greater than 22 then V1 V2 is greater than is equal to​

Answer»

Answer:

Electric Potential

The electric potential energy per unit CHARGE is

V=\frac{U}{Q}.

Since U is proportional to q, the dependence on q CANCELS. Thus, V does not depend on q. The change in potential energy \text{Δ}U is crucial, so we are concerned with the difference in potential or potential difference \text{Δ}V between two points, where

\text{Δ}V={V}_{B}-{V}_{A}=\frac{\text{Δ}U}{q}.

Electric Potential Difference

The electric potential difference between points A and B, {V}_{B}-{V}_{A}, is defined to be the change in potential energy of a charge q moved from A to B, divided by the charge. Units of potential difference are joules per coulomb, given the name volt (V) after Alessandro Volta.

1\phantom{\rule{0.2em}{0ex}}\text{V}=1\phantom{\rule{0.2em}{0ex}}\text{J/C}

The familiar term voltage is the COMMON name for electric potential difference. Keep in mind that whenever a voltage is quoted, it is understood to be the potential difference between two points. For example, every battery has two TERMINALS, and its voltage is the potential difference between them.

38.

Is this circuit in series or parallel​

Answer»

ANSWER:

CIRCUIT is SERIES PARALLEL

39.

State one way to obtain a greater moment of a forceabout a given axis of rotation.​

Answer»

Explanation:

To obtain a greater MOMENT of force about a GIVEN axis of ROTATION the force should be APPLIED at the maximum distance from the axis and by increasing the magnitude of the force

40.

What is linear motion???. pls give ans in easy language.

Answer»

Answer:

hii..

EXPLANATION:

Linear EQUATION means equation in which two variables gives a straight LINE on the GRAPH.....

May it helps you...

41.

Equi potential surface are perpendicular to field line Wohy?​

Answer»

ANSWER:

sfgghhgwethvcdaqqrhlp8742227

42.

9. State one way to obtain a greater moment of a forceabout a given axis of rotation.​

Answer»

Moment of force is also called Torque represented by \tau .

It can be defined as the PRODUCT of force and perpendicular distance between the line of force and axis of ROTATION .

Torque = Force × Perpendicular distance

In vector FORM ,

\tt  \vec{\tau} =  \vec{r}\times  \vec{f}

The moment of force , hence , BECOMES DIRECTLY proportional to the force and perpendicular distance .

Therefore , to increase moment of force , following of the two could be done :

1) The magnitude of the force could be made larger .

2) The distance between axis of rotation and line of force could be increased .

SI unit of torque is Nm .

43.

2AAmteĘ RcheInuseven circuitlarocalculate-Chrough 5 ohmgiotoKirchoff's(1) current(18) valueFR​

Answer»

ANSWER:

SORRY but I can't understand the QUSTION and the language

44.

We can absorb ink using a piece of chalk? How it is posible?

Answer»

\mathcal{\huge{\underline{\underline{\red{Question:-}}}}}

Q. We can absorb ink using a piece of chalk? How it is POSIBLE?

\mathcal{\huge{\underline{\underline{\green{Answer:-}}}}}

✒ It is POSSIBLE to absorb ink using a piece of chalk.We can prove it experimentally.

Aim :- To absorb ink using a piece of chalk

Material Required :- Chalk, Inkpot, Dropper

Theory :- If a component of the gas mixture, transferred to liquid, is a gas at operating condition of mass transfer, then it is CALLED Absorption .

Procedure :-

  • Take a piece of chalk.
  • Take inkpot & dropper
  • PUT little amount of ink & repeat the process till observe.

Observation :- The chalk took color of ink.

Conclusion :- It's possible to absorb ink using a piece of chalk.

Precautions :-

  • Wear gloves .
  • Use aprain.
  • Do it on a piece of newspaper.

⬛ Hence, Proved , We can absorb ink using a piece of chalk. ✔

________________________________

45.

Why null vector is a vector?plz answe it in 20-30 words​

Answer»

ANSWER:

A vector is represented by direction and MAGNITUDE. If we take the number 0, it has no magnitude, and it can be given any sign. Similarly, null vector, also KNOWN as zero vector has no magnitude but can be given a direction. ... It MEANS that the vector is pointing in a certain direction but is still there.

Explanation:

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46.

The equation of motion v=u+at can be applied in which of the following cases

Answer»

Answer:

v = u + at

Explanation:

v = u + at can be applied when we have to FIND :-

1. final velocity when INITIAL velocity , acceleration ANT time is GIVEN.

2. initial velocity when final velocity , acceleration and time is given.

3. acceleration when initial velocity, final velocity and time is given.

4. time when initial velocity, acceleration and final velocity is given.

47.

Find atmospheric pressure 1.0*10^5N/m^2 value in CGS system

Answer»

1 N/m^2 = 10 dyne/cm^2

Therefore

1 atmospheric pressure = 1.01*10^6 dyne/cm^2 in CGS system

Explanation:

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48.

A piece of brass(alloy of zinc and copper weighs 12.9 gram in air when completely immersed in water, it weighs 11.3 gram. What is the mass of copper in the alloy And and I will mark u brain list

Answer»

A piece of BRASS ( ALLOY of COPPER and zinc) WEIGHS 12.9 gram in air. When completely immersed in water it weighs 11.3 G...

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49.

Find number of erg in 10 joule

Answer»

Explanation:

1 JOULE= 10^7 erg . Like all derived units of the CGS system, the erg is DEPRECATED and SI units should be USED instead (see SI BROCHURE, section 4.1, table 9). BUT , both are in CGS system.

50.

he percentage error in the measurement of mass and velocity of an object are 3 % and 5 % respectively. The percentage error in the measurement of the kinetic energy is

Answer»

Answer:

The PERCENTAGE errors in the measurement of mass and SPEED

Percentage error in the measurement of mass and speed are 2% and 3% RESPECTIVELY. The error in the measurement of kinetic energy OBTAINED by measuring mass and speed will be. ∴% error in K= (% error in m) +2(% error in v).

Explanation:

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