A body is released from a height of 19.6 m. Find the velocity by which

1.	A body is released from a height of 19.6 m. Find the velocity by which it strikes the groundand also find time taken to reach the ground.
Answer» GiVen h=19.6m u=0 g=9.8m/s² To find i.final VELOCITY(v) ii.TIME Solution-- i.v²-u²=2gh v²-0=2×9.8×19.6 v²=384.16 v=19.6m/s ii.v=u+gt 19.6=0+9.8t 19.6=9.8t t=19.6/9.8 t=2s Thus,velocity by which it srikes the ground is 19.6m/s and time taken is 2 seconds.

A body is released from a height of 19.6 m. Find the velocity by which it strikes the groundand also find time taken to reach the ground.

Answer»

GiVen

h=19.6m

u=0

g=9.8m/s²

To find

i.final VELOCITY(v)

ii.TIME

Solution--

i.v²-u²=2gh

v²-0=2×9.8×19.6

v²=384.16

v=19.6m/s

ii.v=u+gt

19.6=0+9.8t

19.6=9.8t

t=19.6/9.8

t=2s

Thus,velocity by which it srikes the ground is 19.6m/s and time taken is 2 seconds.

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A body is released from a height of 19.6 m. Find the velocity by which it strikes the groundand also find time taken to reach the ground.​