1.

Dimension of Planck's constant is(B)ML2T-2ML27-1(D)MLT-2(C)MLT-1​

Answer»

ANSWER :

[ML^2T^{-1}]

Planck's constant is given by the formula

\tt Planck's\ constant = \dfrac{energy}{<klux>FREQUENCY</klux>}

\tt h =  \dfrac{e}{ \nu}

The dimensions of energy E is [ML^2T^{-2}] and DIMENSION of frequency is [T^{-1}] .

Using them in the above formula :

\tt h = \dfrac{[ML^2T^{-2}]}{[T^{-1}]}

\tt h = [ML^2T^{-1}]

_________________________

Planck's constant gives the energy radiated by one QUANTA of photon to the frequency of the radiation .

Its value of 6.62 × 10^{-34} Js.

Its SI unit is Joule second .

It was given by Planck hence named after him .



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