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In physics and mathematics, the dimension of a mathematical space (or object) is informally defined as the MINIMUM number of coordinates needed to specify any point within it.[1][2] Thus a line has a dimension of ONE because only one COORDINATE is needed to specify a point on it – for example, the point at 5 on a number line. A surface such as a plane or the surface of a cylinder or sphere has a dimension of two because two coordinates are needed to specify a point on it – for example, both a latitudeand longitude are required to locate a point on the surface of a sphere. The inside of a cube, a cylinder or a sphere is THREE-dimensional because three coordinates are needed to locate a point within these spaces.
In mathematics, a set of elements (vectors) in a vector space V is called a basis, or a set of basis vectors, if the vectors are linearly independent and every vector in the vector space is a linear combination of this set. In more general terms, a basis is a linearly independent spanning set.

Give each of them in 8 whole and 3/4 part of each banana.
Or
Give 8 to each of them and EAT 3.
Hope it HELPED
-Ad.

Here we can SOLVE this QUESTION by METHOD of SUBSTITUTION

Amount is 6400.
divided amount THREE workers in the ratio 3/5:2:3/5.
add the ratio : 3/5+2/+3/5=16/5
he ASKED the share of second person whose ratio is 2.
that is equal to 2 divided by 16/5
we know that the denominator of a denominator will be shifted to numerator.
so,the 5 of 16/5 GOES to the numerator and gets multiplied by 2
and finally we get,
2×5/16×6400=10/16×6400
6400 can be divided by 16 as 16 × 4 is 6400
then we get 10 × 400=4000
therefore,the share of the second worker is 4000 rs.

PLEASE TYPE THE QUESTION DIRECTLY AS MUCH AS POSSIBLE, AS IT ALLOWS SEARCH THROUGH BRAINLY AND GOOGLE.

Q: Find the LAST digit of the sum of


Final Answer : 4

Solution : See Pic

Shri RAM MURTI Smarak College of Engineering and Technology (SRMSCET Lucknow), 
or
Saroj INSTITUTE of Technology and Management (SITM, Lucknow)
.
HOPE it helps..
.
Plz mark as brainiest :-)

Total no: of balls = 13

probablity of DRAWING a white ball in 1ST draw is 10/13

white ball in the 2nd draw is 9/12

white ball in the 3rd draw is 8/11

a black ball in 4th draw is 3/10

a black ball in the 5th draw is 2/9

a black ball in the 6th draw is 1/8

Therefore the REQUIRED probablity is 10/13 x 9/12 x 8/11 x 3/10 x 2/9 x 1/8 = 4320/1235520 = 432/123552

2square 3square 4square 5square 6square ETC...

Algebraic tooology is BRANCH of MATHS that TOOLS used to absract ALGEBRA to study topologyical SPACES

Hey...Mate...!!!!
Here's ur answer.....

Some important formulas of..

1). STATISTICS : —

>> MODE = l + f1 – f0 / 2f1 – f0 –f2 × h .
>> MEAN ( for grouped data )
= sigma fixi / sigma fi.
>> Mean ( for UNGROUPED data )
= sigma x / n
>> Median ( for grouped data )
= l + ( n/2 – cf / f ) × h
>> Empirical FORMULA
= 3 median = Mode + 2Mean.

2). Probability :–

>> P (E) = No.of outcomes favourable to E
/ No.of all possible outcomes.
>> P (E) = 1– P ( E).

Hope it helps....!!!!!

HOPE IT HELP U....
.... this 5 PICS help u

if yes PLEASE mark brainlist

In ONE DAY CLOTH is PRODUCED= 3746m
in 286 day cloth is produced=3746x286=1071356m

Please ASK CLEAR QUESTION so that you might get your ANSWER.

0.2424424442444 and 0.2442442444244442444444444424444

I HOPE this ANSWER HELP you

The auctioneer GETS 8% (0.08 in DECIMAL form) of the sale price:

($230,500)*(0.08) = $_______

You can also solve this by setting up a PROPORTION:

8% $x
-------- = -------------
100% $230,500

Solve for x, where x is the amount of MONEY the auctioneer gets.

Your QUESTION is not CLEAR.

5x-6y=-30
First SOLUTION can be
x=0,y=5
Second solution can be
x=5,y=0
Third solution can be
x=3,y=5

The SQUARE ROOT of 151129 is 123.................123*123=151129

A=bq+r 0_b=3 r=0,1,2
r=0
a=3q+0
SQUARE on both SIDE
A2 = 9q2
a2=3 (3Q2) p=3q2
a2=3p
r=1
a=3q+1
square on both side
a2=9q2+1+6q
a2=3 (3q2+2q)+1 p=3q2+2q
a2=3p+1
r=2
a=3q+2
square on both side
a2=9q2+4+12q
a2=9q2+3+1+12q
a2=3 (3q2+1+4q)+1 p=3q2+1+4q
a2=3p+1

Hola!
_______________________

Let the speed of JOSEPH = x km/h

Let the speed of Hamid = y km/h

Case 1. ]
Approaching one another, combined speed = (x+y)km/h

Time TAKEN to meet = 30/(x+y) = 1/3  (20 minutes = 1/3 hours)

x+y = 90 ------ [ i ]

Case 2. ]
When moving in opposite direction, combined speed = (x-y)km/h

Time taken for Hamid to CATCH up = 30/(x-y) = 3

x-y = 10 ----[ ii ]

Solving [ i ] and [ ii ] simultaneously,

x = 40
n'
y = 50

Hence,

Speed of Joseph = x = 40km/h
Speed of Hamid = y = 50km/h

_______________________

Hope it helps! :D

I DONT KNOW SORRY sorry sorry

Here is your ANSWER 0.00000059=59/100000000 or 59/10^8

Abx2+b2x-acx-bc=0
Bx(ax+b)-C(ax+b)=0
(ax+b) (bx-c) =0
X=-b/a,x=c/b=0
Hope it's HELP you FRIEND ☺️

Here is your answer
-------------------------------

1 lakh => 100 Thousand

5 LAKHS => 100 × 5
=> 500

===================================================

THEREFORE answer is 500

There are 10 THOUSANDS in TEN thousand...i hope its help U..

1/3=0.333333333.......
1/2=0.5

There are 5 TEN THOUSANDS

★Ello ★

here is your answer !!


X = 3 + ✓8


there FORE ,

1 /x = 1 / 3 + √ 8 × 3 -✓8 / 3 - ✓ 8

{ rationalize. }


1 / x = 3 -✓8 / 9 -8

=> 1 / x = 3 -✓ 8 / 1


now ,.



x + 1 / x => 3 + √ 8 + 3 - ✓ 8

=> x + 1 / x = 6



=> (x + 1 / x )² = x² + 1 / x² + 2 × x × 1 / x


=> ( 6 )² = x² + 1 / x² + 2


x² + 1 / x² = 36 -2


=> x² + 1/ x² = 34 .



hence proved !!!



hope it helps you dear !!

THANKS !!