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Answer» Hola! _______________________
Let the speed of JOSEPH = x km/h
Let the speed of Hamid = y km/h
Case 1. ] Approaching one another, combined speed = (x+y)km/h
Time TAKEN to meet = 30/(x+y) = 1/3 (20 minutes = 1/3 hours)
x+y = 90 ------ [ i ]
Case 2. ] When moving in opposite direction, combined speed = (x-y)km/h
Time taken for Hamid to CATCH up = 30/(x-y) = 3
x-y = 10 ----[ ii ]
Solving [ i ] and [ ii ] simultaneously,
x = 40 n' y = 50
Hence,
Speed of Joseph = x = 40km/h Speed of Hamid = y = 50km/h
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Hope it helps! :D
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