1.

For what value of k are the following system of equation have a unique solution 2x+3y=5, 6x+ky=15

Answer» HI ,

COMPARE 2x + 3y - 5 = 0 , 6x + ky - 15= 0 , with a1x + b1y + c1 = 0 and

a2 x + b2 y + c2 = 0 , we get

a1 = 2 , B1 = 3 , c1 = - 5 ;

a2 = 6 , b2 = k , c2 = - 15 ;

a1/a2 ≠ b1/b2

[ Since system of EQUATIONS has

UNIQUE solutions ]

2/6 ≠ 3/k

1/3 ≠ 3/k

3/3 ≠ k

Therefore ,

k ≠ 1

I hope this helps you.

: )


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