This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the power set of the following. [i] A=∅ [ii] B={1,2} [iii] C={p,q,r} NO OPTIONS PLEASE |
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Answer» ong>Answer:P> 1. Nothing2. 1 and 23. p,Q and R |
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| 2. |
Find the value of the unknownvariables in all the parts. ofx-15 = 1/2(x+5) |
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Answer» ONG>Answer: x=35 Step-by-step explanation: by SOLVING the EQUATION USING TRANSPOSITION method |
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| 3. |
Whichofthefollowingexpressionis not zero |
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Answer» WER : The QUESTION is INCOMPLETE. |
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| 4. |
Solve these questions with explanation. |
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Answer» ONG>Answer: 13. y-25° x-155° z-155° |
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| 5. |
The value of log 1 base2 × log 1 base 2× log 16 base 2. |
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Answer» ong>ANSWER: VALUE \: of \: log_{2}16-log_{2}2 = 3Valueoflog 2
16−LOG 2
2=3 |
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| 6. |
Use suitable special products to find each of the following: ( x + 7 ) ( x + 13 ) |
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Answer» ONG>Step-by-step EXPLANATION: (x+7)(x+13) = x²+13x+7x+91 = x²+20x+91 |
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| 7. |
The sides of a triangle are in the Ratio 3:5:7 and its perimeter is 75cm. Find its all sides |
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Answer» ONG>Answer: 15cm, 25CM, 35cm Step-by-step EXPLANATION: |
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| 8. |
List the member of set {x | x is a positive integer less than 12} |
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Answer» the MEMBER of SET {x | x is a positive INTEGER LESS than 12} |
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| 9. |
Plz solve this guys plz give correct answer |
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Answer» ONG>Answer: 85 Step-by-step EXPLANATION: because it has factors that are 5, 3, and more.... so it's a composite ONE while OTHERS are not having factors other than 1 and the number itself.. If this helps plz mark braniliest |
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| 10. |
Please write and solve |
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Answer» hshhsbwbaisbashajssnsbshhsjqnsbbs |
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| 13. |
1. Find the point of intersection of the straight lines4x + 8y-1 =0, 2x-y+1=0 |
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Answer» ong>ANSWER: simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3 Step-by-step explanation: |
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| 14. |
How to find magnitude of applied force |
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Answer» ong>Answer: USING the x and y coordinates for the components, this gives F = √(X2 + Y2) for the magnitude of the force. Find the resultant force from TWO vectors by first ADDING the x-components and y-components to find the resultant vector and then use the same formula for its magnitude. |
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| 15. |
G. 2 Evaluatei) 22-4 of (9-4)+4x3 |
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Answer» ONG>Answer: 102 Step-by-step explanation: 22-4 of (9-4)+4x3 18×5+12 102 hope it will help and... |
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| 18. |
Use the fundamental definition of derevative to show that the function f(x) = x^2/3 does not enist at tangent x= o ?. Does it have a tangent At x=0? |
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Answer» ONG>Answer: SMCHD skshf kw dkjdbdjdnbeheidnjcjf rckndn xkdklend djebjs d Step-by-step explanation: neejfh ejwbvr jebdjkde kdklwhfb rjjeone jejrjbbf dkkeken kwpdjd. kdkkwhe. jdjeken.vhwkjdbe, jdjenfbbfbfn(₹+_+&!(7916bxhekhxbsbshfb djdhfn jednjfjfhrkkd fjjrhgjfkkdfjg gktjhr dkfbfjkd kdndbdn dknrr lfnf kf if ffkfn jkdxhdoddj kdbd dmsndxndk and fkd kdfnr fkfkbff. fleebd FGK fkfkbff |
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| 19. |
Difference of squares of two numbers is 200 and six times The square of one number Is equal To tenTimes The larger number . Then the larger number is |
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Answer» ong>Given : Difference of SQUARES of two NUMBERS is 200 and six times The square of one number Is equal To TENTIMES The larger number To Find : the larger number LET say smaller number = S Larger number = L Difference of squares of two numbers is 200 => L² - S² = 200 The square of one number Is equal To ten Times The larger number . => 6S² = 10L => S² = 10L/6 => S² = 5L/3 L² - S² = 200 => L² - 5L/3 = 200 => 3L² - 45L + 40L - 600 = 0 => 3L(L - 15) + 40(L - 15) = 0 => (L - 15)(3L + 40) = 0 L = 15 Larger Number is 15 Learn More: the sum of a number and its positive square root is 6 / 25 find the ... Difference of the square and square root of a perfect square number ... |
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| 20. |
Which of the following is a pair of twin primes |
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Answer» ong>(A) Option 5 & 7 is the CORRECT pair of twin prime numbers. HoPe iT HELPS YoU ♥️♥️♥️ |
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| 21. |
Log 256 base 4 + log 81 base 3 - log x base 2 |
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Answer» ONG>ANSWER: hshsjxnxndkdnbdhdbcncjc Step-by-step EXPLANATION: hxbxixbbdudbdndhhdndbdbdj |
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| 22. |
Prove that -x = (-1)x. and what kind of axiom? |
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Answer» ONG>ANSWER: hshshdhdudududu Step-by-step EXPLANATION: don't KNOW ushshshdhdhfud7383728736$-$:$({¢{`×~¶}©® |
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| 23. |
Plz solve this ...plz |
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Answer» Step-by-step explanation: maximum measuring weight=HCF of 75&69 HCF=3, so maximum measuring weight=3 |
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| 24. |
10thterm of ap sequence √2,√8,√18... |
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Answer» ong>ANSWER: SIMPLY and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3simply and write the answer in exponential form 1. (-4)^-3*(5)^-3*(-5)^-3 Step-by-step EXPLANATION: |
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| 25. |
A car covers 72 km in 2 hrs and a train 120 km in 3 hrs find the ratio of their speed |
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Answer» ONG>Answer: 9 : 10 Or 9/10 Step-by-step EXPLANATION: |
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| 26. |
Q2. Find the value of x for which the distance between points A(x,7) and B (-2,3) is 4V5 units. |
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Answer» ong>Answer: Q2. Find the value of x for which the DISTANCE between POINTS A(x,7) and B (-2,3) is 4V5 UNITS. |
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| 27. |
parallel sides of trapeziumm is 7 cm and 13 cm and each is non parallel side is 5cm long .Find the area of trapezium |
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Answer» ong>Answer: SOLUTION Let PQRS be the given trapezium in which PQ ║ SR.
Draw RX ⊥ PQ and RY ║ SP, these meeting PQ at X and Y.
It is clear that PYRS is a parallelogram.
∴ PY = SR = 13 cm YQ = PQ - PY = 25 cm - 13 cm = 12 cm
Now, RY = SP = 10 cm and RQ = 10 cm
∴ ΔRYQ is an ISOSCELES triangle and RX ⊥ YQ.
Clearly, X is the midpoint of YQ. ∴ XY = XQ = 1/2 × YQ = 1/2 × 12 CM = 6 CM
In ΔRXY, we have (RX)² = (RY)² - (XY)² (Here we use Pythagoras theorem) = (10)² - (6)² = 100 - 36 = 64 ⇒ RX = 8 cm
Area of the trapezium PQRS = 1/2 × (25+13) × 8 = 152 cm² |
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| 28. |
Given a=2 ,d=8, Sn=90, find a= ? and A9 |
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Answer» ONG>Step-by-step explanation: Here, Given : a = 2 d = 8 sn = 90 So, According to formula , Sn = a + ( 2d - a)d = A9 90 = 2 + ( 16 - 2) 8 90 = 2 + 128 - 16 90 = 130 -16 90A9= 114 A9 = 114/90 |
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| 29. |
Use the sign of >,< or = in the box a) (-3) + 8 - (10) _ 12- 8+ (-7)b) 10+ (-12) - 5__ (-16) + 3+6c) -1+(-2)+(-3)__(-3)+(-4)+(-1) |
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Answer» ong>ANSWER: a) -3+8-10___12-8-7 -3-2 ____4-7 -5___-3 -5 < - 3 b) 10-12-5____-16+3+6 - 2-5 ___-16+9 -7___-7 - 7 = - 7 c)-1-2-3____-3-4-1 - 3-3____-7-1 -6____-8 -6 > - 8 |
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| 30. |
an alloy of copper and zinc consists of 30% and 70% respectively how many parts of zinc are there in the alloy to every 39 parts of copper ? |
| Answer» ONG>ANSWER: | |
| 31. |
The area of a room is 65 1 by 4 metre square if its breadth is 5 1 by 16 what is its length |
| Answer» ONG>ANSWER: | |
| 32. |
the population of a town decreases to 100000 in the year 2010 at a rate of 5% per annum . find the population before 5 years in the year 2005. |
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| 33. |
An object is sold at a profit of 10 percent . What is the ratio of its cost price to sale price ? |
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Answer» ong>Answer: s.p =10 % s.p = 10/100 s.p=1/10 s.p -c.p = PROFIT so the RATIO is 2:3
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| 34. |
Which of the following are quadratic equation 2x²-√5x+7=0 |
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Answer» ONG>Answer: yes it is QUADRATIC equation because HIGHEST power of equation is 2 hope it will help youfollow me on brainly ALSO on Instagram I'd skg9304 |
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| 35. |
find LCM and HCF of the following number using prime factorization method (1) 455 and 78 (2) 408 and 170 (3)275, 225, 175 (4) 765, 510, 408 (5) 19, 13, 7 (6) 96 404 |
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Answer» ong>Answer: Find the LCM and HCF of 455 and 78 by using the PRIME factorization method. 455 = 5 × 13 × 7 78 = 2 × 3 × 13. HCF = 13. LCM = 2730.lcm (408; 170) = 2,040: least common multiple, calculated. The NUMBERS have common prime FACTORS. |
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| 36. |
Value of (sin30° + cos30°) – (sin 60° + cos60°). |
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Answer» ONG>Answer: 0. given that, =(sin30+cos30)-(sin60+cos60) [sin30=1/2,cos30=root3/2 and sin60=root3/2 ,cos60=1/2] Now, =(1/2+root3/2)-(root3/2-1/2) =(root3+1÷2)-(root3+1÷2) Here,same VALUES with + and - =0 so ,=0. |
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| 37. |
Two polygons are similar, if their corresponding sides are proportional (True or False) . the answer is False mentioned in rd sharma but i think it should be true |
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Answer» ONG>ANSWER: don't KNOW if you yfgiesg |
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| 38. |
1 log, y'log, y log, zlog, a 1. log, zlog, x log, y lх= 0 |
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Answer» ong>ANSWER: ans is 0 of the question |
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| 39. |
If the sum of two number's is 15 and their HCF is 5. Find all such possible pairs of number |
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Answer» ong>Answer: Answer KANCHAN Sinha only TWO PAIRS. Step-by-step EXPLANATION: (5,10);(10,5) |
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| 40. |
33) A card is drawn from a well shuffled deck of 52 card. Find the probability of being (i) A jack or king.(ii) A black ace.(iii) A seven of hearts. |
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Answer» WER : (i) 4/52 + 4/52 = 8/52 = 2/13 (II) 2/52 (III) 1/52 |
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| 41. |
Good whorth ₹3000 were stolen by an employee |
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Answer» ONG>Answer: them what can I do please tell FULL question Step-by-step EXPLANATION: |
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| 42. |
What should be fill up in the following a)0 b)1 c)-1 |
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Answer» ONG>Answer: 0 Step-by-step EXPLANATION: |
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| 43. |
✓sin²+cosec² = tan+cot |
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Answer» ong>Answer: SOHCAHTOA Sin θ = Opposite side / HYPOTENUSE side Cos θ = ADJACENT side / Hypotenuse side Tan θ = Opposite side / Adjacent side Csc θ = Hypotenuse side / Opposite side Sec θ = Hypotenuse side / Adjacent side Cot θ = Adjacent side / Opposite side Reciprocal Trigonometric Identities Sinθ = 1 / Cosecθ Cscθ = 1 / Sinθ Cosθ = 1 / Secθ Secθ = 1 / Cosθ Tanθ = 1 / Cotθ Cotθ = 1 / Tanθ Other Trigonometric Identities Sin²θ + Cos²θ = 1 Sin²θ = 1 - Cos²θ Cos²θ = 1 - Sin²θ Sec²θ - Tan²θ = 1 Sec²θ = 1 + Tan²θ Tan²θ = Sec²θ - 1 Csc²θ - Cot²θ = 1 Csc²θ = 1 + Cot²θ Cot²θ = Csc²θ - 1 Double Angle Identities Sin2A = 2 ⋅ SinA ⋅ CosA Cos2A = Cos²A - Sin²A Tan2A = 2 ⋅ TanA / (1 - Tan²A) Cos2A = 1 - 2 ⋅ Sin²A Cos2A = 2 ⋅ Cos²A - 1 Sin2A = 2 ⋅ TanA / (1 + Tan²A) Cos2A = (1 - Tan²A) / (1 + Tan²A) Sin²A = (1 - Cos2A) / 2 Cos²A = (1 + Cos2A) / 2 Half Angle Identities SinA = 2 ⋅ Sin(A/2) ⋅ Cos(A/2) CosA = Cos²(A/2) - Sin²(A/2) TanA = 2 ⋅ Tan(A/2) / [1 - Tan²(A/2)] CosA = 1 - 2 ⋅ Sin²(A/2) CosA = 2 ⋅ Cos²(A/2) - 1 SinA = 2 ⋅ Tan(A/2) / [1 + Tan²(A/2)] CosA = [1 - Tan²(A/2)] / [1 + Tan²(A/2)] Sin²A/2 = (1 - Cos A) / 2 Cos²A/2 = (1 + Cos A) / 2 Tan²(A/2) = (1 - CosA) / (1 + CosA) Compound Angles Identities Sin(A + B) = SinA ⋅ CosB + CosA ⋅ SinB Sin(A + B) = SinA ⋅ CosB + CosA ⋅ SinB Cos(A + B) = CosA ⋅ CosB - SinA ⋅ SinB Cos(A - B) = CosA ⋅ CosB + SinA ⋅ SinB Tan(A + B) = [TanA + TanB] / [1- TanA ⋅ TanB] Tan(A - B) = [TanA - TanB] / [1 + TanA ⋅ TanB] Sum to PRODUCT Identities SinC + SinD = 2 ⋅ Sin[(C+D) / 2] ⋅ cos [(C-D) / 2] SinC - SinD = 2 ⋅ Cos [(C+D) / 2] ⋅ Sin [(C-D) / 2] Step-by-step EXPLANATION: pls follow |
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| 44. |
Arjun deposited a sum of ₹8000 in the Bank for 1 year, compounded half-yearly at 10% per annum. Find the compound interest he gets. |
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Answer» ong>Answer: Arjun deposited a sum of ₹8000 in the Bank for 1 year, compounded half-yearly at 10% PER annum. Find the COMPOUND INTEREST he GETS. |
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| 45. |
Some of first 20 odd natural numbers is:- |
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Answer» ong>Answer: 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25 + 27 + 29 + 31 + 33 + 35 + 37 + 39 = 400 |
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| 47. |
Find the value of - 56 - ( -13) + 15 |
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Answer» ong>Answer: -28 Step-by-step EXPLANATION: -56 -(-13) + 15 we KNOW, minus × minus = positive so,
-56 +13 +15 -56 +28 = -28 is the answer Love you ❤ and thank you |
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| 48. |
Please do this, rationalise the denominator , I will mark brainliest plz urgently. |
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Answer» ong>Step-by-step EXPLANATION: Answer : Now, y = {√(a + X) + √(a - x)}/{√(a + x) - √(a - x)} We RATIONALISE the denominator by multiplying both the numerator and the denominator by {√(a + x) + √(a - x)} So, y = {√(a + x) + √(a - x)}{√(a + x) + √(a - x)}/{√(a + x) - √(a - x)}/{√(a + x) + √(a - x)} = {a + x + 2√(a² - x²) + a - x}/(a + x - a + x) = {2a + 2√(a² - x²)}/(2x) ⇒ XY = a + √(a² - x²) ⇒ xy - a = √(a² - x²) Now, squaring both sides, we get (xy - a)² = a² - x² ⇒ x²y² - 2axy + a² = a² - x² ⇒ xy² - 2ay = - x ⇒ xy² - 2ay + x = 0 |
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| 49. |
Ehat is the answer to this math problem 0.59–0.46 for me?? |
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Answer» ONG>Answer: 0.13 Step-by-step EXPLANATION: |
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| 50. |
Express the following in the form p/q, where p and q are integers and q = 0. 0.47 0.001 . |
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Answer» er: 47/100 1/1000 Step-by-step EXPLANATION: |
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