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✓sin²+cosec² = tan+cot |
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Answer» ong>Answer: SOHCAHTOA Sin θ = Opposite side / HYPOTENUSE side Cos θ = ADJACENT side / Hypotenuse side Tan θ = Opposite side / Adjacent side Csc θ = Hypotenuse side / Opposite side Sec θ = Hypotenuse side / Adjacent side Cot θ = Adjacent side / Opposite side Reciprocal Trigonometric Identities Sinθ = 1 / Cosecθ Cscθ = 1 / Sinθ Cosθ = 1 / Secθ Secθ = 1 / Cosθ Tanθ = 1 / Cotθ Cotθ = 1 / Tanθ Other Trigonometric Identities Sin²θ + Cos²θ = 1 Sin²θ = 1 - Cos²θ Cos²θ = 1 - Sin²θ Sec²θ - Tan²θ = 1 Sec²θ = 1 + Tan²θ Tan²θ = Sec²θ - 1 Csc²θ - Cot²θ = 1 Csc²θ = 1 + Cot²θ Cot²θ = Csc²θ - 1 Double Angle Identities Sin2A = 2 ⋅ SinA ⋅ CosA Cos2A = Cos²A - Sin²A Tan2A = 2 ⋅ TanA / (1 - Tan²A) Cos2A = 1 - 2 ⋅ Sin²A Cos2A = 2 ⋅ Cos²A - 1 Sin2A = 2 ⋅ TanA / (1 + Tan²A) Cos2A = (1 - Tan²A) / (1 + Tan²A) Sin²A = (1 - Cos2A) / 2 Cos²A = (1 + Cos2A) / 2 Half Angle Identities SinA = 2 ⋅ Sin(A/2) ⋅ Cos(A/2) CosA = Cos²(A/2) - Sin²(A/2) TanA = 2 ⋅ Tan(A/2) / [1 - Tan²(A/2)] CosA = 1 - 2 ⋅ Sin²(A/2) CosA = 2 ⋅ Cos²(A/2) - 1 SinA = 2 ⋅ Tan(A/2) / [1 + Tan²(A/2)] CosA = [1 - Tan²(A/2)] / [1 + Tan²(A/2)] Sin²A/2 = (1 - Cos A) / 2 Cos²A/2 = (1 + Cos A) / 2 Tan²(A/2) = (1 - CosA) / (1 + CosA) Compound Angles Identities Sin(A + B) = SinA ⋅ CosB + CosA ⋅ SinB Sin(A + B) = SinA ⋅ CosB + CosA ⋅ SinB Cos(A + B) = CosA ⋅ CosB - SinA ⋅ SinB Cos(A - B) = CosA ⋅ CosB + SinA ⋅ SinB Tan(A + B) = [TanA + TanB] / [1- TanA ⋅ TanB] Tan(A - B) = [TanA - TanB] / [1 + TanA ⋅ TanB] Sum to PRODUCT Identities SinC + SinD = 2 ⋅ Sin[(C+D) / 2] ⋅ cos [(C-D) / 2] SinC - SinD = 2 ⋅ Cos [(C+D) / 2] ⋅ Sin [(C-D) / 2] Step-by-step EXPLANATION: pls follow |
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