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Value of (sin30° + cos30°) – (sin 60° + cos60°). |
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Answer» ONG>Answer: 0. given that, =(sin30+cos30)-(sin60+cos60) [sin30=1/2,cos30=root3/2 and sin60=root3/2 ,cos60=1/2] Now, =(1/2+root3/2)-(root3/2-1/2) =(root3+1÷2)-(root3+1÷2) Here,same VALUES with + and - =0 so ,=0. |
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