Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Integrate with special from

Answer»

What PERCENTAGE of 36 is 144

2.

A man travels 370 km, by the train and partly by car. If he covers 250 km by train and the rest by car, it takes him 4 hours. But if he travels 130 km by train and rest by car , he takes 18 minutes longer. Find the speed of the car.

Answer»

I HOPE it will HELP you

3.

Let a b and c be the sets such that aub=auc and

Answer»

This MEANS that, SET B=set C

4.

Please answer these . All 3

Answer» 7. (D)6
8. (D)not defined
9. (B)-5/2
5.

Solution for 12 science mathematics

Answer»

This is the BOOK for 12TH SCIENCE MATHEMATICS

6.

7. Express y in terms of x and x in terms of y from the following equation 5 x +2 y −15=0

Answer»

5x +2Y -15=0

=>5x+2y=15

=>5x =(15-2y)

=>X=(15-2y)/5 ......(1)

again 5x+2y=15

=>2y=15-5x

2y=5(1-x)

=>y=5(1-x)/2.......(2)

7.

Solution Math alternative

Answer» 1 - (C) 45 DEGREE

I KNOW only 1
8.

on dividing a natural number by 13 the remainder is 3 and on dividing a number by 21 the remainder is 11 if the number lies between 500 and 600 then find the number and find the remainder on dividing the number by 19

Answer»

Answer:

The required Number is 536 and remainder is 4.

Step-by-step EXPLANATION:

Let x be the number.

using DIVISION algorithm we get,

x = 21A + 11.

Also, x = 13b + 3

Now let's find the smallest such number.

21a + 11 = 13b + 3.  

21a - 13b = - 8

The smallest a and b which ensures that we get an integer is a = 12 and b = 20. Substitute in above equations and we get the smallest number to be 260.

Now to get the next solution, we can take a=25 and b=41.

So, the number is 536, which as required lies between 500 and 600.

Now DIVIDING 536 by 19.

We get remainder = 4.

Therefore, The required Number is 536 and remainder is 4.

9.

1+tan²x=sec²x is an identity

Answer»

I THINK it will HELP you

10.

Write the the answer

Answer»

When we add 7 on the RHS side the LHS side which was PREVIOUSLY EQUAL to the RGS side becomes 7times more
here it can be expressed mathematical
RHS = LHS ---1
7 RHS = LHS---2

11.

Factorize this sum...The fastest and correct answer will be marked as the brainliest answer.... Answer asap!!!!!!!!!!

Answer» SEE this PIC DEAR...........
12.

.5g Express it into gram, decagram,centigram,milligram

Answer» 5G 5 GM
15g = 5000 decegram
5g= 500 centigram
5g= 0.005
13.

Solve: 2x/2x^2+5x+2 > 1/x+1

Answer» ANSWER is
x >  \frac{ - 1}{5}
14.

This Point of bisectots is known as

Answer»

✔✔ The POINT of BISECTORS is KNOWN as INCENTER...

HOPE it helps to you!!!!!✌✌

15.

if 20% of a certain quantity of work is done by A abd after that the remaining 80% of work is done by B the work will be completed in 20 days if 80% of the work is done by A and after that the remaining 20 % of tge work is done by B the work will be completed in 30 days how many days are required to complete the work if A and B work together?

Answer»

LET,


A TAKE 'a' days to complete 100% work.

B take 'b' days to complete 100% work.


I. 20% by A and 80% by B :


20% of work by A => A took a/5 days

80% of work by B => B took 4b/5 days


So, (a/5) + (4b/5) = 20

=> a+4b = 100 ---->(1)


II. 80% by A and 20% by B :


80% of work by A => A took 4a/5 days

20% of work by B => B took b/5 days


So, (4a/5) + (b/5) = 30

=> 4a+b = 150 ---> (2)



Solving (1) and (2), we GET ,


a = 100/3 days , b = 50/3 days


A's one-day work = 3/100 and B's one-day work = 3/50

Thus, A and B's one-day work (combined) = 3/100 + 3/50 = 9/100


Thus they WOULD take 100/9 = 11 1/9 days to complete the work.


Regards,

KKKoppu


16.

Angle of elevation of a point 100 mts from the foot of the tree is 60°.find height of the tree

Answer» HEYA !!

LET AB be the three .




BC = 100 m



Angle ACB = 60°



Tan60° = AB/BC




✓3 = AB/100



AB = 100✓3 m.




Hence,



Height of TREE ( AB ) = 100✓3 m.
17.

Integrate it with special from

Answer»
\frac{ {t}^{3} }{3}  - t
t = COS(X)
PUTTING t in the EQUATION

\frac{ { \cos(x) }^{3} }{3}  -  \cos(x)



18.

27 a ka whole cube - 216 b ka whole cube minus b ka whole cube minus 54 ABC

Answer»

A3+b3+c3=3abc USE FORMULA

19.

Find the value of sin 340

Answer»

0.65 is the APPROX VALUE of SIN 340

20.

Solve the given equation x+y = 6, x = y+2

Answer» HOPE this HELPS you☺️
21.

Please give me answer of questions 70 and 71 in detail

Answer»

for ques 71 just do the expansion

for

e^x = 1 + x + x^2/2

cosx = 1 - x^2/2

tan^x = x^2

now KEEP these VALUES and u will get the ANSWER


22.

Reena has 524 twenty rupee notes.how much money does she have

Answer»

No of 20 RUPEE NOTE- 524
Total money=524×20= RS 10480

23.

in triangle ABC angle A- angle B is equal to 33 degree and Angle B- angle C is equal to 18 degree find the measure of each of the angle of the triangle

Answer»

Angle A is 88 DEGREE
angle B is 55 degree
angle C is 37 degree......

24.

Solve the given equation x-2y = 5, 2x-4y = 6

Answer»

X=5-2y -----1
put EQU 1 in equ. 2
2(5-2y) -4Y =6
10-4y-4y = 6
10-8y =6
-8y=6-10
-8y= -4
therefore
y =1/2 or 0.5

25.

How many seconds are there in 35 minutes

Answer»

Heya mate,
Here's your answer
=> 1 minute=60 SEC.
Therefore,35 min=35×60=2100 seconds.
HOPE it HELPS you
Plz MARK my answer as branliest :)

26.

Plzz solve the question

Answer»

HOPE it HELP u

plz MARK as a BRAINLIEST

27.

Find x.Please solve this question as soon as possible...

Answer»
16 \sqrt[4]{3} \:  is \: the \: answer
28.

if one angle of a triangle is greater than the sum of other two show that the triangle is obtuse angled

Answer» YES it is a OBTUSE ANGLE because ONE angle Is GREATER than other
29.

One packet contains 24 pencils. he many pencils do 400 packets contains?

Answer»

1 PACKET = 24 pencils

so 400 PACKETS will contain = 24*400

= 9600 pencils

30.

Help me solve this question in the picture

Answer»

where is PIC......??????

31.

एक व्यक्ति अपनी 3 बहनों स मिलने कुछ रकम लेकर घर से निकला~~पहले दिन वो बड़ी बहन के घर गयाजब वो स्नान करने गया तो बड़ी बहन ने भाई के कपड़ों की जेबों की तलाशी ली । जितनी रकम जेब में थी, उतनी ही रकम बड़ी बहन ने अपने पास से मिलाकर वापस भाई की जेब में रख दी विदा लेते समय भाई ने बहन को 2000 रुपए दिए । अगले दिन भाई मंझली बहन के घर गयाभाई के स्नान को जाते ही मंझली बहन ने भी तलाशी ली और जेब में जितनी रकम थी उतनी ही अपनी तरफ से मिलाकर भाई की जेब में रख दीविदा लेते समय भाई ने बहन को 2000 रुपए दिए । अगले दिन भाई छोटी बहन के घर गया।छोटी बहन ने भी जेब की रकम के बराबर रकम भाई की जेब में रख दी । विदा लेते समय भाई ने छोटी बहन को भी 2000 रुपए दिए । घर पहुँचने पर भाई की जेब में 5000 रुपए बचे हुए थे । तो अब सवाल ये है कि,तीनों बहनों से मिलने के लिए भाई, कितनी रकम लेकर घर से निकला था ???

Answer»

Let the amount of money with the brother be X .
This money was doubled by ELDEST sister.
Now money with brother = 2x
Money given to sister = 2000.
Money LEFT = 2x - 2000.
This amount was again doubled by second sister .
Amount becomes = 4X-4000.
Amount given to sister = 2000.
Amount left = 4x - 6000.
This is again doubled by third sister.
Amount becomes = 8x - 12000.
Amount given to sister = 2000.

Amount left = 8x - 14000.
This is equal to 5000.
8x - 14000 = 5000.
x = 2375 rupees.
Hope you understood my answer. If yes then plz mark me as the brainliest.

32.

A got 30%concession on the label price of an article sold for Rs.8750 with 25% profit on the price he bought the label price was what

Answer»
=  > cp = ( \frac{100}{125}   \times 8750) \\  \\  = >  cp = 7000
__________________

LET's the LABELLED PRICE be "X"

then

=  >  \frac{70x}{100}  = 7000 \\  \\  =  > x =  \frac{7000 \times 100}{70}  \\  \\  =  > x = 10000
_________________[ANSWER]

33.

Express (xsquare-1by ysquare)(ysquare-1by xsquare)as a perfect square

Answer» \bold{Answer :}

Now,

(x² - 1/y²) (y² - 1/x²)

= x²y² - x²/x² - y²/y² + 1/(x²y²)

= (xy)² - 1 - 1 + 1/(xy)²

= (xy)² - 2 + 1/(xy)²

= (xy)² - 2 (xy) (1/xy) + 1/(xy)²

= (xy - 1/xy)², which is a PERFECT square

We used the IDENTITY -

(a - B)² = a² - 2ab + b²

#\bold{MarkAsBrainliest}
34.

Find all real values of c for which the pair of linear equations 2x+y=c and 5x-2y=c have a unique solutionNCERT Class 10Previous Year Question PaperChapter:3 - Pair of Linear Equation In Two Variables.

Answer»
2X +y-C =0 a=2,b=1 ,c= -1
35.

1,5,7,14,18,20,40,44,46,?

Answer»

Here is your ANSWER....
the NEXT number in the given series is 92...
HOPE this helps you....

36.

(x-2)/4+1/3=x-2x-1/3 plzz give me the correct answer

Answer»

Here is your answer...
the value of X is 2 ...
hope this helps you...

37.

Solve the given equation x-y = -1,3x-2y =12

Answer» HEY I ATTACH a PIC for you
38.

Find answer for above question

Answer»

4/15*(4/15)^6=(4/15)^2x-4
(4/15)^1*(4/15)^6=(4/15)^2x-4
(4/15)^1+6=(4/15)^2x-4
2x-4=7
x=11/2 ANSWER

39.

On dividing 2x2-4x3-4x2+7x-2 by a Polynomial g[x], the quotient and the remainder were 2x2-4x and -x-2 respectively. Find g[x].NCERT Class10Previous Year Question paper.Chapter 2- Polynomials

Answer»

The SYMBOL is X YA MULTIPLY ...

40.

3+1/√3+1/√3+3+1/√3-3

Answer»

________________________✍

=>3 + \frac{1}{ \sqrt{3} } + \frac{1}{ \sqrt{3} + 3} + \frac{1}{ \sqrt{3} - 3} \\ \\ = > \frac{3 \sqrt{3} + 1 }{ \sqrt{3} } + \frac{ \sqrt{3} - 3 + \sqrt{3} + 3 }{ - 6} \\ \\ = > \frac{ - 18\sqrt{3} - 6 + 3 - 3 \sqrt{3} + 3 + 3 \sqrt{3} }{ - 6 \sqrt{3} } \\ \\ = > \frac{18\sqrt{3}}{6 \sqrt{3} } = > 3
==========================

41.

प्रथम 100 प्राकृतिक संख्या का average ज्ञात करे

Answer»

(1+2+3.......+100)/100
use formula for sum N(n+1)/2
100(100+1)/2= 100*101/2 = 5050
average is 5050/100 = 50.5 is your ANSWER

42.

simplify ........................... who is genius she or he can solve this problem and give an award of brain list answers

Answer»

(1/64)rays to power 1/3[CUBE ROOT (64)-cube root (64)rays to power 2
cube root of 1/64[4-16]
1/4[-12]
-3
therefor TGE answer is -3

43.

Linear Equations equations in one variable exercise 2.5

Answer»

This EQUATION is RELATED from for EXERCISE 4.1

44.

a Garrison of 120 man has provision for 30 days at the end of 5 days 5 more men joined them how many days can be sustained on the remaining provisions

Answer»


SOLUTION:

____________


Initial strength of men = 120 men

Remaining provision to LAST = 30 - 5 = 25 days


New strength of men = 120 + 5 = 125 ............... ( 5 more men join after 5 days)


Using Unitary Method (inverse relation between men and days))


Provision for 120 men COULD last = 25 days


Provision for 1 man could last for = 25 x 120 ............( inverse relation)


Provision for 125 men would last =   \frac{25 X 120}{125} = 24


So, the required answer is 24 days


__________________________________________

Any problem in understanding the solution , please feel FREE to ask in the comment box.


45.

How to be good in quadratic equation of class 11

Answer»

TRY practicing the questions as much as U can...N try SOLVING all the questions of RD SHARMA for it

46.

4 th part answer is nI want steps please

Answer»

This is the ANSWER. L HOPE it will HELP you.

47.

Mean based on distance

Answer»

You are alli / freine from LUCKNOW (up) WRITE a letter to the editor Lucknow times DAILY to look into the bad conditions of the highway roads damaged by the mansoon rains

48.

28 + (6 + 3 \times (27 \div 9 \div 5)))[/tex]

Answer» 0
49.

Find the HCF of frnd

Answer»

13/3 is the HCF or these NUMBERS

50.

Standard form of 0.52 with steps

Answer» HEY friend
here's your ANSWER