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Angle of elevation of a point 100 mts from the foot of the tree is 60°.find height of the tree |
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Answer» HEYA !! LET AB be the three . BC = 100 m Angle ACB = 60° Tan60° = AB/BC ✓3 = AB/100 AB = 100✓3 m. Hence, Height of TREE ( AB ) = 100✓3 m. |
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