a Garrison of 120 man has provision for 30 days at the end of 5 days 5

1.	a Garrison of 120 man has provision for 30 days at the end of 5 days 5 more men joined them how many days can be sustained on the remaining provisions
Answer» SOLUTION: ____________ Initial strength of men = 120 men Remaining provision to LAST = 30 - 5 = 25 days New strength of men = 120 + 5 = 125 ............... ( 5 more men join after 5 days) Using Unitary Method (inverse relation between men and days)) Provision for 120 men COULD last = 25 days Provision for 1 man could last for = 25 x 120 ............( inverse relation) Provision for 125 men would last = $\frac{25 X 120}{125} = 24$ So, the required answer is 24 days __________________________________________ Any problem in understanding the solution , please feel FREE to ask in the comment box.

a Garrison of 120 man has provision for 30 days at the end of 5 days 5 more men joined them how many days can be sustained on the remaining provisions

Answer»

SOLUTION:

____________

Initial strength of men = 120 men

Remaining provision to LAST = 30 - 5 = 25 days

New strength of men = 120 + 5 = 125 ............... ( 5 more men join after 5 days)

Using Unitary Method (inverse relation between men and days))

Provision for 120 men COULD last = 25 days

Provision for 1 man could last for = 25 x 120 ............( inverse relation)

Provision for 125 men would last = $\frac{25 X 120}{125} = 24$

So, the required answer is 24 days

__________________________________________

Any problem in understanding the solution , please feel FREE to ask in the comment box.

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