332354 + Interview Questions in Secondary School in Math

1.	a box is made up of wood which is 1 cm thick the outer dimensions of the box are 5 cm into 4 cm into 7 cm find the volume of the wood used
Answer» Step-by-step EXPLANATION: HOPE it will HELP you.....

1.

a box is made up of wood which is 1 cm thick the outer dimensions of the box are 5 cm into 4 cm into 7 cm find the volume of the wood used

Answer»

Step-by-step EXPLANATION:

HOPE it will HELP you.....

Discussion

2.	50of4÷10of2-5×6+10×3
Answer» ANSWER is 10. (some RANDOM sentence to make 20 CHARACTERS)

2.

50of4÷10of2-5×6+10×3

Answer»

ANSWER is 10.

(some RANDOM sentence to make 20 CHARACTERS)

Discussion

3.	Differentiate the following functions with respect to x(without using first principle) :
Answer» $\huge\mathfrak{solution}$ In both questions we USE , Chain rule . $\star \boxed{ \bold{ \frac{d}{dx} f(g(x)) = f' (x) \frac{d}{dx} g(x)}}$ $1) \sqrt{sin \: x}$ Let $y = \sqrt{sin \: x}$ Differentiate w.r.t X both SIDES , $\rightarrow \: \frac{dy}{dx} = \frac{d}{dx} ( \sqrt{sin \: x} ) \\ \\ \rightarrow \: \frac{dy}{dx} = \frac{1}{2 \sqrt{sin \: x} } \frac{d}{dx} (sin \: x) \\ \\ \rightarrow \: \frac{dy}{dx} = \frac{1}{2 \sqrt{sin \: x} } (cosx) \\ \\ \rightarrow \: \frac{dy}{dx} = \frac{cos \: x}{2 \sqrt{sin \: x} }$ $2) \: sin \: \sqrt{x}$ Let $y = sin \: \sqrt{x}$ Differentiate w.r.t X both sides, $\star \frac{dy}{dx} = \frac{d}{dx} (sin \: \sqrt{x} ) \\ \\ \star \frac{dy}{dx} = cos \: \sqrt{x} \frac{d}{dx} ( \sqrt{x} ) \\ \\ \star \frac{dy}{dx} = cos \: \sqrt{x} ( \frac{1}{2 \sqrt{x} } ) \\ \\ \star \: \frac{dy}{dx} = \frac{cos \: \sqrt{x} }{2 \sqrt{x} }$ Formula USED: $\red \star \boxed{ \bold{ \frac{d}{dx} ( \sqrt{x} ) = \frac{1}{2 \sqrt{x} } }}$ $\green\star \boxed{\bold{ \frac{d}{dx} (sin \: x) = cos \: x}}$

3.

Differentiate the following functions with respect to x(without using first principle) :

Answer»

$\huge\mathfrak{solution}$

In both questions we USE ,

Chain rule .

$\star \boxed{ \bold{ \frac{d}{dx} f(g(x)) = f' (x) \frac{d}{dx} g(x)}}$

$1) \sqrt{sin \: x}$

Let

$y = \sqrt{sin \: x}$

Differentiate w.r.t X both SIDES ,

$\rightarrow \: \frac{dy}{dx} = \frac{d}{dx} ( \sqrt{sin \: x} ) \\ \\ \rightarrow \: \frac{dy}{dx} = \frac{1}{2 \sqrt{sin \: x} } \frac{d}{dx} (sin \: x) \\ \\ \rightarrow \: \frac{dy}{dx} = \frac{1}{2 \sqrt{sin \: x} } (cosx) \\ \\ \rightarrow \: \frac{dy}{dx} = \frac{cos \: x}{2 \sqrt{sin \: x} }$

$2) \: sin \: \sqrt{x}$

Let

$y = sin \: \sqrt{x}$

Differentiate w.r.t X both sides,

$\star \frac{dy}{dx} = \frac{d}{dx} (sin \: \sqrt{x} ) \\ \\ \star \frac{dy}{dx} = cos \: \sqrt{x} \frac{d}{dx} ( \sqrt{x} ) \\ \\ \star \frac{dy}{dx} = cos \: \sqrt{x} ( \frac{1}{2 \sqrt{x} } ) \\ \\ \star \: \frac{dy}{dx} = \frac{cos \: \sqrt{x} }{2 \sqrt{x} }$

Formula USED:

$\red \star \boxed{ \bold{ \frac{d}{dx} ( \sqrt{x} ) = \frac{1}{2 \sqrt{x} } }}$

$\green\star \boxed{\bold{ \frac{d}{dx} (sin \: x) = cos \: x}}$

Discussion

4.	Total number of results are called
Answer» Step-by-step explanation: The total NUMBER of RESULTS are called the sample space of an experiment. * In probability, the results produced by an experiment can be REFERRED to as outcomes and the COLLECTION of all these results is the sample space.

4.

Total number of results are called

Answer»

Step-by-step explanation:

The total NUMBER of RESULTS are called the sample space of an experiment. * In probability, the results produced by an experiment can be REFERRED to as outcomes and the COLLECTION of all these results is the sample space.

Discussion

5.	If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term.
Answer» Solution : LET a and d be the FIRST term and common DIFFERENCE of the AP Since, $\sf a_9 = 0 \\ \\ \leadsto \sf a + 8D = 0 \\ \\ \leadsto \boxed{\boxed{\sf{a = - 8D}}}$ $\rule{300}{2}$ $\sf a_{29} = a + 28D \\ \\ \leadsto \sf a_{29} = - 8D + 28D \\ \\ \leadsto \sf a_{29} = 20D$ $\rule{300}{2}$ $\sf a_{19} = a + 18D \\ \\ \leadsto \sf a_{19} = - 8D + 18D \\ \\ \leadsto \sf a_{19} = 10 D$ Since, $\sf a_{29} = 2a_{19}$ HENCE,PROVED

5.

If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term.

Answer»

Solution :

LET a and d be the FIRST term and common DIFFERENCE of the AP

Since,

$\sf a_9 = 0 \\ \\ \leadsto \sf a + 8D = 0 \\ \\ \leadsto \boxed{\boxed{\sf{a = - 8D}}}$

$\rule{300}{2}$

$\sf a_{29} = a + 28D \\ \\ \leadsto \sf a_{29} = - 8D + 28D \\ \\ \leadsto \sf a_{29} = 20D$

$\rule{300}{2}$

$\sf a_{19} = a + 18D \\ \\ \leadsto \sf a_{19} = - 8D + 18D \\ \\ \leadsto \sf a_{19} = 10 D$

Since,

$\sf a_{29} = 2a_{19}$

HENCE,PROVED

Discussion

6.	Differentiate the following functions with respect to x (without using first principle) :i) Sin 2xii) Sin² xiii) Sin x²
Answer» $\huge \red{ \mathfrak{solution}}$ We USE chain RULE in all questions : $\star \bold{ \frac{d}{dx} f(g(<klux>X</klux>)) = f' (x) \frac{d}{dx} g(x)}$ $1) \: sin2x$ LET $y = \: sin \: 2x$ Differentiate w.r.t X both sides , $\star \frac{dy}{dx} = \frac{d}{dx} (sin \: 2x) \\ \\ \star \: \frac{dy}{dx} = cos \: 2x \frac{d}{dx} (2x) \\ \\ \star \: \frac{dy}{dx} = cos \: 2x(2) \\ \\ \star \: \frac{dy}{dx} = 2 \: cos \: 2x$ Formula: $\star \bold{ \frac{dy}{dx} sinx = cosx}$ $2) y = {sin}^{2} x$ Differentiate w.r.t X both sides, $\star \: \frac{dy}{dx} = \frac{d}{dx} ( {sin}^{2} x) \\ \\ \star \frac{dy}{dx} = 2 \: sinx \frac{d}{dx} (sin \: x) \\ \\ \star \: \frac{dy}{dx} = 2 \: sinx \: cosx \\ \\ \star \: \frac{dy}{dx} = sin2x$ Formula : $\leadsto \boxed{ \bold{ \frac{d}{dx} ( {x}^{n} ) = n {x}^{n - 1} }}$ $\leadsto \boxed { \bold {sin \: 2x = 2 \: sinx \: cosx}}$ $3) \: y = sin \: {x}^{2}$ Differentiate w.r.t.X both sides , $\star \: \frac{dy}{dx} = \frac{d}{dx} sin {x}^{2} \\ \\ \star \frac{dy}{dx} = cos \: {x}^{2} \frac{d}{dx} {x}^{2} \\ \\ \star \: \frac{dy}{dx} = cos \: {x}^{2} (2x) \\ \\ \star \: \frac{dy}{dx} = 2x \: cos \: {x}^{2}$

6.

Differentiate the following functions with respect to x (without using first principle) :i) Sin 2xii) Sin² xiii) Sin x²

Answer»

$\huge \red{ \mathfrak{solution}}$

We USE chain RULE in all questions :

$\star \bold{ \frac{d}{dx} f(g(<klux>X</klux>)) = f' (x) \frac{d}{dx} g(x)}$

$1) \: sin2x$

LET

$y = \: sin \: 2x$

Differentiate w.r.t X both sides ,

$\star \frac{dy}{dx} = \frac{d}{dx} (sin \: 2x) \\ \\ \star \: \frac{dy}{dx} = cos \: 2x \frac{d}{dx} (2x) \\ \\ \star \: \frac{dy}{dx} = cos \: 2x(2) \\ \\ \star \: \frac{dy}{dx} = 2 \: cos \: 2x$

Formula:

$\star \bold{ \frac{dy}{dx} sinx = cosx}$

$2) y = {sin}^{2} x$

Differentiate w.r.t X both sides,

$\star \: \frac{dy}{dx} = \frac{d}{dx} ( {sin}^{2} x) \\ \\ \star \frac{dy}{dx} = 2 \: sinx \frac{d}{dx} (sin \: x) \\ \\ \star \: \frac{dy}{dx} = 2 \: sinx \: cosx \\ \\ \star \: \frac{dy}{dx} = sin2x$

Formula :

$\leadsto \boxed{ \bold{ \frac{d}{dx} ( {x}^{n} ) = n {x}^{n - 1} }}$

$\leadsto \boxed { \bold {sin \: 2x = 2 \: sinx \: cosx}}$

$3) \: y = sin \: {x}^{2}$

Differentiate w.r.t.X both sides ,

$\star \: \frac{dy}{dx} = \frac{d}{dx} sin {x}^{2} \\ \\ \star \frac{dy}{dx} = cos \: {x}^{2} \frac{d}{dx} {x}^{2} \\ \\ \star \: \frac{dy}{dx} = cos \: {x}^{2} (2x) \\ \\ \star \: \frac{dy}{dx} = 2x \: cos \: {x}^{2}$

Discussion

7.	If two numbers have same number of digits, we compare them by their leftmost digit. Exp. 3 Which is greater, 318 or 224?
Answer» Answer: 318 is greater Step-by-step EXPLANATION: yes, if TWO numbers have the same NUMBER of digits, we compae them by their leftmost DIGIT

7.

If two numbers have same number of digits, we compare them by their leftmost digit. Exp. 3 Which is greater, 318 or 224?

Answer»

Answer:

318 is greater

Step-by-step EXPLANATION:

yes, if TWO numbers have the same NUMBER of digits, we compae them by their leftmost DIGIT

Discussion

8.	Please answer it fast!!!!!!!
Answer» Step-by-step explanation: given they are perpendicular to each other i. e. they are interesting lines condition = a1/a2 is not equal to b1 /B2 line 1 = 2X-y+5=0 a1= 2x ; b1 = -y line 2 = px+3y=4 a2= px; b2= 3y i. e. a1/a2 not eqal to b1/b2 =2/p=1/3 p=3 X 2 p= 6

8.

Please answer it fast!!!!!!!

Answer»

Step-by-step explanation:

given they are perpendicular to each other

i. e. they are interesting lines

condition = a1/a2 is not equal to b1 /B2

line 1 = 2X-y+5=0

a1= 2x ; b1 = -y

line 2 = px+3y=4

a2= px; b2= 3y

i. e. a1/a2 not eqal to b1/b2

=2/p=1/3

p=3 X 2

p= 6

Discussion

9.	enter the biggest possible number. 9. 0. 0. 3. 2. 8. 7
Answer» ☆:.｡.o(≧▽≦)o.｡.:☆ ♪H♪E♪Y♪ ♪M♪A♪T♪E♪ ♪H♪E♪R♪E♪ ♪I♪S♪ ♪Y♪O♪U♪ ♪A♪N♪S♪W♪E♪R♪ 9873200 ⚡H⚡O⚡P⚡E⚡ ⚡I⚡T⚡ ⚡W⚡I⚡L⚡L⚡ ⚡H⚡E⚡L⚡P⚡ ⚡Y⚡O⚡U⚡ ☾F☽☾O☽☾L☽☾L☽☾O☽☾W☽ ☾F☽☾O☽☾R☽ ☾M☽☾O☽☾R☽☾E☽ ☾A☽☾N☽☾S☽☾W☽☾E☽☾R☽☾S☽ (◕‿◕)♡

9.

enter the biggest possible number. 9. 0. 0. 3. 2. 8. 7

Answer»

☆*:.｡.o(≧▽≦)o.｡.:*☆

♪H♪E♪Y♪ ♪M♪A♪T♪E♪ ♪H♪E♪R♪E♪ ♪I♪S♪ ♪Y♪O♪U♪ ♪A♪N♪S♪W♪E♪R♪

9873200

⚡H⚡O⚡P⚡E⚡ ⚡I⚡T⚡ ⚡W⚡I⚡L⚡L⚡ ⚡H⚡E⚡L⚡P⚡ ⚡Y⚡O⚡U⚡

☾F☽☾O☽☾L☽☾L☽☾O☽☾W☽ ☾F☽☾O☽☾R☽ ☾M☽☾O☽☾R☽☾E☽ ☾A☽☾N☽☾S☽☾W☽☾E☽☾R☽☾S☽

(◕‿◕)♡

Discussion

10.	· If S = n² + 2n then find T?
Answer» Solution : Explanation : GIVEN, Sum of n terms of the AP is n² + 2N To finD nth TERM Let a be the first term and d be the COMMON difference in the required AP Putting n = 1,we get the first term : $\sf S_1 = a_1 = 1^2 + 2(1) = 2$ Putting n = 2,we get the sum of first and second terms : $\sf S_2 = a_1 + a_2 = 2^2 + 2(2) = 8$ Now, Second Term would be : $\sf a_2 = S_2 - a_1 \\ \\ \implies \sf a_2 = 8 - 2 \\ \\ \implies \sf a_2 = 6$ Now, Common Difference $\sf D = a_2 - a_1 = 6 - 2 = 4$ Nth term of an AP : $\sf T = a + (N - 1)D \\ \\ \longrightarrow \sf T = 2 + (N - 1)4 \\ \\ \longrightarrow \sf T = 4N - 2$ THUS,the nth term of the above AP is 4N - 2

10.

· If S = n² + 2n then find T?

Answer»

Solution :

Explanation :

GIVEN,

Sum of n terms of the AP is n² + 2N

To finD

nth TERM

Let a be the first term and d be the COMMON difference in the required AP

Putting n = 1,we get the first term :

$\sf S_1 = a_1 = 1^2 + 2(1) = 2$

Putting n = 2,we get the sum of first and second terms :

$\sf S_2 = a_1 + a_2 = 2^2 + 2(2) = 8$

Now,

Second Term would be :

$\sf a_2 = S_2 - a_1 \\ \\ \implies \sf a_2 = 8 - 2 \\ \\ \implies \sf a_2 = 6$

Now,

Common Difference

$\sf D = a_2 - a_1 = 6 - 2 = 4$

Nth term of an AP :

$\sf T = a + (N - 1)D \\ \\ \longrightarrow \sf T = 2 + (N - 1)4 \\ \\ \longrightarrow \sf T = 4N - 2$

THUS,the nth term of the above AP is 4N - 2

Discussion

11.	can you find the four digit pin number pqrs of an ATM card such that P power 2 into 1 into 4 into 10 power 3 is equal to 350000
Answer» The four digit number pin is 3752 Step-by-step EXPLANATION: Let Q be 7 p.p×R.r.r.r.r×s.s.s=45000 Let r be 5 p.p×625×a.s.s=45000/625=72 Let s be 2 p.p=72/8=9 p=3 Hence,The ATM pin is 3752 Sorry,I could not find "raised to"sign in my phone Thank you

11.

can you find the four digit pin number pqrs of an ATM card such that P power 2 into 1 into 4 into 10 power 3 is equal to 350000

Answer»

The four digit number pin is 3752

Step-by-step EXPLANATION:

Let Q be 7

p.p×R.r.r.r.r×s.s.s=45000

Let r be 5

p.p×625×a.s.s=45000/625=72

Let s be 2

p.p=72/8=9

p=3

Hence,The ATM pin is 3752

Sorry,I could not find "raised to"sign in my phone

Thank you

Discussion

12.	A batsman scored some singles, some 4's and some 6's in a cricket match. The number of singles made by a batsman is three times the number of 4's and number of 6's is one more than number of 4's made by the batsman. The batsman scored a total of 84 runs.
Answer» Step-by-step EXPLANATION: LET no. of 4S be x then SINGLES=3x and 6s = x+1 runs due to 4s=4x runs due to singles=3x runs due to 6s=6(x+1)=6x+6 ATQ 4x+3x+6x+6=84 13x=78 x=78/13 x= 6 no. of 4s = 6 no. of singles = 18 no. of 6s= 7 Hope that helps. Follow for more.

12.

A batsman scored some singles, some 4's and some 6's in a cricket match. The number of singles made by a batsman is three times the number of 4's and number of 6's is one more than number of 4's made by the batsman. The batsman scored a total of 84 runs.

Answer»

Step-by-step EXPLANATION:

LET no. of 4S be x

then SINGLES=3x

and 6s = x+1

runs due to 4s=4x

runs due to singles=3x

runs due to 6s=6(x+1)=6x+6

ATQ

4x+3x+6x+6=84

13x=78

x=78/13

x= 6

no. of 4s = 6

no. of singles = 18

no. of 6s= 7

Hope that helps.

Follow for more.

Discussion

13.	The height of thickness of a frustum in the perpendicular distance between its two circular bases.
Answer» Answer: this statement is true... hope you UNDERSTAND... MARK as BRAINLIEST...

13.

The height of thickness of a frustum in the perpendicular distance between its two circular bases.

Answer»

Answer:

this statement is true...

hope you UNDERSTAND...

MARK as BRAINLIEST...

Discussion

14.	(iv) If for an A.P., t, = 4 and d= – 2, then what is the value of a?
Answer» ANSWER: a+3d=0 a+3is MULTIPLY by -2=0 a=6

14.

(iv) If for an A.P., t, = 4 and d= – 2, then what is the value of a?

Answer»

ANSWER:

a+3d=0

a+3is MULTIPLY by -2=0

a=6

Discussion

15.	गए. समतलों r. (i+j+k) = 6 और 7. (2i + 3j+ 4k) = -5 केप्रतिच्छेदन तथा (1, 1, 1) से जाने वाले समतल का सदिश समीकरणज्ञात करो। ans.
Answer» ANSWER: Bhai smj nahi AAYA ask your QUESTION in English PLZ give RESPONSE with thanked and mark as brainliest

15.

गए. समतलों r. (i+j+k) = 6 और 7. (2i + 3j+ 4k) = -5 केप्रतिच्छेदन तथा (1, 1, 1) से जाने वाले समतल का सदिश समीकरणज्ञात करो। ans.

Answer»

ANSWER:

Bhai smj nahi AAYA

ask your QUESTION in English

PLZ give RESPONSE with thanked and mark as brainliest

Discussion

16.	Can you find the 4-digit pin number ‘pqrs' of anATM card such that p’ xq' xrX =3,15,000?
Answer» Answer: Bhai ase ATM ka pin share NAHI KARTE galat bat HAU

16.

Can you find the 4-digit pin number ‘pqrs' of anATM card such that p’ xq' xrX =3,15,000?

Answer»

Answer:

Bhai ase ATM ka pin share NAHI KARTE galat bat HAU

Discussion

17.	If x+y+z=0 show thatx+y+zº = 3xyz
Answer» I think the QUESTION is if x+y+z=0then SHOW XCUBE +ycube+ zcube= 3xyz then the answer is If X+y+z =0 We know that: a cube + B cube + c cube -3ABC = (a+B+c) ( a ^2 + b^2 + c^2 -ab-bc-ca) Now if we put the value of X+y+z that is 0, we will get: = (0) ( X sq + y sq + z sq- xy- yz-zx) If we multiply anything by zero,the answer is 0 Therefore, X cube + y cube+ zcube- 3 X y z = 0 Therefore X cube + y cube + z cube = 3 X y z

17.

If x+y+z=0 show thatx+y+zº = 3xyz

Answer»

I think the QUESTION is if x+y+z=0then SHOW XCUBE +ycube+ zcube= 3xyz

then the answer is

If X+y+z =0

We know that: a cube + B cube + c cube -3ABC = (a+B+c) ( a ^2 + b^2 + c^2 -ab-bc-ca)

Now if we put the value of X+y+z that is 0, we will get:

= (0) ( X sq + y sq + z sq- xy- yz-zx)

If we multiply anything by zero,the answer is 0

Therefore,

X cube + y cube+ zcube- 3 X y z = 0

Therefore

X cube + y cube + z cube = 3 X y z

Discussion

18.	In power supply theI talkiI unatAt the start of experiment, the vemp is off and the bell-jar contains air teto electric bell is now switched on the bellstart ringing and the ringing can be heard fromoutside the bell jar. Now, if the vacuumis switched on, it starts removing the air fromthethe bell jar. As the quantity of air inside the bell mofor decreases, the level of ringing sound heard thenoutside also decreases. If the pump is operated forfor sufficiently long period, the quantity of air Solike inside the bell jar will be low. At this pointthe level of ringing sound will also be verylow. This experiment demonstrates that sounddnronation needs a medium,
Answer» ANSWER: HII....FOLLOW me I follow U BACK.....

18.

In power supply theI talkiI unatAt the start of experiment, the vemp is off and the bell-jar contains air teto electric bell is now switched on the bellstart ringing and the ringing can be heard fromoutside the bell jar. Now, if the vacuumis switched on, it starts removing the air fromthethe bell jar. As the quantity of air inside the bell mofor decreases, the level of ringing sound heard thenoutside also decreases. If the pump is operated forfor sufficiently long period, the quantity of air Solike inside the bell jar will be low. At this pointthe level of ringing sound will also be verylow. This experiment demonstrates that sounddnronation needs a medium,

Answer»

ANSWER:

HII....FOLLOW me I follow U BACK.....

Discussion

19.	Show that 1 by root 2 is a irrational number please explain me in understanding method
Answer» Answer: rationalise ✓2 by MULTIPLYING with NUMERATOR and denominator and just prove it like the NORMAL one's

19.

Show that 1 by root 2 is a irrational number please explain me in understanding method

Answer»

Answer:

rationalise ✓2 by MULTIPLYING with NUMERATOR and denominator

and just prove it like the NORMAL one's

Discussion

20.	The sum of interior angles of a polygon of n sides is_________ right angles
Answer» ANSWER: The answer is.... 180°

20.

The sum of interior angles of a polygon of n sides is_________ right angles

Answer»

ANSWER:

The answer is.... 180°

Discussion

21.	What is the income on the investment of Rs. 32000 in 8% stock at 95.
Answer» Answer: 2,43,200. Step-by-step explanation: 32000895

21.

What is the income on the investment of Rs. 32000 in 8% stock at 95.

Answer»

Answer:

2,43,200.

Step-by-step explanation:

32000*8*95

Discussion

22.	Using Euclid's division algorithm,find hcf of 272 & 1040
Answer» $\underline { \pink { Euclid's \: Division \: Algorithm :}}$ Given positive integers a and b , there exists unique pair of integers q and R satisfying $\boxed{ \blue { a = bq + r , 0 \leq r < b }}$ $Given \: numbers \: 272 \:and \: 1040.$ When 1040 is divided by 272 ,the remainder is 224 we get 1040 = 272 × 3 + 224 Now consider division of 272 with remainder 224 and apply the division lemma to get 272 = 224 × 1 + 48 Continue the process 224 = 48 × 8 + 32 48 = 32 × 1 + 16 32 = 16 × 2 + 0 The remainder has now become zero , so our procedure stops . Since ,the DIVISOR at this stage is 16 , Therefore., $\red{ HCF \:of \: 272 \:and \:1040 } \green {= 16}$ •••♪

22.

Using Euclid's division algorithm,find hcf of 272 & 1040

Answer»

$\underline { \pink { Euclid's \: Division \: Algorithm :}}$

Given positive integers a and b , there exists unique pair of integers q and R satisfying

$\boxed{ \blue { a = bq + r , 0 \leq r < b }}$

$Given \: numbers \: 272 \:and \: 1040.$

When 1040 is divided by 272 ,the remainder is 224 we get

1040 = 272 × 3 + 224

Now consider division of 272 with remainder 224 and apply the division lemma to get

272 = 224 × 1 + 48

Continue the process

224 = 48 × 8 + 32

48 = 32 × 1 + 16

32 = 16 × 2 + 0

The remainder has now become zero , so our procedure stops .

Since ,the DIVISOR at this stage is 16 ,

Therefore.,

$\red{ HCF \:of \: 272 \:and \:1040 } \green {= 16}$

•••♪

Discussion

23.	Given that log m=x+y and log n=x-y, express the value of log m^2n in terms of x and y.
Answer» $\Huge{\underline{\underline{\mathfrak{ Solution \colon }}}}$ We know that according to the quotient LAW we can write log (10x/y2) as log 10x – log y2 Now applying the law of product & power we get log 10 + log x – 2 log y We know that value of log 10 = 1. Putting its value we get, 1 + (m+n) – 2(m-n) = 1 - m + 3N (Ans)

23.

Given that log m=x+y and log n=x-y, express the value of log m^2n in terms of x and y.

Answer»

$\Huge{\underline{\underline{\mathfrak{ Solution \colon }}}}$

We know that according to the quotient LAW we can write log (10x/y2) as

log 10x – log y2

Now applying the law of product & power we get

log 10 + log x – 2 log y

We know that value of log 10 = 1.

Putting its value we get, 1 + (m+n) – 2(m-n) = 1 - m + 3N (Ans)

Discussion

24.	6. (A) With the help of given statistical data, prepare a simple bar graph199020002010YearBrazil74.681.584.6India25.627.831.2
Answer» Answer: kuhd Nana chal also first TIME pe hi 4 left a message for you to COME home and get some REST and feel better soon

24.

6. (A) With the help of given statistical data, prepare a simple bar graph199020002010YearBrazil74.681.584.6India25.627.831.2

Answer»

Answer:

kuhd Nana chal also

first TIME pe hi 4 left a message for you to COME home and get some REST and feel better soon

Discussion

25.	(ii) How many alpha numerals are there in the format of GSTIN ?
Answer» Answer: \HUGE{\underline{\underline{\mathfrak{Answer}}}} Answer Sikkim's ruling party, the Sikkim Democratic Front (SDF), recently declared to include the Universal BASIC INCOME scheme in its manifesto ahead of the Assembly election in 2019 and aims to implement it by 2022. If everything goes according to the plan, it will be the first state to implement UBI in India. \huge{\underline{\underline{\mathfrak{Thank \: You}}}} ThankYou

25.

(ii) How many alpha numerals are there in the format of GSTIN ?

Answer»

Answer:

\HUGE{\underline{\underline{\mathfrak{Answer}}}}

Answer

Sikkim's ruling party, the Sikkim Democratic Front (SDF), recently declared to include the Universal BASIC INCOME scheme in its manifesto ahead of the Assembly election in 2019 and aims to implement it by 2022. If everything goes according to the plan, it will be the first state to implement UBI in India.

\huge{\underline{\underline{\mathfrak{Thank \: You}}}}

ThankYou

Discussion

26.	Purchase goods for cash
Answer» Step-by-step EXPLANATION: !!!!!!!!!!!!!???????????

26.

Purchase goods for cash

Answer»

Step-by-step EXPLANATION:

!!!!!!!!!!!!!???????????

Discussion

27.	2 + 2 = 5?solve and prove it step by step plz attempt only when u know that answer.
Answer» Step-by-step EXPLANATION: PLZ.. REFER the above ATTACHMENT.

27.

2 + 2 = 5?solve and prove it step by step plz attempt only when u know that answer.

Answer»

Step-by-step EXPLANATION:

PLZ.. REFER the above ATTACHMENT.

Discussion

28.	2) In the circle with centre o, chords AB and CD areperpendicular to each other at M. Arcs ABD and CAB aremajor arcs. if LABD = x and CAB = y then prove that x+y=90°
Answer» Answer: DRAW a circle CENTER o and TWO chords ab and CD do perpendicular bisector on both Step-by-step EXPLANATION: HOPE THIS ANSWER HELP YOU

28.

2) In the circle with centre o, chords AB and CD areperpendicular to each other at M. Arcs ABD and CAB aremajor arcs. if LABD = x and CAB = y then prove that x+y=90°

Answer»

Answer:

DRAW a circle CENTER o and TWO chords ab and CD

do perpendicular bisector on both

Step-by-step EXPLANATION:

HOPE THIS ANSWER HELP YOU

Discussion

29.	What is the income on the investment of Rs. 32000 in 8% stock at 95
Answer» ANSWER: 32000 /8 *100 is your answer

29.

What is the income on the investment of Rs. 32000 in 8% stock at 95

Answer»

ANSWER:

32000 /8 *100 is your answer

Discussion

30.	A person deposits * x in savings bank account at the rate of 5% per annum andy infixed deposit at 10% per annum. At the end of first year he gets * 400 as total interest.He deposit y in savings bank account and * x in fixed deposit he would get astotal interest. Find the total amount he deposited.
Answer» ANSWER: Step-by-step EXPLANATION:

30.

A person deposits * x in savings bank account at the rate of 5% per annum andy infixed deposit at 10% per annum. At the end of first year he gets * 400 as total interest.He deposit y in savings bank account and * x in fixed deposit he would get astotal interest. Find the total amount he deposited.

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

31.	Please finds the value of x :2x +3/5 =4
Answer» HOPE it will HELP you.....

Discussion

32.	6. The priest said, Tomorrow Will Dealuw vegung,7. The minister said to the crowd, "I will provide you with all the facilities8. The author said, "I have written a new novel."9. Jaya said to her mother, "Have you seen my goggles?”1. The teacher said to the class, "The moon reflects the light of the sun.cise-2 : Convert the following sentences into direct speech.The tourist asked the guide the places he could visit in a short time.The girl asked her father whether she could join the airhostess trainThe team exclaimed with delight that they had won the trophy.The doctor told Sumita not to eat sweets at all.The colony people requested the mayor to have a proper road mmain road.Priya acknowledged that she had received her birthday card.The mobike rider enquired if the children were going to the tenniShe asked me that how many classes was I taking.
Answer» what is the question plzz GIVE an appropriate question this is learning app not a GAME

32.

6. The priest said, Tomorrow Will Dealuw vegung,7. The minister said to the crowd, "I will provide you with all the facilities8. The author said, "I have written a new novel."9. Jaya said to her mother, "Have you seen my goggles?”1. The teacher said to the class, "The moon reflects the light of the sun.cise-2 : Convert the following sentences into direct speech.The tourist asked the guide the places he could visit in a short time.The girl asked her father whether she could join the airhostess trainThe team exclaimed with delight that they had won the trophy.The doctor told Sumita not to eat sweets at all.The colony people requested the mayor to have a proper road mmain road.Priya acknowledged that she had received her birthday card.The mobike rider enquired if the children were going to the tenniShe asked me that how many classes was I taking.

Answer»

what is the question

plzz GIVE an appropriate question

this is learning app not a GAME

Discussion

33.	(11) How many alpha numerals are there in the format of GSTIN?
Answer» 5 NUMBERS are there...

33.

(11) How many alpha numerals are there in the format of GSTIN?

Answer»

5 NUMBERS are there...

Discussion

34.	If the speed of the aircraft was reduced by 120 km per hour, it would take 18 minutes more to travel the specified distanceTakes If the speed of the aircraft increased by 180 km per hour, the same distance would be 18 minutes less Takes; So calculate the average speed of the aircraft and the distance traveled.
Answer» Step-by-step EXPLANATION: FOLLOW me then I follow you

34.

If the speed of the aircraft was reduced by 120 km per hour, it would take 18 minutes more to travel the specified distanceTakes If the speed of the aircraft increased by 180 km per hour, the same distance would be 18 minutes less Takes; So calculate the average speed of the aircraft and the distance traveled.

Answer»

Step-by-step EXPLANATION:

FOLLOW me then I follow you

Discussion

35.	If a=5+√2. Then find the whole root of a+1/a
Answer» ANSWER: SORRY I don't KNOW the answer

35.

If a=5+√2. Then find the whole root of a+1/a

Answer»

ANSWER:

SORRY I don't KNOW the answer

Discussion

36.	When a fraction is divided by the difference of 1/3 and 1/9,we get 3/4. what is the fraction?please solve someone i will mark as BrainlistAnswer is 1/6 i don't know how to solve
Answer» Answer: DIFFERENCE of 1/3 - 1/9 = 2/9 Let the fraction be x Given, x divided by 2/9 = 3/4 To find x, we have to transpose 3/4 to RHS which then GIVES, x = 3/4*2/9 x = 1/6 Thus, the fraction is 1/6 Please MARK it has BRAINLIEST.

36.

When a fraction is divided by the difference of 1/3 and 1/9,we get 3/4. what is the fraction?please solve someone i will mark as BrainlistAnswer is 1/6 i don't know how to solve

Answer»

Answer:

DIFFERENCE of 1/3 - 1/9 = 2/9

Let the fraction be x

Given, x divided by 2/9 = 3/4

To find x, we have to transpose 3/4 to RHS which then GIVES,

x = 3/4*2/9

x = 1/6

Thus, the fraction is 1/6

Please MARK it has BRAINLIEST.

Discussion

37.	What is square of (a+b)(a-b)(a+b)
Answer» ANSWER: (a+b)(a-b)(a+b) a^2-b^2(a+b) Step-by-step EXPLANATION:

37.

What is square of (a+b)(a-b)(a+b)

Answer»

ANSWER:

(a+b)(a-b)(a+b)

a^2-b^2(a+b)

Step-by-step EXPLANATION:

Discussion

38.	Determine the value of the following log 5 Base 25
Answer» Answer: 2 Step-by-step EXPLANATION: GIVEN : log₅ 25 We know if : logₓ x then VALUE is 1. log₅ 25 = > log₅ 5² = > 2 log₅ 5 = > 2 Therefore , the answer is 2 .

38.

Determine the value of the following log 5 Base 25

Answer»

Answer:

2

Step-by-step EXPLANATION:

GIVEN :

log₅ 25

We know if :

logₓ x then VALUE is 1.

log₅ 25

= > log₅ 5²

= > 2 log₅ 5

= > 2

Therefore , the answer is 2 .

Discussion

39.	Australia has three Tyres balls red green and blue is gear ratio is 2 ratio 3 ratio 5 what percent of ball green
Answer» Answer:30% Step-by-step explanation: Red:Green:BLUE =total 2: 3: 5 =10 Now Green balls are 3 we have to find them in PERCENTAGE 3/10100 310= 30%

39.

Australia has three Tyres balls red green and blue is gear ratio is 2 ratio 3 ratio 5 what percent of ball green

Answer»

Answer:30%

Step-by-step explanation:

Red:Green:BLUE =total

2: 3: 5 =10

Now

Green balls are 3 we have to find them in PERCENTAGE

3/10*100

3*10= 30%

Discussion

40.	B) A hemispherical bowl has diameter 30cm. Find the capacity of the bowl.Some water is poured into the bowl as shown in the figure. If the radius of thesurface of the water is 9 em. Find the depth of water in the bowl.( Take II = 3.14.)
Answer» Given Diameter of a hemispherical bowl (D) = 30cm , $Radius \: of \:the \: bowl (R) = \frac{D}{2} \\= \frac{30}{2} \\= 15 \:cm$ $Capacity \: of \:the \:Bowl (V) \\= \frac{2}{3} \pi R^{3} \\= \frac{2}{3}\times 3.14 \times 15^{3}\\= 7065 \:cm^{3} \:--(1)$ /* According to the problem GIVEN / Some water is poured into the bowl as shown in the figure. If the radius of the* Some water is poured into the bowl as shown in the figure. If the radius of thesurface of the water is 9 cm. radius of the surface (r) = QD = 9 cm . OD = 15 cm ( Radii OB = OD ) In ∆OQD , <Q = 90° By Pythagoras Theorem : OD² = OQ² + QD² => 15² = OQ² + 9² => 15² - 9² = OQ² => 225 - 81 = OQ² => 144 = OQ² => OQ = 12 cm Now , Depth of the water (H) = OP - OQ = 15 cm - 12 cm = 3 cm THEREFORE., $\red {Capacity \: of \:the \:Bowl} \green { = 7065 \:cm^{3} }$ $\red { Depth\: of \:the \:water }\green {= 3\:cm }$ •••♪

40.

B) A hemispherical bowl has diameter 30cm. Find the capacity of the bowl.Some water is poured into the bowl as shown in the figure. If the radius of thesurface of the water is 9 em. Find the depth of water in the bowl.( Take II = 3.14.)

Answer»

Given Diameter of a hemispherical bowl (D) = 30cm ,

$Radius \: of \:the \: bowl (R) = \frac{D}{2} \\= \frac{30}{2} \\= 15 \:cm$

$Capacity \: of \:the \:Bowl (V) \\= \frac{2}{3} \pi R^{3} \\= \frac{2}{3}\times 3.14 \times 15^{3}\\= 7065 \:cm^{3} \:--(1)$

/* According to the problem GIVEN */

Some water is poured into the bowl as shown in the figure. If the radius of the

Some water is poured into the bowl as shown in the figure. If the radius of thesurface of the water is 9 cm.

radius of the surface (r) = QD = 9 cm .

OD = 15 cm ( Radii OB = OD )

In ∆OQD , <Q = 90°

By Pythagoras Theorem :

OD² = OQ² + QD²

=> 15² = OQ² + 9²

=> 15² - 9² = OQ²

=> 225 - 81 = OQ²

=> 144 = OQ²

=> OQ = 12 cm

Now ,

Depth of the water (H) = OP - OQ

= 15 cm - 12 cm

= 3 cm

THEREFORE.,

$\red {Capacity \: of \:the \:Bowl} \green { = 7065 \:cm^{3} }$

$\red { Depth\: of \:the \:water }\green {= 3\:cm }$

•••♪

Discussion

41.	In the circle with centre 0, chords AB and CD areperpendicular to each other at M. Arcs ABD and CAB aremajor arcs. if LABD = x® and LCAB = yº then suggest any twoairs of values of x and y. Justify your answer.MODEL QUESTION PAPER
Answer» ANSWER: PLS ATTACH the PICTURE of DIAGRAM

41.

In the circle with centre 0, chords AB and CD areperpendicular to each other at M. Arcs ABD and CAB aremajor arcs. if LABD = x® and LCAB = yº then suggest any twoairs of values of x and y. Justify your answer.MODEL QUESTION PAPER

Answer»

ANSWER:

PLS ATTACH the PICTURE of DIAGRAM

Discussion

42.	-825 + (-75)-(+25)Show the working
Answer» Step-by-step EXPLANATION: -825 + (-75) - (+25) -825 - 75 - 25 -825 - 100 -925

42.

-825 + (-75)-(+25)Show the working

Answer»

Step-by-step EXPLANATION:

-825 + (-75) - (+25)

-825 - 75 - 25

-825 - 100

-925

Discussion

43.	किसी चुनाव में जिसमें प्रत्येक मतदाता दो प्रत्याशियों को मत दे सकता था । आधे मतदाताओं ने अपना पहला मत A को दिया और दूसरा मत B , C और D में 3 : 2 : 1 के अनुपात में बाँट दिया । शेष मतदाताओं के आधे ने अपना पहला मत B को दिया तथा दूसरा मत C तथा D को 2 : 1 के अनुपात में बाँट दिया । शेष मतदाताओं के आधे ने अपना मत C तथा D को दिया । यदि शेष 840 मतदाताओं ने किसी को भी मत नहीं दिया , तो प्रत्याशी A ने कितने मत प्राप्त किया ?
Answer» Answer: 1600 Step-by-step explanation: HOPE U FOUND it useful mark it BRAINLIST

43.

किसी चुनाव में जिसमें प्रत्येक मतदाता दो प्रत्याशियों को मत दे सकता था । आधे मतदाताओं ने अपना पहला मत A को दिया और दूसरा मत B , C और D में 3 : 2 : 1 के अनुपात में बाँट दिया । शेष मतदाताओं के आधे ने अपना पहला मत B को दिया तथा दूसरा मत C तथा D को 2 : 1 के अनुपात में बाँट दिया । शेष मतदाताओं के आधे ने अपना मत C तथा D को दिया । यदि शेष 840 मतदाताओं ने किसी को भी मत नहीं दिया , तो प्रत्याशी A ने कितने मत प्राप्त किया ?

Answer»

Answer:

1600

Step-by-step explanation:

HOPE U FOUND it useful

mark it BRAINLIST

Discussion

44.	The area of triangle formed by (a,b + c) (b,c + a) and (a,c + b) is__________.
Answer» ACCORDING to QUESTION .......

44.

The area of triangle formed by (a,b + c) (b,c + a) and (a,c + b) is__________.

Answer»

ACCORDING to QUESTION

.......

Discussion

45.	F when a fraction is divided by the difference of when a fraction is divided by the difference of
Answer» Is this a CORRECT QUESTION?? I don't THINK so!!!

45.

F when a fraction is divided by the difference of when a fraction is divided by the difference of

Answer»

Is this a CORRECT QUESTION??

I don't THINK so!!!

Discussion

46.	If A ={ } , write power set of A
Answer» <P>ANSWER: p(a) is the POWER SET of the baove

46.

If A ={ } , write power set of A

Answer»

<P>ANSWER:

p(a) is the POWER SET of the baove

Discussion

47.	Tell me this questions ans
Answer» Answer: 1.)60-70 2.)20-30,90-100 3.)50-60 HOPE THIS HELPS YOU....

47.

Tell me this questions ans

Answer»

Answer:

1.)60-70

2.)20-30,90-100

3.)50-60

HOPE THIS HELPS YOU....

Discussion

48.	Ule-Q. 1The decimal expansion of the rationaldecimal? Write the decimal expansionQ2.Show that 5 x 7 x 11 + 11 is a composite.
Answer» Answer: Step-by-step explanation: take 11 as common factor then you WOULD get this NUMBER as 11×36 which implies that it has more than two factors which is sufficent to say that it is a composite

48.

Ule-Q. 1The decimal expansion of the rationaldecimal? Write the decimal expansionQ2.Show that 5 x 7 x 11 + 11 is a composite.

Answer»

Answer:

Step-by-step explanation:

take 11 as common factor then you WOULD get this NUMBER as 11×36 which implies that it has more than two factors which is sufficent to say that it is a composite

Discussion

49.	Find the value of x in the triangle show below
Answer» Answer: 61+x+x=180 2x+61=180 2x=180-61 2x=119 x=54.5

49.

Find the value of x in the triangle show below

Answer»

Answer:

61+x+x=180

2x+61=180

2x=180-61

2x=119

x=54.5

Discussion

50.	5. The prices of two articles are as 3: 4. Ifthe price of the first article is increasedby 10% and that of the second by * 4,original ratio remains the same. Theoriginal price of the second article is
Answer» ANSWER: The ORIGINAL price of the SECOND article is 20% more than the INITIAL price.

50.

5. The prices of two articles are as 3: 4. Ifthe price of the first article is increasedby 10% and that of the second by * 4,original ratio remains the same. Theoriginal price of the second article is

Answer»

ANSWER:

The ORIGINAL price of the SECOND article is 20% more than the INITIAL price.

Discussion

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Determine the value of the following log 5 Base 25

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