Saved Bookmarks
| 1. |
If x+y+z=0 show thatx+y+zº = 3xyz |
|
Answer» I think the QUESTION is if x+y+z=0then SHOW XCUBE +ycube+ zcube= 3xyz then the answer is If X+y+z =0 We know that: a cube + B cube + c cube -3ABC = (a+B+c) ( a ^2 + b^2 + c^2 -ab-bc-ca) Now if we put the value of X+y+z that is 0, we will get: = (0) ( X sq + y sq + z sq- xy- yz-zx) If we multiply anything by zero,the answer is 0 Therefore, X cube + y cube+ zcube- 3 X y z = 0 Therefore X cube + y cube + z cube = 3 X y z |
|