Given that log m=x+y and log n=x-y, express the value of log m^2n in t

1.	Given that log m=x+y and log n=x-y, express the value of log m^2n in terms of x and y.
Answer» $\Huge{\underline{\underline{\mathfrak{ Solution \colon }}}}$ We know that according to the quotient LAW we can write log (10x/y2) as log 10x – log y2 Now applying the law of product & power we get log 10 + log x – 2 log y We know that value of log 10 = 1. Putting its value we get, 1 + (m+n) – 2(m-n) = 1 - m + 3N (Ans)

Given that log m=x+y and log n=x-y, express the value of log m^2n in terms of x and y.

Answer»

$\Huge{\underline{\underline{\mathfrak{ Solution \colon }}}}$

We know that according to the quotient LAW we can write log (10x/y2) as

log 10x – log y2

Now applying the law of product & power we get

log 10 + log x – 2 log y

We know that value of log 10 = 1.

Putting its value we get, 1 + (m+n) – 2(m-n) = 1 - m + 3N (Ans)

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Given that log m=x+y and log n=x-y, express the value of log m^2n in terms of x and y.​

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Given that log m=x+y and log n=x-y, express the value of log m^2n in terms of x and y.