This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Q16. check whether the belowequation in an quadratic equation:x2 + 3 x + 1 = (x - 2)2 |
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Answer» Step-by-step EXPLANATION: X^2+3X+1=2X-4 X^2+1X+5 as the GIVEN EQUATION is in the FORM of aX^2+bX+c it is a QUADRATIC equation........ |
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| 2. |
ABC is an isosceles triangle with AC =BC. If AB=2AC, prove that ABC is a right triangle |
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Answer» hope it will be HELPFUL to you |
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| 3. |
Find 3 irrational number between 1/6 and 1/5 |
Answer» An IRRATIONAL NUMBER between 5 and 6 is2:28.4:11.1:46.2:24.0:59.3:31.0:59.2:03. |
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| 5. |
A3 For what wahur K, the quadrstic equationKx(x-2)=0 has real roots? |
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Answer» the given equation can be written in the FORM of now it has EQUAL roots that means The DISCRIMINANT is 0 D = 0 Also Hence the value of K is 6. |
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| 6. |
Two pillars of equal heights stand on either side of a road which is 150 m wide. At a point on the road between the pillars, the angles of elevation of the tops of the pillars are 45∘ and 30∘. Find their height and position of the point. |
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Answer» Step-by-step explanation: Let AB and CD be two PILLARS ,each of HEIGHT hmetres. Let P be a point on the road such that AP=xm. Then,CP =(150−x)m In triangle PAB , we have tan60o=APAB =3=xh =3x=h.....................1 In triangle PCD , we have tan30o=CPCD =31=150−xh =h3=150−x....................2 Eliminating h between eq. 1 and 2, we get 3x=150−x =x=37.5 Substituting x=37.5 in eq.1 we get , h=64.95 Thus the required point is at the distance of 37.5 m from the first pillar and 112.5 m from the SECOND pillar. The height of the pillars is 64.95 m  |
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| 9. |
What should be addedto -315 toget -715 |
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Answer» -400 May be.......... |
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| 10. |
When, sinA+sinB =2 then what's the value of cosA+cosB ? |
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Answer» Answer: It means A and B are 90 because SIN90 = 1 sin A = 1/Cos A and Sin b = 1/cos B ACCORDING to trignomatry 1/Cos A + 1/ Cos B = 2 Cos A + Cos B = 2 X Cos A Cos B Cos A + Cos B = 2 x Cos 90 x Cos 90 = 0 Answer |
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| 11. |
4 friends A, B, C and D can do a work P in 12 days if they all work together. Efficiency of A, B and C are in ratio 5:4:3. D completes 20% of the work alone. A and B can complete work P in Q days. C and D can complete the work in R days. All four friend can do another work S in (Q+ R-15) days. Find the total unit of work S. |
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Answer» Given, 4 FRIENDS A,B,C,D can do work P in 12 days if they all work together, then only A,B,C do work the ratio will be 5:4:3, D will complete 20% of its work, A and B complete P work, C and D complete Q work, then all friends can do another work S(Q+R-15). Answer, :- A and B = 12/2 = 6 and 6/2 = 3 then A=3, B=3, THEREFORE A×B = 3×3=9, therefore A and B complete the work P in 9 days [equation 1] :- C and D = 9 days [ from equation 1] proof, Q=9 days, R=9 days, therefore, = Q + R - 15 = 9 + 9 - 15 Here, pluse × minus = minus = 9 - 9 - 15 = 0 - 15 = 15 |
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| 12. |
Distribute rupees1500 among A,B and c in the ratio 2:3:5 |
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Answer» Step-by-step EXPLANATION: |
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| 13. |
A + COS A) (sec A - COS A)COS A) = tan- A + sin- Ai) (1 + tan 0 + sec 0) (1 + cot 0 - cosec 0) = 2 |
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Answer» I don't know Step-by-step EXPLANATION: |
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| 14. |
4. If D, E, F are respectively the mid-points of the sides AB, BC and CA of an equilateralABC, prove that triangle DEF is also an equilateral triangle. |
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Answer» Step-by-step explanation: Since LINE SEGMENT joining the mid-points of two sides of a triangle is half of the third side. THEREFORE, D and E are mid-points of BC and AC respectively. ... Hence, DEF is an equilateral triangle . |
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| 15. |
A.Distance = 160 km, timeExercise-11 (A)Find the speed, when :(a) Distance = 30 km, time = 2 hours(6)(0) Distance = 1625 km, time = 5 hoursA bus travelled from Delhi to Bulandshahar in 23 hours. If the distance betweenBulandshahar is 70 km, find the speed of the bus.An aeroplane travels 1800 km in 2 hour 30 minutes. Find its speed.A car travelled 420 km in 6 hours 40 minutes. Find the speed of the car.in an athletic meet, a runner covered 1.5 km in 5 minutes. What was his speed inIr. Gupta and Mr. Jain go to their offices. by cars. Mr. Gupta covers a distancehile Mr. Jain covers a distance of 12 km in 20 minutes. Which of the two drivesress each of the following speeds in metres/sec:54 km/hour2. 72 km/hour3. 300 km/houress each of the following speeds in km/hour:0 m/sec2. 25 m/sec3. 45 m/secvtar travelled a distance of 216 km by car in 4 hours. Find his speed inEtravelled a distance of 204 km by his car in 3 hours. Find his speed in |
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Answer» Hi TELL me what is Colon and semi colon
2. 72 km/hour 3. 45 m/sec |
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| 16. |
18x²-3x = 6 by factorization method |
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Answer» Answer: Step-by-step explanation: 18x²-3x = 6 18x²-3x-6=0 18x²-12x+9x-6=0 6x(3x-2)+3(3x-2)=0 (6x+3)(3x-2)=0 x=-1/2,2/3 THANK you |
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| 17. |
a man of mass 75kg stands on a weighting machine in a lift which is moving upward with an uniform acceleration 1.2ms then what is his apprent weight |
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Answer» Answer: Step-by-step explanation: 1.2 MAS so the weight will be 76.500 GM |
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| 18. |
अ पार्टिकल मूव्स इन ए सर्कुलर ट्रेक ऑफ रेडियस आर इनवर्टर विद यूनिफार्म वेलोसिटी दो आरएडीएल शोधन एक्सप्लेनेशन ऑन द होरिजेंटल थीटा इज इक्वल टू 6 डिग्री इज |
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Answer» Answer: परिपत्र पथ की त्रिज्या, आर = 20 सेमी वृत्ताकार पथ में गतिमान कण की गति, V = 10m / s हम जानते हैं सूत्र v = WR है कहाँ पे, W कोणीय वेग है v कण का रैखिक वेग है और R वृत्ताकार पथ की त्रिज्या है। w = आर v
= 20 10 = 0.5rad / s
अत, कण का कोणीय वेग 0.5rad / s है Step-by-step explanation: |
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| 19. |
Find aunit of digit (564)^2 |
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Answer» I THINK you are LOOKING for a units PLACE after squaring the no. After squaring (4 × 4) the digit = 16 Therefore, 6 is the digit at Units place. |
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| 20. |
√3 is rational or irrationalandprove that √3is irrational |
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Answer» I will PROOF .. |
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| 22. |
Lines m and n are parallel find angle y if one angle is 125 degree and another is 65 degree |
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Answer» Step-by-step EXPLANATION: |
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| 23. |
Prime factorisation 325 |
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Answer» Answer: 5×65 5×655×13 5×655×131×13 Step-by-step EXPLANATION: HOPE it HELPS MARK me BRAINLIEST |
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| 24. |
Find the number of two digit odd multiple with explanation |
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Answer» 31*31/=961 hope it HELPS you |
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| 25. |
The sum of two integers is-11 and their product is -88 find the integers |
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Answer» not EXIST |
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| 26. |
K) *Find z where 3^6 x 8^2 = 36^3 |
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Answer» Step-by-step EXPLANATION: sorry. I didn't know. |
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| 27. |
If the sum of first m terms of an AP is 3m2 + 2m, then Find a1,a2,s4, & a25 |
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Answer» Answer: Now, you can FIND the values of A2, a25, S4 by putting m= 2 and 25 And by sum of n terms formula you can find S4. Hope it helps you thank you |
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| 28. |
The price of a scooter was rs32000 in 2001. It rose uniformly by rs1500 every year. How much should it cost in 2010 chapter ap |
Answer» HOPING IT WOULD BE HELPFUL !! |
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| 29. |
Verify that -(-x) = x for x = 2/5 |
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Answer» Step-by-step explanation: Givenx= 15 2
−−(1) \begin{gathered}LHS = -(-X)\\=-\BIG(-\frac{2}{15}\big)\end{gathered} LHS=−(−x) =−(− 15 2
)
\* from (1)*\ =\frac{2}{15}= 15 2
\begin{gathered}=x \\=RHS\end{gathered} =x =RHS
/* from (1)*/ -(-x)=x−(−x)=x i) Given \: x = \frac{-13}{17}--(2)i)Givenx= 17 −13
−−(2) \begin{gathered}LHS = -(-x)\\=-\big(-\LEFT(\frac{-13}{17}\right)\big)\end{gathered} LHS=−(−x) =−(−( 17 −13
))
\* from (2)*\ =-\frac{13}{17}=− 17 13
\begin{gathered}=x \\=RHS\end{gathered} =x =RHS
/* from (2)*/ Therefore, -(-x)=x−(−x)=x plz like me |
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| 30. |
the train travels a distance of 480 km at a uniform speed if the speed had been 8 kilometre per hour more, than it would have taken 2 hours less to cover the same distance. the quadratic equation is. |
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Answer» Answer: If the speed had been 8 km/h less, then it would have taken 3 hours more to COVER the same DISTANCE. We need to find the speed of the train. But speed of the train cannot be –ve. x = 40. |
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| 31. |
If the difference between compound interest and simple interest for 3 years is 840/- and the rate of interest is 11 1/9 %, then what's the principal?(a) 21,8701 (b) 20,780 (C) 18,225 (d) 24,300 (e) NOTA |
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Answer» simple interest= PTR/100. formula . compound interest = AMOUNT - principal. calculate your SELF. |
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| 32. |
1)Kiran deposited Rs.200 per month for 36 months in a bank’s recurring deposit account.If the bank pays interest at 11 % per annum ,find the amount she gets on maturity. |
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| 33. |
4x²-4a²x-(a⁴-b⁴) by middle term split |
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Answer» 4x^2 - 4xa^2 +a^4 = b^4 ( 2X -a^2 )^2 = (b^2)^2 2x - a^2 = + b^2 or - b^2 x = (a^2 - b^2 ) / 2 or ( a^2 + b^2 ) /2 |
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| 34. |
Form the pde by eliminating arbitrary constants and b from z=(x^2+a^2)(y^2+b^2) |
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Answer» Answer: hey MAN who has the right now 8GCxBt the BEST price 87354298648ehebcvdh |
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| 35. |
Add:a-3b+3;2a+5-3c;6c-15+6b |
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Answer» (a-3b+3) +(2a+5-3c)+(6c-15+6b) a+2a-3b+6b+3+5-15-3c+6c 3a+3b+8-15+3c 3a+3b-7+3c Answer: 3a+3b-7+3c |
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| 36. |
If xtan 45° sin 30° =cos30° tan 30", then is equal tocos x(a) v3b)½(C)1/v2(d) 1 |
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Answer» Answer: |
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| 37. |
Find the ratio in which the y axis divides the line segment joining the points (5,_6) and (_1,4) and also find the point of intersections |
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| 38. |
The Cost Price Of 16 articles is equal to the selling price of 12 articles. Find The Gain Percent |
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Answer» Answer: 33.33% Step-by-step explanation: CP of 16 ARTICLES = SP of 12 articles CPof 1 ARTICLE = SP of 1 article CP of 1/16 of article = SP of 1/12 of article GAIN% = (1/12-1/16)/(1/16) * 100 % =(1/48)/(1/16) * 100% =100/3% =33.33% |
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| 39. |
4. If p and q are two consecutive odd positive integers such that p > q then prove that the twop+q P-9numbersand are even and odd integers respectively.225. (a) Show that any positive odd integer is of the form 49 + 1 or 49 +3, where q is some integer. |
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Answer» <P>Step-by-step explanation: As we know, even numbers are always divisible by 2. So if any number is divisible by 2, it is an even number. Even & odd number come ALTERNATIVELY om number line. So, if 2a is even, 2a + 1 or 2a + any odd number, MUST be odd. Now, let q = 2a + 1 & p(>q) = 2b + 1. So, p + q = 2a + 1 + 2b + 1 = 2(a + b) + 2 p + q = 2(a + b + 1) As p + q is divisible by 2, it is an even number. p - q = 2b + 1 - (2a - 1) = 2b + 1 - 2a - 1 p - q = 2(b - a) p - q = number divisible by 2, it is also an even number. Check your quetion. (5): As mentioned above ' if any number is divisible by 2, it is an even number. Even & odd number come alternatively om number line. So, if 2a is even, 2a + 1 or 2a + any odd number, must be odd', Similarly, 4A is even, 4a + 1 or 4a + any odd number, must be odd. Thus, 4q + 1 and 4q + 3, both are odd numbers. |
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| 40. |
3. The weights (in kg) of 30 students of a class are39, 43, 32, 37, 29, 26, 31, 45, 46, 31, 37, 38, 30, 39, 36, 41, 35, 34, 41, 46, 39, 38, 36,38, 40, 42, 33, 43, 44, 33. draw a histogram. |
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Answer» Answer: The weight (in kg) of 30 students of a class To find: Draw histogram Solution: 39, 38, 36, 38, 40, 42, 43, 44, 33, 33, 31, 45, 46, 38, 37, 31, 30, 39, 41, 41, 46, 36, 35, 34, 39, 43, 32, 37, 29, 26. Marks f 26 | 29 | 30 | 31 || 32 | 33 || 34 | 35 | 36 || 37 || 38 ||| 39 ||| 40 | 41 || 42 | 43 || 44 | 45 | 46 || Class f 25- 28 1 29 - 32 5 33 - 36 6 37 - 40 9 41 - 44 6 45 - 48 3 Histogram attached Histogram: a graphical display of data using bars of different HEIGHTS. It is similar to a Bar Chart, but a histogram groups numbers into RANGES |
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| 41. |
A man daily goes to temple which is 4km/h once he decided to take his dog with him |
Answer» ANSWER:That's FINE. No NEED to WORRY. |
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| 42. |
The side of a square is 10 meter The same square is d divided into four equal squares. find the area of each square |
Answer» Answer:25m².Step-by-step explanation:Area of the Square is 100m², as sides are of 10m.No. of SMALL SQUARES divided into are 4.So, 100m² ÷ 4 = 25m². |
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| 43. |
Please friends answer this question i will Mark you Brainliest |
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Answer» Step-by-step explanation: PLEASE mark me BRAINILEST and this PICTURE all I give ANS in pictures |
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| 44. |
Palce valve and face value 4 in 23469 |
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Answer» Answer: face value of 4 is 4 Step-by-step explanation: |
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| 45. |
Differentiate 103x^6 . sec x ( 3x+2) |
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Answer» Answer: Note that, y = sec x + tan 2 x sec x ,
= sec x ( sec 2 x + tan 2 x ) ,
= sec x { sec 2 x + ( sec 2 x − 1 ) } ,
= sec x ( 2 sec 2 x − 1 ) .
∴ y = 2 sec 3 x − sec x .
∴ d y d x = d d x { 2 sec 3 x − sec x } ,
= 2 d d x { ( sec x ) 3 } − d d x { sec x } ,
= 2 ⋅ 3 ( sec x ) 2 d d x { sec x } − d d x { sec x } ,
= 6 sec 2 x d d x { sec x } − d d x { sec x } ,
= ( 6 sec 2 x − 1 ) d d x { sec x } ,
⇒ d y d x = ( 6 sec 2 x − 1 ) sec x tan x ,
or, what is the same as, { 6 ( tan 2 x + 1 ) − 1 } sec x tan x = ( 6 tan 2 x + 5 ) sec x tan x . Enjoy MATHS.! |
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| 46. |
Tan60°\sec60°+cosec60° |
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Answer» he CORRECT answer is 7/2√3.. Step-by-step EXPLANATION: TAN 60°/sec 60°+cosec 60°. =√3/2+2/√3. =3+4/2√3 =7/2√3...... |
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| 47. |
Followingthe value of k 4Findk for which theequationhas equal roots(K-12) x² + 2 (k-12) x + 2 eq. 0 |
Answer» I couldn't UNDERSTAND what you WANT to SAY about it and I did not KNOW it... |
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| 48. |
19. F A, B, C, D are angles of a cyclic quadrilateral, prove that sin A + sin B = sin C+ sin D. |
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Answer» This FORM is no longer accepting RESPONSES, and has been SET to automatically close by |
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| 49. |
X²+5px+16 has no real roots than |
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Answer» Answer: Given quadratic EQUATION is=x² + 5px +16 = 0 On comparing with standard FORM of quadratic equation i.e ax² + bx + c =0, Here, a = 1 , b= 5p, c= 16 D(discriminant)= b²-4ac = (5p)² - 4× 1 × 16 = 25p² - 64 Since, roots of given equation has no real roots. D < 0. 25p² - 64 <0 5p² - 8² < 0 (5p +8)(5p -8)< 0 [ a² - b² = (a-b)(a+b)] 5p +8 <0 or 5p - 8< 0 k > -8/5 or k < 8/5 -8/5 < k < 8/5 Hence, the required value of k is -8/5 < k < 8/5. HOPE THIS WILL HELP YOU... Step-by-step EXPLANATION:you are free fire player i haved followed you |
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| 50. |
Find the value ofwhen the distancebetween the points (3.a) and (4,1) isTo units. |
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Answer» Step-by-step explanation: applydistance FORMULA here √ so 2^2 = (4-3)^2 + (a-1)^2 4 = 1 + (a-1)^2 3 = (a-1)^2 so a^2 - 2a -2 = 0 so (a-1) (a-2) = 0 so a=1 ,2 |
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