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A3 For what wahur K, the quadrstic equationKx(x-2)=0 has real roots?​

Answer»

ANSWER:

the given equation can be written in the FORM of

k {x}^{2} - 2kx + 6 = 0

now it has EQUAL roots that means The DISCRIMINANT is 0

D = 0

Also

{b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6

Hence the value of K is 6.


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