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X²+5px+16 has no real roots than |
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Answer» Answer: Given quadratic EQUATION is=x² + 5px +16 = 0 On comparing with standard FORM of quadratic equation i.e ax² + bx + c =0, Here, a = 1 , b= 5p, c= 16 D(discriminant)= b²-4ac = (5p)² - 4× 1 × 16 = 25p² - 64 Since, roots of given equation has no real roots. D < 0. 25p² - 64 <0 5p² - 8² < 0 (5p +8)(5p -8)< 0 [ a² - b² = (a-b)(a+b)] 5p +8 <0 or 5p - 8< 0 k > -8/5 or k < 8/5 -8/5 < k < 8/5 Hence, the required value of k is -8/5 < k < 8/5. HOPE THIS WILL HELP YOU... Step-by-step EXPLANATION:you are free fire player i haved followed you |
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