1.

Find the value ofwhen the distancebetween the points (3.a) and (4,1) isTo units.​

Answer»

Step-by-step explanation:

applydistance FORMULA here

√

(distance)^(2) = ( x1 - x2)^2 + (y2 - y1)^(2)

so 2^2 = (4-3)^2 + (a-1)^2

4 = 1 + (a-1)^2

3 = (a-1)^2

so a^2 - 2a -2 = 0

so (a-1) (a-2) = 0

so a=1 ,2



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