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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
5kl 100ml is how many kilolitres |
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Answer» Answer: 5.000001 Step-by-step explanation: 1 LITRE = 1000ml and 1000 litres = 1 kl hence, 1kl = 1000000 ml 1ML = 1 by 1000000ml = 0.000001 kl 5+0.000001 = 5.000001kl MARK this as BRAINLIEST |
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| 2. |
For any three sets P,Q and R, P-(QnR) is _________ . |
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Answer» <P>Answer: the answer is R- (p & Q) plzz FOLLOW me |
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| 3. |
Yvonne picks a blueberry on the first try and pops it into her mouth. Kate wants a green-apple candy. What are the chances Kate will pick green-apple? |
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Answer» Answer: |
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| 4. |
the first , third and fourth term of a proportion are 12, 8 and 14 respectively find the second term |
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Answer» 34 is very currently answer MATE 10 THANKS please |
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| 5. |
Find the value ofx+2=9 then x= |
Answer» Step-by-step EXPLANATION:➡️X+2=9➡️x=9-2➡️x=7☜☆☞hence value of x =7hope it HELPS you dear FRIEND please MARK me as brainliest ⚠️⚠️↪️➡️➡️↩️↩️↩️⬆️⬆️⬆️⬆️ |
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| 7. |
Yvonne closes her eyes and picks a candy from the bag, hoping for a blueberry. What are the chances she will pick a blueberry candy? |
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Answer» jhuh Step-by-step EXPLANATION: |
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| 8. |
Show that the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. |
Answer» Given,Diagonals are equal Diagonals are equalAC=BD .......(1) Diagonals are equalAC=BD .......(1)and the diagonals bisect each other at right angles Diagonals are equalAC=BD .......(1)and the diagonals bisect each other at right anglesOA=OC;OB=OD ...... (2) Diagonals are equalAC=BD .......(1)and the diagonals bisect each other at right anglesOA=OC;OB=OD ...... (2)∠AOB= ∠BOC= ∠COD= ∠AOD= 90 Diagonals are equalAC=BD .......(1)and the diagonals bisect each other at right anglesOA=OC;OB=OD ...... (2)∠AOB= ∠BOC= ∠COD= ∠AOD= 90 0 Diagonals are equalAC=BD .......(1)and the diagonals bisect each other at right anglesOA=OC;OB=OD ...... (2)∠AOB= ∠BOC= ∠COD= ∠AOD= 90 0 ..........(3) Proof:Proof:Consider △AOB and △COB Proof:Consider △AOB and △COBOA=OC ....[from (2)] Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COB Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common side Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common sideTherefore, Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common sideTherefore,△AOB≅ △COB Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common sideTherefore,△AOB≅ △COBFrom SAS criteria, AB=CB Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common sideTherefore,△AOB≅ △COBFrom SAS criteria, AB=CBSimilarly, we prove Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common sideTherefore,△AOB≅ △COBFrom SAS criteria, AB=CBSimilarly, we prove△AOB≅ △DOA, so AB=AD Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common sideTherefore,△AOB≅ △COBFrom SAS criteria, AB=CBSimilarly, we prove△AOB≅ △DOA, so AB=AD△BOC≅ △COD, so CB=DC Proof:Consider △AOB and △COBOA=OC ....[from (2)]∠AOB= ∠COBOB is the common sideTherefore,△AOB≅ △COBFrom SAS criteria, AB=CBSimilarly, we prove△AOB≅ △DOA, so AB=AD△BOC≅ △COD, so CB=DCSo, AB=AD=CB=DC ....(4) ....(4)So, in quadrilateral ABCD, both pairs of opposite sides are equal, hence ABCD is PARALLELOGRAM. In △ABC and △DCB In △ABC and △DCBAC=BD ...(from (1)) In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$) In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCB In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCB In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow, In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 ∠B+∠B= 180 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 ∠B+∠B= 180 0 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 ∠B+∠B= 180 0 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 ∠B+∠B= 180 0 ∠B= 90 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 ∠B+∠B= 180 0 ∠B= 90 0 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 ∠B+∠B= 180 0 ∠B= 90 0 In △ABC and △DCBAC=BD ...(from (1))AB=DC ...(from $$(4)$$)BC is the common side△ABC≅ △DCBSo, from SSS criteria, ∠ABC= ∠DCBNow,AB∥CD,BC is the tansversal∠B+∠C= 180 0 ∠B+∠B= 180 0 ∠B= 90 0 Hence, ABCD is a parallelogram with all sides equal and one ANGLE is 90 0
So,ABCD is a square.Hence proved. Hope its helpful for u sis...☺️Inbox pls. @BrainlyAnyu
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| 9. |
Divide please give me answer |
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Answer» do yourself and MAKE me BRAINLIEST |
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| 11. |
X+y+z=20 and 3x+y+0.25z=20 solve the equation. |
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Answer» soonajahbshxsahwhx e9s |
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| 12. |
Find the Zeros,the sum and the product of Zeros of p (x)=4x2+12x+5 |
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Answer» product of zeros=5/4 |
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| 13. |
A pilot jumps from an aeroplane, falls freely for 4 seconds.After 4 seconds, he opens the parachute and moves with uniform retardation of 5m/s2 for 4 seconds. Then he descends with uniform velocity for 4 seconds.draw x-t, v-t and a-t graphs for the motion of the pilot. Take acceleration due to gravity as 10m/s2. |
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Answer» Answer: S=4 m Step-by-step explanation: As the parachutist jump from the areoplane, he has no VELOCITY in the vertical DIRECTION. The initial velocity of the parachutist in the vertical direction is 0 m/s The final velocity of the parachutist is 4 m/s The acceleration of the parachutist is 2 m/s 2
The distance covered by the parachutist in the air is: v 2 =U 2 +2aS 4 2 =0+2×2×S S= 4 16
S=4 m |
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| 14. |
in a proportion the first second and fourth term are51 ,68 and 108 respectively . find the third term |
Answer»
so,
therefore the third term is 81.... hope this answer helps you dude!! MARK as brainliest!!! |
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| 15. |
(6) Simplify.(i) 5 √3 +8 √3 |
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Answer» Answer: THE FIRST STEP 5 +8=13 √3+√3=√6 Step-by-step explanation: SO ANSWER 13√6 I HOPE IT IS CORRECT |
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| 16. |
He wants to 150 kilocalories he spend x on walking and y on jogging find linear equation and graph |
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Answer» don't KNOW Step-by-step EXPLANATION: |
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| 17. |
Plzz help me. you are genius.brainlist and thanks sure. |
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Answer» Step-by-step EXPLANATION: |
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| 18. |
Simplify the rationalising the denominator 7+2 root 5/7-2root 5 |
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Answer» ROOT 5.2425783 Step-by-step explanation: |
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| 19. |
The ratio of age of rahul & vimal 4 yeras ago is 4:3.the ratio of sum & difference of their present age is 9:1.what will be the age of vimal after 4 years |
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Answer» Answer: 20 year Step-by-step explanation: As the ratio is 4:3, LET the age of RAHUL & VIMAL, that time, be 4a and 3a. So, PRESENT age of: Rahul = 4a + 4 Vimal = 3a + 4 In question, = > (sum of their ages):(difference in their ages) = 9:1 = > (4a + 4 + 3a + 4):{4a+4-(3a+4)} = 9:1 = > (7a + 8):(4a + 4 - 3a - 4) = 9:1 = > (7a + 8): a = 9:1 = > 7a + 8 = 9a = > 8 = 9a - 7a = > 8 = 2a = > 4 = a Present age of vimal = 3a + 4 = 3(4) + 4 = 16 year So, after 4 years, age of vimal = 16+4 = 20 year |
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| 20. |
Find the value of y-6=8 then x= |
Answer» Answer :- |
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| 22. |
Expand this question (3x+5)³ |
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Answer» Answer: 3x+45=48x Step-by-step EXPLANATION: |
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| 23. |
Find five rational numbers between -2/7 and -3/7 |
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Answer» -21/70, -22/70, -23/70, -24/70 and -25/70. |
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| 25. |
The sum of two angles is 5πcand their difference is 60°. Find their measures in degree. |
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Answer» ANGLES are 480degree and 420degree |
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| 26. |
If -50 means spending rs.50 than what meaning will +200 have |
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Answer» I don't know if you have any QUESTIONS please FEEL free to contact me at any TIME and I will be there at any time and I will be there at any time and I |
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| 27. |
A nesklace is made of gold and sipver weighs 65 g. If it consists of 2/13 parts of copper find the weight of gold in the necklace. |
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Answer» GIVEN, weight of ornament = 52gm copper = 2/13 so gold must be = 11/13 Ornament = total weight * parts of gold 52* 11/13 =44 gm Hope this helps you Please mark me as brainliest |
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| 28. |
8-{4(10-8) -16÷2} is equals to what please tell emergency my exam is their tomorrow. |
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Answer» =5. Step-by-step EXPLANATION: |
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| 29. |
Find the smallest number which when divided by t 39, 52,and 65, leaves a remainder of 5 in each case |
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Answer» Answer: Step-by-step explanation: 39= 13*3 52= 2*2*13 65= 13*5 L.C.M (39,52,65)= 2² * 3 * 5 * 13 L.C.M (39,52,65)= 20*39 L.C.M. (39,52,65)= 780 780+5 = 785 Therefore, 785 is the smallest NUMBER which when divided by 39,52 and 65, leaves a remainder of 5 in each CASE. |
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| 30. |
One of the factors of the polynomial Xcube-8 is |
Answer» FACTOR of X³-8 is X -2Step-by-step EXPLANATION: HOPE IT WILL HELP YOU ❣️❣️❣️❣️PLEASE MARK AS BRAINLIEST ♥️♥️♥️♥️ |
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| 31. |
To side of a triangle are 8 cm oeremeter is 32 cm. Find the length of the third side |
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Answer» no IDEA Step-by-step EXPLANATION: |
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| 32. |
The classes which are in the form of 10-20,20-30,30-40.. are called as.. |
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Answer» CLASS interval Step-by-step EXPLANATION: |
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| 33. |
How can we calculate the value of tan 10` |
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Answer» here is your answer Step-by-step explanation: Draw a RIGHT angled triangle having 10,80,90 degrees, Now take the ratio of SIDE opposite to the 10 DEGREE with the side COMMON to the 10,90 degree. The ratio is the value of tan10. |
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| 35. |
Solve the pair of linear equations using cross multiplication method: 5x-2y=14 and -2x+y=-5 . Also, verify the solutionPlease please give the answer as quickly as possible with full explanation. |
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Answer» Step-by-step explanation: your answer you please FOLLOW me I follow BACK you PROMISE paka..... |
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| 36. |
36a² + 36a + 9 pls solv this |
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Answer» no idea Step-by-step EXPLANATION: |
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| 37. |
Find the zeros of 3x^2-x-4and verify the relation ship between the zeros And the co efficients |
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| 38. |
a man cycles at a speed of 18 kilometre per hour what distance does he cover in 3 second if he increase his speed to 200% of his initial speed what distance will he cover in 19/8hrs also how much time does he take to cycle 2km at a pace of 18km/hrur |
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Answer» ___________ Step-by-step EXPLANATION: I don't KNOW |
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| 40. |
(1-1/2)(1-1/3)(1-1/4)(1-1/5).......(1-1/100) is equal to |
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Answer» Step-by-step EXPLANATION: |
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| 41. |
Evaluate the give equation 2.789 multiply 6.328 and round oof the hundredth place |
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Answer» 19.648792 is the answer |
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| 42. |
If the sum of three consecutive odd number is 33then what are the numbers? |
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Answer» Answer: 10+11+12 = 30 Mark as a BRAINLIEST |
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| 43. |
Mr lovely invested RS 480000in a bank at 9% compound invest for 2 years. mr jhon invested RS150000 in a mutual fund is 2years. after 2years mr jhon got RS 240000. whose investment turn out to be more profitable. |
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Answer» HOPE this helps please MRAK me brainlist Step-by-step EXPLANATION: |
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| 44. |
आकृति में ab||dc,यदि X=4_3y तथा y=3_8z तो[bcd,[abc तथा [badज्ञात कीजिए |
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| 45. |
EXFind the terms (written against them) of the following series :(i) 1, 2, 4, 8.... 10th term. |
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Answer» Answer: Step-by-step EXPLANATION: the given series is a geometric progression where 1st term is 1. (a=1) tenth term = a * r^9 =1*2^9 =2^9 = 512 |
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| 47. |
(x-3)^2 step by step explaination from algebraic Identities |
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| 48. |
Check if 64 is a perfect square or perfect cubr if yes find square root or cube root |
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Answer» Answer: Prime FACTORISATION of 64, 64 = 2⁶ So it can be written as, 64 = 4x4x4 or, 64 = 8x8 Therefore,64 is a perfect SQUARE as well as perfect cube. square ROOT = 8 cube root = 4 hope this helps please mark Brainliest |
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| 50. |
Given l parallel m and p parallel q find x and y please answer me |
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Answer» Hi mate , who came to Brainly newly. ツ When you are posting these type of questions also add the related pic, along with it. |
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