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A pilot jumps from an aeroplane, falls freely for 4 seconds.After 4 seconds, he opens the parachute and moves with uniform retardation of 5m/s2 for 4 seconds. Then he descends with uniform velocity for 4 seconds.draw x-t, v-t and a-t graphs for the motion of the pilot. Take acceleration due to gravity as 10m/s2. |
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Answer» Answer: S=4 m Step-by-step explanation: As the parachutist jump from the areoplane, he has no VELOCITY in the vertical DIRECTION. The initial velocity of the parachutist in the vertical direction is 0 m/s The final velocity of the parachutist is 4 m/s The acceleration of the parachutist is 2 m/s 2
The distance covered by the parachutist in the air is: v 2 =U 2 +2aS 4 2 =0+2×2×S S= 4 16
S=4 m |
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