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Find the smallest number which when divided by t 39, 52,and 65, leaves a remainder of 5 in each case |
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Answer» Answer: Step-by-step explanation: 39= 13*3 52= 2*2*13 65= 13*5 L.C.M (39,52,65)= 2² * 3 * 5 * 13 L.C.M (39,52,65)= 20*39 L.C.M. (39,52,65)= 780 780+5 = 785 Therefore, 785 is the smallest NUMBER which when divided by 39,52 and 65, leaves a remainder of 5 in each CASE. |
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