332354 + Interview Questions in Secondary School in Math

1.	2x-3y+15=0,3x-5=0 substitution method
Answer» Step-by-step EXPLANATION: HOPE it's HELPING...... ..

1.

2x-3y+15=0,3x-5=0 substitution method

Answer»

Step-by-step EXPLANATION:

HOPE it's HELPING...... ..

Discussion

2.	Verify the stetment of this question
Answer» ANSWER: 1.(3/4×1/2)×5/7=3/4×(1/2×5/7) Step-by-step EXPLANATION: solution: 3/4×(1/2×5/7)=3/4×(1/2×5/7) (3/4×5/14)=(3/4×5/14) 15/56=15/56 This is answer...

2.

Verify the stetment of this question

Answer»

ANSWER:

1.(3/4×1/2)×5/7=3/4×(1/2×5/7)

Step-by-step EXPLANATION:

solution:

3/4×(1/2×5/7)=3/4×(1/2×5/7)

(3/4×5/14)=(3/4×5/14)

15/56=15/56 This is answer...

Discussion

3.	6+5 answw my guestion
Answer» 11 is the answer. hope it HELPS you FOLLOW me

3.

6+5 answw my guestion

Answer»

11 is the answer.

hope it HELPS you FOLLOW me

Discussion

4.	A car covers 800km in 16hours. Find the distance covered by the car in our hour?
Answer» Answer: If it covers 800 km in ,16 hrs then It will cover in an hour 800/16 =50km/hr

4.

A car covers 800km in 16hours. Find the distance covered by the car in our hour?

Answer»

Answer:

If it covers 800 km in ,16 hrs then

It will cover in an hour

800/16

=50km/hr

Discussion

5.	from the sum of largest 6 digit number and smallest 6 digit number ,subtract the largest 5 digit number
Answer» Answer: 1000000 Step-by-step explanation: 999999+100000=1099999 1099999 - 99999= 1000000

5.

from the sum of largest 6 digit number and smallest 6 digit number ,subtract the largest 5 digit number

Answer»

Answer:

1000000

Step-by-step explanation:

999999+100000=1099999

1099999 - 99999= 1000000

Discussion

6.	Find coordinates of a point whose ordinate is 4 and which lies on y axis
Answer» ANSWER: (0,4) is the correct answer of your QUESTION PLEASE mark as BRAINLIEST

6.

Find coordinates of a point whose ordinate is 4 and which lies on y axis

Answer»

ANSWER:

(0,4) is the correct answer of your QUESTION PLEASE mark as BRAINLIEST

Discussion

7.	A number is first increased by 15% and then reduced by 15%. By what percentage does the number change?
Answer» ANSWER: THUMBS up with the ATTACHED DOCUMENT

7.

A number is first increased by 15% and then reduced by 15%. By what percentage does the number change?

Answer»

ANSWER:

THUMBS up with the ATTACHED DOCUMENT

Discussion

8.	A bag contain 150 coins of 50 paise and 25 Paise denominations. The total worth of these coins is rs 55. Find the number of each type
Answer» Answer Let the no of 50 PAISE coins ie 0.5 ruppees Be x and let the number of 25 paise coins ie 0.25 ruppees be y As per given conditions X+y=150 X=150-y........(I) 0.5x+0.25y=55 0.5(150-y)+0.25y=55 75-0.5y+0.25y=55 -0.25y=55-75 -0.25y=-20 0.25y=20 Y=80.........yes here we got no. Of 25 paise coins Now from (i)equation X+y=150 X=150-80 X=70 Here we got no. Of 50 paise coins to be 70 ,......hope it helps .pls mark as brainliest pls

8.

A bag contain 150 coins of 50 paise and 25 Paise denominations. The total worth of these coins is rs 55. Find the number of each type

Answer»

Answer

Let the no of 50 PAISE coins ie 0.5 ruppees

Be x and let the number of 25 paise coins ie 0.25 ruppees be y

As per given conditions

X+y=150

X=150-y........(I)

0.5x+0.25y=55

0.5(150-y)+0.25y=55

75-0.5y+0.25y=55

-0.25y=55-75

-0.25y=-20

0.25y=20

Y=80.........yes here we got no. Of 25 paise coins

Now from (i)equation

X+y=150

X=150-80

X=70

Here we got no. Of 50 paise coins to be 70

,......hope it helps .pls mark as brainliest pls

Discussion

9.	The time taken by Ram to cover 150 kilometre was 2.5 hours more than the time taken in the return journey is returned at a speed of 10 kilometre per hour more than the speed of going what was the speed per hr in each direction(step by step explanation need )
Answer» ANSWER: he GOES at a speed of 20km PER hour and came back at a speed of 30km per hour

9.

The time taken by Ram to cover 150 kilometre was 2.5 hours more than the time taken in the return journey is returned at a speed of 10 kilometre per hour more than the speed of going what was the speed per hr in each direction(step by step explanation need )

Answer»

ANSWER:

he GOES at a speed of 20km PER hour and came back at a speed of 30km per hour

Discussion

10.	3126/125*1/49plz answer in fraction
Answer» ANSWER: FIRST COMPLETE the given QUESTION or correct the answer

10.

3126/125*1/49plz answer in fraction

Answer»

ANSWER:

FIRST COMPLETE the given QUESTION or correct the answer

Discussion

11.	Multiply 4/11*(-2/9)
Answer» Step-by-step explanation: 4/11×(-2/9) =-8/99 . so the ANSWER is -8/99.

11.

Multiply 4/11*(-2/9)

Answer»

Step-by-step explanation:

4/11×(-2/9)

=-8/99 .

so the ANSWER is -8/99.

Discussion

12.	Insert commas suitably and write the names according to the Indian system of numeration for digit 7
Answer» Answer: 00,00,000 Step-by-step EXPLANATION: PLEASE MARK it as brinlylist ANSWERS

12.

Insert commas suitably and write the names according to the Indian system of numeration for digit 7

Answer»

Answer:

00,00,000

Step-by-step EXPLANATION:

PLEASE MARK it as brinlylist ANSWERS

Discussion

13.	Convert 25degree to radian
Answer» Answer: To convert DEGREE into RADIAN multiply the GIVEN number by π/180 Therefor, 25 x π / 180 = (5 π/ 36 ) radian

13.

Convert 25degree to radian

Answer»

Answer:

To convert DEGREE into RADIAN multiply the GIVEN number by π/180

Therefor,

25 x π / 180

= (5 π/ 36 ) radian

Discussion

14.	2+3= answer my question
Answer» 5 is the ANSWER. HOPE IT HELPS YOU FOLLOW ME

14.

2+3= answer my question

Answer»

5 is the ANSWER.

HOPE IT HELPS YOU FOLLOW ME

Discussion

15.	Only one curved face
Answer» Cylinder have only ONE CURVED surface. Hope this HELPS you.

15.

Only one curved face

Answer»

Cylinder have only ONE CURVED surface.

Hope this HELPS you.

Discussion

16.	Sum of first 3 terms of AP is 57 and sum of last 3 terms is 246 .find n if d= 7
Answer» ANSWER: There are TOTAL 12 TERMS in this A.P

16.

Sum of first 3 terms of AP is 57 and sum of last 3 terms is 246 .find n if d= 7

Answer»

ANSWER:

There are TOTAL 12 TERMS in this A.P

Discussion

17.	எடுத்துக்காட்டு 1.2 மக்கள்தொகை 5000 உள்ள ஒரு நகரத்தில் நடத்தப்பட்ட ஒரு கணக்கெடுப்பில், மொழி தெரிந்தவர்கள் 45%, மொழி B தெரிந்தவர்கள் 25%, மொழி - தெரிந்தவர்கள் 10%, Aமற்றும் 5 மொழிகள் தெரிந்தவர்கள் 5%, B மற்றும் C மொழிகள் தெரிந்தவர்கள் 4%, A மற்றும் Cமொழிகள் தெரிந்தவர்கள் 4% ஆகும். இதில் மூன்று மொழிகளையும் தெரிந்தவர்கள் 3% எனில், மொழி4 மட்டும் தெரிந்தவர்கள் எத்தனை பேர்?
Answer» PLZ WRITE in ENGLISH .... It can’t be UNDERSTOOD by EVERYONE...

17.

எடுத்துக்காட்டு 1.2 மக்கள்தொகை 5000 உள்ள ஒரு நகரத்தில் நடத்தப்பட்ட ஒரு கணக்கெடுப்பில், மொழி தெரிந்தவர்கள் 45%, மொழி B தெரிந்தவர்கள் 25%, மொழி - தெரிந்தவர்கள் 10%, Aமற்றும் 5 மொழிகள் தெரிந்தவர்கள் 5%, B மற்றும் C மொழிகள் தெரிந்தவர்கள் 4%, A மற்றும் Cமொழிகள் தெரிந்தவர்கள் 4% ஆகும். இதில் மூன்று மொழிகளையும் தெரிந்தவர்கள் 3% எனில், மொழி4 மட்டும் தெரிந்தவர்கள் எத்தனை பேர்?

Answer»

PLZ WRITE in ENGLISH ....

It can’t be UNDERSTOOD by EVERYONE...

Discussion

18.	Find the sum of first term and common difference of the sequence 3036
Answer» Step-by-step explanation: Common DIFFERENCE = 0-(-3) =3 First term is -3 But U did not MENTION the sum of HOW MANY TERMS! OR common difference is known as d and d formula is:- d = a2-a1 d = 0-(-3) d= 0+3 d=3 HOPE IT'S HELP YOU

18.

Find the sum of first term and common difference of the sequence 3036

Answer»

Step-by-step explanation:

Common DIFFERENCE

= 0-(-3)

=3

First term is -3

But U did not MENTION the sum of HOW MANY TERMS!

OR

common difference is known as d and d formula is:-

d = a2-a1

d = 0-(-3)

d= 0+3

d=3

HOPE IT'S HELP YOU

Discussion

19.	Show (x-2y^3)+(2y-3z) ^3+(3z-x) ^3=3(x-2y)(2y-3x) (3z-x)plz solve my this question please
Answer» ANSWER: you can SOLVE this by FOLLOWING FORMULA

19.

Show (x-2y^3)+(2y-3z) ^3+(3z-x) ^3=3(x-2y)(2y-3x) (3z-x)plz solve my this question please

Answer»

ANSWER:

you can SOLVE this by FOLLOWING FORMULA

Discussion

20.	Write in Roman numerals. 438, 1432, 256and 109
Answer» Step-by-step explanation: 438=CDXXXVIII 1432=MCDXXXII 256=CCLVI 109=CIX

20.

Write in Roman numerals. 438, 1432, 256and 109

Answer»

Step-by-step explanation:

438=CDXXXVIII

1432=MCDXXXII

256=CCLVI

109=CIX

Discussion

21.	ABCD IS A trapezium with AB parallel to Dc and angle DAB =90degree. prove triangle DEC is congruent to triangle BEC
Answer» ANSWER: SHUT off Step-by-step EXPLANATION: you are TOPPER

21.

ABCD IS A trapezium with AB parallel to Dc and angle DAB =90degree. prove triangle DEC is congruent to triangle BEC

Answer»

ANSWER:

SHUT off

Step-by-step EXPLANATION:

you are TOPPER

Discussion

22.	57. Find the cost of 33/4 meter of cloth at rs.362/3per meter.
Answer» Answer: it is very EASY and the answer of this question is 137 WHOLE 1 by 2

22.

57. Find the cost of 33/4 meter of cloth at rs.362/3per meter.

Answer»

Answer:

it is very EASY and the answer of this question is 137 WHOLE 1 by 2

Discussion

23.	OS An-omament is made of gold and copper and weighs 52 grams. If 2/13 of its part IS copperfind the weight of pure gold in it
Answer» ANSWER: Step-by-step EXPLANATION: (2/13)(52) =8 Remaining is GOLD 52-8=44 GRAMS

23.

OS An-omament is made of gold and copper and weighs 52 grams. If 2/13 of its part IS copperfind the weight of pure gold in it

Answer»

ANSWER:

Step-by-step EXPLANATION:

(2/13)(52)

=8

Remaining is GOLD

52-8=44 GRAMS

Discussion

24.	Pls solve 14 problem
Answer» ANSWER: is 16 PLS SEE this ATTACHMENT

24.

Pls solve 14 problem

Answer»

ANSWER:

is 16 PLS SEE this ATTACHMENT

Discussion

25.	last year Bunty waited 75 KGS this year he waited 90 kgs with what percentage did his weight increase
Answer» ANSWER: BUNTY original weight=75 increased weight=90 increase PERCENT =NEW weight-original/original 100 9075/75*100 20% therefore increased percent is20

25.

last year Bunty waited 75 KGS this year he waited 90 kgs with what percentage did his weight increase

Answer»

ANSWER:

BUNTY original weight=75

increased weight=90

increase PERCENT =NEW weight-original/original *100

90*75/75*100

20%

therefore increased percent is20

Discussion

26.	З/4×[8/9-40] in distributive form
Answer» Answer: 3/4×[8/9-40] 0.75×[0.88-40] 0.66-40 -39.34 Step-by-step EXPLANATION: mark.me as a BRAINLIEST

26.

З/4×[8/9-40] in distributive form

Answer»

Answer:

3/4×[8/9-40]

0.75×[0.88-40]

0.66-40

-39.34

Step-by-step EXPLANATION:

mark.me as a BRAINLIEST

Discussion

27.	Ram nath govind ka jivan parichay in hindi
Answer» ANSWER: SRY DEAR don't KNOW HINDI

27.

Ram nath govind ka jivan parichay in hindi

Answer»

ANSWER:

SRY DEAR don't KNOW HINDI

Discussion

28.	Solve the following questioms plz
Answer» Answer: 1. 3X-8/2X = 1 3x - 8 = 2x 3x- 2x = 8 x=8 2. 5X/2x- 1 = 2 5x = 4x - 2 5x - 4x = -2 x = -2

28.

Solve the following questioms plz

Answer»

Answer:

1. 3X-8/2X = 1

3x - 8 = 2x

3x- 2x = 8

x=8

2. 5X/2x- 1 = 2

5x = 4x - 2

5x - 4x = -2

x = -2

Discussion

29.	A can do work in 18 days b can do in 15 days b wof for 10 days and left
Answer» ANSWER: Step-by-step explanation: b worked for 10 days. So, REMAINING 5 days WORK is pending. This is 5/15 = 1/3rd of work. a can finish the work in 18 days. So, 1/3rd of work can be DONE in 18 × 1/3 = 6 days.

29.

A can do work in 18 days b can do in 15 days b wof for 10 days and left

Answer»

ANSWER:

Step-by-step explanation:

b worked for 10 days. So, REMAINING 5 days WORK is pending. This is 5/15 = 1/3rd of work.

a can finish the work in 18 days. So, 1/3rd of work can be DONE in 18 × 1/3 = 6 days.

Discussion

30.	After how many yrs does a leap year repeat the same calendar year as 2004
Answer» Answer: 2008, 2012, 2016 and NEXT 2020

30.

After how many yrs does a leap year repeat the same calendar year as 2004

Answer»

Answer:

2008, 2012, 2016 and NEXT 2020

Discussion

31.	After how many decimal places the decimal expansion of 51/150 will terminate
Answer» The decimal expansion $\frac{51}{150}$ will terminate after 2 decimal places. Step-by-step EXPLANATION: To find : After how many decimal places the decimal expansion of 51/150 will terminate ? SOLUTION : The decimal expansion is terminating when the DENOMINATOR is in the form of $2^n\times 5^m$ otherwise it is non-terminating. Factor the denominator, $\dfrac{51}{150}=\dfrac{51}{2\times3\times 5 \times5}$ $\dfrac{51}{150}=\dfrac{17}{2\times 5^2}$ The denominator is in the required form so it is terminating. $\dfrac{51}{150}=\dfrac{17\times 2}{2^2\times 5^2}$ $\dfrac{51}{150}=\dfrac{34}{10^2}$ $\dfrac{51}{150}=0.34$ The decimal expansion $\frac{51}{150}$ will terminate after 2 decimal places. #Learn more The decimal expansion of the rational number 33/22.5 will TERMINATES after How many places of decimal brainly.in/question/8036392

31.

After how many decimal places the decimal expansion of 51/150 will terminate

Answer»

The decimal expansion $\frac{51}{150}$ will terminate after 2 decimal places.

Step-by-step EXPLANATION:

To find : After how many decimal places the decimal expansion of 51/150 will terminate ?

SOLUTION :

The decimal expansion is terminating when the DENOMINATOR is in the form of $2^n\times 5^m$ otherwise it is non-terminating.

Factor the denominator,

$\dfrac{51}{150}=\dfrac{51}{2\times3\times 5 \times5}$

$\dfrac{51}{150}=\dfrac{17}{2\times 5^2}$

The denominator is in the required form so it is terminating.

$\dfrac{51}{150}=\dfrac{17\times 2}{2^2\times 5^2}$

$\dfrac{51}{150}=\dfrac{34}{10^2}$

$\dfrac{51}{150}=0.34$

The decimal expansion $\frac{51}{150}$ will terminate after 2 decimal places.

#Learn more

The decimal expansion of the rational number 33/22.5 will TERMINATES after How many places of decimal

brainly.in/question/8036392

Discussion

32.	Cos a = 3/4 find 16cosÂ²(a/2) - 32sin(a/2)sin(5a/2)
Answer» Answer: 32sinA/2.sin5A/2 use formula , 2sinA.sinB = cos(A -B) -cos(A+B) cos2A = 2cos²A -1 cos3A = 4cos³A -3COSA now, 32sinA/2sin5A/2 = 16cos2A -16cos3A 16{ 2cos²A -1 -4cos³A+3cosA} =16{ 2(3/4)²-1-4(3/4)³+3(3/4)} =16{ 18/16 -1 -27/16 +36/16} =( 18 -16 -27 +36} =11 Read more on Brainly.in - brainly.in/question/1122560#readmore

32.

Cos a = 3/4 find 16cosÂ²(a/2) - 32sin(a/2)sin(5a/2)

Answer»

Answer:

32sinA/2.sin5A/2

use formula ,

2sinA.sinB = cos(A -B) -cos(A+B)

cos2A = 2cos²A -1

cos3A = 4cos³A -3COSA

now,

32sinA/2sin5A/2 = 16cos2A -16cos3A

16{ 2cos²A -1 -4cos³A+3cosA}

=16{ 2(3/4)²-1-4(3/4)³+3(3/4)}

=16{ 18/16 -1 -27/16 +36/16}

=( 18 -16 -27 +36}

=11

Read more on Brainly.in - brainly.in/question/1122560#readmore

Discussion

33.	In a plate there were 9 sweetscach. 3 of the Sweets in eachPlate were roso gullas and theremaining were burfees. How manyberfees are there in 7 plates ?write the mathematical statement.
Answer» Step-by-step explanation: Number of SWEETS in ONE plate=9 Number of rasgullas in a plate=3 Number of BURFEES in a plate=9-3=6 Number of burfees in 7 plate=7*6=42

33.

In a plate there were 9 sweetscach. 3 of the Sweets in eachPlate were roso gullas and theremaining were burfees. How manyberfees are there in 7 plates ?write the mathematical statement.

Answer»

Step-by-step explanation:

Number of SWEETS in ONE plate=9

Number of rasgullas in a plate=3

Number of BURFEES in a plate=9-3=6

Number of burfees in 7 plate=7*6=42

Discussion

34.	Substitution method
Answer» ANSWER: Step-by-step EXPLANATION:

34.

Substitution method

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

35.	What is the h.c.f of p and q where p=a^2 b^3 and q=b^3 ^2
Answer» HEY MATE! HERE IS YOUR ANSWER: p=a^2b^3 and q=b^3a^2 HCF = a^2b^3

35.

What is the h.c.f of p and q where p=a^2 b^3 and q=b^3 ^2

Answer»

HEY MATE!

HERE IS YOUR ANSWER:

p=a^2b^3 and q=b^3a^2

HCF = a^2b^3

Discussion

36.	18. If pth term of an A.P. be q and the qth term be p. Then (p+q)th term is(a) 0 (b) -1 (c) 1 (d) none of these
Answer» Answer: option a is correct t (p + q) = 0 step by step explanation: ☑ pth term of an A.P. be q and the qth term be p. let, TP = q tq = p we know the FORMULA, TN = a + (n - 1)d so, tp = a + ( p - 1)d q = a + (p - 1 ) d..........(1) and tq = a + ( q - 1) d p = a + (q - 1 ) d ...........(2) were, a = 1st term d = common difference from 1 and 2 , subtract the equation (2) from (1) q = a + (p - 1 ) d p = a + (q - 1 ) d - - - ____________________ (q - p) = (p - 1)d - (q - 1)d = dp - d - dq + d = dp - dq (q - p) = d ( p - q) (q - p) / (p - q) = d - ( - q + p) / ( p - q) =d - (p - q) / (p - q) = d d = - 1 ☑ put the value of d in equation (1) q = a + (p - 1 ) d = a + ( p - 1) (-1) = a - p + 1 a = q + p - 1 Therefor, t (p + q) = a + ( (p + q) - 1 ) ( -1) = q + p -1 - p - q + 1 = 0

36.

18. If pth term of an A.P. be q and the qth term be p. Then (p+q)th term is(a) 0 (b) -1 (c) 1 (d) none of these

Answer»

Answer:

option a is correct

t (p + q) = 0

step by step explanation:

☑ pth term of an A.P. be q and the qth term be p.

let,

TP = q

tq = p

we know the FORMULA,

TN = a + (n - 1)d

so, tp = a + ( p - 1)d

q = a + (p - 1 ) d..........(1)

and

tq = a + ( q - 1) d

p = a + (q - 1 ) d ...........(2)

were,

a = 1st term

d = common difference

from 1 and 2 , subtract the equation (2) from (1)

q = a + (p - 1 ) d

p = a + (q - 1 ) d

- - -

____________________

(q - p) = (p - 1)d - (q - 1)d

= dp - d - dq + d

= dp - dq

(q - p) = d ( p - q)

(q - p) / (p - q) = d

- ( - q + p) / ( p - q) =d

- (p - q) / (p - q) = d

d = - 1

☑ put the value of d in equation (1)

q = a + (p - 1 ) d

= a + ( p - 1) (-1)

= a - p + 1

a = q + p - 1

Therefor,

t (p + q) = a + ( (p + q) - 1 ) ( -1)

= q + p -1 - p - q + 1

= 0

Discussion

37.	Find two rational number √3and√5
Answer» ANSWER: √3=1.73. √5=2.26 between it's 1.74......and 1.75......

37.

Find two rational number √3and√5

Answer»

ANSWER:

√3=1.73. √5=2.26

between it's

1.74......and 1.75......

Discussion

38.	Find 3/4×[8/9-40] in distribution property
Answer» ANSWER: -88/3 Step-by-step explanation: 1) APPLY the BODMAS rule 2) First solve the BRACKET and then multiple. HOPE IT HELPS

38.

Find 3/4×[8/9-40] in distribution property

Answer»

ANSWER:

-88/3

Step-by-step explanation:

1) APPLY the BODMAS rule

2) First solve the BRACKET and then multiple.

HOPE IT HELPS

Discussion

39.	Number lineLocate onاز 3 یزی)5 (3/ ((
Answer» ANSWER: i don't UNDERSTAND UR question m SORRY

39.

Number lineLocate onاز 3 یزی)5 (3/ ((

Answer»

ANSWER:

i don't UNDERSTAND UR question

m SORRY

Discussion

40.	Show that if 2(a^2+b^)=(a+b)^2 then a=1plz solve my this question
Answer» ANSWER: you can SOLVE this by FOLLOWING FORMULA

40.

Show that if 2(a^2+b^)=(a+b)^2 then a=1plz solve my this question

Answer»

ANSWER:

you can SOLVE this by FOLLOWING FORMULA

Discussion

41.	If alpha and beta are the zeros of the polynomial 5x²+2x+3.Find the value of 1/ alpha+1/beta
Answer» HEY MATE! HERE IS YOUR ANSWER: STEP BY STEP EXPLANATION: *POLYNOMIAL: 5x^2+2x+3=0 ; where* a=5 , b=2 *and* c=3 *Now, sum* of *zeroes* = -b/a so, *ALPHA* +*beta* =-2/5 *And* *product* of *zeroes* =c/a so, *alpha* ×*beta* =3/5 *Now* 1/*alpha* +1/*beta=beta+alpha/alpha×beta* =-2/5÷3/5=-2/5×5/3 =-2/3 HOPE IT HELPED ^_^

41.

If alpha and beta are the zeros of the polynomial 5x²+2x+3.Find the value of 1/ alpha+1/beta

Answer»

HEY MATE!

HERE IS YOUR ANSWER:

STEP BY STEP EXPLANATION:

POLYNOMIAL: 5x^2+2x+3=0 ; where a=5 , b=2 and c=3

Now, sum of zeroes = -b/a

so, ALPHA +beta =-2/5

And product of zeroes =c/a

so, alpha ×beta =3/5

Now 1/alpha +1/beta=beta+alpha/alpha×beta

=-2/5÷3/5=-2/5×5/3

=-2/3

HOPE IT HELPED ^_^

Discussion

42.	There are 785 students on roll in a Residential Public school. If the annual fee per student is rupees 62,606.What is the total fee collected annually by the school
Answer» Here Is Your Ans ⤵ *** ANNUAL FEE of ONE student = Rs. 62606 Number of students = 785 Thus, the TOTAL annual collection of fee = Rs. 62606 × 785 = Rs. 49145 Rs. 49145710 *** $hope it helps u$

42.

There are 785 students on roll in a Residential Public school. If the annual fee per student is rupees 62,606.What is the total fee collected annually by the school

Answer»

Here Is Your Ans ⤵

*****

ANNUAL FEE of ONE student = Rs. 62606

Number of students = 785

Thus, the TOTAL annual collection of fee = Rs. 62606 × 785 = Rs. 49145

Rs. 49145710

*****

$hope it helps u$

Discussion

43.	I am the smallest number , having four different prime factors. can you find me ?
Answer» Answer:1235 Step-by-step EXPLANATION:

43.

I am the smallest number , having four different prime factors. can you find me ?

Answer»

Answer:1235

Step-by-step EXPLANATION:

Discussion

44.	4/√11-√7 rationalising the denominator .please tell me explanation help box (answer ) :--- √11+√7 it will help youplease give correct explanation
Answer» this is ur ANSWER dont be wortied u will laern it easily i was LASO confused in this topic a lot hope it helps stay HAPPY

44.

4/√11-√7 rationalising the denominator .please tell me explanation help box (answer ) :--- √11+√7 it will help youplease give correct explanation

Answer»

this is ur ANSWER dont be wortied u will laern it easily i was LASO confused in this topic a lot

hope it helps

stay HAPPY

Discussion

45.	Factorise the given polynomial :-2x^2-4
Answer» x=+-2is your answer HOPE this will HELP you MARK me as BRAINLIST and follow me

Discussion

46.	Tan^-1{x^1/3+a^1/3÷1-(ax)^1/3}
Answer» ANSWER: hxbexshshskxJbydbejdn3rd

46.

Tan^-1{x^1/3+a^1/3÷1-(ax)^1/3}

Answer»

ANSWER:

hxbexshshskxJbydbejdn3rd

Discussion

47.	Is there a number which is equal to its cube but not equal to square
Answer» ANSWER:No Step-by-step EXPLANATION:

47.

Is there a number which is equal to its cube but not equal to square

Answer»

ANSWER:No

Step-by-step EXPLANATION:

Discussion

48.	25 +1/125 find the answer
Answer» Answer: 3126/125 Step-by-step explanation: 25/1+1/125 =3125+1/125 =3126/125

48.

25 +1/125 find the answer

Answer»

Answer:

3126/125

Step-by-step explanation:

25/1+1/125

=3125+1/125

=3126/125

Discussion

49.	Rationalise 2plus un rt4 /3-2 un rt
Answer» HOPE this is HELPFUL to you.. THANK you.

49.

Rationalise 2plus un rt4 /3-2 un rt

Answer»

HOPE this is HELPFUL to you..

THANK you.

Discussion

50.	Find 621/2% of 512 I want a clear explanation pls
Answer» Answer: 621/200of512 621/100of256 621/50 of128 621/25of64

50.

Find 621/2% of 512 I want a clear explanation pls

Answer»

Answer:

621/200of512

621/100of256

621/50 of128

621/25of64

Discussion

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