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Answer:

mu me SUPPLEMENT or each of the FOLLOWING angles.

(i) 429

(ii) 90°

(iii) 1240

(iv) of a right angle

4. Find the measure of an angle which is

(i) equal to its complement, (ii) equal to its supplement.

5. Find the measure of an angle which is 36° more than its complement.

6. Find the measure of an angle which is 30° less than its supplement

7. Find the angle which is four times its complement.

8. Find the angle which is five times its supplement

9. Find the angle whose supplement is four times its complement.

9. Find the angle whose complement is one third of its supplement.

. TWO complementary angles are in the RATIO 4:5. Find the angles.

Find the value of x for which the angles (2x - 5) and (x - 10) are the

complementary angles.

Step-by-step EXPLANATION:

ISORRY, I don't no tha answer of first QUESTION

Here is UR answer...

Hope it helps...

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Answer:

i m not understanding UR QUESTION WRITE it properly......

Answer:

ohkk so what we have to FINE PLZZ complete UR QUESTION

Answer:

If you are talking about an n-sided CONVEX polygon, then its number of diagonals are given by nC2 - n; and if

nC2 - n = 44 (given), then

½ n (n - 1) - n = 44

n^2 - n - 2 n = 88

n^2 - 3 n - 88 = 0

Solving the quadratic, we have

n^2 - 11 n + 8 n - 88 = 0

(n - 11) (n + 8) = 0

Since, n = -8 is not applicable, hence the polygon in QUESTION must have 11 number of sides to it.

Hope it helps

2/3 is the ANSWER of this QUESTION

When SIDES and diagonals are equal then,

AREA of the PARALLELOGRAM = area of square

= (side)^2

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ANSWER:

96$ is the answer of this question

Step-by-step explanation:

1-13$

7-13$.7

so ,

cost of seven items is 96$

Step-by-step EXPLANATION:

HOPE this will be HELPFUL to you.

Answer:

I don't know

dghfhhggughh so all lashing him good in for FIX fix TIC EX to srtdyryp to POP over

given:

the DENOMINATOR of a fraction is 12 more than the NUMERATOR

let the numerator be x and denominator be x+12

so the fraction is => x/x+12

If 16 is added to both the numerator and denominator than the new fraction will be 10/13

=> x+16/x+12+16 = 10/13

=> x+16/x+28 = 10/13

by cross multiplying

=> 13(x+16) = 10(x+28)

=> 13x+208 = 10x+280

=> 13x-10x = 280-208

=> 3x = 72

=> x = 72/3

=> x = 24

so x/x+12

=> 24/24+12

=> 24/36

so the original fraction is 24/36

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Answer:

1 HOUR. 60 minutes

15/60×100

15×5/3

5×5

25

ANSWER:

25+1/125=

25+0.008=

25.008 this is answer

Step-by-step EXPLANATION:

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Answer:

62606 × 75 = 4695450

the TOTAL fees COLLECTED ANNUAL by the SCHOOL is 4695450

After 1 minute,

Thief = 50m

POLICE= 0m

After 2 minutes,

Thief = 100M

Police= 0m

After 3 minutes,

Thief = 150m

Police= 60m

After 4 minutes,

Thief = 200m

Police= 60+65m = 125m

After 5 minutes,

Thief = 250m

Police= 125+70m = 195m

After 6 minutes,

Thief = 300m

Police= 195+75m = 270m

After 7 minutes,

Thief = 350m

Police= 270+80m = 350m

Hence, thief will be caught after 7 minutee

Hope it helps!!! :)

Step-by-step EXPLANATION:

we know that ,

So ,

SUBSTITUTE this for tan^2alpha

Hence proved ! !

Answer:

8√2cm

Step-by-step EXPLANATION:

Given PERIMETER is 32

4×side =peeimereter

Side=8

Diagonal =side√2

Diagonal is=8√2cm

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ANSWER:

x=0.2363636....

10x=2.363636....

EQ-1

1000x=236.363636...

eq-2

from eq 2-1

990x=234

x=234/990

Step-by-step EXPLANATION:

ANSWER:

I don't KNOW this answer

HEY MATE!

HERE IS YOUR ANSWER:

STEP BY STEP EXPLANATION:

binomial

hope it HELPS you...

ANSWER:

cos

tan

cot

ratio

percentage

sin

cosec

median

angle

congruency

matrices

accute

obtuse

isoscles

Answer:

Numbers are in ratio 4:1

Step-by-step explanation:

Given :

The harmonic mean and geometric mean of two positive numbers are in the ratio = 4:5

Both are positive numbers

To find : The ratio in which the numbers are

Let the numbers be KA and a

so, a> 0 as number is positive.

APPLY RELATION for G.M

Now apply relation for H.M

Now using the given Ratio relation

Put the values

Now divide by 2 both sides

°•° Solve this Quadratic equation

•°• Apply Quadratic Formula

Finally, we get

Two values of k are

•Taking +ve sign

Next root,

•Taking -ve sign

Now A/c to QUESTION

•°•Required Ratio

•°• The numbers are in ratio 4:1

◾ Geometric mean =

◾Harmonic mean

◾Quadratic formula =

Where a,b c are respective co-efficients

HEY MATE!

HERE IS YOUR ANSWER:

STEP BY STEP EXPLANATION:

Step-by-step explanation:

rectangle ABCD, diagonals bisect the ANGLES. Consider ΔAOD and ΔBOC AD = BC (ABCD is a rectangle) ∠AOD = ∠BOC (Vertically opposite angles) ∠OAD = ∠OCB = 45° (Diagonals bisect the angles) ΔAOD ≅ ΔBOC (AAS CONGRUENCE criterion) Therefore, OA = OC and OB = OD Thus the diagonals bisect each other in a rectangle.

60.714257is the ANSWER of 850/14

Answer:

1.5000000

2.500000

3.50000000

4.500000

4.5000

heyy mate...!!

A line that intersects a CIRCLE in exactly one point is called a TANGENT and the point where the intersection occurs is called the point of tangency. The tangent is always PERPENDICULAR to the radius DRAWN to the point of tangency. A secant is a line that intersects a circle in exactly two points.

thanks ...!!!

ANSWER:

1 is the answer of this EXPRESSION

HEY MATE!

HERE IS YOUR ANSWER:

STEP BY STEP EXPLANATION :

X(20-x)=100

20x-x^2=100

x^2-20x+100=0

x^2-10x-10x+100=0

x(x-10)-10(x-10)=0

(x-10)(x-10)=0

x=10

HOPE IT HELPED ^_^

ANSWER:

x=5

Step-by-step explanation:

2x-3=x+2

x=5

this is your answer.....

the small NUMBER=11

the LARGE number =25

Step-by-step explanation:

The sum of two numbers=36

Now, let the small number be x

therefore, larger number=x*2+3 as PER the formula divident = DIVISOR*quotient+remainder

so the larger number = 2x+3

therefore, ATQ,

2x+3+x=36

3x=36-3

x=33/3

x=11

therefore if the smaller number is 11, the larger number=2*11+3

=22+3

=25

I THINK the QUESTION has some mistake...

check it please....

ENJOY YOUR STUDIES.......

STEP ONE

23+18 =41

Step two

41×6=246

Answer=246

ANSWER:

4 is the answer for you by the END of the DAY

Step-by-step EXPLANATION:

MALA LOTTERY lagli TAR nibandh

brainly.in/question/3570833

Marathi COMPO on mala lottery lagli tar - Brainly.in

ANSWER:

-21/5

Step-by-step explanation:

7×-3/5

-21/5

this is your answer

1.Let A and B be two finite sets such that n(A) = 20, n(B) = 28 and n(A ∪ B) = 36, find n(A ∩ B).

Solution: 

Using the formula n(A ∪ B) = n(A) + n(B) - n(A ∩ B). 

then n(A ∩ B) = n(A) + n(B) - n(A ∪ B) 

                     = 20 + 28 - 36 

                     = 48 - 36 

                     = 12 

2. If n(A - B) = 18, n(A ∪ B) = 70 and n(A ∩ B) = 25, then find n(B).

Solution: 

Using the formula n(A∪B) = n(A - B) + n(A ∩ B) + n(B - A) 

                                 70 = 18 + 25 + n(B - A) 

                                 70 = 43 + n(B - A) 

                         n(B - A) = 70 - 43 

                         n(B - A) = 27 

Now n(B) = n(A ∩ B) + n(B - A) 

               = 25 + 27 

               = 52 

3. In a group of 60 people, 27 like COLD drinks and 42 like hot drinks and each person likes at least one of the two drinks. How many like both coffee and tea? 

Solution: 

Let A = Set of people who like cold drinks. 

     B = Set of people who like hot drinks. 

Given 

(A ∪ B) = 60            n(A) = 27       n(B) = 42 then;

n(A ∩ B) = n(A) + n(B) - n(A ∪ B) 

            = 27 + 42 - 60 

            = 69 - 60 = 9 

            = 9 

THEREFORE, 9 people like both tea and coffee. 

4.There are 35 students in art class and 57 students in dance class. Find the number of students who are either in art class or in dance class.

• When two classes meet at different hours and 12 students are enrolled in both activities. 

• When two classes meet at the same hour. 

Solution: 

n(A) = 35,       n(B) = 57,       n(A ∩ B) = 12 

(Let A be the set of students in art class. 

B be the set of students in dance class.) 

(i) When 2 classes meet at different hours n(A ∪ B) = n(A) + n(B) - n(A ∩ B) 

                                                                          = 35 + 57 - 12 

                                                                          = 92 - 12 

                                                                          = 80 

(II) When two classes meet at the same hour, A∩B = ∅ n (A ∪ B) = n(A) + n(B) - n(A ∩ B) 

                                                                                              = n(A) + n(B) 

                                                                                              = 35 + 57 

                                                                                              = 92

5.. In a group of 100 persons, 72 people can speak English and 43 can speak French. How many can speak English only? How many can speak French only and how many can speak both English and French?

Solution: 

Let A be the set of people who speak English. 

B be the set of people who speak French. 

A - B be the set of people who speak English and not French. 

B - A be the set of people who speak French and not English. 

A ∩ B be the set of people who speak both French and English. 

Given, 

n(A) = 72       n(B) = 43       n(A ∪ B) = 100 

Now, n(A ∩ B) = n(A) + n(B) - n(A ∪ B) 

                     = 72 + 43 - 100 

                     = 115 - 100 

                     = 15 

6.. In a competition, a school awarded medals in different categories. 36 medals in dance, 12 medals in dramatics and 18 medals in music. If these medals went to a total of 45 persons and only 4 persons got medals in all the three categories, how many received medals in exactly two of these categories?

Solution: 

Let A = set of persons who got medals in dance. 

B = set of persons who got medals in dramatics. 

C = set of persons who got medals in music. 

Given, 

n(A) = 36                              n(B) = 12       n(C) = 18 

n(A ∪ B ∪ C) = 45       n(A ∩ B ∩ C) = 4 

We know that number of elements belonging to exactly two of the three sets A, B, C 

= n(A ∩ B) + n(B ∩ C) + n(A ∩ C) - 3n(A ∩ B ∩ C) 

= n(A ∩ B) + n(B ∩ C) + n(A ∩ C) - 3 × 4       ……..(i) 

n(A ∪ B ∪ C) = n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(A ∩ C) + n(A ∩ B ∩ C) 

Therefore, n(A ∩ B) + n(B ∩ C) + n(A ∩ C) = n(A) + n(B) + n(C) + n(A ∩ B ∩ C) - n(A ∪ B ∪ C) 

From (i) required number 

= n(A) + n(B) + n(C) + n(A ∩ B ∩ C) - n(A ∪ B ∪ C) - 12 

= 36 + 12 + 18 + 4 - 45 - 12 

= 70 - 57 

= 13 

7.. Each student in a class of 40 plays at least one indoor GAME chess, carrom and scrabble. 18 play chess, 20 play scrabble and 27 play carrom. 7 play chess and scrabble, 12 play scrabble and carrom and 4 play chess, carrom and scrabble. Find the number of students who play (i) chess and carrom. (ii) chess, carrom but not scrabble.

Solution: 

Let A be the set of students who play chess 

B be the set of students who play scrabble 

C be the set of students who play carrom 

Therefore, We are given n(A ∪ B ∪ C) = 40, 

n(A) = 18,         n(B) = 20         n(C) = 27, 

n(A ∩ B) = 7,     n(C ∩ B) = 12    n(A ∩ B ∩ C) = 4 

We have 

n(A ∪ B ∪ C) = n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(C ∩ A) + n(A ∩ B ∩ C) 

Therefore, 40 = 18 + 20 + 27 - 7 - 12 - n(C ∩ A) + 4 

40 = 69 – 19 - n(C ∩ A) 

40 = 50 - n(C ∩ A) n(C ∩ A) = 50 - 40 

n(C ∩ A) = 10 

Therefore, Number of students who play chess and carrom are 10. 

Also, number of students who play chess, carrom and not scrabble. 

= n(C ∩ A) - n(A ∩ B ∩ C) 

= 10 – 4 

= 6

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ANSWER is 1

ANSWER:

PRECEDING MEAN before

before no of 729001

729000,728999,728998

Given:

boys=23 and girls=18

total NUMBER of students in a CLASS=41

there are 41 students in a class

for SIX classes:41×6=246

there are 246 students in six classes

Answer:

2a^2+ax

__________

x^2-a^2

Step-by-step EXPLANATION:

a/(x-a) + a^2/(x^2-a^2)

a/(x-a) + a^2/{(x-a)(x+a)}

{a(x+a)+a^2}/{(x-a)(x+a)}

(ax+a^2+a^2)/(x^2-a^2)

(2a^2+ax)/(x^2-a^2)

) 24

A

Step-by-step EXPLANATION:

1. Hftggcffgffccffgfggh

Bb

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Step-by-step explanation:

Perimeter of SQUARE GARDEN = 4* 560 m

= 2240 m

Cost of fencing = Rs12/10m * 2240 m

= Rs 12*224

= Rs 2668

ANSWER:

by SEARCHING in GOOGLE

ANSWER:

456 is the answer .....

ANSWER:

1) 34/100

2) 163/1000

Hope U LIKE my answer.....

Step-by-step EXPLANATION:

its UR ANSWER..................