Prove that :-

1.	Prove that :-
Answer» Step-by-step EXPLANATION: $rhs \: \: = \frac{ {tan}^{2} \alpha }{ \sec\alpha + 1 }$ we know that , ${tan}^{2} \alpha = {sec}^{2} \alpha - 1$ $=( { \sec\alpha })^{2} - ({1})^{2}$ $= ( \sec\alpha - 1)(sec \alpha + 1)$ So , SUBSTITUTE this for tan^2alpha $rhs \: \: = \: \: \frac{(sec \alpha + 1)(sec \alpha - 1)}{(sec \alpha + 1)}$ $= sec \alpha - 1$ $= \frac{1}{cos \alpha } - 1$ $= \frac{1 - cos \alpha }{cos \alpha } = rhs$ Hence proved ! !

Answer»

Step-by-step EXPLANATION:

$rhs \: \: = \frac{ {tan}^{2} \alpha }{ \sec\alpha + 1 }$