Prove that diagonals of rectangle bisect each other and equal

1.	Prove that diagonals of rectangle bisect each other and equal
Answer» Step-by-step explanation: rectangle ABCD, diagonals bisect the ANGLES. Consider ΔAOD and ΔBOC AD = BC (ABCD is a rectangle) ∠AOD = ∠BOC (Vertically opposite angles) ∠OAD = ∠OCB = 45° (Diagonals bisect the angles) ΔAOD ≅ ΔBOC (AAS CONGRUENCE criterion) Therefore, OA = OC and OB = OD Thus the diagonals bisect each other in a rectangle.

Answer»

Step-by-step explanation:

rectangle ABCD, diagonals bisect the ANGLES. Consider ΔAOD and ΔBOC AD = BC (ABCD is a rectangle) ∠AOD = ∠BOC (Vertically opposite angles) ∠OAD = ∠OCB = 45° (Diagonals bisect the angles) ΔAOD ≅ ΔBOC (AAS CONGRUENCE criterion) Therefore, OA = OC and OB = OD Thus the diagonals bisect each other in a rectangle.

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Prove that diagonals of rectangle bisect each other and equal​

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Prove that diagonals of rectangle bisect each other and equal