Saved Bookmarks
| 1. |
Cos a = 3/4 find 16cos²(a/2) - 32sin(a/2)sin(5a/2) |
|
Answer» Answer: 32sinA/2.sin5A/2 use formula , 2sinA.sinB = cos(A -B) -cos(A+B) cos2A = 2cos²A -1 cos3A = 4cos³A -3COSA now, 32sinA/2sin5A/2 = 16cos2A -16cos3A 16{ 2cos²A -1 -4cos³A+3cosA} =16{ 2(3/4)²-1-4(3/4)³+3(3/4)} =16{ 18/16 -1 -27/16 +36/16} =( 18 -16 -27 +36} =11 Read more on Brainly.in - brainly.in/question/1122560#readmore |
|