332354 + Interview Questions in Secondary School in Math

1.	mean is 18. C.I 11-13,13-15,15-17,17-19,19-21,21-23,23-25 and F.I is 7,6,9,13,f,5,4 find the value of 'f' by step - deviation method
Answer» Answer: Lets TAKE assumed MEAN, A as 16 Class INTERVAL =2 ∴u i = h x i −A = 2 x i −16 Now, we have A=16, x ˉ =18 and h=2 We know that, Mean, x ˉ =A+h( N 1 ∑f i u i ) ⇒18=16+2( f+44 2f+24 ) ⇒ f+44 2f+24 =1 ⇒f+44=2f+24 ⇒f=20 Hence, the value of missing frequency, f=20 Step-by-step explanation: MARK ME AS BRAINLIEST IF IT IS CORRECT.. PURPLE u sorry i tried yo copy paste but this happened...inner screaming༼;´༎ຶ ۝ ༎ຶ༽

1.

mean is 18. C.I 11-13,13-15,15-17,17-19,19-21,21-23,23-25 and F.I is 7,6,9,13,f,5,4 find the value of 'f' by step - deviation method

Answer»

Answer:

Lets TAKE assumed MEAN, A as 16

Class INTERVAL =2

∴u

i

=

h

x

i

−A

=

2

x

i

−16

Now, we have A=16,

x

ˉ

=18 and h=2

We know that,

Mean,

x

ˉ

=A+h(

N

1

∑f

i

u

i

)

⇒18=16+2(

f+44

2f+24

)

⇒

f+44

2f+24

=1

⇒f+44=2f+24

⇒f=20

Hence, the value of missing frequency, f=20

Step-by-step explanation:

MARK ME AS BRAINLIEST IF IT IS CORRECT.. PURPLE u sorry i tried yo copy paste but this happened...*inner screaming*༼;´༎ຶ ۝ ༎ຶ༽

Discussion

2.	The lateral surface area of a cube is 256cm^3. Find its volume and surface area.
Answer» Answer: 256=4a² a²=64 a=8cm Volume=512cm³ Surface AREA =6a²=384cm²

2.

The lateral surface area of a cube is 256cm^3. Find its volume and surface area.

Answer»

Answer:

256=4a²

a²=64

a=8cm

Volume=512cm³

Surface AREA =6a²=384cm²

Discussion

3.	(sec A + tan A) (1 - sin A)choose the correct option
Answer» ANSWER: (SEC A + TAN A) (1 - SIN A)= cos A Hope it helps<3

3.

(sec A + tan A) (1 - sin A)choose the correct option

Answer»

ANSWER:

(SEC A + TAN A) (1 - SIN A)= cos A

Hope it helps<3

Discussion

4.	Integrate it???.....
Answer» ANSWER: sec^2 Step-by-step EXPLANATION: this GENERAL IDENTITY of trignometric

4.

Integrate it???.....

Answer»

ANSWER:

sec^2

Step-by-step EXPLANATION:

this GENERAL IDENTITY of trignometric

Discussion

5.	Find the equation of a straight line which passes through the point (1, - 3) and makes an intercept on y-axis twice as long as on x-axis.
Answer» Answer: INTERCEPT FORM of equation of line is given by: a x + b y =1, where a is x-intercept and b is y-intercept Now, we are given that b=2a ⇒ equation of line is given by 2x+y=2a Distance of this line from origin is 1 units. Applying the formulae for distance of a POINT from a line, and EQUATING it to 1, we get ∣ 2 2 +1 2 −2a ∣=1 ⇒ 2a=+ 5 and − 5

5.

Find the equation of a straight line which passes through the point (1, - 3) and makes an intercept on y-axis twice as long as on x-axis.

Answer»

Answer:

INTERCEPT FORM of equation of line is given by:

a

x

+

b

y

=1, where a is x-intercept and b is y-intercept

Now, we are given that b=2a

⇒ equation of line is given by 2x+y=2a

Distance of this line from origin is 1 units.

Applying the formulae for distance of a POINT from a line, and EQUATING it to 1, we get

∣

2

+1

2

−2a

∣=1

⇒ 2a=+

5

and −

5

Discussion

6.	There are two sizes of fish that he wants to create. Accorhas, he has decided to have the area of each big fish as 35Question 11: What should the side of each square be?a 18.66 cmb) 8 cmc) 64 cmd) 32 cm*School of fish = a group of fish
Answer» *If two chords of a circle interest within the circle, PROVE that the segments of one CHORD are equal to correspond* In mathematics, the irrational numbers are all the real numbers which are not rational numbers. That is, irrational numbers cannot be expressed as the ratio of two integers. ... For EXAMPLE, the decimal representation of π starts with 3.14159, but no finite number of DIGITS can represent π exactly, nor does it REPEAT.

6.

There are two sizes of fish that he wants to create. Accorhas, he has decided to have the area of each big fish as 35Question 11: What should the side of each square be?a 18.66 cmb) 8 cmc) 64 cmd) 32 cm*School of fish = a group of fish

Answer»

If two chords of a circle interest within the circle, PROVE that the segments of one CHORD are equal to correspond

In mathematics, the irrational numbers are all the real numbers which are not rational numbers. That is, irrational numbers cannot be expressed as the ratio of two integers. ... For EXAMPLE, the decimal representation of π starts with 3.14159, but no finite number of DIGITS can represent π exactly, nor does it REPEAT.

Discussion

7.	A bullet fired at an angle of 30° with the horizontal hits the ground 4.0 km away. Byadjusting its angle of projection, can one hope to hit a target 5.0 km away ? Assumethe muzzle speed to be fixed, and neglect air resistance.
Answer» Answer : Bullet can not hit a TARGET 5 km away. Step-by-step explanation : we know, $\boxed{\bf Range=\frac{u^2sin2\theta}{g} }$ LET the speed of the bullet be "u" A bullet fired at an angle of 30° with the HORIZONTAL hits the ground 4.0 km away. Range (R) = 4 km angle of projection (θ) = 30° By SUBSTITUTING it's values in the above formula, $4=\frac{u^2sin2(30^{\circ})}{g} \\\\ 4\frac{u^2sin60^{\circ}}{g} \\\\ \frac{u^2(\frac{\sqrt{3}}{2})}{g} =4 \\\\ \frac{u^2}{g} =\frac{8}{\sqrt{3}} \\\\ \frac{u^2}{g} =\frac{8}{\sqrt{3}} \times \frac{\sqrt{3} }{\sqrt{3} } \\\\ \frac{u^2}{g} =\frac{8\sqrt{3}}{3}$ Range is maximum at θ = 45° $R_{max}=\frac{u^2sin2(45^{\circ})}{g} \\\\ R_{max} =\frac{u^2sin90^{\circ}}{g} \\\\ R_{max}=\frac{u^2}{g}$ substitute the value of u²/g here, Rₘₐₓ = $\frac{8\sqrt{3}}{3}$ $\simeq\frac{13.856}{3} \\\\ \simeq\text{4.618 km}$ Hence, bullet can not hit the target 5 km away. SINCE, the maximum range with the same speed is 4.618 km which is less than 5 km _______________________

7.

A bullet fired at an angle of 30° with the horizontal hits the ground 4.0 km away. Byadjusting its angle of projection, can one hope to hit a target 5.0 km away ? Assumethe muzzle speed to be fixed, and neglect air resistance.

Answer»

Answer :

Bullet can not hit a TARGET 5 km away.

Step-by-step explanation :

we know,

$\boxed{\bf Range=\frac{u^2sin2\theta}{g} }$

LET the speed of the bullet be "u"

A bullet fired at an angle of 30° with the HORIZONTAL hits the ground 4.0 km away.

Range (R) = 4 km

angle of projection (θ) = 30°

By SUBSTITUTING it's values in the above formula,

$4=\frac{u^2sin2(30^{\circ})}{g} \\\\ 4\frac{u^2sin60^{\circ}}{g} \\\\ \frac{u^2(\frac{\sqrt{3}}{2})}{g} =4 \\\\ \frac{u^2}{g} =\frac{8}{\sqrt{3}} \\\\ \frac{u^2}{g} =\frac{8}{\sqrt{3}} \times \frac{\sqrt{3} }{\sqrt{3} } \\\\ \frac{u^2}{g} =\frac{8\sqrt{3}}{3}$

Range is maximum at θ = 45°

$R_{max}=\frac{u^2sin2(45^{\circ})}{g} \\\\ R_{max} =\frac{u^2sin90^{\circ}}{g} \\\\ R_{max}=\frac{u^2}{g}$

substitute the value of u²/g here,

Rₘₐₓ = $\frac{8\sqrt{3}}{3}$

$\simeq\frac{13.856}{3} \\\\ \simeq\text{4.618 km}$

Hence, bullet can not hit the target 5 km away.

SINCE, the maximum range with the same speed is 4.618 km which is less than 5 km

_______________________

Discussion

8.	A park, in the shape of a quadrilateral ABCD, has angle C = 90° l, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?[NCERT MATHS CLASS 9TH CH 12 - HERON's FORMULA EX 12.2 Q2]Best Answer will instantly mark as brainliest❤❤❤
Answer» <P> Given : ∠C = 90° AB = 9 m BC = 12 m CD = 5 m AD = 8 m To FIND : Area of the park . Solution : In Δ BCD : Base = 5 m Height = 12 m Hypotenuse = ? By Pythagorus THEOREM : \longmapsto\tt{{(H)}^{2}={(B)}^{2}+{(P)}^{2}}⟼(H) 2 =(B) 2 +(P) 2 \longmapsto\tt{{(H)}^{2}={(5)}^{2}+{(12)}^{2}}⟼(H) 2 =(5) 2 +(12) 2 \longmapsto\tt{{(H)}^{2}=25+144}⟼(H) 2 =25+144 \longmapsto\tt{{(H)}^{2}=169}⟼(H) 2 =169 \longmapsto\tt{H=\sqrt{169}}⟼H= 169 \longmapsto\tt\bf{H=13\:m}⟼H=13m Now , a = 5 m b = 12 m c = 13 m \longmapsto\tt{s=\dfrac{a+b+c}{2}}⟼s= 2 a+b+c \longmapsto\tt{s=\dfrac{5+12+13}{2}}⟼s= 2 5+12+13 \longmapsto\tt{s=\cancel\dfrac{30}{2}}⟼s= 2 30 \longmapsto\tt\bf{s=15\:m}⟼s=15m \longmapsto\tt{Area=\sqrt{s(s-a)(s-b)(s-c)}}⟼Area= s(s−a)(s−b)(s−c) \longmapsto\tt{\sqrt{15(15-5)\:(15-12)\:(15-13)}}⟼ 15(15−5)(15−12)(15−13) \longmapsto\tt{\sqrt{15\:(10)\:(2)\:(2)}}⟼ 15(10)(2)(2) \longmapsto\tt{5\times{3}\times{2}}⟼5×3×2 \longmapsto\tt\bf{30\:{m}^{2}}⟼30m 2 Area of Δ BCD is 30 m² . Similarly , In Δ ABD : a = 9 m b = 8 m c = 13 m \longmapsto\tt{s=\dfrac{a+b+c}{2}}⟼s= 2 a+b+c \longmapsto\tt{s=\dfrac{9+8+13}{2}}⟼s= 2 9+8+13 \longmapsto\tt{s=\cancel\dfrac{30}{2}}⟼s= 2 30 \longmapsto\tt\bf{s=15\:m}⟼s=15m \longmapsto\tt{Area=\sqrt{s(s-a)(s-b)(s-c)}}⟼Area= s(s−a)(s−b)(s−c) \longmapsto\tt{\sqrt{15(15-8)\:(15-9)\:(15-13)}}⟼ 15(15−8)(15−9)(15−13) \longmapsto\tt{\sqrt{15\:(7)\:(6)\:(2)}}⟼ 15(7)(6)(2) \longmapsto\tt{3\times{2}\sqrt{5\times{7}}}⟼3×2 5×7 \longmapsto\tt\bf{6\sqrt{35}\:{m}^{2}}⟼6 35 m 2 Area of Δ ABD is 30 m² . Total Area of Park : \longmapsto\tt{Area\:of\:\triangle\:BCD+Area\:of\:\triangle\:ABD}⟼Areaof△BCD+Areaof△ABD \longmapsto\tt{30+6\sqrt{35}}⟼30+6 35 \longmapsto\tt\bf{65.4\:{m}^{2}}⟼65.4m 2 So , The Area Occupied by the park is 65.4 m² ..

8.

A park, in the shape of a quadrilateral ABCD, has angle C = 90° l, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?[NCERT MATHS CLASS 9TH CH 12 - HERON's FORMULA EX 12.2 Q2]Best Answer will instantly mark as brainliest❤❤❤

Answer»

<P>

Given :

∠C = 90°

AB = 9 m

BC = 12 m

CD = 5 m

AD = 8 m

To FIND :

Area of the park .

Solution :

In Δ BCD :

Base = 5 m

Height = 12 m

Hypotenuse = ?

By Pythagorus THEOREM :

\longmapsto\tt{{(H)}^{2}={(B)}^{2}+{(P)}^{2}}⟼(H)

2

=(B)

2

+(P)

2

\longmapsto\tt{{(H)}^{2}={(5)}^{2}+{(12)}^{2}}⟼(H)

2

=(5)

2

+(12)

2

\longmapsto\tt{{(H)}^{2}=25+144}⟼(H)

2

=25+144

\longmapsto\tt{{(H)}^{2}=169}⟼(H)

2

=169

\longmapsto\tt{H=\sqrt{169}}⟼H=

169

\longmapsto\tt\bf{H=13\:m}⟼H=13m

Now ,

a = 5 m

b = 12 m

c = 13 m

\longmapsto\tt{s=\dfrac{a+b+c}{2}}⟼s=

2

a+b+c

\longmapsto\tt{s=\dfrac{5+12+13}{2}}⟼s=

2

5+12+13

\longmapsto\tt{s=\cancel\dfrac{30}{2}}⟼s=

2

30

\longmapsto\tt\bf{s=15\:m}⟼s=15m

\longmapsto\tt{Area=\sqrt{s(s-a)(s-b)(s-c)}}⟼Area=

s(s−a)(s−b)(s−c)

\longmapsto\tt{\sqrt{15(15-5)\:(15-12)\:(15-13)}}⟼

15(15−5)(15−12)(15−13)

\longmapsto\tt{\sqrt{15\:(10)\:(2)\:(2)}}⟼

15(10)(2)(2)

\longmapsto\tt{5\times{3}\times{2}}⟼5×3×2

\longmapsto\tt\bf{30\:{m}^{2}}⟼30m

2

Area of Δ BCD is 30 m² .

Similarly ,

In Δ ABD :

a = 9 m

b = 8 m

c = 13 m

\longmapsto\tt{s=\dfrac{a+b+c}{2}}⟼s=

2

a+b+c

\longmapsto\tt{s=\dfrac{9+8+13}{2}}⟼s=

2

9+8+13

\longmapsto\tt{s=\cancel\dfrac{30}{2}}⟼s=

2

30

\longmapsto\tt\bf{s=15\:m}⟼s=15m

\longmapsto\tt{Area=\sqrt{s(s-a)(s-b)(s-c)}}⟼Area=

s(s−a)(s−b)(s−c)

\longmapsto\tt{\sqrt{15(15-8)\:(15-9)\:(15-13)}}⟼

15(15−8)(15−9)(15−13)

\longmapsto\tt{\sqrt{15\:(7)\:(6)\:(2)}}⟼

15(7)(6)(2)

\longmapsto\tt{3\times{2}\sqrt{5\times{7}}}⟼3×2

5×7

\longmapsto\tt\bf{6\sqrt{35}\:{m}^{2}}⟼6

35

m

2

Area of Δ ABD is 30 m² .

Total Area of Park :

\longmapsto\tt{Area\:of\:\triangle\:BCD+Area\:of\:\triangle\:ABD}⟼Areaof△BCD+Areaof△ABD

\longmapsto\tt{30+6\sqrt{35}}⟼30+6

35

\longmapsto\tt\bf{65.4\:{m}^{2}}⟼65.4m

2

So , The Area Occupied by the park is 65.4 m² ..

Discussion

9.	The length of a room is 50% more than its breadth. The cost of carpeting the room at the rate of ₹38.50 m² is ₹924 and the cost of papering the walls at ₹3.30 m² is ₹214.50 . If the room has one door of dimensions 1 m × 2 m and two windows each of dimensions 1 m × 1.5 m, find the dimensions of the room.
Answer» Answer: Length of the room = 6 meters Breadth of the room = 4 meters Height of the room = 3.5 meters Given: The length of a room is 50% more than its breadth The cost of CARPETING the room at the rate of ₹ 38.50 The cost of papering the walls at ₹ 3.30 m² is ₹ 214.50 One dimension of the room = 1 m × 2 m Second dimension of the room = 1 m × 1.5 m To Find: The dimensions of the room =?

9.

The length of a room is 50% more than its breadth. The cost of carpeting the room at the rate of ₹38.50 m² is ₹924 and the cost of papering the walls at ₹3.30 m² is ₹214.50 . If the room has one door of dimensions 1 m × 2 m and two windows each of dimensions 1 m × 1.5 m, find the dimensions of the room.

Answer»

Answer:

Length of the room = 6 meters

Breadth of the room = 4 meters

Height of the room = 3.5 meters

Given:

The length of a room is 50% more than its breadth

The cost of CARPETING the room at the rate of ₹ 38.50

The cost of papering the walls at ₹ 3.30 m² is ₹ 214.50

One dimension of the room = 1 m × 2 m

Second dimension of the room = 1 m × 1.5 m

To Find:

The dimensions of the room =?

Discussion

10.	Write the following into algebraic expressionThe total cost of m stamps of 50p and n stamps of 25p
Answer» ANSWER: m STAMPS of 50p = m X 50 p = 50pm n stamps of 25P = n x 25 p = 25pn Algebraic EXPRESSION = 50pm + 25 pn

10.

Write the following into algebraic expressionThe total cost of m stamps of 50p and n stamps of 25p

Answer»

ANSWER:

m STAMPS of 50p = m X 50 p = 50pm

n stamps of 25P = n x 25 p = 25pn

Algebraic EXPRESSION = 50pm + 25 pn

Discussion

11.	at what rate of interest will rs 2400amount to rs 2778. 30 in 3yrs if interest being compounded annually?
Answer» Answer: 5% Step-by-step EXPLANATION: A=p(1+r)^n 2778.3 = 2400(1+r)^3 2778.3/2400 = (1+r)^3 1+r=1.05 r=0.05×100=5%

11.

at what rate of interest will rs 2400amount to rs 2778. 30 in 3yrs if interest being compounded annually?

Answer»

Answer:

5%

Step-by-step EXPLANATION:

A=p(1+r)^n

2778.3 = 2400(1+r)^3

2778.3/2400 = (1+r)^3

1+r=1.05

r=0.05×100=5%

Discussion

12.	D/dx [tan²2x] - evaluate this
Answer» Answer: 2x TAN x^4 Step-by-step EXPLANATION: ...............................

12.

D/dx [tan²2x] - evaluate this

Answer»

Answer:

2x TAN x^4

Step-by-step EXPLANATION:

...............................

Discussion

13.	4.13. In the figure given below ZA = 90°, AD isperpendicular to BC. Find x.
Answer» Step-by-step EXPLANATION: by theorem of perpendicular drawn from right ANGLE then both the triangles similar to each other so, AC/BC=DC/AC 12√3/6+x=x/12√3 by SOLVING we GET quadratic equation ${x }^{2} + 6x - 432 = 0 \\ {x}^{2} + 24x - 18x - 432 = 0 \\ x(x + 24) - 18(x + 24) = 0 \\ (x + 24)(x - 18) = 0 \\ \\ x = 18 \: or \: x = - 24$ length cannot be negative so ANSWER is 18.

13.

4.13. In the figure given below ZA = 90°, AD isperpendicular to BC. Find x.

Answer»

Step-by-step EXPLANATION:

by theorem of perpendicular drawn from right ANGLE then both the triangles similar to each other
so, AC/BC=DC/AC
12√3/6+x=x/12√3
by SOLVING we GET quadratic equation
${x }^{2} + 6x - 432 = 0 \\ {x}^{2} + 24x - 18x - 432 = 0 \\ x(x + 24) - 18(x + 24) = 0 \\ (x + 24)(x - 18) = 0 \\ \\ x = 18 \: or \: x = - 24$
length cannot be negative so ANSWER is 18.

Discussion

14.	Usman's father is twice as old as he is twenty years ago Usman'n was seven time as old as his son.find their ages.
Answer» ANSWER:- x=father's age now y=son's age now x= 2(x-21) x= 2x-42 x-2x= -42 -x= -42 x= 42 x= 7y y= x/7 y= 42/7 y= 6 Therefore, the father's present age is 42 and the son's present age is 6 @BengaliBeauty Feel free to ASK your doubts anytime

14.

Usman's father is twice as old as he is twenty years ago Usman'n was seven time as old as his son.find their ages.

Answer»

ANSWER:-

x=father's age now

y=son's age now

x= 2(x-21)

x= 2x-42

x-2x= -42

-x= -42

x= 42

x= 7y

y= x/7

y= 42/7

y= 6

Therefore, the father's present age is 42 and the son's present age is 6

@BengaliBeauty

Feel free to ASK your doubts anytime

Discussion

15.	2. Without actually performing division, state whether the following rational numbers willhave a terminating decimal form or a non-terminating, repeating decimal form.
Answer» ANSWER: where's the RATIONAL no. Step-by-step explanation: B.T.W without actual division you can TELL whether it have a terminat......... decimal form on the basis of the above INSTRUCTION GIVEN .

15.

2. Without actually performing division, state whether the following rational numbers willhave a terminating decimal form or a non-terminating, repeating decimal form.

Answer»

ANSWER:

where's the RATIONAL no.

Step-by-step explanation:

B.T.W without actual division you can TELL whether it have a terminat......... decimal form on the basis of the above INSTRUCTION GIVEN .

Discussion

16.	Me Find the value of :-3-2
Answer» Answer: 3-2 =1 how SIMPLE! don't ASK this SILLY QUESTION again

16.

Me Find the value of :-3-2

Answer»

Answer:

3-2

=1

how SIMPLE! don't ASK this SILLY QUESTION again

Discussion

17.	Some students planned a one day trip. The budget for tiffin was ₹360. Since four students did not join, the cost of tiffin per student gone up by ₹1. Find the original number of students.
Answer» Step-by-step EXPLANATION: here is ur ANS pls follow me and HOPE it's HELPFUL

17.

Some students planned a one day trip. The budget for tiffin was ₹360. Since four students did not join, the cost of tiffin per student gone up by ₹1. Find the original number of students.

Answer»

Step-by-step EXPLANATION:

here is ur ANS pls follow me and HOPE it's HELPFUL

Discussion

18.	Show that the axes of co ordinator trisect the staright line joining the point (2,-2) and (-1,4)
Answer» ANSWER: ..........................................

18.

Show that the axes of co ordinator trisect the staright line joining the point (2,-2) and (-1,4)

Answer»

ANSWER:

..........................................

Discussion

19.	The volume of a solid 2 pointscylinder is 448Tt cms andit's height is 7cm find itslateral surface area (chठोस बेलन का आयतन 448T1cm है व ऊँचाई 7cm है तोउसका वक्र पृष्ठीय क्षेत्रफल ज्ञात
Answer» For a SOLID cylinder - Given :- $\sf{Volume \: (V) = 448\pi \: cm^{3}}$ $\sf{height \: (h) = 7 \: cm}$ To FIND :- $\sf{Lateral \: Surface \: Area \: of \: this \: solid \: cylinder = ?}$ Using FORMULAS :- $\sf{Volume \: of \: Solid \: Cylinder = \pi r^{2} h}$ $\sf{Lateral \: Surface \: Area = 2\pi r h}$ Solution :- $\sf{Volume \: of \: Solid \: Cylinder = 448\pi}$ $\sf{\pi r^{2} h = 448\pi}$ $\sf{r^{2} h = 448}$ $\sf{r^{2}(7) = 448}$ $\sf{7r^{2} = 448}$ $\sf{r^{2} = 64}$ $\sf{r=\sqrt{64}}$ $\sf{r = 8 \: cm}$ Now , $\sf{Lateral \: Surface \: Area \: of \: Solid \: Cylinder -}$ $\sf{2\pi r h}$ $\sf{2\times \frac{22}{7}\times 8\times 7}$ $\sf{2\times 22\times 8}$ $\sf{2\times 176}$ $\sf{352 \: cm^{2}}$ RESULT :- $\sf{Lateral \: Surface \: Area \: of \: this \: Solid \: Cylinder \: is \: 352 \: cm^{2}.}$

19.

The volume of a solid 2 pointscylinder is 448Tt cms andit's height is 7cm find itslateral surface area (chठोस बेलन का आयतन 448T1cm है व ऊँचाई 7cm है तोउसका वक्र पृष्ठीय क्षेत्रफल ज्ञात

Answer»

For a SOLID cylinder -

Given :-

$\sf{Volume \: (V) = 448\pi \: cm^{3}}$

$\sf{height \: (h) = 7 \: cm}$

To FIND :-

$\sf{Lateral \: Surface \: Area \: of \: this \: solid \: cylinder = ?}$

Using FORMULAS :-

$\sf{Volume \: of \: Solid \: Cylinder = \pi r^{2} h}$

$\sf{Lateral \: Surface \: Area = 2\pi r h}$

Solution :-

$\sf{Volume \: of \: Solid \: Cylinder = 448\pi}$

$\sf{\pi r^{2} h = 448\pi}$

$\sf{r^{2} h = 448}$

$\sf{r^{2}(7) = 448}$

$\sf{7r^{2} = 448}$

$\sf{r^{2} = 64}$

$\sf{r=\sqrt{64}}$

$\sf{r = 8 \: cm}$

Now ,

$\sf{Lateral \: Surface \: Area \: of \: Solid \: Cylinder -}$

$\sf{2\pi r h}$

$\sf{2\times \frac{22}{7}\times 8\times 7}$

$\sf{2\times 22\times 8}$

$\sf{2\times 176}$

$\sf{352 \: cm^{2}}$

RESULT :-

$\sf{Lateral \: Surface \: Area \: of \: this \: Solid \: Cylinder \: is \: 352 \: cm^{2}.}$

Discussion

20.	If AuBuC =S (the sample space) and A,B and C are mutually exclusive events, can the following represent probability assignment? i. P(A) = 0.2, P(B)= 0.7, P(C) =0.1
Answer» ANSWER: ভ্রান্ত আকিদার কুফল Step-by-step EXPLANATION: ভ্রান্ত আকিদার কুফল

20.

If AuBuC =S (the sample space) and A,B and C are mutually exclusive events, can the following represent probability assignment? i. P(A) = 0.2, P(B)= 0.7, P(C) =0.1

Answer»

ANSWER:

ভ্রান্ত আকিদার কুফল

Step-by-step EXPLANATION:

ভ্রান্ত আকিদার কুফল

Discussion

21.	So, f(x) isQ. 20 Examine the differentiability of f, where f is defined byx[x]if O S x
Answer» Step-by-step explanation: f(1 − )= h→0 lim (1−h)0=0 f(1 + )= h→0 lim 1+h=1 Since f is not CONTINUOUS at x=1, its also not differentiable at that point. f(2 − )= h→0 lim (2−h)(1)=2 f(2 + )= h→0 lim (2+h−1)2=2 f ′ (2 − )= h→0 lim −h 2−h−2 =1 f(2 + )= h→0 lim h 2+2h−2 =2 Hence, the function is continuous but not differentiable at x=2.

21.

So, f(x) isQ. 20 Examine the differentiability of f, where f is defined byx[x]if O S x

Answer»

Step-by-step explanation:

f(1

−

)=

h→0

lim

(1−h)0=0

f(1

+

)=

h→0

lim

1+h=1

Since f is not CONTINUOUS at x=1, its also not differentiable at that point.

f(2

−

)=

h→0

lim

(2−h)(1)=2

f(2

+

)=

h→0

lim

(2+h−1)2=2

f

′

(2

−

)=

h→0

lim

−h

2−h−2

=1

f(2

+

)=

h→0

lim

h

2+2h−2

=2

Hence, the function is continuous but not differentiable at x=2.

Discussion

22.	{11/14 + 3(3/4 + 1/4)}
Answer» Answer: 67/14(i am not SURE)..PLEASE CHECK other ANSWWR

22.

{11/14 + 3(3/4 + 1/4)}

Answer»

Answer:

67/14(i am not SURE)..PLEASE CHECK other ANSWWR

Discussion

23.	30 - 1.5 answer with explain
Answer» Answer: 28.5 woejehhdjelldlngebsle Step-by-step explanation: 30.0 01.5 28.5 hdiekeiejekek

23.

30 - 1.5 answer with explain

Answer»

Answer:

28.5 woejehhdjelldlngebsle

Step-by-step explanation:

30.0

01.5

28.5

hdiekeiejekek

Discussion

24.	Free pointsss....................
Answer» ANSWER: freeeeeeeree pointssssssss.

24.

Free pointsss....................

Answer»

ANSWER:

freeeeeeeree pointssssssss.

Discussion

25.	What is 2x+6y+7x?Please to show the working
Answer» Answer: 15xy FOLLW me you all

25.

What is 2x+6y+7x?Please to show the working

Answer»

Answer:

15xy FOLLW me you all

Discussion

26.	Find The Ratio In Which the point P(2,1) divide the line joining the points A(2,7) and B(2,-3).
Answer» $\LARGE{ \underline{\underline{ \sf{Required \: answer:}}}}$ GiveN: The points are A(2,7) and B(2,-3). The point which divides them is P(2,1) To Find: The ratio in which P divides AB? Step-by-step Explanation: Let the ratio be k:1 Hence, m1 = k and M2 = 1 Also, if we see the points: x1 = 2 and y1 = 7 x2 = 2 and y2 = -3 x = 2 and y = 1 Using Section formula, $\cdot{ \boxed{ \rm{x = \frac{m1x2 + m2x1}{m1 + m2} \:}} \boxed{ \rm{ \: y = \frac{m1y2 + m2y1}{m1 + m2} }}}$ Putting the given values, $\rm{1 = \dfrac{k( - 3) + 1(7)}{k + 1} }$ Cross MULTIPLYING, ⇒ k + 1 = -3k + 7 ⇒ k + 3k = 6 ⇒ 4k = 6 ⇒ k = 3/2 The ratio is k : 1 ⇒ 3/2 : 1 ⇒ 3 : 2 Hence, the ratio is 3 : 2 (Ans)

26.

Find The Ratio In Which the point P(2,1) divide the line joining the points A(2,7) and B(2,-3).

Answer»

$\LARGE{ \underline{\underline{ \sf{Required \: answer:}}}}$

GiveN:

The points are A(2,7) and B(2,-3).
The point which divides them is P(2,1)

To Find:

The ratio in which P divides AB?

Step-by-step Explanation:

Let the ratio be k:1

Hence, m1 = k and M2 = 1

Also, if we see the points:

x1 = 2 and y1 = 7
x2 = 2 and y2 = -3
x = 2 and y = 1

Using Section formula,

$\cdot{ \boxed{ \rm{x = \frac{m1x2 + m2x1}{m1 + m2} \:}} \boxed{ \rm{ \: y = \frac{m1y2 + m2y1}{m1 + m2} }}}$

Putting the given values,

$\rm{1 = \dfrac{k( - 3) + 1(7)}{k + 1} }$

Cross MULTIPLYING,

⇒ k + 1 = -3k + 7

⇒ k + 3k = 6

⇒ 4k = 6

⇒ k = 3/2

The ratio is k : 1

⇒ 3/2 : 1

⇒ 3 : 2

Hence, the ratio is 3 : 2 (Ans)

Discussion

27.	divide rupees 5000 in two parts that si 11 part at 5% per annum for 3 years is double that of the other part at 6% per annum for 2 years
Answer» MARK me as BRAINLIEST PLEASE

Discussion

28.	What is the value of a²+b² if a+b=9 and ab=20
Answer» Answer: hope it will help you ....... PLZZ MARK me as BRAINLIEST

28.

What is the value of a²+b² if a+b=9 and ab=20

Answer»

Answer:

hope it will help you ....... PLZZ MARK me as BRAINLIEST

Discussion

29.	Q.3Do as directed.1. Ravina has to cover a distance of 2 - km to reach her school. Then how much (2)distance does she covers while going to school and come back home?2. What time will be after 2 hour on the given clock
Answer» Step-by-step explanation: Q1 answer is 4KM q2- it has to be a FIGURE GIVEN can't solve without that

29.

Q.3Do as directed.1. Ravina has to cover a distance of 2 - km to reach her school. Then how much (2)distance does she covers while going to school and come back home?2. What time will be after 2 hour on the given clock

Answer»

Step-by-step explanation:

Q1 answer is 4KM

q2- it has to be a FIGURE GIVEN can't solve without that

Discussion

30.	The circumference of a circle is 12 m greater than the perimeter of a square if the ratio of the diameter of the circle is to the length of the square is 4 :3, find the area of the square?explain step by step.please don't spamit's very important.answer as soon as possible
Answer» Answer: Let the radius of the CIRCLE ber. ∴ Area of Circle= πr 2 . and the circumference=2πr The perimeter of the square is equal to circumference of circle. ∴ Its one side = 4 1 ×2πr= 2 πr . So Area of Square =( 2 πr ) 2 . ∴ AreaOfSquare AreaOfcircle =πr 2 :( 2 πr ) 2 = π 4 = 22 4×7 = 11 14 >1. So, Area of Circle > Area of Square Step-by-step explanation: HOPE it will help you

30.

The circumference of a circle is 12 m greater than the perimeter of a square if the ratio of the diameter of the circle is to the length of the square is 4 :3, find the area of the square?explain step by step.please don't spamit's very important.answer as soon as possible

Answer»

Answer:

Let the radius of the CIRCLE ber.

∴ Area of Circle= πr

2

.

and the circumference=2πr

The perimeter of the square is equal to circumference of circle.

∴ Its one side =

4

1

×2πr=

2

πr

.

So Area of Square =(

2

πr

)

2

.

∴

AreaOfSquare

AreaOfcircle

=πr

2

:(

2

πr

)

2

=

π

4

=

22

4×7

=

11

14

>1.

So, Area of Circle > Area of Square

Step-by-step explanation:

HOPE it will help you

Discussion

31.	If A is a square matrix of order 3 having a row of zeros then the determinant of A is
Answer» ANSWER: CORRECT answer is ZERO (0).

31.

If A is a square matrix of order 3 having a row of zeros then the determinant of A is

Answer»

ANSWER:

CORRECT answer is ZERO (0).

Discussion

32.	An aeroplane takes 3 hours to cover a distance of 3,600 km. Another aeroplane travels at a speed which is 100 km per hour less than the first aeroplane. How long will the second aeroplane take to cover the same distance?
Answer» Answer : 3.27 hours Step-by-step explanation : we know, $\boxed{\bf Speed=\frac{distance \ <klux>COVERED</klux>}{time \ taken}}$ An aeroplane takes 3 hours to cover a distance of 3,600 km Distance covered = 3600 km Time taken = 3 hours => Speed of first aeroplane = 3600 km/3 H = 1200 km/h Another aeroplane travels at a speed which is 100 km per hour less than the first aeroplane. => Speed of second aeroplane = (1200 - 100) km/h = 1100 km/h we have to find the time taken to cover the same distance by the second aeroplane. Distance covered = 3600 km 1100 km/h = 3600 km/time taken time taken = 3600/1100 time taken = 36/11 time taken = 3.27 hours (approximately) ∴ The time taken by the second aeroplane TAKE to cover the same distance = 3.27 hours

32.

An aeroplane takes 3 hours to cover a distance of 3,600 km. Another aeroplane travels at a speed which is 100 km per hour less than the first aeroplane. How long will the second aeroplane take to cover the same distance?

Answer»

Answer :

3.27 hours

Step-by-step explanation :

we know,

$\boxed{\bf Speed=\frac{distance \ <klux>COVERED</klux>}{time \ taken}}$

An aeroplane takes 3 hours to cover a distance of 3,600 km

Distance covered = 3600 km

Time taken = 3 hours

=> Speed of first aeroplane = 3600 km/3 H

= 1200 km/h

Another aeroplane travels at a speed which is 100 km per hour less than the first aeroplane.

=> Speed of second aeroplane = (1200 - 100) km/h

= 1100 km/h

we have to find the time taken to cover the same distance by the second aeroplane.

Distance covered = 3600 km

1100 km/h = 3600 km/time taken

time taken = 3600/1100

time taken = 36/11

time taken = 3.27 hours (approximately)

∴ The time taken by the second aeroplane TAKE to cover the same distance = 3.27 hours

Discussion

33.	Draw a circle with center O and radius 3 cm . Take a point P on the circle . Draw a tangent to the circle passing through the point P
Answer» Answer: oh I have practised and my teacher gave this in EXAM again and again... Step-by-step EXPLANATION: Ok and I have learn it but I can't draw a CIRCLE in the screen ok so I will keep it in brainly. in...

33.

Draw a circle with center O and radius 3 cm . Take a point P on the circle . Draw a tangent to the circle passing through the point P

Answer»

Answer:

oh I have practised and my teacher gave this in EXAM again and again...

Step-by-step EXPLANATION:

Ok and I have learn it but I can't draw a CIRCLE in the screen ok so I will keep it in brainly. in...

Discussion

34.	A mobile phone was sold for 4800. Find the cost price of the mobile phone if the profit is 20%
Answer» HOPE It will HELP you. If it is HELPFUL then FOLLOW me if you WANT.

34.

A mobile phone was sold for 4800. Find the cost price of the mobile phone if the profit is 20%

Answer»

HOPE It will HELP you.

If it is HELPFUL then FOLLOW me if you WANT.

Discussion

35.	If tan35°+cot37°+tan325°= xtan53°+tan127° then x isa)1b)+1c)2d)5pls say detailedly. If say the step by step answer. I will make you a brainlist
Answer» Step-by-step explanation: 1 afgnkdaegkmbvcdssgh

35.

If tan35°+cot37°+tan325°= xtan53°+tan127° then x isa)1b)+1c)2d)5pls say detailedly. If say the step by step answer. I will make you a brainlist

Answer»

Step-by-step explanation:

1 afgnkdaegkmbvcdssgh

Discussion

36.	Find the largest possible decimal number between 0.1 and 0.2 whose sum of the digits is 20.
Answer» Step-by-step EXPLANATION: ahhhhhhh ahhhhhhh ahhhhhhh ahhhhhhh ahhhhhhh are the most BEAUTIFUL WORD in hi I am Mythpat are you going to be a GOOD time in the FUTURE and I am Ankita Chouhan

36.

Find the largest possible decimal number between 0.1 and 0.2 whose sum of the digits is 20.

Answer»

Step-by-step EXPLANATION:

ahhhhhhh ahhhhhhh ahhhhhhh ahhhhhhh ahhhhhhh are the most BEAUTIFUL WORD in hi I am Mythpat are you going to be a GOOD time in the FUTURE and I am Ankita Chouhan

Discussion

37.	Find the perpendicular distance from the point (2, 3) to the line 3x-4y=0
Answer» ANSWER: perpendicaul DISTANCE is 2 UNITS

37.

Find the perpendicular distance from the point (2, 3) to the line 3x-4y=0

Answer»

ANSWER:

perpendicaul DISTANCE is 2 UNITS

Discussion

38.	If property of addition is verified when (a+b)=(b+a)
Answer» ANSWER: (a+b)=(b+a) this PROPERTY is commutavity property

38.

If property of addition is verified when (a+b)=(b+a)

Answer»

ANSWER:

(a+b)=(b+a)

this PROPERTY is commutavity property

Discussion

39.	Find x and y in the fallowing :1. ( x-a/3x)+(2x + y)2. [ 2x / x ]-[4y+ 9x ]3. (4y+8x) +( 5x -10y)
Answer» Step-by-step EXPLANATION: I HOPE it's HELP you! .BB

39.

Find x and y in the fallowing :1. ( x-a/3x)+(2x + y)2. [ 2x / x ]-[4y+ 9x ]3. (4y+8x) +( 5x -10y)

Answer»

Step-by-step EXPLANATION:

I HOPE it's HELP you!

.BB

Discussion

40.	PAGE NO.:DATE:is equal to-12& les x totSin nit sinX122T/2bu3T1/4
Answer» ANSWER: প্রশ্ন বোঝা যাচ্ছে না। পুনরায় প্রশ্ন দিন।

40.

PAGE NO.:DATE:is equal to-12& les x totSin nit sinX122T/2bu3T1/4

Answer»

ANSWER:

প্রশ্ন বোঝা যাচ্ছে না। পুনরায় প্রশ্ন দিন।

Discussion

41.	Is -6/-12 equivalent to-1/2
Answer» ANSWER: DIVIDE 6/12 then you GET the answer is 1/2

41.

Is -6/-12 equivalent to-1/2

Answer»

ANSWER:

DIVIDE 6/12 then you GET the answer is 1/2

Discussion

42.	if a b is equal to 1 then 1 divided by 1 + a raised to minus 1 + 1 divided by 1 + b raise to minus 1 is equal to
Answer» the above is the answer. I HOPE it HELPS

42.

if a b is equal to 1 then 1 divided by 1 + a raised to minus 1 + 1 divided by 1 + b raise to minus 1 is equal to

Answer»

the above is the answer.

I HOPE it HELPS

Discussion

43.	7+{1/3+2/12(7/4-5/12)} solve this
Answer» Answer: 23/3 Step-by-step EXPLANATION: STEPS in the above PHOTO....

43.

7+{1/3+2/12(7/4-5/12)} solve this

Answer»

Answer:

23/3

Step-by-step EXPLANATION:

STEPS in the above PHOTO....

Discussion

44.	Heyy guys plz answer my questionsubject-Maths Q. Round of nearest 1003794579it's very easy
Answer» Step-by-step explanation: If it is easy then do it on your own When rounding to the NEAREST hundred, look at the TENS DIGIT of the number. If that digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred. If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.

44.

Heyy guys plz answer my questionsubject-Maths Q. Round of nearest 1003794579it's very easy

Answer»

Step-by-step explanation:

If it is easy then do it on your own

When rounding to the NEAREST hundred, look at the TENS DIGIT of the number.

If that digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.

If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.

Discussion

45.	If a=1 , tn=149 , find n
Answer» ANSWER: the VALUE of N is (148+d)/d

45.

If a=1 , tn=149 , find n

Answer»

ANSWER:

the VALUE of N is (148+d)/d

Discussion

46.	Ankita and Nagma are friends. They were both born in 1998. What is the probability that they have[ 1 ] same birthday ? [ 2 ] different birthdays ?
Answer» Answer: 1)1/365 2)364/365 Step-by-step explanation: Here 1998 is not a leap YEAR 1)only one DAY in the year . 2)except one day in that year.

46.

Ankita and Nagma are friends. They were both born in 1998. What is the probability that they have[ 1 ] same birthday ? [ 2 ] different birthdays ?

Answer»

Answer:

1)1/365

2)364/365

Step-by-step explanation:

Here 1998 is not a leap YEAR

1)only one DAY in the year .

2)except one day in that year.

Discussion

47.	In what time will rs 2500 amount to rs2809 at 12% p. a compounded semi anually?
Answer» ANSWER: $principal(p) = \: rs \: 2500 \\ amount(a) = \: rs \: 2809 \\ rate(r) = 12\% \: per \: annum \\ convert \: rate \: in \: semi \: annually \\ rate = \frac{12}{2} \% = 6\% \: per \: semi \: annually \\ let \: the \: time \: in \: annually \: be \: t \\ then \\ convert \: time \: in \: semi \: annually \\ time = 2t$ $a = p \times (1 + \frac{r}{100} ) {}^{2t} \\ 2809 = 2500 \times (1 + \frac{6}{100} ) {}^{2t } \\ (1 + \frac{3}{50} ) {}^{2t} = \frac{2809}{2500} \\ ( \frac{50 + 3}{50} ) {}^{2t} = ( \frac{53}{50} ) {}^{2} \\ (\frac{53}{50}) {}^{2t} = (\frac{53}{50} ) {}^{2} \\ base \: are \: same \: so \\ 2t = 2 \\ t = 1 \: year = 2 \: semi \: year$

47.

In what time will rs 2500 amount to rs2809 at 12% p. a compounded semi anually?

Answer»

ANSWER:

$principal(p) = \: rs \: 2500 \\ amount(a) = \: rs \: 2809 \\ rate(r) = 12\% \: per \: annum \\ convert \: rate \: in \: semi \: annually \\ rate = \frac{12}{2} \% = 6\% \: per \: semi \: annually \\ let \: the \: time \: in \: annually \: be \: t \\ then \\ convert \: time \: in \: semi \: annually \\ time = 2t$

$a = p \times (1 + \frac{r}{100} ) {}^{2t} \\ 2809 = 2500 \times (1 + \frac{6}{100} ) {}^{2t } \\ (1 + \frac{3}{50} ) {}^{2t} = \frac{2809}{2500} \\ ( \frac{50 + 3}{50} ) {}^{2t} = ( \frac{53}{50} ) {}^{2} \\ (\frac{53}{50}) {}^{2t} = (\frac{53}{50} ) {}^{2} \\ base \: are \: same \: so \\ 2t = 2 \\ t = 1 \: year = 2 \: semi \: year$

Discussion

48.	Find the value of 649x8 +649x2
Answer» Answer: HLO MATE here is your answer Step-by-step explanation: hi the answer is 6490 649×8 =5192 649×2 =1298 adding both the MULTIPLICATION we GET..... 5192+1298 =6490

48.

Find the value of 649x8 +649x2

Answer»

Answer:

HLO MATE here is your answer

Step-by-step explanation:

hi

the answer is 6490

649×8

=5192

649×2

=1298

adding both the MULTIPLICATION we GET.....

5192+1298

=6490

Discussion

49.	What is the radius of curvature of the curve x4+y4=2 at (1,1)
Answer» SOLUTION TO DETERMINE The radius of curvature of the CURVE $\sf{ {x}^{4} + {y}^{4} = 2 }$ at (1,1) EVALUATION Here the given EQUATION of the curve is $\sf{ {x}^{4} + {y}^{4} = 2 }$ Differentiating both sides with respect to x we get $\sf{4 {x}^{3} + 4 {y}^{3} \: y_1 = 0 }$ $\sf{ \implies \: {x}^{3} + {y}^{3} \: y_1 = 0 } \: \: \: \: \: \: - - (1)$ Putting x = 1 & y = 1 we get $\sf{ \implies \: {(1)}^{3} + {(1)}^{3} \: y_1 = 0 }$ $\sf{ \implies \: \: y_1 = - 1 }$ Again Differentiating equation (1) with respect to x we get $\sf{ \implies \: 3{x}^{2} + {y}^{3} \: y_2 +3 {y}^{2} \: {y_1}^{2} = 0 } \:$ $\sf{Putting \: \: x = 1 \: , \: y = 1, y_1 = - 1 \: we \: \: get }$ $\sf{ \implies \: 3 + \: y_2 + 3 = 0 } \:$ $\sf{ \implies \: \: y_2 = - 6 } \:$ Hence the the required radius of curvature at any point (x, y) is $\displaystyle \sf{ R = \frac{{(1 + {y_1}^{2})}^{ \frac{3}{2} } }{y_2} }$ $\displaystyle \sf{ = \frac{{(1 + {y_1}^{2})}^{ \frac{3}{2} } }{y_2} }$ $\displaystyle \sf{ = \frac{{(1 + 1)}^{ \frac{3}{2} } }{ - 6} }$ $\displaystyle \sf{ = \frac{{(2)}^{ \frac{3}{2} } }{ - 6} }$ $\displaystyle \sf{ = - \frac{2 \sqrt{2} }{6} }$ $\displaystyle \sf{ = - \frac{ \sqrt{2} }{3} }$ ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. FIND the radius of curvature for the curve xy3=a4 at (a,a) brainly.in/question/22270223 2. radius of curvature of the curve x^2/3 + y^2/3 = a^2/3 brainly.in/question/13357557

49.

What is the radius of curvature of the curve x4+y4=2 at (1,1)

Answer»

SOLUTION

TO DETERMINE

The radius of curvature of the CURVE

$\sf{ {x}^{4} + {y}^{4} = 2 }$

at (1,1)

EVALUATION

Here the given EQUATION of the curve is

$\sf{ {x}^{4} + {y}^{4} = 2 }$

Differentiating both sides with respect to x we get

$\sf{4 {x}^{3} + 4 {y}^{3} \: y_1 = 0 }$

$\sf{ \implies \: {x}^{3} + {y}^{3} \: y_1 = 0 } \: \: \: \: \: \: - - (1)$

Putting x = 1 & y = 1 we get

$\sf{ \implies \: {(1)}^{3} + {(1)}^{3} \: y_1 = 0 }$

$\sf{ \implies \: \: y_1 = - 1 }$

Again Differentiating equation (1) with respect to x we get

$\sf{ \implies \: 3{x}^{2} + {y}^{3} \: y_2 +3 {y}^{2} \: {y_1}^{2} = 0 } \:$

$\sf{Putting \: \: x = 1 \: , \: y = 1, y_1 = - 1 \: we \: \: get }$

$\sf{ \implies \: 3 + \: y_2 + 3 = 0 } \:$

$\sf{ \implies \: \: y_2 = - 6 } \:$

Hence the the required radius of curvature at any point (x, y) is

$\displaystyle \sf{ R = \frac{{(1 + {y_1}^{2})}^{ \frac{3}{2} } }{y_2} }$

$\displaystyle \sf{ = \frac{{(1 + {y_1}^{2})}^{ \frac{3}{2} } }{y_2} }$

$\displaystyle \sf{ = \frac{{(1 + 1)}^{ \frac{3}{2} } }{ - 6} }$

$\displaystyle \sf{ = \frac{{(2)}^{ \frac{3}{2} } }{ - 6} }$

$\displaystyle \sf{ = - \frac{2 \sqrt{2} }{6} }$

$\displaystyle \sf{ = - \frac{ \sqrt{2} }{3} }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. FIND the radius of curvature for the curve xy3=a4 at (a,a)

brainly.in/question/22270223

2. radius of curvature of the curve x^2/3 + y^2/3 = a^2/3

brainly.in/question/13357557

Discussion

50.	The average of 26 numbers is 22.If each number is increased by 8.What will be the new average.
Answer» Answer: 126 will be the NEW AVERAGE.

50.

The average of 26 numbers is 22.If each number is increased by 8.What will be the new average.

Answer»

Answer:

126 will be the NEW AVERAGE.

Discussion

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Usman's father is twice as old as he is twenty years ago Usman'n was seven time as old as his son.find their ages.​

ANSWER:-

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2. Without actually performing division, state whether the following rational numbers willhave a terminating decimal form or a non-terminating, repeating decimal form.​

Me Find the value of :-3-2 ​

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{11/14 + 3(3/4 + 1/4)}​

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Answer :

Step-by-step explanation :

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If property of addition is verified when (a+b)=(b+a)​

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PAGE NO.:DATE:is equal to-12& les x totSin nit sinX122T/2bu3T1/4​

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SOLUTION

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Usman's father is twice as old as he is twenty years ago Usman'n was seven time as old as his son.find their ages.

2. Without actually performing division, state whether the following rational numbers willhave a terminating decimal form or a non-terminating, repeating decimal form.

Me Find the value of :-3-2

Some students planned a one day trip. The budget for tiffin was ₹360. Since four students did not join, the cost of tiffin per student gone up by ₹1. Find the original number of students.

Show that the axes of co ordinator trisect the staright line joining the point (2,-2) and (-1,4)

The volume of a solid 2 pointscylinder is 448Tt cms andit's height is 7cm find itslateral surface area (chठोस बेलन का आयतन 448T1cm है व ऊँचाई 7cm है तोउसका वक्र पृष्ठीय क्षेत्रफल ज्ञात

If AuBuC =S (the sample space) and A,B and C are mutually exclusive events, can the following represent probability assignment? i. P(A) = 0.2, P(B)= 0.7, P(C) =0.1

{11/14 + 3(3/4 + 1/4)}

30 - 1.5 answer with explain

Free pointsss....................

Find The Ratio In Which the point P(2,1) divide the line joining the points A(2,7) and B(2,-3).

divide rupees 5000 in two parts that si 11 part at 5% per annum for 3 years is double that of the other part at 6% per annum for 2 years

What is the value of a²+b² if a+b=9 and ab=20

Q.3Do as directed.1. Ravina has to cover a distance of 2 - km to reach her school. Then how much (2)distance does she covers while going to school and come back home?2. What time will be after 2 hour on the given clock

The circumference of a circle is 12 m greater than the perimeter of a square if the ratio of the diameter of the circle is to the length of the square is 4 :3, find the area of the square?explain step by step.please don't spamit's very important.answer as soon as possible

An aeroplane takes 3 hours to cover a distance of 3,600 km. Another aeroplane travels at a speed which is 100 km per hour less than the first aeroplane. How long will the second aeroplane take to cover the same distance?

Draw a circle with center O and radius 3 cm . Take a point P on the circle . Draw a tangent to the circle passing through the point P

If tan35°+cot37°+tan325°= xtan53°+tan127° then x isa)1b)+1c)2d)5pls say detailedly. If say the step by step answer. I will make you a brainlist

Find the perpendicular distance from the point (2, 3) to the line 3x-4y=0

If property of addition is verified when (a+b)=(b+a)

Find x and y in the fallowing :1. ( x-a/3x)+(2x + y)2. [ 2x / x ]-[4y+ 9x ]3. (4y+8x) +( 5x -10y)

PAGE NO.:DATE:is equal to-12& les x totSin nit sinX122T/2bu3T1/4

if a b is equal to 1 then 1 divided by 1 + a raised to minus 1 + 1 divided by 1 + b raise to minus 1 is equal to

7+{1/3+2/12(7/4-5/12)} solve this

Heyy guys plz answer my questionsubject-Maths Q. Round of nearest 1003794579it's very easy

If a=1 , tn=149 , find n

Ankita and Nagma are friends. They were both born in 1998. What is the probability that they have[ 1 ] same birthday ? [ 2 ] different birthdays ?

In what time will rs 2500 amount to rs2809 at 12% p. a compounded semi anually?