4.13. In the figure given below ZA = 90°, AD isperpendicular to BC. F

1.	4.13. In the figure given below ZA = 90°, AD isperpendicular to BC. Find x.
Answer» Step-by-step EXPLANATION: by theorem of perpendicular drawn from right ANGLE then both the triangles similar to each other so, AC/BC=DC/AC 12√3/6+x=x/12√3 by SOLVING we GET quadratic equation ${x }^{2} + 6x - 432 = 0 \\ {x}^{2} + 24x - 18x - 432 = 0 \\ x(x + 24) - 18(x + 24) = 0 \\ (x + 24)(x - 18) = 0 \\ \\ x = 18 \: or \: x = - 24$ length cannot be negative so ANSWER is 18.

4.13. In the figure given below ZA = 90°, AD isperpendicular to BC. Find x.

Answer»

Step-by-step EXPLANATION:

by theorem of perpendicular drawn from right ANGLE then both the triangles similar to each other
so, AC/BC=DC/AC
12√3/6+x=x/12√3
by SOLVING we GET quadratic equation
${x }^{2} + 6x - 432 = 0 \\ {x}^{2} + 24x - 18x - 432 = 0 \\ x(x + 24) - 18(x + 24) = 0 \\ (x + 24)(x - 18) = 0 \\ \\ x = 18 \: or \: x = - 24$
length cannot be negative so ANSWER is 18.

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4.13. In the figure given below ZA = 90°, AD isperpendicular to BC. Find x.​

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4.13. In the figure given below ZA = 90°, AD isperpendicular to BC. Find x.