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505050 is not a PERFECT SQUARE as only if the NUMBER has even number of zeroes it is considered as a perfect square

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I number which do not have factor between them and other are COMING PRIME number LIKE 1,5,7 ETC.

This should be your ANSWER.

Is this the ANSWER????..................

THE ANSWER IS 111/900

I HOPE it will HELP you

X-y=36. (1)
x÷y=4
-->x=4y
substituting in (1) 4y-y=36 =3y=36
MEANS,y=12
so, x-12=36
which means x=48

Here is the SOLUTION ..

length of ROD is 2*2/5

=4/5

=0.8m

The rod is DIVIDED into 5 equal parts

So, the length of each PART is 0.8/5

=0.16m

First find the L.C.M of 6,8,10,12
2 |6,8,10,12
3 |3,4,5,6
2 |1,4,5,2
2 |1,2,5,1
5 |1,1,5,1
|1,1,1,1 least common MULTIPLE of 6,8,10,12 is 2×3×2×2×5=60. As he left with 5 PLANTS in each case , 60+5 can be number of plants with him as it is divisible by 13. So number of plants with him =65.
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Here is the SOL. HOPE it will HELP if it. then FOLLOW.

To prove=AOC is CONGRUENT to BOD

ANGLE O =angle O{V.O.A}

AO=OB{O is BISECTOR}

CO=OD{O is the bisector}

THEREFORE both TRIANGLES are congruent

To VERIFY: a ÷ (B + C) ≠ (a ÷ b) + (a÷c)

What do you WANT????

-1×-1×-1
(-1)^3
=-1


regards MOHIT khairnar

HEYA MATE,

HERE IS UR ANSWER.

Thanks for asking this question.

Tipu Sultan was a ruler of the Kingdom of Mysore renowned for his bravery in the wars against the British East India COMPANY. Well known for his valor and courage, he is REGARDED as the first freedom fighter of India for his fierce battles against the British who tried to conquer the territories under the sultan’s rule. The Treaty of Mangalore, which he signed with the British East India Company to bring an end to the Second Anglo-Mysore WAR, was the last occasion when an Indian king dictated terms to the British. As the eldest son of Sultan Hyder Ali of Mysore, Tipu Sultan ascended to the throne after the death of his FATHER in 1782. As ruler, he implemented several innovations in his administration and also expanded the iron-cased Mysorean rockets which he would later deploy against the advances of the British forces. His father had diplomatic political relations with the French and thus Tipu Sultan had received military training from French officers as a young man. After becoming the ruler, he continued his father’s policy of aligning with the French in their struggle against the British. He fought several wars against the British and tried his best to defend his kingdom from falling into the hands of the British East India Company. COMMITTED to his country till the very end, he died while fighting in the Fourth Anglo-Mysore War.

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a=8+3√7 and b=1/8+3√7
Therefore a^2=(8+3√7)^2
=8^2+2(8)(3√7)+
(3√7)^2
=64+48√7+63
=127+48√7....
And b^2=(1/8+3√7)^2
=(1/8)^2+2(1/8)(3√7)+
(3√7)^2
=1/64+3√7/4+63
=(1+48√7+4032)/64
=(4033+48√7)/64......

W=2nπ
=2π*540/6*60
=3π is the ANGULAR ACCELERATION

Let X = NUMBER of shirts
Then X× 8/9×3/8=81 given
X×1/3 = 81
X=243 TOTAL no of shirts
Now printed - coloured = 162- 81 = 81
Is the final answer...

S.P=₹27600
Loss=8%
27600×8/100)
ACTUAL loss=₹2208
C.P=27600-2208
=₹25392

Hope it HELPS you

SECTION FORMULA;

x = ( mx2+nx1 )/ ( m+N )

y = ( my2 + ny1 )/ ( m+n )

1 = (-m*3 +n*4)/(m+n)

m + n = -3m + 4n

4m - 3n = 0

4m = 3n

m/n = 3/4

m:n = 3:4

Ratio = 3:4

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Given Data :

Total Profit = RS. 16,500

Total TIME period = 1 year

Girish = Rs. 45000, Time period = 12 MONTHS

Vijay = Rs. 60000, Time period = 9 months

Ankush = Rs. 90000, Time period = 6 months

Therefore asserting the data, we get the share values as follows:

Girish : Vijay : Ankush = 45000 * 12 : 60000 * 9 : 90000 * 6

=> RATIO of Girish : Vijay : Ankush = 540000 : 720000 : 540000

=> Ratio = 3 : 4 : 3

=> Girish has 3 percent of Total profit share.

Total profit share = 3 + 4 + 3 = 10

=> Girish share = 3 / 10 * 16500

=> Girish' s Share = 3 * 1650 = 4,950

Hence share of Girish = Rs. 4950

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