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If a= 8+ 3√7 and b= 1/ 8+3√7 then find the value of a²+b²pls answer no one is answeing my question pls the best will be selected as brainliest

Answer»

a=8+3√7 and b=1/8+3√7
Therefore a^2=(8+3√7)^2
=8^2+2(8)(3√7)+
(3√7)^2
=64+48√7+63
=127+48√7....
And b^2=(1/8+3√7)^2
=(1/8)^2+2(1/8)(3√7)+
(3√7)^2
=1/64+3√7/4+63
=(1+48√7+4032)/64
=(4033+48√7)/64......


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