This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
the perimeter of an isosceles triangle is 10 3 by 4 cm if one of its equal side is 2 5 by 6 find the third side |
|
Answer» Answer: The perimeter of an isosceles TRIANGLE =10- 3/4 or we can also WRITE 43/4cm If one of the EQUAL SIDE is 2-5/6 or 17/6cm Then the third side will be =43/4-34/6 =(258-136)/24 =122/24 =5-1/12cm.
|
|
| 2. |
. In a class of 60 students 22 take table tennis, 32 take karate, and 4 take both. How manystudents in the class have not enrolled in any of these two?A)10 B)15 c)12 D)8 |
|
Answer» C is the answer Mark as BRAINLEST |
|
| 3. |
If 1/a+1/b+1/c =0then a^2+b^2+c^2= |
|
Answer» now, 1/a²+b²+c² + 1/b²+c²-a² + 1/c²+a²-b² =1/a²+(b+c)(b-c) + 1/b²+(c+a)(c-a) + 1/c²+(c+b)(a-b) =1/a²+(-a)(b-c) + 1/b²+ (-b)(c-a) + 1/c²+ (-c)(a-b) (from 1) =1/a(a-b+c) + 1/b(a+b-c) = 1/c(c-a+b) =1/a(a+c-b) + 1/b(a+b-c) + 1/c(b+c-a) =1/a(-b-b) + 1/b(-c-c) + 1/ c (-a-a) (from 1) =1/-2ab + 1/-2bc + 1/-2ac = 1/-2 (1/ab + 1/bc+ 1/ac ) = -1/2 (a+b+c/abc) =-1/2 (0) (from 1) = 0 |
|
| 4. |
What is the minimum number of cuts required to cut a cube into 50 identical pieces?Select one:a. 10b. 9c. 8d. 7 |
|
Answer» B. 9 Step-by-step EXPLANATION: this is CORRECT answer |
|
| 5. |
What is the minimum number of cuts required to cut a cube into 24 identical pieces?Select one:a. 6b. 4c. 5d. 3 |
| Answer» | |
| 7. |
13,169,7, 49,4,16 next number |
|
Answer» Answer: 2.5,6.25 Step-by-step explanation: 13,(13*13),(13+1)/2,the answer will be 7 ,then (7*7) (7+1)/2;the answer will be 4 ,(4*4), NEXT, (4+1)/2 ; answer will be 2.5 then (2.5 *2.5) |
|
| 8. |
. सिद्ध कीजिए कि 3-3 एक परिमेय संख्या नहीं है। |
|
Answer» SORRY maths hindi me ni aata h English me aata h krepa English me LIKHE |
|
| 9. |
Square root of 390625 by long division |
|
Answer» Answer: 625 Step-by-step explanation: 390625 .... LAST to digits are 25 hence _ _ 5 it can be solution first to NUMBER are 62 because 62×63=3906 eg. square of 35 last digit is five so square can be _ _ 25 first digit is 3 ..... then 3×4 =12 square=1225 Similarly for 625 62×63 =3906 last digit is 5 SQuare=390625 |
|
| 10. |
Find the area of triangle by joining the points (2,3),(6,3),(4,7) |
|
Answer» Step-by-step explanation: area of TRIANGLE = 1/2|x1(y2-y3)+x2(y3-Y1)+X3(y1-y2)| where (x1,y1) (x2,y2) (x3,y3) are the points JOINED to FORM triangle substitute and get the answer |
|
| 11. |
रतन का व्यय 5:1 के अनुपात में है। यदिउसका वेतन 25:/. बढ़ा दिया प्यार और बग्त15-/तो उसके यय मे प्रतिशत हदि है |
| Answer» | |
| 12. |
What is the length L2, if total length (L) is 2.75 metre and L1:L2 = 2:37 |
Answer» HEY MATE HOPE it HELPS you...L1/L2 = 2/37 2.75/ L2 = 2/37 2L2 = 37×2.75 2L2 = 101.75 L2 = 101.75/2 = 50.875 m |
|
| 13. |
Find the cost of 3 2/5metres of cloth at 36 3/4 per metre. |
|
Answer» Step-by-step explanation: Length \: of \: cloth = 3\frac{2}{5} m \\ = \frac{3 \times 5 + 2}{5} \\ = \frac{15 + 2}{5} \\ = \frac{17}{5} \: m \\ COST \: of \: cloth \: = 36 \frac{3}{4} m \\ = \frac{36 \times 4 + 3}{4} \\ = \frac{144 + 3}{4} \\ = \frac{147}{4} Rs. \: per \: METRE \\ now \: cost \: of \: \frac{17}{5} \: m \: = \frac{17}{5} \times \frac{147}{4} \\ = Rs \frac{2499}{20} = Rs \: 124 \frac{19}{20} |
|
| 14. |
Please answer this math question asap!!! 30 points and brainliest!! Only brainliest IF YOU SHOW YOUR WORK!! thank you! Round the final answer to the nearest tenth of a metre.Before you start!!! Test your calculator to make sure it is in degrees. Find sine of 90, if it equals 1you are ready to start. If it does not equal 1, you are in radians and must switch to degrees. |
|
Answer» Answer: CHECK the ATTACHMENT for the COMPLETE answer.. hope this helps you... |
|
| 15. |
Whole numbers are closed under _&_option |
|
Answer» ADDITION and multiplication Step-by-step EXPLANATION: |
|
| 16. |
There are 259 questions in an examination on each right answer a student get 3 marks and on each wrong answer. 0.5 marks deducted Find the number of wrong questions answered by him, if in whole exam he get 477 marks? |
|
Answer» I THINK .... QUESTION is just WRONG...it should be 476...then.... 173 right ANS ×3=519 86 wrong ans×0.5=43 519-43=476 86(Ans) |
|
| 17. |
write the smallest and greatest 6 digit numbers formed by using digits 1,0,5,7 with repetition then find their sum |
|
Answer» Answer: 000000001 77777777777777777 |
|
| 18. |
What us thedomain andrange ofafunction ? |
|
Answer» DOMAIN : x^2 + 1 >/ 0 x^2>/ -1 therefore domain of x is real numbers range : as x can be any real number range of F(x) is R-{0} |
|
| 19. |
4/5+1/5÷1/3 का1/5=? |
|
Answer» Answer: 4/5+1/5×3×1/5 4/5+3/5×1/5 4/5+3/25 20+3/25 23/25 ANS. |
|
| 20. |
11 X square + 18 x + 7 factorise |
|
Answer» 11x² + 18x + 7 = 11x(x + 1) + 7(x + 1) = (11x + 7)(x + 1) |
|
| 22. |
Find two integers whose sum is 16 and product is 55 |
|
Answer» Since the sum of the two numbers is 16, let ONE AMONG them be Given that their product is 55. Then, If If However, |
|
| 23. |
Two blocks A and B of same masses attatched with a light spring are suspended by a string as shown in figure .Find the acceleration of block A and block B just after cut the string . |
Answer» Answer :-To Find :-→ Acceleration of block "A" and "B" . Explanation:-According to the question - → Mass of both blocks is same . (1) Before cut the string ( refer to attachment ) Before cut the string TENSION (T) , spring force (kx) and gravitational force (mg) is working on block "A" , Before cut the string there is no acceleration in both blocks . hence , → T - kx - mg = 0 .....eq.(1) ( on block A) and , → kx - mg = 0 ( on block B) → kx = mg [ put in eq.(1) ]→ T - mg - mg = 0 → T = 2mgnow, (2) Just after cut the string ( refer to the attachment ) After cutting the string these is Acceleration in both block .( After cut the string Tension is REMOVED on block "A" ) hence , • On block "B"• On block "A"Note - After cut the string these is no normal CONTACT force .( so NEGLECT it ) |
|
| 24. |
Place value of 6 in the following(1) 69(2) 76 |
|
Answer» Answer: |
|
| 25. |
If a-b = -1 and a-b = -12 ,find a^3 - b^3 |
|
Answer» Answer: Step-by-step explanation: Before going into a representation of the decimal expansion of rational numbers, let US UNDERSTAND what rational numbers are. Any number that can be REPRESENTED in the form of p/q, such that p and q are integers and q ≠ 0 are known as rational numbers. So when these numbers have been simplified further, they result in decimals. Let us LEARN here how to expand such decimals. EXAMPLES: 6,−8.1,45 etc. are all examples of rational numbers. |
|
| 26. |
an envelope from the post office is 3 inches wide with a total area of 30 square inches what is the height of the envelope |
|
Answer» Answer: 10 inches Step-by-step EXPLANATION: 30sq inches= h*3 h = 30/3 h = 10 inches |
|
| 29. |
Verify a+(b)= a+b tor each for the following value a & ba=32,b=18a=275,b=112 a=78,b=84a=195,b=27a=64,b=36 |
|
Answer» Answer: it's done the answer Step-by-step explanation: 1.32+18=32+18 50.=50 2.275+112=275+112 387. =387. 3.78+84=78+84 162. = 162 4.195+27=195+27 222. =222 5.64+36=64+36 100 =100. |
|
| 31. |
How many different triangles can you make if you are given these three lengths for sides A17. b23. c13 |
|
Answer» Answer: 4 Step-by-step EXPLANATION: |
|
| 33. |
एक कार्य 40 दिनों में पूरा करना था तथा इसके लिए 24 आदमी काम पर लगाये गये 28 दिनों के बाद 11 आदमी और काम पर लगा दिए गये।और काम निश्चित समय पर समाप्त हो गया। यदि अतरिक्त आदमी काम पर नही लगाये गये होते ।तो काम कितने दिन विलम्ब से समाप्त होता। |
|
Answer» Answer: Step-by-step explanation: एक दिन। मान लीजिए 1 आदमी 1 दिन में 1 यूनिट काम कर सकता है 25 दिन = 750 इकाई में 30 पुरुषों द्वारा किया गया कार्य काम कुल 37 दिनों में पूरा हो जाता है। इसलिए 35 आदमियों ने 12 और दिनों के लिए काम किया 35 * 12 = 420 यूनिट अब क्या होगा अगर 5 अतिरिक्त पुरुषों को रोजगार नहीं मिलेगा, 420 इकाइयों (420/30) को पूरा करने में 30 पुरुषों को 14 दिन लगेंगे 30 पुरुषों को 25 + 14 = 39 दिन लगते हैं। वे 38 दिनों में काम करने वाले थे। तो काम में 1 दिन की देरी हो जाती। ek din. maan leejie 1 aadamee 1 din mein 1 yoonit kaam kar sakata hai 25 din = 750 ikaee mein 30 purushon dvaara kiya gaya kaary kaam kul 37 dinon mein poora ho jaata hai. isalie 35 aadamiyon NE 12 aur dinon ke lie kaam kiya 35 * 12 = 420 yoonit ab kya hoga agar 5 atirikt purushon ko rojagaar NAHIN milega, 420 ikaiyon (420/30) ko poora karane mein 30 purushon ko 14 din lagenge 30 purushon ko 25 + 14 = 39 din lagate HAIN. ve 38 dinon mein kaam karane vaale the. to kaam mein 1 din kee deree ho jaatee. |
|
| 34. |
Minus a minus b ples c whole square |
|
Answer» Step-by-step EXPLANATION: |
|
| 35. |
Solve this with details |
|
Answer» answer is 524.94 pls MARK as BRAINLIEST |
|
| 36. |
If 4x² - 6x - m is divisible by x-3 , the value of m is |
|
Answer» If this SOLUTION REALLY HELPS you Than plz Mark me as brainliest plz And if u want to FOLLOW than follow me |
|
| 37. |
Verify the following:1. -2{-1(1 - 4) + 2(4-2) + 3(2-1)} + 3{5(-3+5) - 9(-5-2)-3(2+3)} = 154 |
|
Answer» Step-by-step explanation: solution:--2{-1(1-4)+2(4-2)+3(2-1)}+3{5(-3+5)-9(-5-2)-3(2+3)} =-2{-1*(-3)+2*(2)+3*(1)}+3{5*(2)-9*(-7)-3*(5)} =-2{3+4+3}+3{10+63-15} =-2*{10}+3*{73-15} =-20+3*{58} =-20+174 =154 verified. I hope it HELPS youPlz......... mark brainliest |
|
| 38. |
What has the same value as 75% of 90 |
|
Answer» Answer: 25% 0F 270 Step-by-step EXPLANATION: |
|
| 39. |
Tell the Roman numbers of :- 1)1277532)447283)1170 4)9026584 |
|
Answer» Answer: 1 - MCCLXXVIILIII 2 - CDXLVIIXXVIII 3 - |
|
| 40. |
Simplify by expanding brackets:(i) 597 +(23x17) |
|
Answer» 988 Step-by-step EXPLANATION: the answer is GIVEN above |
|
| 41. |
The Sum Of Digits In The Units Place Of All The 4 Digits Numbers Formed By Using The Digits 3,4,5,6,7 Is |
|
Answer» I can't UNDERSTAND ur question BRO |
|
| 42. |
രണ്ടു കുട്ടം പക്ഷികൾ എതിരെ പറന്നു വന്നു ഒരു കുട്ടത്തിലെ നേതാവ് പറഞ്ഞു നിങ്ങളുടെ കുട്ടത്തിൽ നിന്നു ഒരാൾ ഇങ്ങോട്ട് വന്നാൽ നമ്മുടെ എണ്ണം പരസ്പരം തുല്യമാകും ഇതു കേട്ട് രണ്ടാമത്തെ കുട്ടത്തിലെ നേതാവ് പറഞ്ഞു നിങ്ങളുടെ ഒരാൾ ഇങ്ങോട്ട് വന്നാൽ നിങ്ങളുടെ ഇരട്ടി ആകും ഞങ്ങൾ ഇരു കുട്ടത്തിലെ യും പക്ഷി കളുടെ എണ്ണം എത്ര...???? |
| Answer» | |
| 43. |
Calculate the amount and the compound intrest on₹2500 for 2 years at 8%p.a.,compounded anually |
|
Answer» R= 8% T=2 YEARS. A= P(1+R/100)² 2500(100+8/100)² 2500×108/100×108/100 29160000/10000 =2916 C.i = AMOUNT- principal 2916 - 2500 = 416..... And 416 |
|
| 44. |
Find the square root of 0.00053361 step by step by this method |
|
Answer» Answer: LONG Division Method Hope this HELPS you Mark as BRAINLIEST answer PLEASE |
|
| 45. |
Find the smallest number which when divided by 6 ,7 ,4 leaves a remainder of 3 in each case. |
|
Answer» HOPE it helpful Please MARKS as brainlist answer |
|
| 46. |
if a number is selected from first 50 natural numbers what is the probability it is multiple of 3 and 4 |
|
Answer» Answer: = > 0.08 Step-by-step explanation: => Numbers Which is a multiple Of Both 3 and 4 => It MEANS LCM of 3 and 4 = 12 => Multiple of 12 in FIRST 50 natural Numbers. Numbers are 12 , 24 , 36 , 48 Total Event = 50 Favorable event = 4 P(Multiple 3 and 4) = Favorable Event/Total Event => 4/50 => 0.08 |
|
| 48. |
Plz answer this question fast |
|
Answer» |
|
| 49. |
2.Findtheproduct bysuitablerearrangement:125×40×8×25. |
|
Answer» Answer: Step-by-step explanation: 125×40×8×25 = (125×8)×(40×25) = (1000)×(1000) = 1000000 |
|