332354 + Interview Questions in Secondary School in Math

1.	In how many ways can a starting team of 5 players be chosen from a team of 14 players
Answer» Answer: 2002 Step-by-step EXPLANATION: It's a problem releted to COMBINATION It's GIVEN by 14C5 14!/5!*9!

1.

In how many ways can a starting team of 5 players be chosen from a team of 14 players

Answer»

Answer:

2002

Step-by-step EXPLANATION:

It's a problem releted to COMBINATION

It's GIVEN by 14C5

14!/5!*9!

Discussion

2.	Show that sin^2(45)-sin^2(15) =root 3/4
Answer» ANSWER: $clearly \: \\ { \sin(45) }^{2} - { \sin(15) }^{2} = \sqrt{ \frac{3}{4} } \\ { \ - sin(15) }^{2} = \sqrt{ \frac{3}{4} } - { \sin(45) }^{2} \\ { \sin(15) }^{2} = \frac{1}{ { \sqrt{2} }^{2} } - \sqrt{ \frac{3}{4} } \\ { \sin(15) }^{2} = \frac{1}{2} - \ \frac{ \sqrt{3} }{2} \\ \sin(15) = \sqrt{ \frac{1 - \sqrt{3} }{2} } \\$

2.

Show that sin^2(45)-sin^2(15) =root 3/4

Answer»

ANSWER:

$clearly \: \\ { \sin(45) }^{2} - { \sin(15) }^{2} = \sqrt{ \frac{3}{4} } \\ { \ - sin(15) }^{2} = \sqrt{ \frac{3}{4} } - { \sin(45) }^{2} \\ { \sin(15) }^{2} = \frac{1}{ { \sqrt{2} }^{2} } - \sqrt{ \frac{3}{4} } \\ { \sin(15) }^{2} = \frac{1}{2} - \ \frac{ \sqrt{3} }{2} \\ \sin(15) = \sqrt{ \frac{1 - \sqrt{3} }{2} } \\$

Discussion

3.	A certain job was assigned to a group of men to be completed in 20 days. But 12 men did not turn up for the job and theremaining men completed the job in 32 days. What was the original number of men in the group?optionsA 32B 34C 36D 40
Answer» Answer: 32 Step-by-step EXPLANATION: Is a ALWAYS correct person then i am SURE but i dont do on the QUESTION on rough

3.

A certain job was assigned to a group of men to be completed in 20 days. But 12 men did not turn up for the job and theremaining men completed the job in 32 days. What was the original number of men in the group?optionsA 32B 34C 36D 40

Answer»

Answer:

32

Step-by-step EXPLANATION:

Is a ALWAYS correct person then i am SURE but i dont do on the QUESTION on rough

Discussion

4.	In a sports academy, out of 40 students, 15 students do not play badminton, 30 students play football and 5 students donot play either. How many students in the academy play both the sports?optionsA 15B 20C 25D none of the above
Answer» Answer: 20 Step-by-step explanation: total 40 students 5 dont play either ==> 35 play ATLEAST one game 15 dont play badminton ==> 25 play badminton 30 play foot ball so from the information who play both were = ( badminton + football ) - ( atleast one game ) = 25+30-35 = 20

4.

In a sports academy, out of 40 students, 15 students do not play badminton, 30 students play football and 5 students donot play either. How many students in the academy play both the sports?optionsA 15B 20C 25D none of the above

Answer»

Answer:

20

Step-by-step explanation:

total 40 students

5 dont play either ==> 35 play ATLEAST one game

15 dont play badminton ==> 25 play badminton

30 play foot ball

so from the information who play both were = ( badminton + football ) - ( atleast one game )

= 25+30-35

= 20

Discussion

5.	620 ÷ 999 = 0.620620620621 ÷ 670 = 0.000926299433762 × 80 = ??
Answer» $\text{[math]}$ $\huge0.0741039547$

5.

620 ÷ 999 = 0.620620620621 ÷ 670 = 0.000926299433762 × 80 = ??

Answer»

$\text{[math]}$

$\huge0.0741039547$

Discussion

6.	Question # 3The sides of a triangular field are 2646 m. 5157 m, and 5634 m in length. What is the greatest length of the tape bywhich the three sides may be measured completely?A 9mB 7mC 12mD 8mE none of the above
Answer» The ANSWER is this So basically you have to find the HCF of the three numbers. As we have options here we can see that one of the numbers is odd. So we can rule out 12 and 8. That LEAVES 9 and 7. As we can see all the numbers are divisible by nine. Therefore, our answer is 9. Pls mark as BRAINLIEST.

Discussion

7.	An art teacher had 57 grams of blue clay. She combined it with 31 grams of yellow clay to make green clay. She let students use the green clay during the week. At the end of the week, the remaining green clay weighed 18 grams.Estimate how many grams of green clay students used during the week.
Answer» $\huge{\red {\mathfrak{Question :-}}}$ An ART teacher had 57 grams of blue clay. She combined it with 31 grams of yellow clay to make green clay. Lets STUDENTS USE the green clay during the week. At the end of the week, the remaining green clay WEIGHED 18 grams. Estimate how many grams of green clay used during the week. $\huge{\red {\mathfrak{Solution :-}}}$ $\underline{\bold {Given:}}$ Quantity of blue clay = 57 grams Quantity of yellow clay = 31 grams Quantity of remaining green clay =18 grams $\underline{\bold {To\:Find:}}$ Quantity of green clay used during the week $\bf{Combining\: of\: blue\: clay\: and \:yellow}\\ {\bf {clay\: to\: make\: green\: clay\: means \:we\: add}} \\{\bf {Quantity\: of \:blue\: clay \:and \:Quantity}}\\{\bf {of\:yellow \:clay.}}$ $\hookrightarrow{\sf{Quantity \:of \: green \: clay = (57 + 31)\:grams = 88 \: grams}}$ $\longrightarrow {\sf {Quantity \: of green \: clay \: used \: during \: the \: week = (88 - 18) \: grams}} \\ \\ \longrightarrow {\sf {Quantity \: of green \: clay \: used \: during \: the \: week = 70 \: grams}}$ $\green {\tt {\therefore{Quantity \: of green \: clay \: used \: during \: the \: week = 70 \: grams.}}}$ $\rule {307}{2}$

7.

An art teacher had 57 grams of blue clay. She combined it with 31 grams of yellow clay to make green clay. She let students use the green clay during the week. At the end of the week, the remaining green clay weighed 18 grams.Estimate how many grams of green clay students used during the week.

Answer»

$\huge{\red {\mathfrak{Question :-}}}$

An ART teacher had 57 grams of blue clay. She combined it with 31 grams of yellow clay to make green clay. Lets STUDENTS USE the green clay during the week. At the end of the week, the remaining green clay WEIGHED 18 grams. Estimate how many grams of green clay used during the week.

$\huge{\red {\mathfrak{Solution :-}}}$

$\underline{\bold {Given:}}$

Quantity of blue clay = 57 grams
Quantity of yellow clay = 31 grams
Quantity of remaining green clay =18 grams

$\underline{\bold {To\:Find:}}$

Quantity of green clay used during the week

$\bf{Combining\: of\: blue\: clay\: and \:yellow}\\ {\bf {clay\: to\: make\: green\: clay\: means \:we\: add}} \\{\bf {Quantity\: of \:blue\: clay \:and \:Quantity}}\\{\bf {of\:yellow \:clay.}}$

$\hookrightarrow{\sf{Quantity \:of \: green \: clay = (57 + 31)\:grams = 88 \: grams}}$

$\longrightarrow {\sf {Quantity \: of green \: clay \: used \: during \: the \: week = (88 - 18) \: grams}} \\ \\ \longrightarrow {\sf {Quantity \: of green \: clay \: used \: during \: the \: week = 70 \: grams}}$

$\green {\tt {\therefore{Quantity \: of green \: clay \: used \: during \: the \: week = 70 \: grams.}}}$

$\rule {307}{2}$

Discussion

8.	What is the first step to evaluate 44 - 4 × 10Choose 1 answer:A: 4 × 10B: 44 - 10C: 44 - 4
Answer» A. 4 X 10 hope this answer will be HELPFUL to you DEAR. . . . . . . . please mark me as a brainliest.........xD

8.

What is the first step to evaluate 44 - 4 × 10Choose 1 answer:A: 4 × 10B: 44 - 10C: 44 - 4

Answer»

A. 4 X 10

hope this answer will be HELPFUL to you DEAR.

.

please mark me as a brainliest.........xD

Discussion

9.	From a selection of 9 different colored notebooks, Tom can take a group of 3. How many groups of 3did he have to choose from if repetition is allowed?
Answer» 3 groups. hope this answer will be helpful to you DEAR. . . . . PLEASE MARK me as a BRAINLIEST.......xD

9.

From a selection of 9 different colored notebooks, Tom can take a group of 3. How many groups of 3did he have to choose from if repetition is allowed?

Answer»

3 groups.

hope this answer will be helpful to you DEAR.

.

PLEASE MARK me as a BRAINLIEST.......xD

Discussion

10.	How would one do this?Write the smaller solution first, then the larger second.g(x)=7x^{2}-567
Answer» ANSWER: G(x) = 7x^2 - 567 LET g(x) = 0 7x^2-567 =0 7x^3=567 x^2=567/7 x^2=81 x= 9

10.

How would one do this?Write the smaller solution first, then the larger second.g(x)=7x^{2}-567

Answer»

ANSWER:

G(x) = 7x^2 - 567

LET g(x) = 0

7x^2-567 =0

7x^3=567

x^2=567/7

x^2=81

x= 9

Discussion

11.	A surveyor stands 185 feet from the base of a bluff and measures an elevation angle of 56.8 °. The level of your eyesIt is 6 feet from the floor. What is the height of the bluff rounded to the nearest foot?
Answer» Answer: Step-by-step explanation: Classity each angle as an angle of elevation or an angle of depression. 1. 21. 2. 22 ... a shadow that is 9 METERS long What is the height of the tree? Round to the ... eye level is 3 feet above the pier He is using binoculars to WATCH a ... is the whale from Kyle's binoculars? Round to the nearest TENTH foot tan(52) - Ă X=11.5m. X.

11.

A surveyor stands 185 feet from the base of a bluff and measures an elevation angle of 56.8 °. The level of your eyesIt is 6 feet from the floor. What is the height of the bluff rounded to the nearest foot?

Answer»

Answer:

Step-by-step explanation:

Classity each angle as an angle of elevation or an angle of depression. 1. 21. 2. 22 ... a shadow that is 9 METERS long What is the height of the tree? Round to the ... eye level is 3 feet above the pier He is using binoculars to WATCH a ... is the whale from Kyle's binoculars? Round to the nearest TENTH foot tan(52) - Ă X=11.5m. X.

Discussion

12.	A 4-pack of key chanins costs $11.32 what is the unit price
Answer» ANSWER: it's $11.32+4=$2.83 PER unit Step-by-step EXPLANATION: MARK BRAINLIEST

12.

A 4-pack of key chanins costs $11.32 what is the unit price

Answer»

ANSWER:

it's $11.32+4=$2.83 PER unit

Step-by-step EXPLANATION:

MARK BRAINLIEST

Discussion

13.	Bala had 240 cards and Tom had 780 cards.After Tom gave some cards to Bala, Bala had twice as manycards as Tom.How many cards did Tom give to Bala?
Answer» Answer: 240 Step-by-step EXPLANATION: Tom's SHARE increased from 120 to 360 marbles. ... Aza and Bala had an equal number of stickers at first. ... Joe, Alex and Sean shared some stamps in"the RATIO 3 ' 6 : 5. ... If she gives 5 cupcakes to each of her puplls, she will ... 16U -- 16x15 = 240 picture cards·.

13.

Bala had 240 cards and Tom had 780 cards.After Tom gave some cards to Bala, Bala had twice as manycards as Tom.How many cards did Tom give to Bala?

Answer»

Answer:

240

Step-by-step EXPLANATION:

Tom's SHARE increased from 120 to 360 marbles. ... Aza and Bala had an equal number of stickers at first. ... Joe, Alex and Sean shared some stamps in"the RATIO 3 ' 6 : 5. ... If she gives 5 cupcakes to each of her puplls, she will ... 16U -- 16x15 = 240 picture cards·.

Discussion

14.	Mr Hassan gave his year seven class a test on Friday the highest possible mark for the test was 10 How many pupils scored more than 8
Answer» Given : Mr Hassan gave his year seven class a test on Friday the highest POSSIBLE mark for the test was 10 . To find : How many pupils scored more than 8 Solution: From The Graph Score Number of pupils 0 0 1 3 2 5 3 0 4 2 5 6 6 0 7 0 8 12 9 1 10 4 Total Pupils = 33 pupils scored more than 8 Means pupils scored 9 & 10 = 1 + 4 = 5 5 pupils scored more than 8 Learn more: 4. Draw Bar graph for the following data:Months July August ... brainly.in/question/13750255 Prepare a bar graph showing SHARE of thermal, nuclear, hydro and ... brainly.in/question/18269671

14.

Mr Hassan gave his year seven class a test on Friday the highest possible mark for the test was 10 How many pupils scored more than 8

Answer»

Given : Mr Hassan gave his year seven class a test on Friday the highest POSSIBLE mark for the test was 10 .

To find : How many pupils scored more than 8

Solution:

From The Graph

Score Number of pupils

0 0

1 3

2 5

3 0

4 2

5 6

6 0

7 0

8 12

9 1

10 4

Total Pupils = 33

pupils scored more than 8

Means pupils scored 9 & 10 = 1 + 4 = 5

5 pupils scored more than 8

Learn more:

4. Draw Bar graph for the following data:Months July August ...

brainly.in/question/13750255

Prepare a bar graph showing SHARE of thermal, nuclear, hydro and ...

brainly.in/question/18269671

Discussion

15.	What is the first 25 numbers of pi?
Answer» ANSWER: HEY .. 3.1415234965872513584976344 hope it HELPS..

15.

What is the first 25 numbers of pi?

Answer»

ANSWER:

HEY ..

3.1415234965872513584976344

hope it HELPS..

Discussion

16.	What is x=12+13 can you help me on this please
Answer» ANSWER: X = 14 Step-by-step explanation: 12 +13 = 14 and x is COMMON

16.

What is x=12+13 can you help me on this please

Answer»

ANSWER:

X = 14

Step-by-step explanation:

12 +13 = 14 and x is COMMON

Discussion

17.	Prove that cos(60+A) +cos(60-A)=cosA
Answer» ANSWER: Step-by-step explanation: I assume the problem involves proving the identity. If so, we PROCEED as FOLLOWS: Using TRIG identities, we can write cos(60 +A)+cos(60 -A)-cosA =

17.

Prove that cos(60+A) +cos(60-A)=cosA

Answer»

ANSWER:

Step-by-step explanation:

I assume the problem involves proving the identity. If so, we PROCEED as FOLLOWS: Using TRIG identities, we can write cos(60 +A)+cos(60 -A)-cosA =

Discussion

18.	A bell tolls at a regular interval of 20 minutes. A second bell tolls ata regular interval of 50 minutes. They toll together at 3 p.m. At whattime will they next toll together
Answer» ANSWER: The answer is 6:20pm i THINK

18.

A bell tolls at a regular interval of 20 minutes. A second bell tolls ata regular interval of 50 minutes. They toll together at 3 p.m. At whattime will they next toll together

Answer»

ANSWER:

The answer is 6:20pm i THINK

Discussion

19.	Un agrimensor se para a 185 pies de la base de un risco y mide un ángulo de elevación de 56.8°. EI nivel de sus ojosestá a 6 pies del piso. ¿Cuál es la altura del risco redondeada al pie más cercano?
Answer» Answer: 43,30 metros Step-by-step explanation: Si el acantilado forma un ángulo de 60° CON el suelo horizontal,¿cuál es la altura del acantilado? ... Si vemos la imagen la distancia del topógrafo a la base representa la ... La altura del acantilado es de 43,30 metros ... de costo de un PAR de zapatos es $33, ¿qué precio SE debe de fijar para su venta, si se ...

19.

Un agrimensor se para a 185 pies de la base de un risco y mide un ángulo de elevación de 56.8°. EI nivel de sus ojosestá a 6 pies del piso. ¿Cuál es la altura del risco redondeada al pie más cercano?

Answer»

Answer:

43,30 metros

Step-by-step explanation:

Si el acantilado forma un ángulo de 60° CON el suelo horizontal,¿cuál es la altura del acantilado? ... Si vemos la imagen la distancia del topógrafo a la base representa la ... La altura del acantilado es de 43,30 metros ... de costo de un PAR de zapatos es $33, ¿qué precio SE debe de fijar para su venta, si se ...

Discussion

20.	Logical questions please answer soon
Answer» Answer: hey .. the ANS . is OPTION 2 hope it helps

20.

Logical questions please answer soon

Answer»

Answer:

hey ..

the ANS . is OPTION 2

hope it helps

Discussion

21.	What is 5² × 96 + 54 - 60 ÷ 3
Answer» $\huge{\fbox{\fbox{\bigstar{\orange{\mathfrak{Answer::}}}}}}$ $==》25 × 96 + 54 - 60 ÷ 3$ $==》2400 + 54 - 20$ $==》2434[Answr.]$ $\small{\blue{@being_SaRcAsTiC}}$

21.

What is 5² × 96 + 54 - 60 ÷ 3

Answer»

$\huge{\fbox{\fbox{\bigstar{\orange{\mathfrak{Answer::}}}}}}$

$==》25 × 96 + 54 - 60 ÷ 3$

$==》2400 + 54 - 20$

$==》2434[Answr.]$

$\small{\blue{@being_SaRcAsTiC}}$

Discussion

22.	6 ÷ 32 x 1.75 × 500 = ??
Answer» Answer: 6 ÷ 32 X 1.75 × 500 = 16.40625.

22.

6 ÷ 32 x 1.75 × 500 = ??

Answer»

Answer:

6 ÷ 32 X 1.75 × 500 = 16.40625.

Discussion

23.	Evaluate 4‾³ x a‾5 x b‾⁴ /4‾⁵ x a‾⁸ x b‾³
Answer» ANSWER: =1/64×455×55 ×445 =567

23.

Evaluate 4‾³ x a‾5 x b‾⁴ /4‾⁵ x a‾⁸ x b‾³

Answer»

ANSWER:

=1/64×455×55

×445

=567

Discussion

24.	Find the 52nd term of the arithmetic sequence 5, 9, 13, ...5,9,13,...
Answer» Answer: 209. Step-by-step explanation: Here, First term of the AP is 5. Common difference is 13 - 9 = 9 - 5 = 4. From the properties of AP : nth term = a + ( N - 1 )d, where a is the first term and d is the common difference Here, we have to find the 52TH term, it means here we have to substitute n as 52. ⇒ 5 + ( 52 - 1 )4 ⇒ 5 + ( 51 )4 ⇒ 5 + 204 ⇒ 209 Hence 52 th term of the AP is 209.

24.

Find the 52nd term of the arithmetic sequence 5, 9, 13, ...5,9,13,...

Answer»

Answer:

209.

Step-by-step explanation:

Here,

First term of the AP is 5.

Common difference is 13 - 9 = 9 - 5 = 4.

From the properties of AP :

nth term = a + ( N - 1 )d, where a is the first term and d is the common difference

Here, we have to find the 52TH term, it means here we have to substitute n as 52.

⇒ 5 + ( 52 - 1 )4

⇒ 5 + ( 51 )4

⇒ 5 + 204

⇒ 209

Hence 52 th term of the AP is 209.

Discussion

25.	The function :f R → R , defined by )x(f = x x , is an odd functio
Answer» Answer: The FUNCTION will be ODD if F(-x) = -f(x) for example f(x) = sin x if x= -x then f(-x) = -sin x

25.

The function :f R → R , defined by )x(f = x x , is an odd functio

Answer»

Answer:

The FUNCTION will be ODD if F(-x) = -f(x)

for example

f(x) = sin x

if x= -x then

f(-x) = -sin x

Discussion

26.	Fiona wrote the linear equation y = x – 5. When Henry wrote his equation, they discovered that his equation had all the same solutions as Fiona’s. Which equation could be Henry’s?
Answer» Step-by-step EXPLANATION: $y = x - 5$ $= x = - 5y$ THEREFORE, ANSWER is this.

26.

Fiona wrote the linear equation y = x – 5. When Henry wrote his equation, they discovered that his equation had all the same solutions as Fiona’s. Which equation could be Henry’s?

Answer»

Step-by-step EXPLANATION:

$y = x - 5$

$= x = - 5y$

THEREFORE, ANSWER is this.

Discussion

27.	A shipping container is in the shape of a right rectangular prism with a length of 4 feet, a width of 3 feet, and a height of 1 feet. The container is completely filled with contents that weigh, on average, 0.52 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?
Answer» ANSWER: AROUND 6pounds Step-by-step explanation: 4x3x1 = 12 cubic feet 12 X 0.52 POUND = 6.24 POUNDS

27.

A shipping container is in the shape of a right rectangular prism with a length of 4 feet, a width of 3 feet, and a height of 1 feet. The container is completely filled with contents that weigh, on average, 0.52 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?

Answer»

ANSWER:

AROUND 6pounds

Step-by-step explanation:

4x3x1 = 12 cubic feet

12 X 0.52 POUND = 6.24 POUNDS

Discussion

28.	The dergee−4t 2+2t 3
Answer» Answer: 3 Step-by-step explanation: The provided polynomial is t-4t^2+2t^3. The largest EXPONENT of the EQUATION is a DEGREE in a polynomial FUNCTION.

28.

The dergee−4t 2+2t 3

Answer»

Answer:

3

Step-by-step explanation:

The provided polynomial is t-4t^2+2t^3. The largest EXPONENT of the EQUATION is a DEGREE in a polynomial FUNCTION.

Discussion

29.	Oh god this math is always my brain wash you can help me
Answer» ANSWER: whoa Step-by-step EXPLANATION:

29.

Oh god this math is always my brain wash you can help me

Answer»

ANSWER:

whoa

Step-by-step EXPLANATION:

Discussion

30.	Plz solve this question I will not only mark u brainliest also follow u plzzz please please please please please
Answer» ANSWER: SORRY but I don't KNOW this

30.

Plz solve this question I will not only mark u brainliest also follow u plzzz please please please please please

Answer»

ANSWER:

SORRY but I don't KNOW this

Discussion

31.	How many cubes with side lengths of \dfrac14\text{ cm}41 cmstart fraction, 1, divided by, 4, end fraction, start text, space, c, m, end text does it take to fill the prism?
Answer» ★ Correct question : How many cubes with SIDE LENGTHS of 1/4 cm needed to FILL the prism of volume 4 cubic UNITS? $\rule{200}{1}$ ☯ Given : Volume of prism = 4 cubic units Side lengths of CUBE = 1/4 $\rule{200}{1}$ ☯ Solution : We know that, $\Large{\implies{\boxed{\boxed{\sf{Volume = a^3}}}}}$ Where, a is the side of the cube $\sf{\dashrightarrow Volume = \bigg(\dfrac{1}{4}\bigg)^3} \\ \\ \sf{\dashrightarrow Volume = \frac{1}{64}} \\ \\ \sf{\dashrightarrow Volume = 0.015625} \\ \\ \Large{\implies{\boxed{\boxed{\sf{Volume = 0.015625 \: unit^3}}}}}$ $\rule{200}{2}$ Now, As, we have to find the number if cubes so we will devide volume of prism by volume of one cube $\small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{Volume \: of \: prism} {Volume \: of \: cube}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{4}{0.015625}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = 256}}$ $\small{\implies{\boxed{\boxed{\sf{No. \: of \: cubes = 256}}}}}$

31.

How many cubes with side lengths of \dfrac14\text{ cm}41 cmstart fraction, 1, divided by, 4, end fraction, start text, space, c, m, end text does it take to fill the prism?

Answer»

★ Correct question :

How many cubes with SIDE LENGTHS of 1/4 cm needed to FILL the prism of volume 4 cubic UNITS?

$\rule{200}{1}$

☯ Given :

Volume of prism = 4 cubic units

Side lengths of CUBE = 1/4

$\rule{200}{1}$

☯ Solution :

We know that,

$\Large{\implies{\boxed{\boxed{\sf{Volume = a^3}}}}}$

Where,

a is the side of the cube

$\sf{\dashrightarrow Volume = \bigg(\dfrac{1}{4}\bigg)^3} \\ \\ \sf{\dashrightarrow Volume = \frac{1}{64}} \\ \\ \sf{\dashrightarrow Volume = 0.015625} \\ \\ \Large{\implies{\boxed{\boxed{\sf{Volume = 0.015625 \: unit^3}}}}}$

$\rule{200}{2}$

Now,

As, we have to find the number if cubes so we will devide volume of prism by volume of one cube

$\small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{Volume \: of \: prism} {Volume \: of \: cube}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{4}{0.015625}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = 256}}$

$\small{\implies{\boxed{\boxed{\sf{No. \: of \: cubes = 256}}}}}$

Discussion

32.	Find r 2p(6,r)=3p(5,r)
Answer» Answer: FIND R 2P(6,r)=3P(5,r) Step-by-step explanation:

32.

Find r 2p(6,r)=3p(5,r)

Answer»

Answer:

FIND R 2P(6,r)=3P(5,r)

Step-by-step explanation:

Discussion

33.	Math math math headache
Answer» Answer: 1.ii,IV,III,i 2.10 3.c 4.350cm³

33.

Math math math headache

Answer»

Answer:

1.ii,IV,III,i

2.10

3.c

4.350cm³

Discussion

34.	I need this question answered, or I am screwed.
Answer» Answer: 510 Step-by-step EXPLANATION: Here, Total area is 2160 inch^2. Given, Area covered by TRIANGLES is 432 inch^2 ; Area covered by squares is 180 inch^2 Lorea wants to the cover the remaining area with the parallelograms of base 2 inch and height 1.5 inch. We know, area of parallelogram is given by the PRODUCT of its base and height. So, area of each parallelogram should be 2 x 1.5 inch^2 = 3 inch^2 Let there are N parallelograms, so total area covered by the parallelograms is 3 inch^2 + 3 inch^2 + 3 inch^2 + ...upto n times, which can be written as 3n inch^2. Total area = area covered by triangles + area covered by squares + area covered by parallelogram. 2160 = 432 + 180 + 3n ⇒ 2160 - 432 - 180 = 3n ⇒ 1548 = 3n ⇒ 510 = n { divide by 3 } Hence the correct option is 510. Looking for a short answer ? let there are n parall. total area = ar. of triangle + ar. of squares + ( 1.5 x 2 x n ) 2160 - 432 - 180 = 3n 1548 = 3n 510 = n

34.

I need this question answered, or I am screwed.

Answer»

Answer:

510

Step-by-step EXPLANATION:

Here,

Total area is 2160 inch^2.

Given,

Area covered by TRIANGLES is 432 inch^2 ;

Area covered by squares is 180 inch^2

Lorea wants to the cover the remaining area with the parallelograms of base 2 inch and height 1.5 inch.

We know, area of parallelogram is given by the PRODUCT of its base and height.

So, area of each parallelogram should be 2 x 1.5 inch^2 = 3 inch^2

Let there are N parallelograms, so total area covered by the parallelograms is 3 inch^2 + 3 inch^2 + 3 inch^2 + ...upto n times, which can be written as 3n inch^2.

Total area = area covered by triangles + area covered by squares + area covered by parallelogram.

2160 = 432 + 180 + 3n

⇒ 2160 - 432 - 180 = 3n

⇒ 1548 = 3n

⇒ 510 = n { divide by 3 }

Hence the correct option is 510.

Looking for a short answer ? let there are n parall.

total area = ar. of triangle + ar. of squares + ( 1.5 x 2 x n )

2160 - 432 - 180 = 3n

1548 = 3n

510 = n

Discussion

35.	You're playing a game where you defend your village from a orc invasion. There are 3 characters left (elf,hobbit, or human) and 5 defense tools (magic, sword, shield, slingshot, or umbrella) to pick from if you randomly choose your character and tool what is the probability that you'll be a magic elf?
Answer» Answer: for me it WOULD be human with magic or SWORD baaki AAP dekh LO aap KHEL rhe ho na XDXD

35.

You're playing a game where you defend your village from a orc invasion. There are 3 characters left (elf,hobbit, or human) and 5 defense tools (magic, sword, shield, slingshot, or umbrella) to pick from if you randomly choose your character and tool what is the probability that you'll be a magic elf?

Answer»

Answer:

for me it WOULD be human with magic or SWORD baaki AAP dekh LO aap KHEL rhe ho na XDXD

Discussion

36.	This somes you can solve it
Answer» Answer: 150 kg ; sister. Step-by-step explanation: Total weight of all family members is the sum of weights of FATHER, mother, brother, REENU and sister. Total weight = weight of father + weight of mother + weight of brother + weight of Reenu + weight of sister. ⇒ Total weight = 53 kg + 47 kg + 23 kg + 18 kg + 9 kg ⇒ Total weight = 150 kg Weight of Reenu is 18 kg. HALF of weight of Reenu is ( 18 kg / 2 ) or 9 kg. In the family, weight of sister is 9 kg. Therefore, sister's weight is half of the Reenu's weight.

36.

This somes you can solve it

Answer»

Answer:

150 kg ; sister.

Step-by-step explanation:

Total weight of all family members is the sum of weights of FATHER, mother, brother, REENU and sister.

Total weight = weight of father + weight of mother + weight of brother + weight of Reenu + weight of sister.

⇒ Total weight = 53 kg + 47 kg + 23 kg + 18 kg + 9 kg

⇒ Total weight = 150 kg

Weight of Reenu is 18 kg.

HALF of weight of Reenu is ( 18 kg / 2 ) or 9 kg.

In the family, weight of sister is 9 kg. Therefore, sister's weight is half of the Reenu's weight.

Discussion

37.	Pak Turk Maarif International Schools and CollegesLinear InequalityClass 7 Worksheet 11. Fill in the blanks with > 5.2,a. 723b. -6X07X0c. 1-51²d. V6V 8e. 3X0-24xof. (0.2)(0.2)V0.8g. V0.8h. If x > y.then 5xi 1fx < y, then1. If x 2 y.then 3xkifxsy.then1. If 15 > 5 and 5 > x, then 15m. If x < 50 and 50
Answer» Answer: hi mehwishlehri I also study in pakturk maarif SCHOOL ....wanna FOLLOW me

37.

Pak Turk Maarif International Schools and CollegesLinear InequalityClass 7 Worksheet 11. Fill in the blanks with > 5.2,a. 723b. -6X07X0c. 1-51²d. V6V 8e. 3X0-24xof. (0.2)(0.2)V0.8g. V0.8h. If x > y.then 5xi 1fx < y, then1. If x 2 y.then 3xkifxsy.then1. If 15 > 5 and 5 > x, then 15m. If x < 50 and 50

Answer»

Answer:

hi mehwishlehri I also study in pakturk maarif SCHOOL ....wanna FOLLOW me

Discussion

38.	1. find the slope-intercept equation of a line through (3,8) with slope (1,4)2. find the slope-intercept equation of a line through (0,9) with slope 3/73. find the slope-intercept equation of a line through (-1,-7) with slope -3
Answer» Answer: A particle has a displacement of 40m along OX in the first 5s and 30m PERPENDICULAR to OX in the NEXT 5s. The magnitude of average velocity of the particle during the time INTERNAL of 10S is a) 6 ms–1 b) 7 ms–1 c) 8 ms–1 d) 5 ms–1 [

38.

1. find the slope-intercept equation of a line through (3,8) with slope (1,4)2. find the slope-intercept equation of a line through (0,9) with slope 3/73. find the slope-intercept equation of a line through (-1,-7) with slope -3

Answer»

Answer:

A particle has a displacement of 40m along OX in the first 5s and 30m PERPENDICULAR to OX in

the NEXT 5s. The magnitude of average velocity of the particle during the time INTERNAL of 10S is

a) 6 ms–1 b) 7 ms–1 c) 8 ms–1 d) 5 ms–1 [

Discussion

39.	2, 6,10,14,18,22,26,30,34,38,42,46,50,54,58इसमे की किसी भी तीन* संख्याओं का जोड़ 60 आना चाहिए
Answer» Answer: ACTUALLY SIMPLE ADDITION can not MAKE this 60

39.

2, 6,10,14,18,22,26,30,34,38,42,46,50,54,58इसमे की किसी भी तीन* संख्याओं का जोड़ 60 आना चाहिए

Answer»

Answer:

ACTUALLY

SIMPLE ADDITION can not MAKE this 60

Discussion

40.	Answer these for me plzzzzzz 100 points if answer all these.
Answer» ANSWER: heya❤️ the answer is OPTION A please MARK me as BRAINLIEST

40.

Answer these for me plzzzzzz 100 points if answer all these.

Answer»

ANSWER:

heya❤️

the answer is OPTION A

please MARK me as BRAINLIEST

Discussion

41.	You can answer this worksheet
Answer» Answer: I don't know what all of them are, but I ANSWERED the ones I do know Step-by-step explanation: 1. 20.62 2. 364 3. 12 7. 2 2/3 11. 10 12. 15

41.

You can answer this worksheet

Answer»

Answer:

I don't know what all of them are, but I ANSWERED the ones I do know

Step-by-step explanation:

1. 20.62

2. 364

3. 12

7. 2 2/3

11. 10

12. 15

Discussion

42.	Find the equivalent expression
Answer» Answer: 6( 2a + b ). Step-by-step explanation: Whenever we open a BRACKET( curly, brace, big ), we multiply all the terms in that the brackets by the number outside the brackets. Suppose we are given with 3( 2a + 4 ), then we will firstly multiply 3 and 2a and then 3 and 4, so the answer will be 3 x 2a + 3 x 4 = 6a + 12 Here, We have 12A + 6b. 12 can be written as 2 x 2 x 3 and 6 can be written as 2 x 3. Here, 2 x 3 are common in both the numbers, so we can write 2 x 3 outside the bracket and the remaining factors inside it. 2 x 3( 2a + b ) ⇒ 6( 2a + b ) 2nd one is the CORRECT.

42.

Find the equivalent expression

Answer»

Answer:

6( 2a + b ).

Step-by-step explanation:

Whenever we open a BRACKET( curly, brace, big ), we multiply all the terms in that the brackets by the number outside the brackets.

Suppose we are given with 3( 2a + 4 ), then we will firstly multiply 3 and 2a and then 3 and 4, so the answer will be 3 x 2a + 3 x 4 = 6a + 12

Here,

We have 12A + 6b. 12 can be written as 2 x 2 x 3 and 6 can be written as 2 x 3.

Here, 2 x 3 are common in both the numbers, so we can write 2 x 3 outside the bracket and the remaining factors inside it.

2 x 3( 2a + b )

⇒ 6( 2a + b )

2nd one is the CORRECT.

Discussion

43.	How many edges you can answer me
Answer» Answer: 18 Step-by-step EXPLANATION: The FOLLOWING SHAPE has 18 edges. hope it HELPS you

43.

How many edges you can answer me

Answer»

Answer:

18

Step-by-step EXPLANATION:

The FOLLOWING SHAPE has 18 edges.

hope it HELPS you

Discussion

44.	In a rectangle if length is increased by 2 and breath is decreased by 2 the area is reduced to 28 meter square and if length is reduced to 1 and breadth is increased to 2 the area increased to 33 meter square find dimensions of the square
Answer» Answer: Let the LENGTH of the RECTANGLE be x units and the breadth be y units. Area of the rectangle=length×breadth =x×y=xy sq. units From the GIVEN information, we have, (x+2)×(y−2)=xy−28 and(x−1)×(y+2)=xy+33 (x+2)×(y−2)=xy−28 =>xy−2x+2y−4=xy−28 =>−2x+2y=−24 =>−x+y=−12 =>x=y+12....(i) Also,(x−1)×(y+2)=xy+33 =>xy+2x−y−2=xy+33 =>2x−y=35....(ii) Substituting equation (i) in equation (ii), we GET, 2x−y=35 =>2(y+12)−y=35 =>2y+24−y=35 =>y=11 Substituting y=11 in equation (i), we get, x=y+12 =>x=11+12 =>x=23 Therefore, length of rectangle =x=23 units and breadth of rectangle =y=11 units Area of rectangle =xy=23×11=253 square units

44.

In a rectangle if length is increased by 2 and breath is decreased by 2 the area is reduced to 28 meter square and if length is reduced to 1 and breadth is increased to 2 the area increased to 33 meter square find dimensions of the square

Answer»

Answer:

Let the LENGTH of the RECTANGLE be x units and the breadth be y units.

Area of the rectangle=length×breadth

=x×y=xy sq. units

From the GIVEN information, we have,

(x+2)×(y−2)=xy−28

and(x−1)×(y+2)=xy+33

(x+2)×(y−2)=xy−28

=>xy−2x+2y−4=xy−28

=>−2x+2y=−24

=>−x+y=−12

=>x=y+12....(i)

Also,(x−1)×(y+2)=xy+33

=>xy+2x−y−2=xy+33

=>2x−y=35....(ii)

Substituting equation (i) in equation (ii), we GET,

2x−y=35

=>2(y+12)−y=35

=>2y+24−y=35

=>y=11

Substituting y=11 in equation (i), we get,

x=y+12

=>x=11+12

=>x=23

Therefore, length of rectangle =x=23 units

and breadth of rectangle =y=11 units

Area of rectangle =xy=23×11=253 square units

Discussion

45.	What is the general idea of the text? What is it about? Who is involved?the thrill of the chase story
Answer» Answer: A particle has a displacement of 40M along OX in the first 5s and 30m perpendicular to OX in the next 5s. The magnitude of average velocity of the particle during the TIME internal of 10s is a) 6 ms–1 b) 7 ms–1 c) 8 ms–1 d) 5 ms–1 [ A uniform metre scale has two weights of 10 gf and 8 gf suspended at the 10 cm and 80 cm marks respectively. If the metre scale itself weights 50 gf, find where MUST the weight be, so that the metre scale stays balanced?. At the balancing condition, Anticlock wise moment must be equal to clock wise moment. Clockwise moment, about the balancing point is = moment by 80 gf =80gf×(80−X)cm =6400gfcm−80Xgfcm.....(1) Anticlock wise moment about the balancing point is = moment by 10 gf + moment by 50 gf =10gf×(X−10)+50gf×(X−50) =10Xgfc,−100gfcm+50Xgfcm−2500gfcm.....(2) At the balancing condition, Clock wise at equilibrium = ANTI clock wise moments. 6400−80X=100X−100+50X−2500 6400+2600=140X⇒140X=8000 ⇒X=1408000=64.28 Scale is balanced at 64.28 cm from the beginning.

45.

What is the general idea of the text? What is it about? Who is involved?the thrill of the chase story

Answer»

Answer:

A particle has a displacement of 40M along OX in the first 5s and 30m perpendicular to OX in

the next 5s. The magnitude of average velocity of the particle during the TIME internal of 10s is

a) 6 ms–1 b) 7 ms–1 c) 8 ms–1 d) 5 ms–1 [ A uniform metre scale has two weights of 10 gf and 8 gf suspended at the 10 cm and 80 cm marks respectively. If the metre scale itself weights 50 gf, find where MUST the weight be, so that the metre scale stays balanced?.

At the balancing condition, Anticlock wise moment must be equal to clock wise moment.

Clockwise moment, about the balancing point is

= moment by 80 gf

=80gf×(80−X)cm

=6400gfcm−80Xgfcm.....(1)

Anticlock wise moment about the balancing point is

= moment by 10 gf + moment by 50 gf

=10gf×(X−10)+50gf×(X−50)

=10Xgfc,−100gfcm+50Xgfcm−2500gfcm.....(2)

At the balancing condition, Clock wise at equilibrium = ANTI clock wise moments.

6400−80X=100X−100+50X−2500

6400+2600=140X⇒140X=8000

⇒X=1408000=64.28

Scale is balanced at 64.28 cm from the beginning.

Discussion

46.	2. Verify that A divide(b+C)= (a+b)+(a+c) for each of the following(a) a = 12,b=-4, c=2(b) a=(-10), b = 1,c=
Answer» ANSWER: here is your answer PLZZ MARK it as a BRAIN LIST ...

46.

2. Verify that A divide(b+C)= (a+b)+(a+c) for each of the following(a) a = 12,b=-4, c=2(b) a=(-10), b = 1,c=

Answer»

ANSWER:

here is your answer

PLZZ MARK it as a BRAIN LIST ...

Discussion

47.	1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2
Answer» Answer: Let the initial velocity of the body be u m/s; and the constsnt acceleration be a m/s². Then displacemet (DISTANCE COVERED) of the body after t second is given by s = u t + ½ a t² ———————————-(1) The body COVERS 20 m in 2s and 80 m in 4 s. 20 = u×2 + ½ a 2²; => 20 = 2 u + 2 a u + a = 10 —————————————(2) 80 = u×4 + ½ a 4²; => 80 = 4 u + 8 a; this GIVES, u + 2 a = 20 ——————————————(3) Solving (2) and (3) for u and a we get u = 0 m/s and a = 10 m/s² ————————(4) To obtain the distance covered in the next 4s we need to find the velocity at the beginning of this interval using, v = u + a t => v = 0 m/s + 1...

47.

1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2

Answer»

Answer:

Let the initial velocity of the body be u m/s; and the constsnt acceleration be a m/s². Then displacemet (DISTANCE COVERED) of the body after t second is given by

s = u t + ½ a t² ———————————-(1)

The body COVERS 20 m in 2s and 80 m in 4 s.

20 = u×2 + ½ a 2²; => 20 = 2 u + 2 a

u + a = 10 —————————————(2)

80 = u×4 + ½ a 4²; => 80 = 4 u + 8 a; this GIVES,

u + 2 a = 20 ——————————————(3)

Solving (2) and (3) for u and a we get

u = 0 m/s and a = 10 m/s² ————————(4)

To obtain the distance covered in the next 4s we need to find the velocity at the beginning of this interval using,

v = u + a t => v = 0 m/s + 1...

Discussion

48.	How many thirds make 5
Answer» ANSWER: 5 THIRDS I THINK so. .........

48.

How many thirds make 5

Answer»

ANSWER:

5 THIRDS

I THINK so. .........

Discussion

49.	What is 4(1.75y−3.5)+1.25y simplified
Answer» ★ To Find : We have to solve the given EQUATION : $\sf{4(1.75u - 3.5) + 1.25y}$ $\<klux>RULE</klux>{200}{1}$ ★ Solution : As, we have to find the value of $\sf{4(1.75y - 3.5) + 1.25y}$ → We will use BODMAS rule to do this question. According to BODMAS firstly we will solve brackets. $\sf{\dashrightarrow 4(1.75y - 3.5) + 1.25y} \\ \\ \sf{\dashrightarrow 4 \times 1.75y - 4 \times 3.5}$ → Now we have to solve DIVISION according to BODMAS rule but there is no division. So, now we solve multiplication. $\sf{\dashrightarrow 7y - 14 + 1.25y}$ → Now, we will solve addition. $\sf{→8.25y - 14} \\ \\ \Large{\implies{\boxed{\boxed{\sf{8.25y - 14}}}}}$ $\therefore$ 8.25y - 14 is the required answer.

49.

What is 4(1.75y−3.5)+1.25y simplified

Answer»

★ To Find :

We have to solve the given EQUATION : $\sf{4(1.75u - 3.5) + 1.25y}$

$\<klux>RULE</klux>{200}{1}$

★ Solution :

As, we have to find the value of $\sf{4(1.75y - 3.5) + 1.25y}$

→ We will use BODMAS rule to do this question.

According to BODMAS firstly we will solve brackets.

$\sf{\dashrightarrow 4(1.75y - 3.5) + 1.25y} \\ \\ \sf{\dashrightarrow 4 \times 1.75y - 4 \times 3.5}$

→ Now we have to solve DIVISION according to BODMAS rule but there is no division. So, now we solve multiplication.

$\sf{\dashrightarrow 7y - 14 + 1.25y}$

→ Now, we will solve addition.

$\sf{→8.25y - 14} \\ \\ \Large{\implies{\boxed{\boxed{\sf{8.25y - 14}}}}}$

$\therefore$ 8.25y - 14 is the required answer.

Discussion

50.	3)/2 Verily that a +(6+C)=(a+b)+(a=c)for each of the follo(a) a = 12, b=-4, C = 2Fill in the blanks:(b) a=(-10), b=1..
Answer» At the balancing condition, ANTICLOCK wise moment must be equal to clock wise moment. Clockwise moment, about the balancing point is = moment by 80 GF =80gf×(80−X)cm =6400gfcm−80Xgfcm.....(1) Anticlock wise moment about the balancing point is = moment by 10 gf + moment by 50 gf =10gf×(X−10)+50gf×(X−50) =10Xgfc,−100gfcm+50Xgfcm−2500gfcm.....(2) At the balancing condition, Clock wise at equilibrium = Anti clock wise moments. 6400−80X=100X−100+50X−2500 6400+2600=140X⇒140X=8000 ⇒X=1408000=64.28 Scale is BALANCED at 64.28 cm from the beginning.

50.

3)/2 Verily that a +(6+C)=(a+b)+(a=c)for each of the follo(a) a = 12, b=-4, C = 2Fill in the blanks:(b) a=(-10), b=1..

Answer»

At the balancing condition, ANTICLOCK wise moment must be equal to clock wise moment.

Clockwise moment, about the balancing point is

= moment by 80 GF

=80gf×(80−X)cm

=6400gfcm−80Xgfcm.....(1)

Anticlock wise moment about the balancing point is

= moment by 10 gf + moment by 50 gf

=10gf×(X−10)+50gf×(X−50)

=10Xgfc,−100gfcm+50Xgfcm−2500gfcm.....(2)

At the balancing condition, Clock wise at equilibrium = Anti clock wise moments.

6400−80X=100X−100+50X−2500

6400+2600=140X⇒140X=8000

⇒X=1408000=64.28

Scale is BALANCED at 64.28 cm from the beginning.

Discussion

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★ Correct question :

☯ Given :

☯ Solution :

Find r 2p(6,r)=3p(5,r)

Math math math headache ​

I need this question answered, or I am screwed.

This somes you can solve it​

1. find the slope-intercept equation of a line through (3,8) with slope (1,4)2. find the slope-intercept equation of a line through (0,9) with slope 3/73. find the slope-intercept equation of a line through (-1,-7) with slope -3

2, 6,10,14,18,22,26,30,34,38,42,46,50,54,58*इसमे की किसी भी *तीन* संख्याओं का जोड़ 60 आना चाहिए

Answer these for me plzzzzzz 100 points if answer all these.

You can answer this worksheet​

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What is 4(1.75y−3.5)+1.25y simplified

★ To Find :

★ Solution :

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Logical questions please answer soon

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How many cubes with side lengths of \dfrac14\text{ cm}41 cmstart fraction, 1, divided by, 4, end fraction, start text, space, c, m, end text does it take to fill the prism?

Math math math headache

This somes you can solve it

2, 6,10,14,18,22,26,30,34,38,42,46,50,54,58इसमे की किसी भी तीन* संख्याओं का जोड़ 60 आना चाहिए

You can answer this worksheet

How many edges you can answer me

2. Verify that A divide(b+C)= (a+b)+(a+c) for each of the following(a) a = 12,b=-4, c=2(b) a=(-10), b = 1,c=

1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2

How many thirds make 5

3)/2 Verily that a +(6+C)=(a+b)+(a=c)for each of the follo(a) a = 12, b=-4, C = 2Fill in the blanks:(b) a=(-10), b=1..