1.

Show that sin^2(45)-sin^2(15) =root 3/4

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ANSWER:

clearly \: \\ { \sin(45) }^{2} - { \sin(15) }^{2} = \sqrt{ \frac{3}{4} } \\ { \ - sin(15) }^{2} = \sqrt{ \frac{3}{4} } - { \sin(45) }^{2} \\ { \sin(15) }^{2} = \frac{1}{ { \sqrt{2} }^{2} } - \sqrt{ \frac{3}{4} } \\ { \sin(15) }^{2} = \frac{1}{2} - \ \frac{ \sqrt{3} }{2} \\ \sin(15) = \sqrt{ \frac{1 - \sqrt{3} }{2} } \\


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