How many cubes with side lengths of \dfrac14\text{ cm}41 cmstart fr

1.	How many cubes with side lengths of \dfrac14\text{ cm}41 cmstart fraction, 1, divided by, 4, end fraction, start text, space, c, m, end text does it take to fill the prism?
Answer» ★ Correct question : How many cubes with SIDE LENGTHS of 1/4 cm needed to FILL the prism of volume 4 cubic UNITS? $\rule{200}{1}$ ☯ Given : Volume of prism = 4 cubic units Side lengths of CUBE = 1/4 $\rule{200}{1}$ ☯ Solution : We know that, $\Large{\implies{\boxed{\boxed{\sf{Volume = a^3}}}}}$ Where, a is the side of the cube $\sf{\dashrightarrow Volume = \bigg(\dfrac{1}{4}\bigg)^3} \\ \\ \sf{\dashrightarrow Volume = \frac{1}{64}} \\ \\ \sf{\dashrightarrow Volume = 0.015625} \\ \\ \Large{\implies{\boxed{\boxed{\sf{Volume = 0.015625 \: unit^3}}}}}$ $\rule{200}{2}$ Now, As, we have to find the number if cubes so we will devide volume of prism by volume of one cube $\small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{Volume \: of \: prism} {Volume \: of \: cube}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{4}{0.015625}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = 256}}$ $\small{\implies{\boxed{\boxed{\sf{No. \: of \: cubes = 256}}}}}$

How many cubes with side lengths of \dfrac14\text{ cm}41 cmstart fraction, 1, divided by, 4, end fraction, start text, space, c, m, end text does it take to fill the prism?

Answer»

★ Correct question :

How many cubes with SIDE LENGTHS of 1/4 cm needed to FILL the prism of volume 4 cubic UNITS?

$\rule{200}{1}$

☯ Given :

Volume of prism = 4 cubic units

Side lengths of CUBE = 1/4

$\rule{200}{1}$

☯ Solution :

We know that,

$\Large{\implies{\boxed{\boxed{\sf{Volume = a^3}}}}}$

Where,

a is the side of the cube

$\sf{\dashrightarrow Volume = \bigg(\dfrac{1}{4}\bigg)^3} \\ \\ \sf{\dashrightarrow Volume = \frac{1}{64}} \\ \\ \sf{\dashrightarrow Volume = 0.015625} \\ \\ \Large{\implies{\boxed{\boxed{\sf{Volume = 0.015625 \: unit^3}}}}}$

$\rule{200}{2}$

Now,

As, we have to find the number if cubes so we will devide volume of prism by volume of one cube

$\small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{Volume \: of \: prism} {Volume \: of \: cube}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = \dfrac{4}{0.015625}}} \\ \\ \small{\sf{\dashrightarrow No. \: of \: cubes = 256}}$

$\small{\implies{\boxed{\boxed{\sf{No. \: of \: cubes = 256}}}}}$