Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The phlogiston theory was suggested for _______ reaction. (A) neutralisation (B) oxidation (C) reduction (D) combustion

Answer»

The correct option is b, i.e. oxidation. According to this, The PHLOGISTON theory was suggested for oxidation reaction.Explanation:The Phlogistan theory was ONE of the most widely KNOWN theories regarding combustion elements. According to this theory it is PROVEN after empirical testing that all items of combustion contained a fire like element, a substance called phlogiston. This reaction of oxidation is EVEN caused because of  the liberation of phlogiston.

2.

The weight of 1 × 10²² molecules of CuSO₄.5H₂O is _______. (A) 41.59 g (B) 415.9 g (C) 4.159 g (D) none of these

Answer»

no of molecules formula =moles ×avagordo nohence ,MASS /215 × avagordo NUMBER =1×10power 22 its GIVES ANSWER

3.

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is _______. (A) 1 : 4 (B) 7 : 32 (C) 1 : 8 (D) 3 : 16

Answer»

: option (B) 7 : 32 explanation : It is given that ratio of masses of oxygen and nitrogen in a particular gaseous MIXTURE is 1 : 4.let mass of oxygen = mthen mass of nitrogen = 4m as we know, MOLECULAR mass of oxygen = 32g/molmolecular mass of nitrogen = 28 g/molso, no of MOLES of oxygen = m/32 and then, no of oxygen molecules = m/32 × N .......(1)where N is AVOGADRO's number.similarly, no of moles of nitrogen = 4m/28 then, no of nitrogen molecules = 4m/28 × N ........(2)from equations (1) and (2), ratio of their no of molecules = {m/32 × N}/{4m/28 × N} = 28/(4 × 32)= 7/32 hence, ANSWER is 7 : 32

4.

The number of gram atom of oxygen in 6.02 × 10²⁴ CO molecules is _______. (A) 1 (B) 0.5 (C) 5 (D) 10

Answer» OPTION is b.PLEASE FOLLOW ME........
5.

The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic mass = 78.4). Then minimum molecular mass of peroxidase anhydrous enzyme is _______. (A) 1.568 × 10⁴ (B) 1.568 × 10³ (C) 15.68 (D) 3.136 × 10⁴

Answer»

: option (A) 1.568 × 10⁴ explanation : percentage of SE in PEROXIDASE anhydrous enzyme is 0.5% by weight. it MEANS, 0.5g of Se PRESENT in 100g of peroxidase anhydrous enzyme.mass of Se = 0.5 gatomic mass of Se = 78.4 g/molso, no of moles = 0.5g/78.4g/MOL ≈ 0.006377 mol as no of mole of Se = no of mole of Peroxidase anhydrous enzymeor, 0.006377 = mass of enzyme/molecular mass of enzymeor, 0.006377 = 100/molecular mass of enzymeor, molecular mass of enzyme = 100/0.006377 ≈ 15,681.3549 g/mol ≈ 1.568 × 10⁴ g/mol

6.

The number of moles of oxygen in 1 L of air containing 21% oxygen by volume in standard conditions is _______. (A) 0.0093 mol (B) 0.186 mol (C) 0.21 mol (D) 2.10 mol

Answer» OPTION is A. PLEASE FOLLOW ME........
7.

The molecular weight of a gas is 45. Its density at STP is _______. (A) 22.4 (B) 11.2 (C) 5.7 (D) 2.0

Answer»

nsity SAT STP is 22.4

8.

The law of multiple proportions was proposed by _______. (A) Lavoisier (B) Dalton (C) Proust (D) Gay-Lussac

Answer» JOHN DaltonExplanation:It's ALSO KNOWN as DALTON's LAW
9.

The molecular mass of an organic compound is 78. Its empirical formula is CH. The molecular formula is _______. (A) C₂H₄ (B) C₂H₂ (C) C₆H₆ (D) C₄H₄

Answer»
10.

Define solubility and Normality​

Answer»

SOLUBILITYSolubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum AMOUNT of solute dissolved in a solvent at equilibrium. The RESULTING solution is called a saturated solution.NORMALITYNormality is a measure of concentration equal to the gram EQUIVALENT weight per liter of solution. Gram equivalent weight is the measure of the reactive capacity of a molecule. The solute's ROLE in the reaction determines the solution's NORMALITY. Normality is also known as the equivalent concentration of a solution.

11.

A certain organic substance used as a solvent in many reactions contains carbon, hydrogen, oxygen and sulphur Weight % of hydrogen in the compound is 7.7. The weight ratio C:O:S= 3.2: 4. What is theleast possible molar mass of the compound ?(A) 86(B) 63(C) 94(D) 78​

Answer»

The correct answer is option D.Explanation:Suppose in 100 gram of organic compound, 7.7 % is hydrogen.And Carbon , oxygen and SULFUR are ratio of 3:2:4.Mass of hydrogen in organic compound = Let the mass of carbon, oxygen and sulfur be 3x,2x and 4x respectively.7.7 G+3x+2x+4x=100 gx = 10.25 gMass of carbon = 3x = 3 × 10.25 g =30.75 gMoles of carbon =Mass of oxygen = 2x = 2 × 10.25 g =20.5 gMoles of oxygen =Mass of sulfur = 4x = 4 × 10.25 g =41 gMoles of sulfur =Moles of hydrogen =Least possible molecular formula will be equivalent to the empirical formula of this organic substance.Empirical formula of the compound can be determined by individually dividing the moles of all element with smallest number of moles.Carbon =Hydrogen =Oxygen =sulfur=The empirical formula or molecular formula the compound is :Molar mass of the molecular formula is:2 × 12 + 6 × 1+ 1 × 16 + 1 × 32 = 78 g/mol

12.

Which of the following materials fall in the category of a " pure substance"?

Answer» PURE substance is that substance which is made up of only one KIND of substances (ATOMS or molecules)
13.

How can ethanol and ethanoic acid be differentiated on the basis of their physical and chemical properties?

Answer» V I don't RIGHT now I have to be a GOOD DAY
14.

Write condensed formula and Bond Line formula for the following structures​

Answer»

The condensed formulae is the formulae in which the sigma BONDS or the single bonds are not shown in the figure.Hence, the formula of the first compound is CH3CH2CH2CH3 and the name of the compound is GIVEN by BUTANE since it has 4 carbon bonded together. The condensed formulae of the second structure is CNCH2CH2CN or C4H4N2 known as the succinonitrile or butanonitrile.The third compound can be WRITTEN in condensed formula as CH3CH2CH2COOH which is having the name as butanoic acid since, it has 4 carbon bond and a oic acid or acid group.

15.

A sample of carbon dioxide occupies 30 cc at 15 degree celsius and 740 mm pressure.find its volume at S.T.P ​

Answer» VOLUME at STP is 27.6ml
16.

The branch of chemistry which deals with the separation, identification and quantitative determination of the composition of different substances is called _______ chemistry. (A) organic (B) inorganic (C) analytical (D) bio

Answer» INORGANIC CHEMISTRY is the CORRECT FILL up WORD
17.

The gram molecule of benzene is equal to _______ g C₆H₆. (A) 70 (B) 72 (C) 10 (D) 78

Answer»

udent,◆ ANSWER - (D)The gram molecule of BENZENE is EQUAL to 78 g.● EXPLAINATION -Gram molecule is nothing but the molecular MASS of compound.Gram molecule of benzene is calculated by -Molecular mass = 6 × M(C) + 6 × M(H)Molecular mass = 6 × 12 + 6 × 1Molecular mass = 72 + 6Molecular mass = 78 gTherefore, gram molecule of benzene is equal to 78 g.Thanks dear. Hope this helps you...

18.

How many moles of magnesium phosphate, Mg₃(PO₄)₂ will contain 0.25 mole of oxygen atoms? (A) 0.02 (B) 3.125 × 10⁻² (C) 1.25 × 10⁻² (D) 2.5 × 10⁻²

Answer»

(B) 3.125 × 10⁻²Explanation:Magnesium phosphate = MG3(PO4)2 (Given)Mole of oxygen ATOMS = 0.25 (Given)Thus,One mole of Mg3(PO4)2 consist of 8 MOLES of oxygen atom = 1/8x moles of Mg3(PO4)2 consist of 0.25 moles of oxygen atom = x/0.25Therefore, 0.25 mole of oxygen = 1/8 × 0.25= 3.125 × 10⁻²Therefore, magnesium phosphate will contain 3.125 × 10⁻² moles.

19.

In chemical scale, the relative mass of the isotopic mixture of oxygen atoms (¹⁶O, ¹⁷O,¹⁸O) is assumed to be equal to _______. (A) 15.002 (B) 16.00 (C) 17.00 (D) 18.00

Answer» B) 16 is relative MASS of ISOTOPES of Oxygen.hope it helps you!!!
20.

The INCORRECT statement for 14 g of CO is _______. (A) it occupies 2.24 L at NTP (B) it corresponds to \frac{1}{2} mole of CO (C) it corresponds to half mole of N₂ (D) it corresponds to 3.01×10²³ molecules of CO

Answer»

the ANSWER is OPTION A.

21.

During electrolysis of water the volume of O₂ liberated is 2.24 dm³. The volume of hydrogen liberated, under same conditions will be _______. (A) 0.56 dm³ (B) 1.12 dm³ (C) 2.24 dm³ (D) 4.48 dm³

Answer» TION:OPTION d) 4.48dm is CORRECT ANSWER
22.

How many litres of ammonia will be formed when 2 L of N₂ and 2 L of H₂ are allowed to react? (A) 0.665 (B) 1.0 (C) 1.33 (D) 4.00

Answer» OPTION is B.PLEASE FOLLOW ME .....
23.

Suppose the elements X and Y combine to form two compounds XY₂ and X₃Y₂. When 0.1 mole of XY₂ weighs 10 g and 0.05 mole of X₃Y₂ weighs 9 g, the atomic weights of X and Y are _______ . (A) 30, 20 (B) 40, 30 (C) 60, 40 (D) 20, 30

Answer»

(B) 40, 30Explanation:As per the question,Let us consider that atomic weight of element X = xAnd the atomic weight of element Y = yAccording to given data of question,When 0.1 mole of XY₂ weighs 10 g, that is,And when 0.05 mole of X₃Y₂ weighs 9 g, that is,Now we have two EQUATIONS and two VARIABLES, on solving we get2x = 80⇒ x = 40And,∴ y = 30Hence, the atomic weights of X and Y are 40 and 30 respectively.Hence, the CORRECT OPTION is (B).

24.

An organic compound contains carbon hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67 % and O, 51.62%. the empirical formula of the compound would be _______. (A) CHO (B) CH₄O (C) CH₃O (D) CH₂O

Answer»

the emparical FORMULA of the COMPOUND is CHO that is the OPTION A

25.

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl? (A) 0.011 (B) 0.029 (C) 0.333 (D) 0.044

Answer»

(B) EXPLANATION:As PER the question,Firstly, write the balanced reaction of lead oxide (PbO) with hydrogen chloride ( HCl), we get:According to question,6.5g PbO X 1mol PbO/223 g = 0.03 mol PbO3.2g HCl x 1mol HCl/36.5g = 0.088 mol HClFrom this balanced equation we can say that PbO is the LIMITING reactant. Therefore, we will use PbO to find out the amount of moles of .That is,0.03 mol PbO x 1mol PbCl2/1molPbO = 0.029 mol PbO.Hence, moles of lead (II) chloride formed =

26.

A hydrocarbon contains 80% carbon. What is the empirical formula of the compound? (A) CH₂ (B) CH₃ (C) CH₄ (D) C₂H₃

Answer»

A hydrocarbon contains 80% carbon.What is the empirical FORMULA of the compound is CH3Explanation:given a hydrocarbon contains 80% of C. That means hydrogen will be 20%Atomic mass of carbon = 12 atomic mass of hydrogen=1moles of carbon= 80/12=6.67moles of hydrogen= 20/1= 20since SMALLEST value is 6.67 by DIVIDING we get RATIO of C:H as 1:3so empirical formula is CH3

27.

27 g of Al (Atomic mass = 27) will combine with _______ of O₂ to form aluminium oxide. (A) 24 g (B) 8 g (C) 40 g (D) 10 g

Answer»

A) 24 g is the correct ans HOPE it HELPS mark me as brilliant plz FOLLOW methanks

28.

20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample? (A) 60 (B) 84 (C) 75 (D) 96 (At. Wt. : Mg = 24)

Answer»

(B) 84Explanation:Quantity of magnesium carbonate ( MgCO3) = 20gQuantity of magnesium oxide ( MgO ) = 8gThe balanced equation will be - MgCO3 → MgO + CO2Therefore, 84g of MgCO3 = 40g of MgO20g of MgCO3 = 40/84 × 20MgO = 9.52Actual yeild = 8G of MgOThus, PURITY % = 8/ 9.52 × 100= 84%THEREFORE, the percentage purity of magnesium carbonate in the sample will be 84%.

29.

Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85 g of BaCO₃ (Atomic mass of Ba = 137) will be _______. (A) 0.84 L (B) 2.24 L (C) 4.06 L (D) 1.12 L

Answer»

Explanation:Quantity of Baco3 = 9.85gBaCO3 can be described as - BaCO3 → BaO+ CO₂2The atomic Mass of BA =137 The atomic Mass of C =12 The atomic Mass of O =16 Therefore, the MOLECULAR mass of BaCO3= 137 + 12 + (16 × 3) = 197 197 GM of BaCO₃ releases carbon dioxide = 22.4 at STP 1 gm of BaCO₃ releases carbon dioxide = 22.4/197  9.85 gm of BaCO₃ released carbon dioxide = 22.4/197 × 9.85 = 1.12 litre

30.

100 mL of PH₃ on decomposition produced phosphorus and hydrogen. The change in volume is _______. (A) 50 mL increase (B) 500 mL decrease (C) 900 mL decrease (D) nil

Answer» 50ML INCREASE (a)is the CORRECT OPTION
31.

1 atom of an element weighs 1.792 × 10⁻²² g. The atomic mass of the element is _______. (A) 1.192 (B) 17.92 (C) 64 (D) 108

Answer»

..............

32.

How how to determine the wavelength of a Photon electromagnetic radiation having energy 2.99 into 10 raise to 3 erg mol raise to minus one(h=6.625×10 raise to minus 34

Answer»

: The wavelength of a photon of electromagnetic radiation is, 400.29 mExplanation :Formula USED :where,E = energy of photon = conversion used : h = Planck's constant = C = speed of light = = Avogadro's NUMBER = = wavelength = ?Now put all the given values in the above formula, we get:THEREFORE, the wavelength of a photon of electromagnetic radiation is, 400.29 m

33.

The relative rates of diffusion of Cl2 and CO2 gases​

Answer»

s law states that the rate of effusion (or of diffusion ) of a gas is INVERSELY proportional to the square root of it's molecular WEIGHT. The rate of diffusion is THEMEASURE of rate at which two gases mix, and the rate of effusion is the measure of rate at which a gas escapes through a PINHOLE into a vacuum.

34.

SF6 is known but SH6 is not why???....plz don't copy​

Answer»

Because the SIZE of H- is very LARGE than F-. Due to this sulphur can't accommodate 6 hydrozens

35.

Complete and balance the following chemical equations: 1) Na + H2O = ? +? 2) Al + HCL = ? + ? 3) Mg + H2SO4 = ? + ? 4) CuSO4 + Fe = ? + ? 5) Fe + HCL = ? + ? 6) MgO + H2O = ? + ?

Answer»

4-FeSO4+Cu, 5-MgSO4+H2

36.

The density of a gas is 2.5g/L at 127°C and 1 atm . the molecular weight of the gas is​ plz answe this question

Answer» MOLECULAR WEIGHT is 82.1
37.

If 16 g of oxygen contain 1 mole of oxygen atom. calculate mass of one atom in oxygen​

Answer» 8 AMU....................
38.

Which scientist discovered PH scale​

Answer»

The CONCEPT of PH was first introduced by the DANISH chemist Søren PEDER Lauritz Sørensen at the Carlsberg Laboratory in 1909 and revised to the modern pH in 1924 to accommodate definitions and measurements in terms of electrochemical cells.

39.

Pieces of calcium floats on the surface of water when it reacts with water. Why? ​

Answer»

Because the PARTICLES of the calcium GOT stick to the SURFACE of water so they FLOATS

40.

'The number of waves made by a bohr electron in one complete revolution in 3rd orbit?' I don't want the answer..... Can anyone please explain this question to me and tell me that does wave in this question mean spectral lines?Please give the formula to find the answer

Answer»

In general, the number of WAVES made by a BOHR electron in an orbit is equal to its QUANTUM number. Thus the circumference of the 3rd orbit is equal to 3 TIMES the WAVELENGTH of electron i.e. the electron makes three revolution around the 3rd orbit

41.

Write Kohlrausch law for molar conductance of Al2(SO4)3​

Answer» KOHLRAUSCH's law states that the equivalent conductivity of an ELECTROLYTE at infinite DILUTION is EQUAL to the sum of the conductances of the ANIONS and cations. If a salt is dissolved in water, the conductivity of the solution is the sum of the conductances of the anions and cations
42.

By decomposition of 25g of CaCO3 the amount of CaO produced will be .......​

Answer»

2.60gm CAO will be producedExplanation:Ca=40C=12O=16O*3=4840+12+16+48=116116÷25=4.64Ca+O40+16=5656÷4.64=2.60CaO=2.60

43.

Hey guys please help me ​

Answer» PH = 3.28PH = -LoG {H^+}{H+} = 10 ^-PH{H+} =10^-3.28 = 1.0 x 10 ^-3.28......................(1).{H+} + {OH-} = 1.0 X 10^-14...........(2).So..ConcenTraTioN OF OH-FroM EquaTioN ..(1).{OH-} = 1.0 x 10^-14/{H+}FroM EquaTioN ...(2).{OH-} = 1.0 x 10^-14 / 1.0 x 10^-3.28 = 5.2480746e - 18 WILL Be.=5.3 x 10 ^-10 M
44.

Why is sodium metal (very soft metal and can be cut easily ) stored under oil ?Write and balance the reaction of sodium with ailute hydrochloric acid ​

Answer» 2NA +2HCL 2NACL +H2............
45.

Hey guys,small question: so why does ink from a fountain pen leak at higher altitude? please give explnation if you can :)

Answer»

tion:The atmospheric PRESSURE decreases with ALTITUDE so INK leak at HIGHER altitude.

46.

The number of electros to balance the following equation NO3- + 4H+ + e- —> 2H2O + NO plzz explain ur answer...............

Answer» 3 electronsExplanation:On the left hand side the no3 contains - 1 charge and H contains +4 charge the NET charge is +3. Now on the right hand side no charge is present. Hence for NEUTRAL the reaction add the electrons on those side where the charge is maximum.
47.

What is the molecular mass of a gas which diffuses 1/3 times faster than hydrogen

Answer»

the GAS which DIFFUSES 1/3 TIMES FASTER is CL2

48.

D. SI unit of the quantity electric current isa. Voltc. Candelab. Ampered. Newton​

Answer» SI unit of the QUANTITY ELECTRIC CURRENT isb)AmpereHope it helps you.
49.

Give one example of each a.Element or compund​

Answer»

, NH3, ..................……

50.

C. Which of the following temperature will read the same value on celsius andFahrenheit scales.a. - 40° b. + 40°c. -800d. -200​

Answer»

a is the CORRECT ANSWER