Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85 g of BaCO₃ (Atomic mass of Ba = 137) will be _______. (A) 0.84 L (B) 2.24 L (C) 4.06 L (D) 1.12 L

Assuming fully decomposed, the volume of CO₂ released at STP on heat

1.	Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85 g of BaCO₃ (Atomic mass of Ba = 137) will be _______. (A) 0.84 L (B) 2.24 L (C) 4.06 L (D) 1.12 L
Answer» Explanation:Quantity of Baco3 = 9.85gBaCO3 can be described as - BaCO3 → BaO+ CO₂2The atomic Mass of BA =137 The atomic Mass of C =12 The atomic Mass of O =16 Therefore, the MOLECULAR mass of BaCO3= 137 + 12 + (16 × 3) = 197 197 GM of BaCO₃ releases carbon dioxide = 22.4 at STP 1 gm of BaCO₃ releases carbon dioxide = 22.4/197 9.85 gm of BaCO₃ released carbon dioxide = 22.4/197 × 9.85 = 1.12 litre