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The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is _______. (A) 1 : 4 (B) 7 : 32 (C) 1 : 8 (D) 3 : 16 |
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Answer» : option (B) 7 : 32 explanation : It is given that ratio of masses of oxygen and nitrogen in a particular gaseous MIXTURE is 1 : 4.let mass of oxygen = mthen mass of nitrogen = 4m as we know, MOLECULAR mass of oxygen = 32g/molmolecular mass of nitrogen = 28 g/molso, no of MOLES of oxygen = m/32 and then, no of oxygen molecules = m/32 × N .......(1)where N is AVOGADRO's number.similarly, no of moles of nitrogen = 4m/28 then, no of nitrogen molecules = 4m/28 × N ........(2)from equations (1) and (2), ratio of their no of molecules = {m/32 × N}/{4m/28 × N} = 28/(4 × 32)= 7/32 hence, ANSWER is 7 : 32 |
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