1.

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl? (A) 0.011 (B) 0.029 (C) 0.333 (D) 0.044

Answer»

(B) EXPLANATION:As PER the question,Firstly, write the balanced reaction of lead oxide (PbO) with hydrogen chloride ( HCl), we get:According to question,6.5g PbO X 1mol PbO/223 g = 0.03 mol PbO3.2g HCl x 1mol HCl/36.5g = 0.088 mol HClFrom this balanced equation we can say that PbO is the LIMITING reactant. Therefore, we will use PbO to find out the amount of moles of .That is,0.03 mol PbO x 1mol PbCl2/1molPbO = 0.029 mol PbO.Hence, moles of lead (II) chloride formed =



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