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Baaic Experiments
in Chemistry experimental yield Percent yield = x 100%
theoretical yield
The theoretical yield is the calculated maximum amount of product which
might be obtained under IDEAL conditions from the starting MATERIALS. In an
experiment, the theoretical yield is seldom, if ever, reached. In this experiment,
the theoretical yield will be the maximum amount of potash alum which might
be obtained from the specified amounts of starting materials.
In calculating the theoretical yield, you should first calculate the moles of each
reactant and then find the limiting reagent. The limiting reagent determines the.
theoretical yield of the product. The reactant that is consumed completely in Ii "'
chemical reaction is called the limiting reagent.
g of Al,(SO4),, 18H,O taken' No. of moles of A12(S04)3. 1 8H20 taken = ----
gram molecular weight
- - 5'0 - 0.0075 MOL 666.2
No. of moles of K2S04 taken = g of K2S04 -- . taken
gram inolecular weight
- - -- 'SO - 0.0085 mol
174.25
Since, aluminium sulphate and potassium sulphate react in equimolar ratio, the
former is the limiting reagent because it is present in less amount. Thus, the
theoretical yield of potash alum is 0.0075 mol. The theoretical yield in gram
can be calculated by multiplying the yield in rnol by the molecular weight.
Theoretical yield = 0.0075 x 948.26 = 7.1 g
experimental yield Percent yield = x ! 00% 7.1
10.7 RESULT
The percent yield of potash alum = %
10.8 SUMMARY
In this experiment, you have performed the following:
prepared potash alum,
crystallized potash alum, and
calculated the percent yield of potash alum.

M/sec is the UNIT of ZERO ORDER REACTION

They are METALLOIDS which are MENTIONED in a seperate COLUMN

The hydrogen in acids is displaced by the metals to produce hydrogen gas. The TWO common acids are SULFURIC acid (H2SO4) and HYDROCHLORIC acid(HCl). No appreciable REACTION would occur, for the reaction lacks driving force, no enthalpy not entropy benefits!

What is HSBC please elaborate ur question.

may be here HSBC - HYDROGEN, SULPHUR, boron , carbon.

please tell me FAST then i will gave U the ANSWER

Boiling point and freezing point. ... Both the boiling point elevation and the freezing point depression are PROPORTIONAL to the lowering of VAPOR pressure in a DILUTE solution. Theseproperties are colligative in systems where the SOLUTE is essentially confined to the liquid phase.

F2O is the ELEMENT that has most COMMON OXIDATION STATE.

The ANS is DI PHENYL

Natural indicators LIKE TURMERIC,red cabbage leaves,flowers like PETUNIA, HYDRANGEA,germanium etc are some natural indicators.But litmus is the most common USED indicator

PH of distilled WATER is 7 unless and until it comes in contact with atmosphere.And the pH of brine solution is almost EQUAL to 7 because BASICITY of CL^- ion is very less.

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤

These r the non METALS among the first ten ELEMENTS of the modern periodic table.


Hydrogen (H) 
Helium (He) 
Carbon (C) 
NITROGEN (N) 
Oxygen (O) 
Fluorine (F) 
Neon (Ne)


HOPE IT HELPS U.✌✌
#BE BRAINLY.❤❤

Rusting is a very complicated process which involves multiple steps. OVERALL it is

4Fe + 3O2 →2Fe2O3

But where is water? We all know that we NEED water for rusting!

2Fe + O2 + 2H2O → 2Fe(OH)2

4Fe(OH)2 + O2 + 2H2O→4Fe(OH)3

2Fe(OH)3 →Fe2O3 + 3H2O

Overall:

4Fe + 2O2 + 4H2O → 4Fe(OH)2

4Fe(OH)2 + O2 + 2H2O→4Fe(OH)3

4Fe(OH)3 →2Fe2O3 + 6H2O

And

4Fe + 3O2 → 2Fe2O3

Bauz gold is very SOFT so MIXED some material to MAKE hard

Lithium aluminium HYDRIDE, LIALH4, ALSO abbreviated as LAH, is a reducing ... Lithium Aluminium Hydride cannot REDUCE isolated C=C double bonds and ... CONJUGATE and nonconjugate reduction with LiAlH4 and NaBH4.

Amount of salt in 12 LITRES of 10% = 12000 X 10/100 = 1200 G

After evaporation the new volume is 10 litres.

1200 g salt present in 10 litres

= 1200 x 100/10000 = 12%

Due to Centifugation the lighter particles FLOAT,and HEAVIER particles (WATER) is FORCED to stay at the BOTTOM

The goal of the project is to INVESTIGATE effect of metal coupling on the RUSTING of IRON. Metal coupling effects the rusting of iron. We will have to study the change in rate of rusting when an iron nail is coupled with METALS more ELECTROPOSITIVE than ironand with metals which are less electro-positive than iron.

As diffusion is inversely proportional to root of MOLECULAR mass of GAS.
hence,molar mass of SO2 is more than CO2 THEREFORE, co2 gas diffuse more faster than so2 gas.

"VITAMIN C " is good in MARKET for hair growth

Hey Friend____

Here is ur answer....





⭐Solids like sugar get charred on heating to DRYNESS during evaporation. There is no such problem in crystallisation .

⭐The SOLUBLE IMPURITIES do not get REMOVED in the process of evaporation but such impurities get removed in crystallisation.



Hope it helps u.....☺☺☺☺

Since it is a Sulphate, the formulae for the Sulphate would be :

Let X be the element hen the formula would be :

XSO₄

Since the element is 42.2%, the SO₄ would be :

100% - 42.2% = 57.8%

MOLAR mass of SO₄:

64 + 32 = 96G / mole

This represents 57.8%

Mass of the METAL THEREFORE is:

(0.422 / 0.578) × 96 = 70.09

(i) Balancing the given chemical equation,

From the equation, 1 MOLE (28 g) of dinitrogen REACTS with 3 mole (6 g) of

dihydrogen to give 2 mole (34 g) of ammonia.

⇒ 2.00 × 103g of dinitrogen will react with dihydrogen i.e.,2.00 × 103g of dinitrogen will react with 428.6 g of dihydrogen.

Given,

Amount of dihydrogen = 1.00 × 103g

Hence, N2 is the limiting reagent.

28 g of N2 produces 34 g of NH3.

Hence, MASS of ammonia produced by 2000 g of N2= 2428.57 g

(II) N2 is the limiting reagent and H2 is the excess reagent. Hence, H2 willremain unreacted.

(iii) Mass of dihydrogen left unreacted = 1.00 × 103g – 428.6 g= 571.4 g

When the SOLUTION is DILUTED then it's PH will INCREASE...

The process of looking lustre of METAL when they COME in CONTACT with oxygen present in air is OXIDATION . They ALSO get rust

You should learn the reagents
By REAGENT what it make the PRODUCT this you have to learn PERFECTLY
By learn and WRITE
Main thing is the named reactions you have to learn it very perfectly
Hope it helps
Wish u all the best

Answer:
f
=
8.225
×
10
14
l
Hz

Explanation:
The Balmer SERIES corresponds to all electron transitions from a higher ENERGY LEVEL to
n
=
2
.

eilat.sci.brooklyn.cuny.edu
eilat.sci.brooklyn.cuny.edu

The wavelength is given by the Rydberg formula

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
∣
a
a
1
λ
=
R
(
1
n
2
1
−
1
n
2
2
)
a
a
∣
∣
∣
∣
−−−−−−−−−−−−−−−−−−−−−−−


where

R
=
the Rydberg constant and
n
1
and
n
2
are the energy levels such that
n
2
>
n
1

Since
f
λ
=
c

we can re-write the equation as

1
λ
=
f
c
=
R
(
1
n
2
1
−
1
n
2
2
)

or

f
=
c
R
(
1
n
2
1
−
1
n
2
2
)
=
R
′
(
1
n
2
1
−
1
n
2
2
)

where
R
′
is the Rydberg constant expressed in energy units (
3.290
×
10
15
l
Hz
).

In this PROBLEM,
n
1
=
2
, and the FREQUENCY of the limiting line is reached
as
n
→
∞
.

Thus,

f
=
lim
n
→
∞

R
′
(
1
4
−
1
n
2
2
)
=
R
′
(
0.25
−
0
)
=
0.25
R
′

=
0.25
×
3.290
×
10
15
l
Hz
=
8.225
×
10
14
l
Hz

Electron gain enthalpy is defined as the energy released when one mole of electron are added to the gaseous state in an atom.

The more the TENDENCY of an element to gain electron, its electron gain enthalpy will be more negative

The elements which have no tendency to gain electrons have POSITIVE electron gain enthalpies LIKE all noble gases like Ne have fully FILLED outer SHELL thus its electron gain enthalpy is positive

2.5 mole of. WATER coz there are 5 mole of HYDROGEN and by using stoichiometry CALCULATION we can say that if 2 mole of hydrogen CONTAIN 1 mole water then 5 mole will contain 5/2 i.e. 2.5

In order to FIND no. of moles of HOW divide the stoichiometric COEFFICIENT of HOW from NH3 and multiply it by no. of moles of NH3

It is the ANSWER of your QUESTION if any DOUBT ASK me

Montelukast is used regularly to prevent the wheezing and shortness of breath caused by asthma and decrease the number of asthma attacks. Montelukast is also used before exercise to prevent breathing problems during exercise (bronchospasm). This medication can help decrease the number of times you need to use your rescue inhaler. This medication is also used to relieve symptoms of hay fever and allergic rhinitis (such as sneezing, stuffy/runny/itchy nose). This medication does not work right away and should not be used to treat sudden asthma attacks or other breathing problems. This drug works by blocking certain natural substances (leukotrienes) that may cause or worsen asthma and allergies. It helps make breathing easier by reducing swelling (inflammation) in the airways.

How to use Montelukast SODIUM: READ the Patient Information Leaflet if available from your pharmacist before you start taking montelukast and each time you get a refill. If you have any questions, ask your doctor or pharmacist. Take this medication by mouth with or without food as directed by your doctor. The dosage is based on your medical condition and response to treatment. If you are using the chewable tablets, chew them thoroughly before swallowing. If your child cannot safely chew and swallow them, consult the doctor or pharmacist for ADVICE. Take this medication at the same time each day. If you are taking this medication for asthma or for both asthma and allergies, take your dose in the evening. If you are taking montelukast to prevent only allergies, take your dose EITHER in the morning or the evening. If you are taking this medication to prevent breathing problems during exercise, take your dose at least 2 hours before exercise. Do not take more than one dose in 24 hours. Do not take a dose before exercise if you are already taking this medication daily for asthma or allergies. Doing so may increase the risk of side effects. Do not increase or decrease your dose or stop using this medication without consulting your doctor. Continue to use this medication regularly to keep your asthma under control, even during sudden asthma attacks or periods when you have no asthma symptoms. Continue to also take other medications for asthma as directed by your doctor. This medication works over time and is not meant to relieve sudden attacks of asthma. Therefore, if an asthma attack or other breathing problem occurs, use your quick-relief inhaler as prescribed. You should always have a quick-relief inhaler with you. Consult your doctor or pharmacist for more details. Get medical help right away if your asthma symptoms worsen and your quick-relief inhaler is not helping. Tell your doctor promptly if asthma symptoms, breathing problems, allergy symptoms, number of times you use your rescue inhaler persist or worsen. 

Levocetirizine is an antihistamine used to relieve allergy symptoms such as watery eyes, runny nose, itching eyes/nose, and sneezing. It is also used to relieve itching and hives. It works by blocking a certain natural substance (histamine) that your body makes during an allergic reaction. Levocetirizine does not prevent hives or prevent/treat a serious allergic reaction (such as anaphylaxis). If your doctor has prescribed epinephrine to treat allergic reactions, always carry your epinephrine injector with you. Do not use levocetirizine in place of your epinephrine.

How to use Levocetirizine DIHYDROCHLORIDE: If you are taking the over-the-counter product to self-treat, read and FOLLOW all directions on the product package before taking this medication. If you have any questions, consult your pharmacist. If your doctor has prescribed this medication, take it as directed. This medication is taken by mouth with or without food, usually once daily in the evening. If you are using the liquid form of this medication, measure the dose carefully using a special measuring device/spoon. Do not use a household spoon because you may not get the correct dose.The dosage is based on your age, medical condition, and response to treatment. Do not increase your dose or take this medication more often than directed. If your condition does not get better or if it gets worse, or if you think you may have a serious medical problem, get medical help right away.

Sorry, if this is too much information.

Answer: 0

Explanation:

The orbital angular momentum of an electron is GIVEN by:

l = azimuthal quantum number

h = PLANK's constant

Principle Quantum NUMBERS : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the SHAPE of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the ORBITALS are s, p, d, f...

For 2 s

n=2  and l = 0

Thus

Because of diffusion. The FRAGRANCE of the STICK SPREADS through the AIR by diffusion.
This is a phenomenon you will study more in class 9

Hii There!!!

The given statement is [False].
Minerals are NATURAL RESOURCES which are naturally AVAILABLE in the Earth Crust.
Hence, it is not man-made resources.


Hope it HELPS

2 molal aq soln means 2 mole SOLUTE in 1000 GM WATER. So mole of water is 1000/18, so mole FRACTION of solute is
Using formula (Xa= [{n(solute)}/ {n(solute)+ n(solvent)}] is [{2}/{(2)+(1000/18)}] = [{2}/{(2)+(55.55)}]= [(2)/(57.55)] = 0.03474 is the answer.

Suppose, ORDER of REACTION is n and the reaction is A (g) =>Products

Rate = k[A]n ...(i)

When VOLUME is doubled, molar conc. becomes half and rate of reaction GETS halved.

Dividing equation (i) by equation (ii),

(2)1 = (2)n

Or n = 1

BiH3 the COACH bond between Bi and H is not STRONG

What is the QUESTION BRO