1.

The orbital angular momentum of an electron in 2s orbital is0.5hπ0h/2π√2h/π

Answer»

Answer: 0

Explanation:

The orbital angular momentum of an electron is GIVEN by:

\sqrt{l(l+1)}\frac{h}{2\pi}

l = azimuthal quantum number

h = PLANK's constant

Principle Quantum NUMBERS : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the SHAPE of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the ORBITALS are s, p, d, f...

For 2 s

n=2  and l = 0

Thus {\sqrt{0(0+1)}\frac{h}{2\pi}=0



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