The sulphate of an element contains 42.2% element . the equivalent wei

1.	The sulphate of an element contains 42.2% element . the equivalent weight of the metal would be?
Answer» Since it is a Sulphate, the formulae for the Sulphate would be : Let X be the element hen the formula would be : XSO₄ Since the element is 42.2%, the SO₄ would be : 100% - 42.2% = 57.8% MOLAR mass of SO₄: 64 + 32 = 96G / mole This represents 57.8% Mass of the METAL THEREFORE is: (0.422 / 0.578) × 96 = 70.09

The sulphate of an element contains 42.2% element . the equivalent weight of the metal would be?

Answer»

Since it is a Sulphate, the formulae for the Sulphate would be :

Let X be the element hen the formula would be :

XSO₄

Since the element is 42.2%, the SO₄ would be :

100% - 42.2% = 57.8%

MOLAR mass of SO₄:

64 + 32 = 96G / mole

This represents 57.8%

Mass of the METAL THEREFORE is:

(0.422 / 0.578) × 96 = 70.09