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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
Explain dispersion force(london dispersion forces)?? |
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Answer» Explanation: The London DISPERSION force is a temporary attractive force that results when the electrons in two adjacent atoms OCCUPY positions that make the atoms FORM temporary dipoles. ... Dispersion FORCES are present between any two molecules (even polar molecules) when they are almost TOUCHING. |
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| 3. |
. Why did Thomson assume that electrons areembedded in a positive mass but not the other wayround? |
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Answer» Why did THOMSON ASSUME that ELECTRONS are embedded in a positive MASS but not the other way round ? SOLUTION : Thomson assumed that electrons are embedded in a positive mass as it could explain several observations like only electrons are ejected when a metal is heated and never positively charged particles. |
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| 4. |
19. Choose the correct match/matches(1) 18 ml of H20 at 4°CNA molecule of H2O(2) 11.2 L of Co, at 273°CNA/2molecule of CO2and 1°C(3) 56 g of Fe57Na atom(4) 5.6 L of CH4 at STP4 g weight with full explanation fast plz |
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Answer» Answer: 5.6 L of CH4 at STP 4 g weight hope this helps u pls follow me and MARK my answer as brainliest |
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| 5. |
Calculate the average atomic mass of chlirine 35(75%)and 37(25%) if it exist in two isotopic form |
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| 6. |
Explain energy sequence rule with example |
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Answer» aattaktartkatmatkztskgstksyksylxlyyydyllydudyldyyaay |
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| 7. |
An element has a valency of 2. Identify the element |
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Answer» Answer: The elements are Be , Mg , Ca , Sr , BA , Ra. Explanation: SINCE they contain 2 FREE electrons in their OUTERMOST shell. |
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| 8. |
what's molarity of solution formed from 6.75g Mack dissolved in water to make a solution with total volume of 452 ml |
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Answer» Explanation: Sound waves are created when sounds MAKE vibrations in the air. In this ACTIVITY, your voice VIBRATES the air inside the cup, which are then transferred to the BOTTOM of the cup. The bottom of the cup passes the sound waves to the string, and so on to the other cup. |
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| 9. |
Q7. Nitrogen and hydrogencombine in the ratio of 14:3 bymass to form ammonia. Whatmass of nitrogen gas would berequired to react completelywith 9g of hydrogen gas? |
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Answer» b Molecular MASS of ammonia NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9g. Explanation: MARK me as BRAINLIEST |
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| 10. |
when 1.438 gm of zinc is added to copper sulphate solution, 1.398 gm of copper is precipitated. If equivalent weight of copper is 31.77, find out the equivalent weight of zinc . |
Answer» ANSWER....HENCE, The equivalent weight of zinc is 32.68. |
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| 11. |
How do loggers use trigonometry?GOOD MORNING HAVE SIS |
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Answer» Answer: SLC uses trigonometry to determine where trees will FALL, how tall they are, their age, THUS LIMITING the IMPACT that falling trees have on SURROUNDING trees. Explanation: Good night |
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| 12. |
Pls answerI will MARK AS BRAINLIEST |
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Answer» 212/10 Explanation: |
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| 13. |
240Pauticles present in240 gcalculateofcgCarbon dioxide |
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Answer» Answer: YIELD of CO2 = (Amount of CO2 actually formed) / (Amount of CO2 that can be formed by complete oxidation of given carbon)
C + O2 \rightarrow CO2 2C + O2 \rightarrow 2CO
1 mole of Carbon(C) YIELDS 1 mole of CO2. Number of MOLES of carbon = (240)/12 = 20 moles. Number of moles of carbon that is used to form CO = Number of moles of CO formed = (280)/(28) = 10 moles \IMPLIES Number of moles of carbon used in the formation of CO2 = Number of moles of CO2 formed = 20 – 10 = 10 moles Number of moles of CO2 that can be formed by the complete oxidation of given amount of carbon = Number of moles of carbon = 20 moles
\implies Yield of CO2 = (10)/(20) = 0.5 \impliespercentage yield of CO2 = 0.5 * 100% = 50% Explanation: mark me as BRAINLIEST |
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| 14. |
The proton concentration of the given glass of lemon juice is 3.45. How much of 0.1MNaOH (pH=13) should you add in order to neutralize the solution to pH 7? |
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Answer» YES i will Anty |
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| 15. |
How will you obtain?[Write balanced equation] [5]a)Silver Chloride from Silver nitrateb) Sodium chloride from Sodium oxidec)Nitric acid from Nitrogen pentoxide.d)Oxygen from watere)Sulphur from Hydrogen sulphide |
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Answer» Answer: (a) Calcium hydroxide + Carbon dioxide → Calcium carbonate + Water Ca(OH)
+CO 2
→CaCO 3
+H 2
O (b) Zinc + Silver nitrate → Zinc nitrate + Silver Zn+2AgNO 3
→Zn(NO 3
) 2
+2Ag (c) Aluminium + Copper chloride → Aluminium chloride + Copper 2Al+3CuCl 2
→2AlCl 3
+3Cu (d) Barium chloride + Potassium SULPHATE → Barium sulphate + Potassium chloride 2
+K 2
SO 4
→BaSO 4
+2KCl |
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| 16. |
Write names of 3 periodic properties |
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Answer» A period 3 element is one of the chemical elements in the THIRD row (or period) of the periodic table of the chemical elements. The periodic table is laid out in rows to illustrate recurring (periodic) trends in the chemical behaviour of the elements as their atomic number increases: a new row is begun when the periodic table skips a row and a chemical behaviour begins to repeat, meaning that elements with similar behavior fall into the same VERTICAL columns. The third period contains eight elements: sodium, magnesium, aluminium, silicon, phosphorus, SULFUR, chlorine, and argon. The first two, sodium and magnesium, are members of the s-block of the periodic table, while the others are members of the p-block. All of the period 3 elements occur in NATURE and have at least one stable isotope. |
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| 18. |
The elements of group 17 are called ------------. |
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Answer» Halogen, any of the SIX nonmetallic elements that constitute Group 17 (Group VIIa) of the periodic table. ... The halogen elements are FLUORINE (F), chlorine (Cl), BROMINE (Br), iodine (I), astatine (At), and tennessine (TS). |
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| 19. |
C) On heating green coloured ferrous sulphatecrystals, reddish brown solid is left and smellof a gas having odour of burning sulphur isexperienced name the type of reaction |
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| 20. |
Which rule is violated by the electron configuration 1s2 2s2 2p6 3s3 3p4 |
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Answer» Explanation: Aufbau rule is violated here.I HOPE IT HELPS YOU...PLEASE MARK ME BRAINLEST ✌ |
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| 21. |
Describe the mechanism of the formation of diethyl ether from ethanol in the presence of concentrated sulphuric acid. |
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Answer» the mechanism of the formation of diethyl ETHER from ethanol in the presence of concentrated SULPHURIC. acid. The carbocation FORMED by the ethanol in the presence of acid is open to attack by nucleophile. ... So, the product is ethoxyethane and this REACTION is dehydration reaction...... |
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| 22. |
state true or false. If false correct it 'Anode rays are stream of very small negatively charged particle'. |
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Answer» True Explanation: |
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| 23. |
The Calium carbonate reacts with aquedoas to produce cos gas accogidling follolownที่ ค์spustionLa cozco + 2Hidra) -Cool (9) +(@cg)+ho calculate the mass of Cacoz requinesug con gasos Craloo 0055 of Caloz= 100gBeware of ittie expenses. A small leak wolt sink a great ship |
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| 24. |
Examine the diagram of the cell cycle.Which label identifies the stage in which the DNA is copied and the cell grows?WXYZ |
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| 25. |
MO diagram of Oxygen molecule (O2 ) |
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Answer»
HOPE it HELPS PLZ MARK it as BRAINLIEST ✌ |
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| 26. |
Укажите, к какому типу относится химическая реакция Na+H2O(стрелка) NaOH+? |
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Answer» Уравновешивание химического уравнения относится к уравновешиванию стехиометрических коэффициентов на стороне реагентов и продуктов. Это необходимо сделать, поскольку химическое уравнение подчиняется закону сохранения массы и количества движения. |
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| 27. |
Why does So3 act as an electrophile??please tell me answer |
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Answer» Answer: SO3 ACTS as an ELECTROPHILE because three highly electronegative oxygen atoms are attached to Sulphur ATOM in SO3 which makes Sulphur atom electron deficient. It can be shown by resonance. Explanation: FOLLOW me like my answer |
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| 28. |
an aqueous 2.00 m hydrochloric acid is prepared with a total of 0.35 L. the molecular weight og hydrochloric acid is 36.46 g/mol |
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| 29. |
What a brief note on the taft equation and the compensation effect |
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| 30. |
What is the electric and thermal conductivity of graphite |
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Answer» For carbon the VALUES range from 0.0037 to 0.021 in the TEMPERATURE range -191° to lOO°e. The ELECTRICAL CONDUCTIVITIES of graphite range for the longitudinal specimen from 900 to 1700 mhos/ em while for the radial specimen they go from 400 to 700 mhos/em. |
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| 31. |
derive relationship between the interplanar spacing of a crystal and the wavelength of x-ray diffracted by it. |
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Answer» The X-rays get diffracted by a CRYSTAL because the wavelength of X-rays is similar to the inter-atomic spacing in the crystals. mujhe bas x RAY diffracted KA hi pta hai I hope this will help you |
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| 32. |
At same temperature which of the following is gas have high density |
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| 33. |
Hybrid orbital having maximum p-character is1) spºd 2) sp 3) sp 4) spd |
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Answer» 4) SPD ( 37- 46÷56,53÷40×33+01=109983) ANS- 109983 |
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| 34. |
Adsorption found in only... solid substance |
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Answer» So what is the QUESTION??? |
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| 36. |
Write the symbols (i) chlorine (ii) sodium (iii)zinc (iv)gold |
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Answer» Answer: 1) Cl 2) Na 3) Zn 4) Au Hope this HELPS you |
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| 37. |
56. Hq + OH2q + H2O), AH =-q, KJHCNag + KOHq → KCNaq + H2O();AH = - q kJHCl + NHOH + NH4Cl + H2O )AH = - qzkJThen AH for HCN2+NH,OH → Products(in KJ)aqaq |
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Answer» Answer: HII PLEASE FOLLOW ME PLEASE FOLLOW ME AND THANKS MY ANSWER AND BRAINLEST MY ANSWER PLEASE THIS IS THE CORRECT ANSWER OKK PLZZ FOLLOW ME AND THANKS MY ANSWERS AND BRAINLEST MY ANSWER HOPE IT IS HELP U Explanation: Our RESULTS indicate that HCN1, 2 and 4 genes and PROTEIN are expressed in the ENS. AH/Dogiel type II neurons, which have a prominent Ih, express HCN2 and 4 |
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| 38. |
Write the reaction of HCl on the following. (a) NaOH (b) CaCO3. please answer |
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Answer» CaCO3 +HCl==> CaOH + Cl + CO2 Explanation: |
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| 39. |
Magnesium ribbon is rubbed before burning because it has a coating of(a) basic magnesium carbonate (b) basic magnesium oxide (c) basic magnesium sulphide (d) basic magnesium chloride |
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Answer» Answer: (B) basic magnesium oxide Explanation: Magnesium ribbon is WRAPPED and cleaned before burning because it has a coating of basic magnesium oxide. |
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| 40. |
How to crystal clear my concepts in all the subjects as I am in class 12? |
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Answer» Explanation: |
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| 41. |
Out of Na and Na+ which has smaller size and why? |
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Answer» Na+ has smaller SIZE because it loses its VALANCE electron as a result it also loses its outermost shell. And hence its size becomes smaller than Na. I HOPE this will help you. |
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| 42. |
СИО27 cooh3Чs s226ч/2Х21illoг1.121111315аси1 чон//оч? |
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Answer» jwjeheoehid in GIRLS ieoei |
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| 43. |
How is hydrogen secreted from carbon die oxide |
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Answer» Answer: Carbon dioxide is produced by cell metabolism in the mitochondria. The amount produced depends on the rate of metabolism and the rel- ative amounts of carbohydrate, fat and protein metabolized.The amountis about 200mlmin1 when at rest and eating a mixed diet; this utilises 80% of the oxygen consumed, giving a respir- atory quotient of 0.8 (respiratory quotient ¼ rate of carbon dioxide production divided by rate of oxygen consumption). A carbohydrate diet gives a quotient of 1 and a fat diet 0.7. Carbon dioxide transport in the blood Carbon dioxide is transported in the blood from the tissue to the lungs in three ways:1 (i) dissolved in solution; (ii) buffered with water as carbonic ACID; (iii) bound to proteins, particularly haemoglobin. Approximately 75% of carbon dioxide is transport in the red blood cell and 25% in the plasma. The relatively small amount in plasma is attributable to a lack of carbonic anhydrase in plasma so association with water is slow; plasma plays little role in buffering and com- bination with plasma proteins is poor. There is a DIFFERENCE between the percentage of the total carbon dioxide carried in each form and the percentage exhaled from them. For example, 5% of the total is in solution but 10% of exhaled carbon dioxide comes from this source; 10% is protein bound, particularly with haemoglobin, but this supplies 30% of the exhaled amount. Dissolved carbon dioxide Carbon dioxide is 20 times more soluble than oxygen; it obeys Henry’s law, which states that the number of molecules in solution is pro- portional to the partial pressure at the liquid surface. The carbon dioxide solubility coeffi- cient is 0.0308 mmol litre–1 mm Hg–1 or 0.231 mmol litre–1 kPa–1 at 37- C. (Solubility increases as the temperature FALLS.) This corres- ponds to 0.5 ml kPa–1 carbon dioxide in 100 ml blood at 37- C. The partial pressure of carbon dioxide is 5.3 pKa in arterial blood and 6.1 kPa in mixed venous blood; therefore, arterial blood will contain about 2.5 ml per 100 ml of dissolved carbon dioxide and venous blood 3 ml per 100 ml. A cardiac output of 5 litre min1 will carry 150 ml of dissolved car- bon dioxide to the lung, of which 25 ml will be exhaled. Because of this high solubility and diffusing capacity, carbon dioxide partial pres- sure of alveolar and pulmonary end-capillary blood are virtually the same. Even a large shunt of 50% will only cause an end-pulmonary capil- lary/arterial carbon dioxide gradient of about 0.4 kPa. Carbonic acid Carbon dioxide combines with water to form carbonic acid, a reaction accelerated by car- bonic anhydrase. The carbonic acid then freely dissociates (Equation 1). CO2 þ H2O Ð carbonic anhydrase H2CO3 Ð Hþ þ HCO 3 ð1Þ The enzyme carbonic anhydrase is present in a number of organs of the body including the eye, kidney and brain; however, for this purpose, it is the red blood cell carbonic anhyd- rase that is important. Once carbonic acid is formed it dissociates easily so that the ratio of H2CO3 to HCO3 – is 1:20 (Equation 2). CO2 H2CO3 ¼ 1000 1 H2CO3 HCO 3 ¼ 1 20 ð2Þ Carbon dioxide and water diffuse freely into the red blood cell and are converted to carbonic acid, which dissociates into hydrogen and bicarbonate ions. Hydrogen ions do not pass through cell membranes but carbon dioxide passes readily. This situation cannot be sustained as the intracellular hydrogen ion hope it helps please mark me branliest and follow me |
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| 44. |
Hydrogen gas ki Das dayi Oxygen gas ke 5 aayatan ke sath abhikriya karen to jalvasp ke kitne Aaytan prapt honge |
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Answer» Answer: plse write your QUESTION correct Explanation: UNABLE to UNDERSTAND |
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| 45. |
C-14 is radioactive whereas c-12 is not ? give reason |
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Answer» COSMIC rays – high-energy particles from beyond the SOLAR SYSTEM – bombard Earth's upper atmosphere continually, in the PROCESS creating the unstable carbon-14. Carbon-14 is considered a radioactive isotope of carbon. Because it's unstable, carbon-14 will eventually decay back to carbon-12 isotopes |
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| 46. |
4. The electronic configuration of two elements are , A and B are2,8,7 and 2,8, 8,2 respectly. Write the atomic number of these elements. What will be the formula of the compound formed and the nature of bond between them when these two elements chemically combined together. |
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Answer» a Explanation: answered answer |
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| 47. |
Complete the following statement aboutmagnetic field lines.,Magnetic field linea__________ |
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| 48. |
Explain why del t is smaller than del o? |
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| 49. |
If x electron are needed to displace 108 g silver from a solution which contains Ag+ ions,how many electrons are needed to displace 9 g of aluminium from a solution which contains Al3+? |
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Answer» Answer: your answer Explanation: 1 FARADAY of charge discharges E gram of an ion, where E is the equivalent weight. For silver, the VALUE of E is 108 g. Thus, the AMOUNT of electricity that can deposit 108 g of silver form AgNO 3
solution is one Faraday. Hence, option A is correct. MARK AS BRAINLIST |
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| 50. |
1. Find themolarity of a solutionprepared by dissolving 45g glucose in 1000ml water. |
Answer» Given:-→ Mass of glucose = 45g → Volume of SOLUTION = 1000mL To find:-→ MOLARITY of the solution. Solution:-• MOLAR mass of Carbon = 12g/mol • Molar mass of Hydrogen = 1g/mol • Molar mass of Oxygen = 16g/mol Hence, molar mass of glucose [C6H12O6] :- = 12×6 + 1×12 + 16×6 = 72 + 12 + 96 = 180g/mol Number of mole in 45g of glucose :- = Given Mass/Molar mass = 45/180 = 0.25 mole Now, let's convert the volume of the solution from mL to L. => 1mL = 0.001L => 1000mL = 1000(0.001) => 1L Molarity of a solution :- = Moles of solute/Liters of solution = 0.25/1 = 0.25 M Thus, molarity of the solution is 0.25 M . |
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