Q7. Nitrogen and hydrogencombine in the ratio of 14:3 bymass to form a

1.	Q7. Nitrogen and hydrogencombine in the ratio of 14:3 bymass to form ammonia. Whatmass of nitrogen gas would berequired to react completelywith 9g of hydrogen gas?
Answer» ANSWER: b Molecular MASS of ammonia NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9g. Explanation: MARK me as BRAINLIEST

Q7. Nitrogen and hydrogencombine in the ratio of 14:3 bymass to form ammonia. Whatmass of nitrogen gas would berequired to react completelywith 9g of hydrogen gas?

Answer»

b Molecular MASS of ammonia NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9g.

Explanation:

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Q7. Nitrogen and hydrogencombine in the ratio of 14:3 bymass to form ammonia. Whatmass of nitrogen gas would berequired to react completelywith 9g of hydrogen gas?​

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Q7. Nitrogen and hydrogencombine in the ratio of 14:3 bymass to form ammonia. Whatmass of nitrogen gas would berequired to react completelywith 9g of hydrogen gas?