240Pauticles present in240 gcalculateofcgCarbon dioxide

1.	240Pauticles present in240 gcalculateofcgCarbon dioxide
Answer» Answer: YIELD of CO2 = (Amount of CO2 actually formed) / (Amount of CO2 that can be formed by complete oxidation of given carbon) C + O2 \rightarrow CO2 2C + O2 \rightarrow 2CO 1 mole of Carbon(C) YIELDS 1 mole of CO2. Number of MOLES of carbon = (240)/12 = 20 moles. Number of moles of carbon that is used to form CO = Number of moles of CO formed = (280)/(28) = 10 moles \IMPLIES Number of moles of carbon used in the formation of CO2 = Number of moles of CO2 formed = 20 – 10 = 10 moles Number of moles of CO2 that can be formed by the complete oxidation of given amount of carbon = Number of moles of carbon = 20 moles \implies Yield of CO2 = (10)/(20) = 0.5 \impliespercentage yield of CO2 = 0.5 * 100% = 50% Explanation: mark me as BRAINLIEST

Answer»

Answer:

YIELD of CO2 = (Amount of CO2 actually formed) / (Amount of CO2 that can be formed by complete oxidation of given carbon)

C + O2 \rightarrow CO2

2C + O2 \rightarrow 2CO

1 mole of Carbon(C) YIELDS 1 mole of CO2.

Number of MOLES of carbon = (240)/12 = 20 moles.

Number of moles of carbon that is used to form CO = Number of moles of CO formed = (280)/(28) = 10 moles

\IMPLIES Number of moles of carbon used in the formation of CO2 = Number of moles of CO2 formed = 20 – 10 = 10 moles

Number of moles of CO2 that can be formed by the complete oxidation of given amount of carbon = Number of moles of carbon = 20 moles

\implies Yield of CO2 = (10)/(20) = 0.5

\impliespercentage yield of CO2 = 0.5 * 100% = 50%

Explanation:

mark me as BRAINLIEST

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