1. Find themolarity of a solutionprepared by dissolving 45g glucose in

1.	1. Find themolarity of a solutionprepared by dissolving 45g glucose in 1000ml water.
Answer» Given:- → Mass of glucose = 45g → Volume of SOLUTION = 1000mL To find:- → MOLARITY of the solution. Solution:- • MOLAR mass of Carbon = 12g/mol • Molar mass of Hydrogen = 1g/mol • Molar mass of Oxygen = 16g/mol Hence, molar mass of glucose [C6H12O6] :- = 12×6 + 1×12 + 16×6 = 72 + 12 + 96 = 180g/mol Number of mole in 45g of glucose :- = Given Mass/Molar mass = 45/180 = 0.25 mole Now, let's convert the volume of the solution from mL to L. => 1mL = 0.001L => 1000mL = 1000(0.001) => 1L Molarity of a solution :- = Moles of solute/Liters of solution = 0.25/1 = 0.25 M Thus, molarity of the solution is 0.25 M .

1. Find themolarity of a solutionprepared by dissolving 45g glucose in 1000ml water.

Answer»

→ Mass of glucose = 45g

→ Volume of SOLUTION = 1000mL

→ MOLARITY of the solution.

• MOLAR mass of Carbon = 12g/mol

• Molar mass of Hydrogen = 1g/mol

• Molar mass of Oxygen = 16g/mol

Hence, molar mass of glucose [C6H12O6] :-

= 12×6 + 1×12 + 16×6

= 72 + 12 + 96

= 180g/mol

Number of mole in 45g of glucose :-

= Given Mass/Molar mass

= 45/180

= 0.25 mole

Now, let's convert the volume of the solution from mL to L.

=> 1mL = 0.001L

=> 1000mL = 1000(0.001)

=> 1L

Molarity of a solution :-

= Moles of solute/Liters of solution

= 0.25/1

= 0.25 M

Thus, molarity of the solution

is 0.25 M .