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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6001. |
In the given figure, the chord AB ofthe larger of the two concentric circles,with centre O, touches the smallercircle at C. Prove that AC- CB |
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Answer» Thanx |
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| 6002. |
4. Principal = * 9600, rate = 7-% p.a. and time = 5 months. |
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Answer» si= 300amount= 9900 is the correct answer of the given 9900 rupees correct answer for this question 9900 is a correct answer 9900 Rs. is correct answer. |
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| 6003. |
In a class of 50 students, 34 passed in mathenatics and 4C passed in science and 312passed in both mathematics and science. Draw a venn diagram. Find how many studentsfailed in both mathematics and science? |
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| 6004. |
10. In the figure, ABCD is a rectangle and AC - ECmanyand D is the mid-point of AE. Find howairs of congruent triangles are there. Write thcongruence in a symbolic form |
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| 6005. |
in a class of 40 students 1/5 of the total students like to study English and 2/5 of the total like to study maths and the students like to study science 1. how many like to study science? 2.how many like to study maths? 3.how many like to study English |
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Answer» students like english=40/5=8students like maths=40×2/5=16students like science=40-(16+8) =40-24=16 |
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| 6006. |
2Inaclassof50students,34passedinmathematicsand40passedinscienceand32passed in both mathematics and science. Draw a venn diagram. Find how many studentsfailed in both mathematics and science? |
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Answer» 18 failed in both maths and science |
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| 6007. |
us, the new cost is2772RCISE 18.152% out of 25 students are good inscience. How many are not good inscience? |
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Answer» 52% are good in science.So (100-52)% are not good in science.So, 48% are not good in science.48% of 25= 48×25/100 =48/4 =12 12 students are not good in science |
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| 6008. |
3., The given figure shows two circles withcentres A and B; and radii 5 cm and 3 cmrespectively, touching each other internally. Ifthe perpendicular bisector of AB meets thebigger circle in P and Q, find the length ofPQ |
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| 6009. |
The figure given alongside shows twodalK&Ucircles with the same centre. The radius ofthe larger circle is 10 cm and the radius ofthe smaller circle is 4 cm.Find the following.A. Area of the larger circleB. Area of the smaller circleArea of shaded partbetween the two circlesC. |
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| 6010. |
he figure shows two concentric circles, and AD is a chord ofthe larger circle. Prove that ABCD.ie ic |
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Answer» Like if you find it useful |
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| 6011. |
25. The figure, shows twoo concentric circles with centre O. AB and APQ are tangents to the inner circle from point Acirlying on the outer circle. If AB - 7.5 cm, then find ad |
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| 6012. |
he given figure shows two parallelangents XY and X'Y'at the points A and Hespectively to the circle with centre OInother tangent CD is drawn parallel to ABat the point P. Show that a circle with P asentre and OP as radius will pass through Cind D |
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Answer» So, AC || BD We know, rangers is perpendicular to the radius at the point of contact. So, angle OAC = angle OBD = 90 in quadrilateral ACDB, AB|| CD AC || BD Angle BAC= 90 Hence, it is clear that Quadrilateral ACDB is a rectangle So, angle C = angle D = 90 Now in quadrilateral OACP, Angle A = 90 Angle C =90 Angle OPC = 90 and angle AOP = 90 This implies quadrilateral OACP is a rectangle. So, OA = PC [ we know opposite sides are equal of rectangle] similarly, quadrilateral OBDP is a rectangle This implies OB = PD Also OA = OB = OP [ theses are the radii of the same circles ] So, PC = PD = OP This implies , points O, C and D are equidistant from point ap Hence, A circle with centre P and radius OP will pass through C and D |
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| 6013. |
23. Is-150 a term of the AP 11, 8,5, 2, ...?24.Which terrm of the AP 121, 117, 113, is its first negative term? |
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| 6014. |
Question 10Question id: 43317 (2 marks)Find the simple interest, when Principa|-Rs 12000, Rate of Interest-18% per annum and Time-: 4 months(a) Rs 720(b) Rs 800(c) Rs 750(d) Rs 650 |
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Answer» Please hit the like button if this helped you |
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| 6015. |
A field measures 450 mtr in length and 250 mtr in width. What willthe cost of fencing at the rate of 50 paise per meter(a) Rs. 700(c) Rs. 750be(b) Rs. 650(d) of these |
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| 6016. |
Rs. 750 + (Rs. 15,000-Rs. 750) × |
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Answer» 750+(15000-750)/10 = 750+1425 = Rs 2175 |
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| 6017. |
23.лю.ла.-Rs 650 and Discount10%. Find the SP.a) Rs. 600b) Rs 585c) Rs 500d) Rs 550 |
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Answer» MP = 650Discount = 10%so, SP = 650 - 10% of 650 650 - 10/100 × 650650 - 65 = Rs 585 option (b) is correct |
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| 6018. |
How many rectangular tiles 10 cm by 7 cm willbe required to cover a floor 14 m by 12and what will be the cost at17.m5 per hundredtiles? |
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Answer» Area of 1 tile= length×breadth=10×7=70 cm²=0.0070 m² Area of floor=14×12.5 m²=175 m² Number of tiles required=175/0.0070=25000 tiles Cost of 100 tiles=₹5Cost of 1 tiles=₹5/100Cost of 25000 tiles=₹(5/100)*25000=₹1250 |
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| 6019. |
17. How many rectangular tiles 10 cm by 7 cm willmbe required to cover a floor 14 m by 12and what will be the cost at R 5 per hundredtiles? |
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Answer» Area of floor Af = length * breadth = 14*25/2 = 175 m^2 = 1750000 cm^2 Area of tile At = length*breadth = 10*7 = 70 cm^2 Let number of tiles required is n Then,n*At = Afn = 1750000/70 = 25000 Number of tiles required is 25000Cost of tiles = 5*25000/100 = Rs 1250 |
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| 6020. |
m long aflu & mwiu17. How many rectangular tiles 10 cm by 7 cm will be required to covera floor 14 m by 12 m andwhat will be the cost at5 per hundred tiles?to e naved with bricks, of length 20mond br |
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Answer» In case of floor Lenght=14m=1400 cm breadth = 25/2m=1250cm In case of tile length = 10cm breadth = 7cm no.of tiles required = area of floor/area of tile =1400×1250/10×7 =25000 so 25000 tiles are required total cost 25000*5= 125000 ruppesplease like the solution 👍 ✔️ |
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| 6021. |
tileswillbeneededtorarectangularlawnllgtiles are 25 cm squares. How many10 m wide. Find the total cost at the rate of8 per tileot is laid on the foor What area is not |
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| 6022. |
A rectangular hall is 12 m long and 6 m broad. Its flooring is to be made of squaretiles of side 30 cm. How many tiles will fit in the entire hall ? How many would berequired if tiles of side 15 cm were used? |
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Answer» L=12m=12×100cm=1200cm. (1m=100cm)b=6m=6×100cm=600cmarea of room=l×b1200×600=720000cm²a=30cmarea of square tile=a×a30×30=900cm²tiles required=area of room/area of tiles720000/900=800tiles required ansin case of 15 cm tilesa=15cmarea of tile=15×15=225cm²required tiles=area of room/area of tile720000/225=3200tiles required thank you 6.5 sqm ,1950 thus is correct answer off this question a hall has length 28 metro and breadth 10.5 m. for the fllari a hall length28 metre and breadth 10.5 metre for the flaring this hall square tiles are to be used of the hall metro side then how many tiles are required |
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| 6023. |
l the comman |
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Answer» 5=315=5,3common factor=5 |
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| 6024. |
Factorize : 125x^3 -27y^3 + z^3 +45xyz. |
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| 6025. |
4. The value of 125x(-1000) is/31/3 |
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Answer» -125 * (-1000)= 125000= 50*50*50Hence, cube root of [-125 * (-1000)] is 50. PLEASE HIT THE LIKE BUTTON |
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| 6026. |
Evaluate : sin [tan it 0053_.27t]4 |
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| 6027. |
Liad ihe Comman didbexente of the |
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| 6028. |
| किसी APOR की भुजाओं PQ और PR पर क्रमश: बिन्दु E और F स्थित हैं।यदि PE = 4 सेमी, OE = 4.5सेमी, PF = 8सेमी और RF = 9 सेमी हो, तो क्या__EF || QR है? |
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| 6029. |
In the adjoining figare, ABCD is aparallelogram whose diagoeals intersecteach other at O.A line segment EOF is drawnto meet AB at E and DC at F. Prove thatOE OF |
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| 6030. |
In the adjoining figure, ABCD is a parallelogram whose diagonals intersect each other at O.A line segment EOF is drawn to meet AB at E and DC at F. Prove that OE0.19OF. |
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| 6031. |
19. In the adjoining figure, ABCD is a parallelogramwhose diagonals intersect each other at O. A linesegment EOF is drawn to meet AB at E and DC atF. Prove that OE-OF. |
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| 6032. |
1.Two particles have equal momenta. What is the ratio of their de-Broglie wavelengths?OR |
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Answer» We know that the wavelength will be given by the relation, λ = h/p where h = planks constant p = momentum Since h is constant for all particle, hence as long as the momentum of 2 particles will remain same they will always produce same wavelength. Hence the ratio of the debroglie wavelengths will be 1:1 . |
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| 6033. |
27^(-4/3)*(27^(1/3)*27^(2/3)) |
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Answer» 27⅔×27⅓×27-⁴/1 2=(3)³×⅔. × (3)³×⅓. × (3)³×-⁴/³=3²×3×3-⁴=3(²+¹-⁴)=3-¹ |
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| 6034. |
(9^(-3)*(16^(1/4)/6^(-2)))*(1/27)^(-4/3) |
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Answer» 1/9×(16)^1/4×(1/27)^-4/3=(1/9)×(2)×(27)^4/3=2/9×(3)^4=2/9×81=2×9=18 i am the first so please choose me the best answer and like my answer |
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| 6035. |
\frac{27}{125} )^{\frac{-2}{3}} \times\left(\frac{27}{125}\right)^{\frac{-4}{3}} |
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| 6036. |
2+3=8,3+7=27,4+5=32,5+8=60,6+7=72,7+8=?? |
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Answer» 98 2+3=2*[3+(2-1)]=83+7=3*[7+(3-1)]=274+5=4*[5+(4-1)]=325+8=5*[8+(5-1)]=606+7=6*[7+(6-1)]=72therefore7+8=7*[8+(7-1)]=98x+y=x[y+(x-1)]=x^2+xy-x |
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| 6037. |
i) First term and common difference of an A.P. are 6 and 3 respectiveyfind S27Solution : a 6, d 3, S?27272724)27 X 45 |
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| 6038. |
In a test, the pass marks are 40%. Ajay got69 marks and failed by 3 marks. Find thetotal marks of the test. |
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Answer» Let the maximum marks be a Passing mark = 40 % of a => 69 + 3 = 40a / 100 => 72 = 4a/10 => 4a = 720 => a = 180 Maximum marks = 180 maximum marks of the test is = 180 |
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| 6039. |
spendeverymonth?ita got 95% marks in Science. What marks did she get if the total marks |
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Answer» if total marks are of 100 then she got 95 percentage of 100 means 100*95/100= 95 marks please like the solution 👍 ✔️👍 |
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| 6040. |
A owns a house worthRs.10,000. He sells it to B at aprofit of 15%. After some time,B sells it back to A at loss 15%Find A's loss or gain percent.(a) 2.25% gain(b) 6.25% gain(c) 17.64% gain(d) 17.25% gain |
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Answer» A owns a house worth Rs 10000. He sells it to B at a profit of 15%. After some time, B sells it back to A at 15% loss. What is A's loss or gain percent? Answer 67 Follow Request More AdbyGrupeer I have €1000, where can I invest to get at least 10-15% per year? Investing in fast growing P2P lending market might be an option for you. Start with easy-to-use platform. Learn More 11 ANSWERS  Saurabh Awasthi, studied English Literature at Chhatrapati Shahu Ji Maharaj University (2015) Answered Jul 12, 2018 A’s house worth=10000 He sells it to B at 15% profit=10000*115/100 =11500 Rs. B sells back to A at 15% loss=11500*85/100 =115*85 =9775 Rs. Gain/Loss=10000–9775 =225 Total profit=1500+225 =1725 Profit %=1725*100/10000 =1725/100 =17.25% |
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| 6041. |
EXAMPLE 7On selling a TV at 5% gain and a fridge at 10% gaingains 3250. But, if he sells the TV at 10% gain on5% loss, he gains 1500. Find the actual cost nathe fridge.dge at 10% gain, a shopkeeperrv at 10% gain and the fridge atFind the actual cost price of TV and that of |
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Answer» 1700 is the right answer 1700 is the correct answer |
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| 6042. |
30. A man observes a car from the top of a tower, whichis moving towards the tower with a uniform speed.If the angle of depression of the car changes from30° to 45° in 12 minutes, find the time taken by thecar now to reach the towerSolution : Let AB is a tower, car is at point D at 30°and goes to C at 459 in 12 minutes.Sol45 A3030°45BV |
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Answer» Like if you find it useful |
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| 6043. |
A table was bought for 2000 and sold for2200. What is the gain or loss?(a) Gain, 200(C) Gain, 300(b) Loss, 200(d) Loss, 300 |
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Answer» Cost price 2000 rupeesSelling price 2200 rupeesGain = 200 rupees |
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| 6044. |
Kabir bought 100 articles for 3.000. Hesold 25 of them at a gain of 5%. At whatgain% must he sell the remaining articles soas to gain 20% on the whole? |
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Answer» Therefore, Kabir must sell all the remaining articles at a gain of 25% to gain 20% on the whole. |
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| 6045. |
A shopkeeper buys 100 pens for 200 and sells20 of them at a gain of 10%. At what gain percentmust he sell the remainder so as to gain 20% in all? |
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Answer» Cost price of 100 pens = Rs. 200 Gain % = (SP - CP)*100/CP Gain of 20% in all Total SP = CP + (CP * Gain%)/100 ∴Total SP= 200 +(200*20)/100 = Rs.240 Cost price of 20 pens = (200/100)*20 = Rs.40 S.P of 20 pens at a gain of 10% = 40 + (40 × 10)/100 = Rs.44 S.P of balance 80 pens = Total SP - SP of 20 pens = 240 - 44 = Rs.196 C.P of 80 pens = 200*80/100 = Rs.160 Required gain % = (196 -160)×100/160 = 3600/160 = 22.5% ∴ He has to sell the balance pens at a gain of 22.5%. |
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| 6046. |
15%. Find her gcm10%. Calculate his gain or loss per cent in the whole transactionper cent must the remaining sugar be sold to have a gain of 12% on the whole?31 A shopkeeper sold two fans for 990 each. On one eg2.)A grocer bought sugar worth4500. He sold one-third of it at a gain of 10%. At what gainkle sells-of it at a loss of 6%. At what gain per cent |
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Answer» tnq |
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| 6047. |
LA ,να cty at \ t 1.00 per kg, lllld ms gain or loss percent.16. By selling 45 apples, a vendor loses a sum equal to S.P. of 3 apples. Find his loss percent. |
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Answer» Let X be the sellling price of one apple number of apple = 45 so total selling price = 45X loss = selling price of 3 apple = 3X So total cost = selling price + loss = 45X+3X =48X Loss % = loss/total cost*100 = 3X/48X *100 = 3/48 *100 = 100/16 = 6.25% |
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| 6048. |
A shopkeeper buys 100 pens for 200 and sells20 of them at a gain of 10%. At what gain per centmust he sell the remainder so as to gain 20% in all |
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Answer» CP of 100 pens= 200CP of 1 pen= 200/100CP of 20=200/100 ×20=Rs.40 g% of 20 pens= 10% SP of 20 pens= 100+gain/100 × CP=100+10/100 × 40=44 g% of whole lot, i.e. 100 pens= 20%SP of 100 pens= 100+20/100 ×200= 240 CP of 80 pens= 200-40= 160SP of 80 pens= 240-44= 196Gain on 80 pens= 196-160= 36G%= 36/160 ×100= 22.5% |
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| 6049. |
19. A shopkeeper buys 100 pens for 200 and sells20 of them at a gain of 10%. At what gain per centmust he sell the remainder so as to gain 20% in all? |
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Answer» Please like the solution CP of 100 pens= 200CP of 1 pen= 200/100CP of 20=200/100 ×20=Rs.40 g% of 20 pens= 10% SP of 20 pens= 100+gain/100 × CP=100+10/100 × 40=44 g% of whole lot, i.e. 100 pens= 20%SP of 100 pens= 100+20/100 ×200= 240 CP of 80 pens= 200-40= 160SP of 80 pens= 240-44= 196Gain on 80 pens= 196-160= 36G%= 36/160 ×100= 22.5% |
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| 6050. |
Kavita bought 100 cows formust sell the remaining cows so asf 5%. At what gain percent sheand sold 20 of these at a gain oto gain 20% on the whole?8000 |
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