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| 6051. |
Calculate the gain or loss percentb).C.P-71500;S.P=ă1650 |
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Answer» CP = 40 SP = 50 GAIN PERCENTAGE = (50-40)/40*100 = 25% CP=1500 SP=1650 GAIN PERCENTAGE = (1650-1500)/1500*100 = 10% |
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| 6052. |
Exercise 5A shopkeeper bought a suit case for480 and sold it for540. Find his gain percent?liu loss percent? |
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Answer» CP = 480 SP = 540 GAIN PERCENTAGE = (540-480)*100/480 = 60*100/480 = 12.5% If you find this answer helpful then like it. |
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| 6053. |
6·The mean proportional between 234 and 104 is |
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Answer» The mean proportional=√234*104=√24336=156 how to find square root of a large no. |
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| 6054. |
What is the mean proportional 16 and 25 |
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| 6055. |
13 If b is the meanproportional between a and c, prove that (ab + be) is the meanproportional between (a2 + b2) and (b2 + c2). |
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Answer» here it is clearly given that b is the mean proportional between a and c . therefore, b^2 = ac Now (a ^2+b^ 2)(b ^2+c ^2) = (a ^2+ ac )( ac +c^ 2) , (a ^2+b^ 2)(b ^2+c ^2) = a(a + c ) c( a + c ) , (a ^2+b^ 2)(b ^2+c ^2) = a c (a + c )^2 , (a ^2+b ^2)(b^ 2+c ^2) = b^2 (a + c )^2 (a ^2+b ^2)(b ^2+c ^2) = (ab + bc )^2 |
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| 6056. |
What is the mean proportional of 4 and 25. |
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Answer» Mean proportion= √a×b. =√4×25. =√100 =10 |
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| 6057. |
(4) What is the mean proportional of 4 and 25? |
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| 6058. |
10% loss on selling price is what percent losson the cost price? |
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Answer» Let the cost price be 11 rupees.If he solds it for 10 rupees Loss on SP=1x(100/10)= 10%Loss on CP=1x(100/11)= 9.09% |
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| 6059. |
12. If q is the mean proportional between p and, prove that: |
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| 6060. |
find the gain or loss percentCP=500, overhead expenses = 50 and = 600 |
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Answer» Thank u Anna !!!!? |
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| 6061. |
uestion hmers2 to br cui25. A plane left 30 minutes later than the schedule time. In order to reach its destination1500 km away in time, it has to increase the speed by 250 km/hr. Find its usual speed. |
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Answer» Sol:Let the usual time taken by the aeroplane = x km/hrDistance to the destination = 1500 kmCase (i)Speed = Distance / Time = (1500 / x) HrsCase (iI)Time taken by the aeroplane = (x - 1/2) HrsDistance to the destination = 1500 kmSpeed = Distance / Time = 1500 / (x - 1/2) HrsIncreased speed = 250 km/hr⇒ [1500 / (x - 1/2)] - [1500 / x] = 250⇒ 1/(2x2- x) = 1/6⇒ 2x2- x = 6⇒ (x - 2)(2x + 3) = 0⇒ x = 2 or -3/2Since, the time can not be negative,The usual time taken by the aeroplane = 2 hrsand the usual speed = (1500 / 2) = 750 km/hr. |
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| 6062. |
A plane left 30 minutes later than the schedule time and in order to reach the destination1500 km away in time it has to increase its speed by 250 km/hr from its usual speed. Find itsusual speed. |
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| 6063. |
31. An old lady while boarding a plane got hurt 3and the captain immediately called for themedical aid. Thus the plane left with the lady,30 minutes later than the scheduled time.Then in order to reach its destination 1500 kmaway in time, it has to increase its speed by250 km/hr from its usual speed. Find theusual speed of the plane. (Delhi 2010 C) |
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Answer» Given: distance=1500km Let the original speed of a plane =x km/h New speed= x+250 ( speed increase by 250 km/h) Time taken at original speed = distance/ speed= 1500/x h Time taken at new speed = distance/ speed= 1500/x+250 h ∴ 1500/x = 1500/x+250 + 30/60 (30 min= 30 /60= 1/2 hr) 1500/x = 1500/x+250 + 1/21500/x - 1500/x+250= 1/2 (1500 (x + 250) - 150 x)/ x(x+250)= 1/2 (1500x +1500× 250 - 1500x)/ x(x+250)= 1/2 1500×250 / x² +250 x = 1/2 2(1500×250) =x² +250 x 2(375000) =x² +250 x 750000 =x² +250 x x² +250 x - 750000=0 x² +1000x - 750x -750000=0 x(x+1000) - 750(x+ 1000)=0 (x+1000) (x-750) =0 (x+1000) =0 x= -1000 ( speed cannot be negative)(x-750) =0 x= 750km/h Like my answer if you find it useful! |
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| 6064. |
plane left 30 minutes late than the scheduled time and other reach to the Seasons 1500 away in time in it had to increase speed per hour find the speed |
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Answer» Let the usual time taken by the aeroplane = x km/hrDistance to the destination = 1500 km --------Speed = Distance / Time = (1500 / x) Hrs ------------Time taken by the aeroplane = (x - 1/2) Hrs Distance to the destination = 1500 kmSpeed = Distance / Time = 1500 / (x - 1/2) HrsIncreased speed = 100 km/hr[1500 / (x - 1/2)] - [1500 / x] = 100150((10/x-1/2)-10/x0=10015 /x -1/2- 15/x =130x -30x +15=2x^2-x15=2x^2-x2x^2-x-15=02x^2 - 6x+5x-15=02x(x-3)+5(x-3)2x+5=0 or x-3 =0x=-5/2 or x=3 Since, the time can not be negative,The usual time taken by the aeroplane = 3hrsand the usual speed = (1500 / 3) = 500km/hr |
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| 6065. |
A car left 30 minutes later than the schedule time. In order to reach its destination 150km away in time, it has to increase its speed by 25km/hr from its usual speed. Find its usual speed. |
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| 6066. |
23A plane left 30 minutes late than its scheduled time and in order to reach thedestination 1500usual speed. Find its usual speed.km away in time, it had to increase the speed by 250 km/h frorn the |
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| 6067. |
5) The larger of two supplementary angles exceeds the smaller by 18° Find them.8 |
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| 6068. |
f the area ol two Sal ulalgies are equal, prove thal tiey die con118. A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km awayin time, it had to increase its speed by 100 km/h from the usual speed. Find its usual speed. |
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| 6069. |
sh starts for his friend's house at 9:30 a.m. He reaches there 45 minutes later. At whatdoes he reach his friend's house?DcePogs |
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Answer» He reaches his friend's home at 10.15 |
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| 6070. |
Ul thei Teliprocals is2020. Divide 16 into two parts such that twice the square of the largerexceeds the square of the smaller part by 164 |
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| 6071. |
x+\frac{1}{x}=\sqrt{5} \quad \text { find } x^{4}+\frac{1}{x^{4}} |
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| 6072. |
6. A and B can do a job in 15 days. They work together for 6 days and then B leaves. If A cando the job alone in 50 days, how long will he take to complete the unfinished job? |
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Answer» if Ram and Raman can do a job in 12 days and 18 days respectively .How many days would they take complete the job altogether |
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| 6073. |
32 men can finish a piece of work in 20 days.Then how many men would be required tofinish the work in 16 days? |
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| 6074. |
If the mean proportional between x and 2 is 4, find x |
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| 6075. |
The side of a rhombus is 5 cm. If the length of one diagonathe length of the other diagonal.of the rhombus is 8 em, then find |
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Answer» it is 6 cm |
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| 6076. |
ABCD is a trapezium in which AB | DC and its diagonaUising Basic Propartionality theomeove thats intersect each other a |
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Answer» Given: □ABCD is a trapezium where, AB ll CDDiagonals AC and BD intersect at point O. Construction: Draw a line EF passing through O and also parallel to AB. Now, AB ll CD, since by construction, EF ll AB ⇒ EF ll CDConsider the ΔADC,EO ll DCThus, by Basic proportionality theorem, (AE / ED) = (AO / OC) .... (i)Now, consider Δ ABD, EO ll AB,Thus, by Basic proportionality theorem, (AE / ED) = (BO / OD) .... (ii)From (i) and (ii), we have, (AO / OC) = (BO / OD) (since L.H.S of i and ii are equal)Hence we proved that, (AO / OC) = (BO / OD) hit like if you find it useful |
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| 6077. |
A tile is a square of side 25 CM. how many such tiles would be required to cover floor of a square bathroom of side 3m. |
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Answer» Area of tile = side² = (25)² = 625 cm² Area of sqaure floor = 3² m² = 9 m² 1 m = 100 cm 1 m² = 100,00 cm² So, tiles needed = Area of sqaure floor/Area of tile Tiles needed = 900,00/625 = 144 tiles thank you so much sir |
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| 6078. |
A square tile is having side of length 15cm . How many such tiles would be required to cover the square floor of a bathroom of side 3m ? |
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Answer» Area of a square tile=side^2=15^2=225cm^2Area of bathroom =side^2=3^2=9m^2=90000cm^2HenceNumber of tiles=90000/225=400tiles |
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| 6079. |
4./ Subtract - 6 from 3 and 3 from – 6. Are the results same? |
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Answer» no,the result is not same result is not same.best answer 3-(-6). -6-3=3+6. =-9=9results are not same |
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| 6080. |
12. A tile is a square of side 20 cm. How many suchtiles would be required to cover the floor of asquare bathroom of side 3 m? |
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Answer» From which book have you taken this question? Please tell us so that we can provide you faster answer. |
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| 6081. |
6. A square tile is having side of length 15 cm. How many such tiles would berequired to cover the square floor of a bathroom of side 3 m? |
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| 6082. |
The side of triangle are in the ration 3:2:5 and its perimeter is 30 cm. the length of thelongest side is.(a) 20 cm (b) 15 cm (c) 10 cm (d) 12 cm |
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Answer» b is the answer 15 cm 20 is the right answer for this b is the right answer 15 cm |
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| 6083. |
8. A rectangular wall is 27 m long, 60 cm thick and 4 m high. If cube-shapbricks of side 30 cm each are used, how many bricks will be required tothe wall? |
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Answer» volume of rectangular wall = 27*0.6*4 = 64.8 m³ volume of cube = 0.3³ = 0.027 m³ No of bricks = 64.8/0.027 = 2400 bricks |
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| 6084. |
x.3.Ifp,q,r,s and t are 5 consecutive odd numbers, theverage is |
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Answer» no ur wrong |
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| 6085. |
parane0 ABCD is a parallelogram whose diagonals intersect each other at right angles. Ifthe length of the diagonals is 6 cm and 8 cm, find the lengths of all the sides ofthe parallelogram. |
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Answer» ABCD is a parallelogram whose diagonals intersect each other at O with 90°.so it's a rhombus as diagonals of rhombus interest each other at right angles. diagonal1 (AC) = 6cmdiagonal 2(BD) = 8cm OD = OB = 3cm eachOA = OC = 4cm each Let, us take triangle AOBit is a right angled triangle => (OA)² + (OB)² = (AB)² => (4)² + (3)² = (AB)² => 16 + 9 = (AB)² => 25 = (AB)² => = AB => 5 = AB So, AB = 5cmAB = BC = CD = AD (all sides of rhombus are equal) Each side of the parallelogram ABCD is 5cm. hit like if you find it useful |
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| 6086. |
ABCD is a parallelogram whose diagonals intersect each other at right angles. Ifthe length of the diagonals ithe parallelogram.s 6 cm and 8 cm, find the lengths of all the sides of of the parallelogram |
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| 6087. |
14.ABCD is a parallelogram whose diagonals intersectat O. If P is any point on BO, prove that(i) ar(AADO) ar(ACDO)(ii) ar(AARP)-ar(ACBP) |
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| 6088. |
parancologram.Aswhose diagonals intersect each other at right angles. fdiagonacm and 8 cm, find the lengths of all the sides ofABCD is a parallelogramngth of the diagonals is 6the length ofthe parallelogram. |
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| 6089. |
x+y=4 x-y=4 find x and y |
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| 6090. |
2·Two APs have the same common difference. The difference between their 100th terms!100, what is the difference between their 1000th terms? |
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Answer» Sol:Let two A.P's have the first terms a , a' and common difference d.Given that difference between their100th term is 100.then a + 99d - a' - 99d = 100⇒ a - a' = 100.Now difference between 1000 th term is⇒ a + 999d - a' - 999d= a - a'= 100∴ difference between 1000 th term is 100. |
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| 6091. |
4^x+4^x-1=24 . Find x |
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| 6092. |
IsBACis 309yclic quadrilateral whose diagonals intersect at a point E.If DBO-, find< BCD. Further, ifARH BOfind 2 ECD. |
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| 6093. |
In an AP if the comman difference =-4, and the seventh term (a7) is 4, than find the first term |
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Answer» an=a+(n-1)dheren=7A7=4d=-4hence4=a+6*-4a=4+6*4a=4+24=28 |
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| 6094. |
Two A.Ps have the same common difference. The difference between their 100th terms is100. What is the difference between their 1000th terms? |
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| 6095. |
27.TheHCFof2numbersis 23 and their LCM is 1449.lf one of the numbers is 161,findthe other. |
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| 6096. |
4. Find the value of €) +-604. Find the value of |
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Answer» answer::::::::::::::::2 |
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| 6097. |
The average of 11 results is 50.If the average offirst 6 results is 49 and the average of last 6results is 52, then find the 6th result? |
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Answer» 11*50=5506*49=2946*52=312550-(294+312)=56 =ans |
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| 6098. |
iuael Test Papverage of 40 results is 60 and average of 11. Iresults is 40. What is the average of all theresults?A) 1000) 58D) 4812. |
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Answer» Answer:D)48Explanation:60 * 40 = 240040 * 60 = 2400 (2400 + 2400) / (60 + 40) =>4800 / 100 =>48 The average is 48 |
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| 6099. |
if PQR is an equilateral triangle in which PQ- 4 cm and PXLQR, then find the valueIf 5 sine 4, then find the value of seci + tan6 is:4Find the value of(sin2θ tan20Page 1 of 7 |
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| 6100. |
If 45 subtracted from twice the greater of twonumbers, it results in the other number. If 22is subtracted from twice the smaller number,it results in the greater number, find thenumbers. |
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Answer» thank you |
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