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-2/3 is the correct answer of the given question

nos. -3×10 -2×10

=-30=-20

rational nos. = -29, -28

5/6+x=-1/2x=-1/2-5/6=(-3-5)/6=-8/6=-4/3

2y^2+7y+5let p and q be zerossum of zeros= -b/ap+q= -7/2product of zeros= C/apq= 5/2p+q+pq= -7/2+5/2=-7+5/2= -2/2=-1in my mobile alpha bita is not coming so I write p q

We know in fourth quadrant, x coordinate is positive and y coordinate is negitive.

Therefore, a > b .

So, b must be smaller

A) is the right answer

This series is an A.P

so, here a = -10 , d = 4

and 20th term will be

a20 = a+(20-1)d = -10+19*4 = 66

so, sum till 20 terms will be

s20 = n/2*(a+l) = 20/2*(-10+66) = 10*56 = 560.

Two rational between -2 and 5 are

-1, 0, 1, 2

Let the ten’s and the unit’s digits in the first number be x and y, respectively. So, the first numbercan be written as 10x + y in the expanded form.

When the digits are reversed, x becomes the unit’s digit and y becomes the ten’s digit. This number, in the expanded notation is 10y + x.

According to the given condition.

(10x + y) + (10y + x) = 66

11(x + y) = 66

x + y = 6 ... (1)

Youare also given that the digits differ by 2. Therefore,

either x – y = 2 ... (2)

or y – x = 2 ... (3)

If x – y = 2, then solving (1) and (2) by elimination, you get x = 4 and y = 2.In this case, the number is 42.

If y – x = 2, then solving (1) and (3) by elimination, you get x = 2 and y = 4.In this case, the number is 24.

Thus, there are two such numbers 42 and 24.

Here is a similar question.

Please mention what needs to be done with the question.

-41/7 is the correct answer of the given question

-41/7 is the correct answer

Each note amount is Rs 20

Total amount of 4 notes is Rs20×4=Rs80

Ans :- One note = 20 rupees 4 notes = 20 × 4 = 80 rupees

For equation x^2 - 8x + k let a and b are zeroes

Then, a + b = - (-8)/1 = 8ab = k/1 = k

Given, a^2 + b^2 = 40

(a + b)^2 = a^2 + b^2 + 2ab64 = 40 + 2k2k = 64 - 40 = 24k = 24/2 = 12

Alpha+ beeta= 3k/2= 93k= 18k= 6

Rational number with positive denominators:

iiMultiplying the number by−-1, we get:

−15−28=−15×−1−28×−1=1528-15-28=-15×-1-28×-1=1528

iiiiMultiplying the number by−-1, we get:

6−9=6×−1−9×−1=−696-9=6×-1-9×-1=-69

iiiiiiMultiplying the number by−-1,we get:

−28−11=−28×−1−11×−1=2811-28-11=-28×-1-11×-1=2811

ivivMultiplying the number by−-1,we get:

19−7=19×−1−7×−1=−197

which following integers as rational number 42

write three equal mint rice ratios numbers with denominator 98 - 105 and 245 corresponding rational number 2 by 7

let the numbers be (a-d),(a),(a+d)

therefore,ATP(a-d)+(a)+(a+d)=21thus,3a=21a=7

again,ATP

(a-d) (a) (a+d)=315(49-d*d)= 45 d*d=4thus,d=2. or -2

thereforethe numbers arewhen d=27-2 =57. =77+2 =9

when d=-27+2 =97 =77-2 =5

x/2 + 7 = 17/2

x+14 = 17

x = 3

Given, product of 2 rational no.s =48/5One of the no. is 66/7.So, let the other no. be 'x'. Now, A. T. Q. 66/7 * x = 48/5x=48/5 / 66/7x=48/5 * 7/66x=8/5 * 7/11x=56/55Hope it will helpvyou understand.....

Same as above it is right

the other national number is 14

Let ten rupees note=10x5 rupees note=5(x+3)=5x+1510X+(5x+15)=19515x+15=19515x=195-15=180X=12So,10 rupees note=12And 5 rupees note=x+3=15

He has 12 notes of 10 and 15 notes of 5 =

Suppose 50 rupee notes are x so 20 rupees notes are 2x Total 2700 Rs. 50×x + 20×2x = 2700 5x + 4x = 270 9x = 270 x = 30 50 rupee notes are 30.

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Explanation : x*x*x - 5x*x - 2x + 24 = x*x*x - 3x*x - 2x*x + 6x - 8x + 24 = x*x(x-3)-2x(x-3)-8(x-3) = (x-3)(x*x-2x-8) = (x-3)(x-4)(x+2)

Solution : (x-3)(x-4)(x+2)

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the correct answer is 12 sq.-m

alpha =1

beta =(-2)

by factorisation

1/alpha +1/beta

1/1+1/(-2)

1/2

hope you understand

The correct answer is 3/2

kx^2+4x+4=kx^2+2x+2x+4====x(kx+2)+2(x+2)=( x+2)(kx+2); x=2; k=-2

Given expressionx^2/2 - y^2/2 + 4xy

Terms and their Coefficients:

Term : x^2, Coefficient = 1/2

Term : y^2, Coefficient = - 1/2

Term : xy, Coefficient = 4

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